# Physical Sciences Grade 12 Free State Mock 2020 Memo > Grade 12 Physical Sciences memorandum from the Free State Mock Exam 2020, 18 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/2020-free-state-physics-memo/c88940d6-da50-4efe-9b18-0ed4e6f18a3c - Updated: 2026-09-27 - Subject: Physical Sciences - Grade: Grade 12 - Document type: Memorandum - Year: 2020 - Exam period: Free State Mock Exam - Curriculum: CAPS - Pages: 18 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Physical Sciences](https://www.hlayiso.com/library/grade-12/physical-sciences) › [Physical Sciences Grade 12 Free State Mock 2020 Memo](https://www.hlayiso.com/library/2020-free-state-physics-memo/c88940d6-da50-4efe-9b18-0ed4e6f18a3c) ## About this document Physical Sciences · Grade 12 · Free State Mock Exam · 2020. Memorandum, 18 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com PREPARATORY EXAMINATION VOORBEREIDENDE EKSAMEN GRADE/GRAAD 12 PHYSICAL SCIENCE: PHYSICS (P1) FISIESE WETENSKAPPE: FISIKA (V1) SEPTEMBER 2020 MARKS/PUNTE: 150 MARKING GUIDELINES NASIENRIGLYNE These marking guidelines consist of 18 pages. Hierdie nasienriglyne bestaan uit 18 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 2 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 2 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne QUESTION/VRAAG 1 1.1 A  (2) 1.2 B  (2) 1.3 C  (2) 1.4 D  (2) 1.5 C  (2) 1.6 B  (2) 1.7 B  (2) 1.8 B  (2) 1.9 C  (2) 1.10 B  (2) [20] QUESTION/VRAAG 2 2.1.1 When a resultant/net force acts on an object, the object will accelerate in the direction of the force at an acceleration directly proportional to the force and inversely proportional to the mass of the object.   Wanneer 'n resulterende krag/netto krag op 'n voorwerp inwerk, sal die voorwerp in die rigting van die krag versnel wat direk eweredig is aan die krag en omgekeerd eweredig aan die massa van die voorwerp. OR/OF The net or resultant force acting on an object is equal to the rate of change of momentum of the object in the direction of the net force.  (2 or 0) Die netto/resulterende krag wat op 'n voorwerp inwerk, is gelyk aan die tempo van die verandering van momentum van die voorwerp in die rigting van die netto krag. (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 3 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 3 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne 2.1.2 F Fg T (3) Accept the following symbols/Aanvaar die volgende simbole F Fapplied /Force applied/ Toegepaste krag/FA  Fg w / Fw / weight /gewig  T FT / Tension/Spanning  NOTE/LET WEL:  Mark awarded for label and arrow./Punt word toegeken vir byskrif en pyltjie.  Do not penalise for length of arrow since drawing is not to scale. Moenie vir die lengte van pyltjies penalseer nie omdat diagram nie volgens skaal geteken is nie.  Any additional force(s)./Enige addisionele krag(te): 32  If force(s) do not make contact with body./Indien krag(te) nie met die voorwerp kontak maak nie: 32  No labels/Geen byskrifte: 03 2.1.3 Option/Opsie 1 Option/Opsie 2 fk  kN   k mg  0,3  5  9,8   14,7 N    N (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 4 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 4 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne 2.1.4 POSITIVE MARKING FROM 2.1.3/POSITIEWE NASIEN VANAF 2.1.3 Option/Opsie 1 Direction of motion as positive/Rigting van beweging as positief  Notes/Aantekeninge:   Formula/Formule  Substitution for forces/ Vervanging van kragte  Substitution for both masses/Vervanging vir beide massas   Equating Tension forces/  Vergelyk spanningskragte  Answer with units/Antwoord met eenhede  N N (6) Option/Opsie 2 Direction of motion as negative/Bewegingsrigting as negatief      N N Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 5 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 5 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne 2.2.1 Each body in the universe attracts every other body with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres.  (2) Elke liggaam in die heelal trek elke ander liggaam aan met 'n krag wat direk eweredig is aan die produk van hul massas  en omgekeerd eweredig is aan die kwadraat van die afstand tussen hul middelpunte.  2.2.2 Fplanet/planeet = 1 Fearth/aarde  2 Notes/Aantekeninge: G Mm2Me  (X)2   Formula of Gravitational law applied for each object. Formule van Gravitasiewet wat vir elke voorwerp  toegepas word.  Relationship between Fplanet and Fearth. Verhouding tussen Fplaneet en Faarde  Answer/Antwoord (4) [20] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 6 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 6 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne QUESTION/VRAAG 3 3.1 Motion of an object under the influence of gravity/gravitational force/weight only. (2 or 0) Beweging van 'n voorwerp slegs onder die invloed van gravitasie/ gravitasiekrag/gewig. OR/OF Motion in which the only force acting on the object is gravity/gravitational force/weight. Beweging waartydens die enigste krag wat inwerk gravitasie/gravitasie- krag/gewig is. ACCEPT/AANVAAR An object that is launched (or synonyms) with an initial velocity under the influence of the force of gravity only. 'n Voorwerp wat gegooi (of sinonieme) word met 'n aanvanklike snelheid onder die invloed van slegs gravitasiekrag.     (2) 3.2 Newton's First Law/Newton se Eerste Wet  A body will remain in its state of rest or motion at a constant velocity unless a non-zero net/resultant force acts on it. 'n Voorwerp sal in sy posisie van rus of beweging bly teen 'n konstante snelheid tensy 'n nie-nul netto/resulterende krag daarop inwerk. (3) 3.3.1 OPTION/OPSIE 1 + Positive/Positief OPTION/OPSIE 2 - Negative/Negatief     Height/ = 13,06 + (2500) Height/Hoogte  Hoogte m = 2513,06 m  (4) 3.3.2 Option/Opsie 1 Option/Opsie 2 Whole motion Positive Whole motion Negative Algehele beweging Positief Algehele beweging Negatief y  v i t  21 at 2     16(15)  21 ( 9,8)(15)2     862,5 height  2500  862,5  Height/Hoogte Height/ = 2500 – 862,5   1637,5 m  Hoogte = 1637,5 m  (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 7 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 7 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne Option/Opsie 3 Option/Opsie 4 Motion from the maximum Motion from the maximum height. Positive height. Negative Beweging vanaf die maksimum Beweging vanaf die maksimum hoogte. Positief hoogte. Negatief Vf = vi + g∆t Vf = vi + g∆t 0 = 16 − 9,8∆t 0 = 16 − 9,8∆t ∆t = 1,63 s ∆t = 1,63 s      = − 875,56  Height/Hoogte  Height/Hoogte = 2513,06 – 875,56 = 1637,5 m  = 1637,5 m  Option/Opsie 5 Option/Opsie 6 Motion point of projection Motion point of projection down. Positive down. Negative Bewegingspunt van afwaartse Bewegingspunt van afwaartse projeksie. Positief projeksie. Negatief Vf = vi + g∆t Vf = vi + g∆t O = 16 − 9,8∆t O = 16 − 9,8∆t ∆t = 1,63 s ∆t = 1,63 s      = − 862,5 = − 862,5 Height/Hoogte = 2500 – 862,5  Height/Hoogte = 2500 – 862,5  = 1637,5 m m = 1637,5 m  RANGE/GEBIED: 1637,5 – 1638,1 m Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 8 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 8 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne 3.3.3 OPTION/OPSIE 1 OPTION/OPSIE 2 Whole motion + Whole motion - Algehele beweging Algehele beweging         Note: For options 3 and 4 use any of the equations of motion containing ∆t to calculate ∆t and substitute into equation of ∆y = vi∆t + ½g∆t2. Aantekening: Vir opsies 3 en 4, gebruik enige van die bewegingsvergelykings wat ∆t bevat om ∆t te bereken en vervang in vergelyking van ∆y = vi∆t + ½g∆t2. 1) vf = vi + g∆t ∆t = 1,633 s 2) ∆y = 13,061 m; Max height/Maks hoogte = 2513,06 m 3) ∆y = 13,061 m; Max height/Maks hoogte = 2513,06 m OPTION/OPSIE 3 OPTION/OPSIE 4 Motion from maximum height + Motion from maximum height - Beweging vanaf maksimum Beweging vanaf maksimum hoogte hoogte       s s (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 9 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 9 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne 3.4 POSITIVE MARKING FROM 3.3.3/POSITIEWE NASIEN VANAF 3.3.3 Take Ground as zero position/Neem grond as zero-posisie Upward motion as positive./Opwaartse beweging as positief. 2 513,06 Position/ 2 500 Posisie (m) 0 Time/Tyd (s) 3,26 24,28 Upwards motion negative/ Opwaartse negatiewe beweging 3,26 24,28 0 Time/Tyd (s) Position/ Posisie (m) -2 500 -2 513,06 Marking criteria/Nasienriglyne Graph with correct shape, starts at 2 500 and ends on x axis at tf (24,28 s).  Grafiek met korrekte vorm begin by 2 500 en eindig op x-as by tf (24,28 s). Maximum height/Maksimum hoogte (2513,06)  Time of/Tyd van 24,28  (3) [21] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 10 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 10 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne QUESTION/VRAAG 4 4.1 When object A exerts a force on object B, object B will simultaneously exert an oppositely directed force of equal magnitude on object A. (2 or 0) Wanneer voorwerp A 'n krag op B uitoefen, sal voorwerp B terselfdertyd 'n krag in die teenoorgestelde rigting, van gelyke grootte op voorwerp A uitoefen. (2) 4.2 Equal in magnitude and opposite in direction. Gelyk in grootte en rigting is teenoorgesteld. (2) 4.3 Motion to the left/Beweging na links (+) ΣPf = ΣPi (mB + mG)viBG = mBvfB + mGvfG Any/Enige   (80 + 50)(4) = 80(8) + 50vfG  vfG = 2,40 m·s-1 to the right/backwards  na regs/terugwaarts (4) Motion to the left/Beweging na links (-) ΣPf = ΣPi (mB + mG)viBG = mBvfB + mGvfG (80 + 50)(–4)= 80(–8) + 50vfG  vfG = 2,40 m·s-1 to the right/backwards na regs/terugwaarts Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 11 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 11 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne 4.4 OPTION/OPSIE 1: OPTION/OPSIE 2: Motion to left//Beweging na links + Motion to right/Beweging na regs (+) Fnet∆t = ∆p (boy/seun) Fnet∆t = ∆p(boy/seun) = m(vfB – viB) Any/Enige  Any/Enige  = m(vfB – viB) = 80(8 – 4)  = 80(– 8 – (–4))  = 320  N·s to the left/na links  = –320  = 320  N·s to the left/na links  OR/OF OR/OF POSITIVE MARKING FROM 4.3/ POSITIEWE NASIEN VANAF 4.3 POSITIVE MARKING FROM 4.3/ POSITIEWE NASIEN VANAF 4.3 Fnet∆t = ∆p(girl/dogter) = m(vfB – viB) Any/Enige  Fnet∆t = ∆p(girl/dogter) Any/Enige  = 50(– 2,4 – 4) = –320 = m(vfB – viB) = 320 N·s to the right/ = 50(2,4 – (–4))  na regs  = 320 N·s to the right/na regs Fnet∆t (boy/seun) = 320 N·s to the  Fnet∆t (boy/seun) = 320  N·s to the left/na links left/na links  (4) [12] QUESTION/VRAAG 5 5.1 A force for which the work done in moving an object between two points is dependent of the path taken. (2 or 0)    'n Krag waarvoor die arbeid wat verrig is om 'n voorwerp tussen twee punte te beweeg, afhanklik is van die pad wat gevolg word.  (2) 5.2 Frictional (force)/Wrywing (krag) (1) 5.3 Option/Opsie 1 (U + K)i = (U + K)f mghi + ½mv2i = mghf +m ½mv2 f Any/Enige   (38)(9,8)(0,75) + ½ 38(1,5)2 = 9,8(0) + ½ 38v2f  vf = 4,12 m·s-1  (4) Option/Opsie 2 Any/Enige    m·s-1  Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 12 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 12 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne 5.4 Any/Enige    N (4) 5.5 POSITIVE MARKING 5.3 AND 5.4/POSITIEWE NASIEN 5.3 EN 5.4 Option/Opsie 1 Wnet  K Wf  Wfg  21 m(v 2f  v i2 ) Any/Enige  fk x cos   mgsin x cos   21 m(v 2f  v i2 )   77,016x cos180  38x9,8 sin10x cos0  21 (38)(0  4,122 )  12,35x  322,514 x  26,11 h sin10  x  h  26,11 h  4,535 m  (6) [17] QUESTION/VRAAG 6 6.1 It is the (apparent) change in frequency (or pitch) of the sound (detected by a listener)  because the sound source and the listener have different velocities relative to the medium of sound propagation.  Dit is die (waarskynlike) verandering in frekwensie (of toonhoogte) van die klank (soos waageneem deur 'n luisteraar) omdat die bron van die klankgolf en die waarnemer verskillende snelhede het relatief tot die medium van klankvoortplanting. (2) OR/OF An (apparent) change in (observed/detected) frequency (pitch), (wavelength) as a result of the relative motion between a source and an observer (listener). 'n (Waarskynlike) verandering in (waargenome) frekwensie (toonhoogte), (golflengte) as 'n gevolg van die relatiewe beweging tussen die bron en die waarnemer (luisteraar). Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 13 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 13 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne 6.2   Hz  (3) 6.3 POSITIVE MARKING FROM 6.2/POSITIEWE NASIEN VANAF 6.2 f=1 f = waves/golwe T OR/OF Time/tyd  1 2 = 8 x 10-4  = 16 x 10-4  = 1250 Hz v±v v fL= (v ± vL ) fs  OR/OF fL = (v − v ) fs S S  340   1250 = ( ) 1133,33 340 − vS (7) vs = 31,73 m·s-1  [12] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 14 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 14 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne QUESTION/VRAAG 7 7.1 The electrostatic force of attraction or repulsion between two point charges is directly proportional to the product (of the magnitudes) of the charges and inversely proportional to the square of the distance between them. Die elektrostatiese aantrekkingskrag of afstootkrag tussen twee puntladings is direk ewereding aan die produk (van die groottes) van die ladings en omgekeerd eweredig aan die kwadraat van die afstand tussen hulle. (2) NOTE/LET WEL: -1 for every key word/phrase omitted. If masses used instead of charges, 0/2. -1 vir elke sleutelwoord/frase wat uitgelaat is. Indien massas en nie ladings gebruik word nie, 0/2. 7.2 Marking criteria/Nasienkriteria Correct direction away from the +  sphere/Korrekte rigting weg van die + sfeer Shape of the electric field/Vorm van die  elektriese veld Field lines starting on the sphere and  not crossing/Veldlyne begin op die sfeer en kruis nie (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 15 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 15 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne 7.3 kQ Q  F 1 2 r2 9 6  1 2  9  10 (6  10 )z kQ Q F  (30  102 )2 13 r2  6  105 z kQ Q 9 6  F  2 3  9  10 (3  10 )z (10  102 )2 23 r2  27  105 z F2  F2  F2 net 13 23  2 (13,83)  (6  105 z)2  (27  105 z)2 (5) z  55x10 6CC 10–6  7.4 The electric field at a point is the (electrostatic) force experienced per unit positive charge placed at that point. Die elektriese veld op 'n punt is die (elektrostatiese) krag wat ervaar word per eenheid positiewe lading wat op daardie punt geplaas word. (2) NOTE/LET WEL: - 1 for every key word omitted. - 1 vir elke sleutelwoord wat uitgelaat is. 7.5 ENET = FNET  q = 13,83  5 x 10-6 = 2,77 x 10-6 N.C-1   (3) [15] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 16 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 16 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne QUESTION/VRAAG 8 8.1 Potential difference across a conductor is directly proportional to the current in the conducter provided the temperature is constant. Potensiaalverskil oor 'n geleier is direk eweredig aan die stroom in die geleier mits die temperatuur konstant is. (2) 8.2 Emf of the battery/Emk van die battery  (1) 8.3.1 Option/Opsie 1 Option/Opsie 2   (3) A   A 8.3.2 Option/Opsie 1 Option/Opsie 2 Vlost = Ir Emf/Emk = IR + Ir (4) 3,25 = I(1) 38,25 = 35 + I(1) I = 3,25 A  I = 3,25 A  8.3.3 POSITIVE MARKING FROM 8.3.1 & 8.3.2 POSITIEWE NASIEN VANAF 8.3.1 & 8.3.2 Option/Opsie 1 Option/Opsie 2 Option/Opsie 3          (7) Ω Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 17 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 17 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. Marking Guidelines/Nasienriglyne 8.4 Increase Total resistance in circuit increase and the total current decrease.  Vinternal will decrease.  Therefore: Vexternal will increase  (because emf stays constant). Toeneem Totale weerstand in stroombaan neem toe en die totale stroom neem af. Vintern sal afneem. Daarom: Vekstern sal toeneem (omdat emk konstant bly). (4) [21] QUESTION/VRAAG 9 9.1 Generators: Electromagnetic induction  Generators: Elektromagnetiese induksie (1) 9.2 A Split ring commutator/Spleetring kommutator  (2) 9.3.1 The rms voltage of AC is the DC potential difference which dissipates the same amount of energy as AC. Die wgk spanning van WS is die GS-potensiaalverskil wat dieselfde hoeveelheid energie as WS verbruik. (2) 9.3.2   V (3) 9.3.3 Increase/Neem toe  (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 18 Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 18 FS/VS/September 2020 Grade 12 Prep. Exam./Graad 12 Prep. Eksam. 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