# Mathematics Grade 12 Paper 2 Western Cape Mock 2014 Memo > Grade 12 Mathematics Paper 2 memorandum from the Western Cape Mock Exam 2014, 8 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/2014-grade-12-math-trial-exam-paper-2-wc-memo-1/1b1abce6-82d3-499a-88ed-40a623c50e98 - Updated: 2026-09-27 - Subject: Mathematics - Grade: Grade 12 - Document type: Memorandum - Year: 2014 - Exam period: Western Cape Mock Exam - Paper: 2 - Curriculum: CAPS - Pages: 8 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Mathematics](https://www.hlayiso.com/library/grade-12/mathematics) › [Mathematics Grade 12 Paper 2 Western Cape Mock 2014 Memo](https://www.hlayiso.com/library/2014-grade-12-math-trial-exam-paper-2-wc-memo-1/1b1abce6-82d3-499a-88ed-40a623c50e98) ## About this document Mathematics · Grade 12 · Western Cape Mock Exam · 2014. Memorandum, 8 pages. 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Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com GANSBAAI ACADEMIA EKSAMEN V2 WISKUNDE September 2014 Graad 12 Totaal: 150 memo VRAAG 1 1.1 1522 ✓ 1522  101,47 ✓ 101,47 15 (2) 1.2 19,07 ✓ 19,07 ✓ 2 desimale plekke (2) 1.3 Onderste kwartiel  89 ✓ 89 Boonste kwartiel  113 ✓ 113 (2) 1.4 ✓ M by 100 ✓ Min=58 EN Max=145 ✓ Q1=89 EN Q3=113 (3) ✓✓ interval 1.5 ( x  1 ; x  1 )  (82,4 ; 120,54) ✓ antwoord  2 dae (3) [12] VRAAG 2 1 ### Page 2 Downloaded from hlayiso.com VRAAG 3 3.1  2  3 1  0  ✓ subst M ;   2 2  ✓ antwoord vir albei  1 1    ;   2 2 (2) 3.2  1 0  3  2  ✓ subst Mid BD  ;   2 2   1 1    ;   2 2 ✓ antwoord Middelpunt van AC en BD is dieselfde ✓ gevolgtrekking Halveer AC en BD mekaar (3) 3.3 20 2 ✓ M AD M AD   03 3 1  2  3 ✓ M CD M CD   20 2 2 3 ✓ =-1 M AD  M CD    1 3 2  AD  CD  ADˆ C  90 ✓ AD ˆ C  90 (4) 3.4 Diagonale halveer mekaar (3.2) ✓ halveer mekaar DWS ABCD is parallelogram ✓ parallelogram ˆ C  90 Vanaf 1.3: Omdat AD ✓ AD ˆ C  90 DWS ABCD reghoek ✓ reghoek M AC  M BD 1 5    1 5 1 AC  BD ✓ diagonal halveer mekaar loodreg Diagonale halveer mekaar loodreg ✓ afleiding DWS ABCD is ‘n vierkant (6) 3.5 2 1  3 ✓ gradient DC tan    3 02 2 ✓   56,30993247...  180 2  123,7 ✓ antwoord (3) 2 ### Page 3 Downloaded from hlayiso.com 3.6 OC 2  (2  0) 2  (1  0) 2 ✓ OC 2 OC 2  5  OC  2,236067977 ✓ antwoord OC  2 Buite sirkel of OC 2  (2  0) 2  (1  0) 2 OC 2  5  OC 2  4 Buite sirkel of x2  y2  4 (2) 2  (1) 2  5  4 Buite sirkel (2) VRAAG 4 4.1   8  0 1 5  ✓ subst Middelpunt AB ;   2 2   (4;3) (1) 4.2 5 1  2 ✓ subst M AD   03 1 ✓ M AD y  mx  c  5  20   c ✓ subst (0;5) c  5 ✓ antwoord y  2 x  5 (4) 4.3 AM  (5  2)  (0  4) 2 2 2 ✓ subst  4  16 ✓ vereenvoudig ✓ antwoord AM  20 (3) 4.4 ( x  4)  ( y  3)  2 2  20  2 ✓ ( x  4) 2  ( x  4) 2  ( y  3) 2  20 ✓ ( y  3)2 ✓  20  x  y  8x  6 y  5  0 2 2 ✓ antwoord (4) 4.5 AT  TK  6 ✓ AT=TK ✓ CD loodreg op AK CD  AK ✓ vlieër ACKD vlieër want diagonal CD halveer ✓ rede diagonal AK reghoekig. (4) ✓ [16] 3 ### Page 4 Downloaded from hlayiso.com VRAAG 5 5.1 cos( ). tan(180   ).cos(90   ) ✓ sin(180   ).sin(540   ) cos( ). tan(180   ).cos(90   ).cos(90   )  sin(180   ).sin(180   ) cos .(  tan  .sin  sin ( sin ) sin cos  cos sin 1 (7) 5.2.1 y  12 12 sin A  13 (3) 5.2.2 sin 2 A =2 sin A. cos A  12   5   2    13  13   120  169 (3) 5.3 1  cos 2 x  sin x sin 2 x  cos x 1  ( 1  2 sin 2 x)  sin x  2 sin x cos x  cos x 2 sin 2 x  sin x  2 sin x cos x  cos x sin x( 2 sin x  1 )  cos x( 2 sin x  1 ) sin x  cos x  tan x (6) 5.3.2 sin 2 x - cos x = 0  cos x( 2 sin x - 1 ) = 0 1 sin x  cos x  0 2 x  90  360k of x  30  360k k  Z x  270  360k x  150  360k (8) 4 ### Page 5 Downloaded from hlayiso.com 5.4 sin 38° = 1 a2  cos52  sin 38  1  a 2 sin 38  cos 52 cos 52. cos14  sin 52. sin 14 sin 38  cos 52  cos ( 52  14 ) sin 38  cos 52  cos 38 1  a2  1  a2  a 2 1  a2  a (5) VRAAG 6 6.1 a2 1 b 2 (2) 6.2 360 (1) 6.3 1 (1) 6.4 3 waardes van x (2) [6] 5 ### Page 6 Downloaded from hlayiso.com VRAAG 7 7.1 CAˆ D  180  (   ) sin[180  (   ) sin    x AC x sin   AC  sin(   ) En AB sin  AC  AB  AC sin x sin  sin   sin(   ) 7.2 40sin15sin70 AB  sin120  11,25m 7.3 40sin70 AC  sin120  43,4m 1 AREA ACD  AC .CD.sin  2 1  (43,4)(40) sin 50 2  664,93m 2 VRAAG 8 8.1 supplementêr ✓ antwoord (1) 8.2.1 Hoek tussen raaklyn en raduis ✓ antwoord (1) 8.2.2 Sˆ3  Sˆ 4  90 (raaklyn  radius) ✓ Stelling Nˆ  Nˆ  90 (raaklyn  radius) 1 2 ✓✓ Stelling & Rede Sˆ3  Sˆ 4  Nˆ 1  Nˆ 2  90  90  180 ✓ Rede  RNOS koordevierhoek teenst hoeke suppl  (4) 8.2.3 Sˆ  x 1 Sˆ1  Nˆ 2  x (Raaklyn koord stelling) ✓✓ Stelling, Rede ✓✓ Stelling, Rede Nˆ  Sˆ  x (basis hoeke gelykbenige Δ) 2 3 ✓✓ Stelling, Rede Sˆ1  Rˆ 2  x (hoeke in dieselfdesegment) ✓✓ Stelling, Rede Nˆ  Rˆ  x (hoeke in dieselfdesegment) 2 1 (8) 6 ### Page 7 Downloaded from hlayiso.com 8.2.4 Oˆ  Qˆ 2  Nˆ 2  Sˆ3  180 (Som van hoeke ΔOSN) Maar Sˆ  Nˆ (Teenst hoeke gelyke sye) 3 2  Oˆ1  Oˆ 2  2Sˆ3  180 Oˆ  Oˆ  Oˆ  180 (hoeke op reguitlyn) 1 2 3  Oˆ1  Oˆ 2  Oˆ 3  Oˆ1  Oˆ 2  2Sˆ3 2Sˆ  Oˆ 3 3 1  Sˆ3  Oˆ 3 2 (4) VRAAG 9 9.1 9.2.1 7 ### Page 8 Downloaded from hlayiso.com 9.2.2 9.3.1 9.3.2 9.3.3 8 ## Related documents - [2014 GRADE 12 MATH TRIAL EXAM PAPER 2 GP](https://www.hlayiso.com/library/2014-grade-12-math-trial-exam-paper-2-gp/f26f183d-a7d7-435f-a39a-fae92714ddb7) — Mathematics · QP · 2014 - [Mathematics P2 English November 2014(amended)](https://www.hlayiso.com/library/mathematics-p2-english-november-2014-amended/aea5827e-f832-419b-a9da-32ae8428f67c) — Mathematics · QP · 2014 · Eng - [2018 GRADE 12 MATH TRIAL EXAM PAPER 2 WC OVERBERG](https://www.hlayiso.com/library/2018-grade-12-math-trial-exam-paper-2-wc-overberg/2c04b71b-1ce2-4985-8996-aec90790d60b) — Mathematics · QP · 2018 - [LP Maths Grade 12 June 2024 P2 and Memo](https://www.hlayiso.com/library/lp-maths-grade-12-june-2024-p2-and-memo/ae975968-03fb-478d-83f9-e424fe245c15) — Mathematics · Memo · 2024 - [MATHS P2 GR12 MEMO SEPT 2022 Afr English](https://www.hlayiso.com/library/maths-p2-gr12-memo-sept-2022-afr-english/484afb47-d30d-4a37-b0fc-e0cc6e34a50f) — Mathematics · Memo · 2022 · Eng - [FS Maths Grade 12 SEPT 2022 P2 and Memo](https://www.hlayiso.com/library/fs-maths-grade-12-sept-2022-p2-and-memo/99fbca0f-2edf-40fb-8442-d4705610d749) — Mathematics · Memo · 2022 ## More from Grade 12 Mathematics - [MATHS P1 ANSWER BOOK GR12 SEPT 2025 English Afrikaans watermark](https://www.hlayiso.com/library/maths-p1-answer-book-gr12-sept-2025-english-afrikaans-watermark/d78c3fd3-dcd5-4f3f-911b-e5635b4686cc) — Addendum · 2025 · Afr - [Maths Grade 12 NSC P2 QP September 2025 Gauteng](https://www.hlayiso.com/library/maths-grade-12-nsc-p2-qp-september-2025-gauteng/1d6bf7fd-d288-4a01-99f7-2c87e247760c) — QP · 2025 - [Maths Grade 12 NSC P2 QP September 2025 Afr Limpopo](https://www.hlayiso.com/library/maths-grade-12-nsc-p2-qp-september-2025-afr-limpopo/f2f8d481-5d87-4e89-bb21-6077bbcf403d) — QP · 2025 · Afr - [Maths Grade 12 NSC P1 QP September 2025 Afr Northern Cape](https://www.hlayiso.com/library/maths-grade-12-nsc-p1-qp-september-2025-afr-northern-cape/f5b3a4ce-fa91-4475-96e0-0654a87e1405) — QP · 2025 · Afr - [Maths Grade 12 NSC P2 QP September 2025 Eng Northern Cape](https://www.hlayiso.com/library/maths-grade-12-nsc-p2-qp-september-2025-eng-northern-cape/4ede8207-ca82-4419-bae1-fae734498cc7) — QP · 2025 · Eng - [MATHS P2 ANSWER BOOK GR12 JUNE 2024 Afr+English](https://www.hlayiso.com/library/maths-p2-answer-book-gr12-june-2024-afr-english/4a71e975-4ac4-4f55-8e23-0b8155a5b0c6) — Addendum · 2024 · Eng ## Collection - [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. 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