# Physical Sciences Grade 12 P2 North West November 2017 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the North West November 2017, 8 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/2017-chemistry-memo-p-2-nw/4aa82fd9-e55f-4bd5-8223-f29b62376369
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2017
- Exam period: North West November
- Paper: 2
- Curriculum: CAPS
- Pages: 8

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## About this document

Physical Sciences · Grade 12 · North West November · 2017. Memorandum, 8 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

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### Page 1

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PhysivalSvienvewP2 NW/September'201%- 4
NSC — Momorandum

QUESTION 1 (Start on a new page.)

110 Cv (2)
12 AW’ 2)
13° BYY 2)
14. Cv 2)
15 AVY (2)
16 Cry (2)
17 AW 2)
18 BYY 2)
19 Dv @)
110 Dvv (2)

[29]

QUESTION 2 {Start on a new page.}

24
24.1 EV Q)
241.2 FY - (1)
213 BY a)
214 DY (1)
22 Busan 2)
2.3
2.3.1 Propyl ethanoate. vv” (2)
2.3.2
aan
—c—te—o w
| I | |
H H H H : .
Marking criteria structural formula:
* Three carbons in longest
N.B. Accept condensed -OH chain
* OH-group on terminal
carbon
Notes:
« One or more H-atoms
omitted: %
« Condensed or semi-
structural formuta:1/2
(2)
uinpueiowiew — OSN toys i

Pn bVOSHOCRURIES/ MAN OL ZqeBBoUsINgeo}shYg

### Page 2

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Physical Sciences/P2 NW/September 2017
NSC — Mermorendum

QUESTION 3 (Start on a new page.)

3.4
3.1.1 Substitution(halogenation/bromination) (1)
3.1.2. Substitution(hydrolysis) ” )
3.1.3. Elimination V e:.iif i OtiC (1)
3.2 CHsCHBrCHs + KOHY —CHsCHCH2z +H20+ KBr bal v’ 3)
N.B. Max 1/3 if extra product or reactant is written
3.3
3.3.1 Ethanoic acid ¥% (®)
3.3.2

-—O—H ve wot You

=p
ie
mp

beet ty a ae

ny Es
3)
[N.B. Accept linear molecule of water. |
3.4
3.4.1 Heat/ Suntight/ UV light or rays/ Sun rays. (1)
3.4.2 Hydrogen bromide. v (1)
3.5
3.5.1 A polymer formed when two monomers combine through an
addition reaction. vv (2)
3.5.2
iy ‘ Marking criteria structural formula:
c= vv * Two carbons in chain
| i ¢ Whole structure correct
HOA Notes:
« Qne or more H-atoms omitted %
* Condensed or semi-structural
formula 1/2
(2)

9)

Pamerinht exnanind Dlanan tien mtine

### Page 3

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Physical Sciences/P2 NWiSeptember 2017

NSC - Memorandum

QUESTION 4 (Start on a new page.)

44
4.1.1 Aseries of organic compounds that can be described by the same
general formula. Vv“ (2)
OR
A series of organic compounds in which the members differ from the
next with a —-CHz group.
42 Alcohol. v @)
43 :
4.3.1 Molecular mass(of different homologous series), (1)
[N.B. Accept surface area, chain length/contact area. |
4.3.2 Vapour pressure. (1)
4.3.3. The larger the molecular mass, the lower the vapour pressure (2)
OR
The smaller the molecular mass, the higher the vapour pressure.
[IN.B. Accept surface area/chain length/contact area’ |
44 Butane
¢ Weak” London forces between its molecules” (2)
OR

» London forces between its molecules”
« less energy is needed for molecules to break out of liquid and form
vapour 7

* Butan -1-o}
« —alcohol, has strongerv hydrogen bonds between its molecules” = (2)
OR
* Hydrogen bonds between its molecules. v
» lots of energy is needed for molecules to break out of liquid and form
vapoury”

4.5 Compound Dv or (Butanol)
« thas stronger hydrogen bonds between its molecules”
« Therefore more energy is required to break the bonds between the
molecules” Juries @)
[N-B. Accept it has lowest vapour pressure. |

[14]

Dianna beim mune

### Page 4

Physical Sciences/P2

NSC - Memorandum

QUESTION 5 (Start on a new page.}

5.1
5.2

5.3

5.4

.

CO2(g) forms during the reaction.

Downloaded from hlayiso.com

NW/September 2017

(1)

4Qs. v The mass of the beaker and its contents remained 60,00g. (2)

NCOz (reacted) = mae
,
= 200

a4
= 0,05 molY

(C02) at STP = n(CO,) x Vmv

= (0,05 x 22 ,4)¥v
= 1,12 dmv"

OR

1 mol = 22,4dm>
0,05mol - X
X= 1,12 dm

More particles per unit volume. ~

More HC£ molecules have enough kinetic energy and

correct orientation.

More effective collisions take place per second/ per unit time.

[N-B. Accept: Higher frequency of effective collisions |

Pantirint enamine

@)

(3)

[12]

Dianna dunn anne

### Page 5

Physical Sciences/P2
NSC — Memorandum

QUESTION 6 (Start on a new page.)

6.1 A reversible reaction in which the rate of the forward reaction

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Nw September 2017

equals to the rate of the reverse reaction. vv" (2)
=
6.1.4 n(NHs) =
= BS,
7
= 1,5 mol
Nag | 3H2jg) | ZNHaig)
Initial quantity(mol} 3 8 0
Change in (mol) 0,75 2,25 1,5v | Ratiov
Quantity at equilibrium(mol) 2,25¥ | 5,75” 1,5
Equilibrium concentration (mol.dm?) Divide
by 5v
_ NEP v Wrong Ke expression Max 6/9
IN, IP
No Ke expression Max 8/9
= 03" oy
(0,45)01.15)°
=0,13V (9)
6.1.2 | Smaller than v
¥ Ke Iv 2)
6.1.3 y Decrease”
Increases in temperature favours the reverse reaction
{endothermic reaction) v’ less product is formedv’, Ke value
decreases. V (4)
N.B. a) Accept: equilibrium position shifls to the left.
b) The sign ¥ means negative marking in 6.1.2 &
6.1.3 above
17]

Comurinht enennind Dtanan tim nuine

### Page 6

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Physical Sciences/P2 NW/September 2017

NSC ~Memorandum

QUESTION 7 (Start on a new page.)

7A
7.1.1. A substance that can act as an acid and as a base. Vv (2)
7.12 Acid.
It is a proton donor/it donates a proton. v (2)
7.4.3 PO*«(aq) “ (1)
7.2
7.24 Basic. v (1)

7.22 pH=-log[H]
13,3¥ =~ log [H*]
[H*] = 5,01 x 104 mol.dm?
10
[#"]
10"

* Fom0*
= 0,2 mol.dm*v (5)

[OH] =v

= N.B Positi ing - 7.2.2 to 7.2.3.
CBYb mn ositive marking - 7.2.2 to 7.2.3.

Cal785) vy = 1y
(0.2(25) 2

Ca = 0,14 moldmsv (5)

7.24 X+16+1=56
X = 39 g.mol!v
X= K (potassium) ¥ {2)

### Page 7

Physical Sciences/P2 NWiSeptember 2017

NSC - Memorandum

QUESTION 8 (Start on a new page.)

8.1. A solution/ liquid/ dissolved substance that conducts electricity through
movement of ions. vv @)

8.2 Salt-bridge. v
- completes the circuit! cell.
- maintains the ceil neutrality.

- Supplies a path through which ions can move to restore neutrality. (2)
8.3 BY Lead is a stronger reducing agent than than Phy’ and Mg will be
oxidised to Mg? (3)
8.4 — Pb(NOs)2 or Pb?(aq)“or any saline solution with the corresponding ion
as the cathode. (2)
85
8.5.1 Mg(s)“ —- Mg@Maq) + 2e “ (2)
Notes:
Mg(s) = Mg?*aq) + 2e° (1/2) Mg?(aq) + 2e° + Mg(s) (2/2)

Mg(s) -- Mg*aq) +20" (0/2) Mg*faq) + 2e" = Ma(s) (0/2)

8.5.2. Mg(g) | Mg?*(aq)( (1 mol-dm) I! (1 mol-dmv3)H*(aq) | H2(g) Pt(s) (3)
OR
Ma(g) | Mg?aq) Il H*(aq) | He(g) Pt(s)
OR
Mg(g) | Mg?* (1 mol-dm) II H* (1 mol-div) | Ha(g) Pt(s)
OR
Mag(q) 1 Mg il H* t H2(g) Pi(s)

8.6 - It has Pt as inert/ does not react with the H* ions OR acid.
- It has Pt as a conductor (of electricity) . (1)
[15]

N.B. QUESTION 8.6, subtract that 1 mark from the total (i.e 14 marks for it)
and hence GRAND TOTAL will be 149 instead of 150 for the paper.

Ranutinkt rannniae Dianna tere mune

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bm hlayiso.com

### Page 8

°
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Physical Sciences/P2 9 NW/September 2017
NSC — Memorandum
QUESTION 9 (Start on a new page.)
9.1 Electrode where reduction takes place Vv“ (2)
9.2 Tv the negative electrode/ cathode “ (2)
93 Cus) > Cu* + 2ev¥ (2)
Notes:
Cus) = Cutag)+2e (1/2) CuPtag)+2e *-Cus) 2/2)
Cu(s) ~ Cu?%ag)+2e (0/2) Cu*4aq) + 2e = Cu(s) (0/2)
(2)
9.5 Ptand Ag are both weaker reducing agents than copper and will be
oxidised to form ions. “¥ 2)
OR
Cu is a stronger reducing agent than Ag & Pt, so it will reduce Ag & Pt.
9.6 The rate at which copper is oxidised at the anode is equal to the rate at
which copper ions are reduced at the cathode. vv (2)
[10]
QUESTION 10 (Start on a new page.)
10.1 Ostwald (process). “ (1)
10.2.
10.2.1 Pt(Platinum)~ (Accept Nicket (Ni)
Temperature _+ 900°C Vv (2)
10.2.2 ANHs+ 502g) Vv -- 4NO(g) +6120 v7’ bal (3)
10.2.3 Catalytic oxidation. “ (1)
10.2.4 Nitrogen dioxide/ Nitrogen(IV)oxide (1)
10.2.5 20 or Water a)
10.3
10.3.1 KNOs vv @)
10.3.2 m(N)= Bx 6.35 ¥ ,
= 3,58 kg (4)
[15]

Panvminint rannntnd

GRAND TOTAL: 149

Dianna tien nune

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