# Mathematics Grade 12 Paper 2 KwaZulu Natal Mock 2020 Memo

> Grade 12 Mathematics Paper 2 memorandum from the KwaZulu Natal Mock Exam 2020, 12 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/2020-grade-12-math-trial-exam-paper-2-kzn-memo/8e7b27c1-2d52-4240-892f-05fdb1c1265e
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 12
- Document type: Memorandum
- Year: 2020
- Exam period: KwaZulu Natal Mock Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 12

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## About this document

Mathematics · Grade 12 · KwaZulu Natal Mock Exam · 2020. Memorandum, 12 pages. Read online or download the PDF.

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## Document text

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### Page 1

Mathematics P2                      NSC           Preparatory Examination September 2020
                                            1

                                     NATIONAL
                            SENIOR CERTIFICATE

                                      GRADE 12

                           MATHEMATICS P2
                      PREPARATORY EXAMINATION
                           SEPTEMBER 2020
                          MARKING GUIDLINES

 MARKS: 150

 TIME:      3 hours

                       This marking guideline consists of 12 pages.

### Page 2

Mathematics P2                                               NSC            Preparatory Examination September 2020
                                                                        2

QUESTION 1

  NUMBER OF RED                                NUMBER OF                MIDPOINT OF            f. x
  CARDS                                        COUNTRIES (f)            INTERVAL (x)

      0< x≤ 2                                          27                             1                     27
      2< x≤ 4                                          15                             3                     45
      4< x≤ 6                                           5                             5                     25
      6< x≤ 8                                           5                             7                     35
     8 < x ≤ 10                                         3                             9                     27
  TOTAL                                                55                                                  159

1.1                                                                                                              CA 159
       Estimated mean =                                         red cards
                                                                                                                 CA  55
                                                                                                                 CA 
       Answer only full marks                                                                                    answer
                                                                                                                        (3)
1.2
                                                                                                                 Full
                                          The red cards issued to countries during a                             marks for
                                                     soccer competition                                          6 correct
                                                                                                                 points
                                 60

          CUMULATIVE FREQUENCY
                                 50                                                                              2
                                 40                                                                              marks for
                                 30
                                                                                                                 4correct
                                                                                                                 points
                                 20
                                 10                                                                              1 mark
                                  0                                                                              for 2
                                      0         2       4           6             8       10          12         correct
                                                            NUMBER OF RED CARDS                                  points

                                                                                                                        (3)
1.3    Q3  4 and Q1  1 IQR  4  1  3 red cards                                                              CA  Q1
       Answer only full marks                                                                                    and Q3
                                                                                                                 CA
                                                                                                                 answer
                                                                                                                        (2)
                                                                                                                        [8]

### Page 3

Mathematics P2                             NSC           Preparatory Examination September 2020
                                                   3

QUESTION 2

2.1                                                                                 A  for A
                                                                                    A for B
                                                                                    A
                                                                                    For equation
      Answer only full marks                                                                      (4)
2.2   Estimated monthly income                                                      CA
                                                                                    substitution
                                                                                    CA answer
                             R25598,89                                                          (2)
      If 9000 is used only 1 mark
2.3   r = 0,94                                                                      CA      (2)
2.4   Very strong positive relationship between the monthly rent and the monthly    CA  strong
      income.                                                                       CA  positive
                                                                                              (2)
                                                                                               [10]

### Page 4

Mathematics P2                               NSC            Preparatory Examination September 2020
                                                      4
QUESTION 3

3.1.1                                                                   A sub into correct formula
                                                                             1
                                                                        A 
                                                                             3

                                                                        A Sub into correct formula
                                                                        A

                                                                                                       (4)
3.1.2   KM      4  42  10  02                                   CA subst

              100                                                      CA 10 units
             10 units                                                                                (2)
        Answer only full marks
3.1.3                                                                                 1
                                                                        CA tan  
                                                                                      2

                                                                        CA    26,570 provided acute
                                                                        angle
        Answer only full marks
                                                                        (2)
3.1.4    x1  x2 y1  y2                                              Acorrect substitution
                ;        
         2           2 
        1 8 1 2 
              ;    
         2      2 
        9 3
         ;                                                            Aanswer                      (2)
        2 2
3.2                                                                     Asubst

                                                                        A3

                                                                        Aproduct = −1
                                                                                                       (3)
3.3

                                                                        AMKN -2

                                                                        AKN  MN
                                                                        ASum of 180o
                 is cyclic quadrilateral (converse, opp   of a cyclic         1        1
                                                                        M MN    2     1
                                           quad are supplementary)            2        2

                                                                        A reason
                                                                                                       (4)
                                                                                                      [17]

### Page 5

Mathematics P2                                 NSC            Preparatory Examination September 2020
                                                        5

QUESTION 4

4.1                                                                    A
                                                                       A
                                                                                                             (2)
4.2                                                                    CA         into equation
                                                                       CA
                                                                       CAequation
                                                                       For CA marks coordinates of M
                                                                       must be in second quadrant
                                                                                                  (3)
4.3                                                                    A       or

                                                                       A

                                                                       Aproduct of gradients = -1
                                                                       A900
                is a tangent   (conv. tangent and diameter)            Areason
                                                                                                       (5)
4.4.1                                                                  CA
                                                                       CAequation
        Subst. (3; 2):                                                 CAsubst of (3; 2) or (2; -2)

                                                                       CAequation
                                                                                                       (4)
4.4.2 Let C(x; y)
                                                                       CAequation of circle
        At C;
                                                                       CAsubst x = 0

                                                                       CAy values
                                                                       CAco-ordinate

                                                                       CAgradient

        Now                                                            CAequation

                                                                                                       (6)
4.5     Lines AT and BT intersect at C
                                                                       CAequations equal

                                                                       CAvalue of a

                                                                       CAvalue of b, For CA marks
                                                                        A and B are points in the 4th
                                                                       quadrant
                                                                                                     (3)
                                                                                                       [23]

### Page 6

Mathematics P2                            NSC       Preparatory Examination September 2020
                                                6
QUESTION 5

5.1
                                                       Acos 49 0 A sin 79 0

                                                       Acos 30 0
                                                       A answer
                                                                                             (4)
        Answer only no marks, used calculator

5.2

                                                       Aexpansion

                                                       Alike terms added

                                                       Adivide

                        :

                                                       A

                                                                                             (4)
5.3.1

        LHS:

                                                       A
                                                       A

                                                       Anumerator

                                                       Aanswer

                                                                                             (4)
         RHS

### Page 7

Mathematics P2        NSC       Preparatory Examination September 2020
                            7

5.3.2

                                                     A

                                                     Astandard quadratic
                 OR                                  form
                                                     A  Factors
                      ref
                                                     CA900
                       OR
                                                     CA228.59
                                                     CA311.41
                                                                     (6)

QUESTION 6

6.1                                            A
                                               A
                                               A
                                               A
                                                                         (4)

6.2                                            A
                                                                      (1)
6.3.1                                          AAvalues and notation
                                                                      (2)
6.3.2                                          AAA values and
                                               correct notation
                                                                      (3)
                                                                     [11]

### Page 8

Mathematics P2   NSC       Preparatory Examination September 2020
                       8

QUESTION 7

7.1    n
                                           
                                           

                                          ASubst. into Area rule

                                          Asin2x
                                          Aanswer
                                                                     (5)

7.2
                                          AUse of sine rule

                                          Asubst into sine Rule

                                          Asin 2x

                                          A2 sin x cos x
                                           (4)

       In

7.3                                       A

                                          ASP = PQ tan y
                                                                    (2)

### Page 9

Mathematics P2                             NSC               Preparatory Examination September 2020
                                                     9

QUESTION 8
8.1

                                                 h
                                                         k

 R.T.P   KP KQ
           
         PL QM

         CONSTRUCTION:
                                                                                        Aconstruction
         In ΔKPQ , draw perpendicular heights, h from Q to KP and K from P to KQ

                        1                                                               Amethod
                          KP  h
         Area of Δ KPQ 2
                      
         Area of ΔLPQ   1
                          PL  h
                        2
                                                                                             KP
                                                                                        A
                             KP                                                              PL
                         =
                             PL

                        1
                          KQ  k
         Area of KPQ                                                                   Amethod
                       2
         Area of MQP 1 QM  k
                        2

                             KQ                                                              KQ
                         =                                                              A
                             QM                                                              QM

         But area of  PLQ = Area of  MPQ      Same base, same height

             Area of ΔKPQ Area of ΔKPQ
                        
             Area of ΔLPQ Area of ΔMQP                                                  Amethod

             KP KQ
              
             PL QM                                                                                       (6)

### Page 10

Mathematics P2                               NSC               Preparatory Examination September 2020
                                                     10
8.2.1   In ΔAPQ:
                                 AB   AC                                          AS AR
        BC PQ                           . ; conv prop
                                 AP   AQ

                                                                                  A S/R
                                               BC                                 A S/R

                                                                                                         (4)
8.2.2   In
                                                                                  A S/R
                                                                                  A S/R
                                                                                  A S/R
                                                                                  A S/R

                                                                                                         (4)
8.2.3                                                                             AS AR
                                                                                  A S

                 is cyclic       conv.                                            A S/R
                                                                                                         (4)
8.2.4                                                                             AS AR
                                                                                  AS
                                                                                  AS/R

                                                                                  AS/R

                                                                                                         (5)
                                                                                                        [23]

QUESTION 9

9.1     In ΔMBC:

        B̂2  B̂3 = x             BE bisects MB̂C                                 AS

         MB̂C  2 x

        MB̂C  MĈB  2 x        angles opposite equal sides                      AS/R

        In ΔBEC :

        Ê 2  180o  ( x  x)    Sum of angles of a Δ                            AS/R

             = 180o –2x
                                                                                  AAnswer

                                                                                                         (4)

### Page 11

Mathematics P2                                  NSC            Preparatory Examination September 2020
                                                        11

   9.2    In ΔMBC: BM̂C  180o  (2 x  2 x)           Sum of angles of a Δ

                               = 180o – 4x                                    AS AR
                          1
          But BÂC         BM̂C                  at centre twice angle
                          2
                                                                              AS/R
                         1
                        = (180o  4 x)
                         2

                        = 90 – 2x                                                                       (3)

   9.3    In ΔABE :

           Ê1  Ê 2  180o                             Straight line        AS/R

           Ê1  180o  E 2

                 = 180o – ( 180o – 2x)

                 = 2x                                                         AS

          In ΔABE :

           AB̂E  BÂC  Ê  180o              Sum of  s of Δ               AS/R

           AB̂E  180o  (BÂC  Ê1 )

                   = 180o  (90o  2 x  2 x)

                    = 90o                                                     AS

           AE is a diameter of circle ABE            (Subtends)  90o
                                                                              AR
                                                                                                        (5)

                                                                                                    [12]

### Page 12

Mathematics P2                              NSC        Preparatory Examination September 2020
                                                  12

QUESTION 10

10.1.1 Let              and
                                                                            A S/R

                                                                            AS AR

                                                                            A S/R

              bisects
                                                                            AS
                                                                                                (5)
10.1.2 In          and
            is common                                                       AS/R
                                                                            AS AR
                              remaining                                     AR
                                                                            AR
                              similar ’s
                                                                            A S/R

                                                                                                (6)
10.2.1                         XY = XT                                      AS AR
                                                                            Aanswer

                                                                                                (3)
10.2.2                                                                      A LHS
                                                                            A RHS

                                                                            ASimplification

                                   mm                                       AAnswer

                                                                                                (4)

                                                                                            [18]

                                                                                      TOTAL: 150

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