# Physical Sciences Grade 12 Limpopo Mock 2020 Memo

> Grade 12 Physical Sciences memorandum from the Limpopo Mock Exam 2020, 10 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/2020-limpopo-chemistry-memo/2d8c7066-b23a-4011-be2d-6ae4a1af4a0d
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2020
- Exam period: Limpopo Mock Exam
- Curriculum: CAPS
- Pages: 10

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### Page 1

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                                 NATIONAL
                             SENIOR CERTIFICATE
                                 NASIONALE
                             SENIOR SERTIFIKAAT

                                  GRADE/GRAAD 12

                      PHYSICAL SCIENCES: CHEMISTRY (P2)
                       FISIESE WETENSKAPPE: CHEMIE (V2)

                                  SEPTEMBER 2020

                                   MEMORANDUM

    MARKS/PUNTE: 150

                          This memorandum consists of 10 pages.
                        Hierdie memorandum bestaan uit 10 bladsye.

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Physical Sciences P2 / Fisiese Wetenskappe V2           2                  LIMPOPO September 2020
                                     NSC Marking Guideline / NSS Nasienriglyn

 QUESTION 1/VRAAG 1

 1.1        C                                                                                        (2)
 1.2        D                                                                                        (2)
 1.3        B                                                                                        (2)
 1.4        A                                                                                        (2)
 1.5        B                                                                                        (2)
 1.6        A                                                                                        (2)
 1.7        C                                                                                        (2)
 1.8        C                                                                                        (2)
 1.9        A                                                                                        (2)
 1.10       B                                                                                        (2)
                                                                                                       [20]

 QUESTION 2/VRAAG 2
 2.1.1  Tertiary (halo-alkane)  the carbon attached to the halogen/Br is attached to
        three other carbons
        Tersiêre (haloalkaan) die koolstof waaraan die halogeen/Br verbind is,is aan drie
        ander koolstowwe verbind                                                          (2)

 2.1.2      2-bromo-2-methylbutane
            2-bromo-2-metielbutaan / 2-broom-2-metielbutaan
            Marking criteria/Nasienriglyne
            • Butane/butaan 
            • Both substituents correct : bromo and methyl /Altwee substituente korrek: bromo
              en metiel
            • Everything correct / Alles reg
              (Any error e.g. hyphens omitted and/or incorrect sequence:
                                                                                                        (3)
               Enige fout, bv. koppeltekens weggelaat en/of verkeerde volgorde: Max./Maks: 2 )
                                                                                            3
 2.1.3      2-methyl-2-butene/ 2-methyl but-2-ene / 2-metiel-2-buteen / 2-metielbut-2-een
            Marking criteria/Nasienriglyne
            • But-2-ene/2-butene/But-2-een/2-buteen 
            • 2-methyl/2-metiel
              Any error e.g. hyphens omitted and/or incorrect sequence:
              Enige fout, bv. koppeltekens weggelaat en/of verkeerde volgorde: Max./Maks: 1            (2)
                                                                                           2

 2.2.1      (A series of) organic compounds which have the same general formula OR which
            differ from each other by a CH2 group/unit / ‘n Homoloë reeks is ‘n reeks
            organiese verbindings wat deur dieselfde algemene formule beskryf word OF
            waarvan die een lid van die volgende lid verskil met ‘n CH 2-groep.          (2)

 2.2.2      Esters                                                                                    (1)

 2.2.3         H H H   O H H H                             Marking criteria/nasienriglyne
                I I I  II I I I                            Functional group
            H—C—C—C— O—C—C— C—C—H                          Everything else correct
              I   I I     I I  I                           funksionele groep
              H H H       H H H                            alles verder korrek                        (2)

 2.2.4      Propanol and butanoïc acid / Propanol en butanoësuur                                    (2)

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Physical Sciences P2 / Fisiese Wetenskappe V2           3                  LIMPOPO September 2020
                                     NSC Marking Guideline / NSS Nasienriglyn

 2.2.5                                               Marking criteria/nasienriglyne
                              O                      Functional group
                              II                     Everything else correct
            CH3CH2CH2CH2CH2CH3 COH                   funksionele groep alles verder korrek            (2)
 2.3        2C4H10 + 13O2 → 8CO2 + 10H2O (Reactants Products  Balancing)
                                          (reaktante, produkte, balansering)                          (3)
                                                                                                      [19]
 QUESTION 3/VRAAG 3
 3.1.1      Organic molecules with the same molecular formular but different structural
            formule /                                                                   (2)
            Organiese molekule met dieselfde molekulêre formule, maar verskillende
            struktuurformules.
 3.1.2      CnH2n+2                                                            (1)
 3.1.3      Chain(isomers) / ketting(isomere)                                  (1)
 3.2.1      The temperature at which the vapour pressure of a substance equals
            atmospheric/external pressure
            Die temperatuur waar die dampdruk van ‘n stof gelyk is aan die
            atmosferiese/eksterne druk                                          (2)
 3.2.2      number of branches /aantal vertakkings                                                   (1)
 3.2.3      Number of C and H atoms,/ molecular mass 
            Aantal C en H atome,/ molekulêre massa                                                    (1)
 3.2.4      From A to C
            (Structure) Branching decreases/molecules become less compact/surface
            area increases (over which intermolecular forces acts)
            (Intermolecular forces) Stronger/more intermolecular forces/Van Der Waals
            forces/London forces
            (Energy) More energy needed to overcome intermolecular forces/Van Der
            Waals forces/ /London forces
            Van A na C
            (Struktuur) Vertakkings verminder/molekule word minder kompak/oppervlakte
            (waaroor intermolekulêre kragte werk) word groter
            (Intermolekulêre kragte} Sterker of meer intermolekulêre kragte /Van Der
            Waalskragte / Londonkragte
            {Energie} Meer energie benodig om intermolekulêre kragte /Van Der
            Waalskragte / Londonkragte te oorkom                                      (3)
 3.2.5      A
            Lowest boiling point / laagste kookpunt                                                  (2)
 3.3        Aldehydes/ aldehiede                                                                     (1)
 3.4        D/butan-1-ol has hydrogen bonding forces between the molecules
            E/butanal has dipole-dipole forces between the molecules
            Hydrogen bonds are stronger than dipole-dipole forces
            D/butan-1-ol het waterstofbindings tussen die molekule
            E/butanaal het dipool-dipoolkragte tussen die molekule
            Waterstofbindings is sterker as dipool-dipool kragte                                      (3)
                                                                                                      [17]

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Physical Sciences P2 / Fisiese Wetenskappe V2           4                  LIMPOPO September 2020
                                     NSC Marking Guideline / NSS Nasienriglyn

 QUESTION 4/VRAAG 4
 4.1.1      Addition / hydration
            Addisie / hidrasie//hidratering                                                            (1)
 4.1.2      Substitution /halogenation/ chloronation
            Substitusie /halogenasie//halogenering//chloronering                                       (1)
 4.1.3      Elimination/dehydration
            Eliminasie//dehidrasie//dehidratering                                                      (1)
 4.1.4      Substitution
            Substitusie                                                                                (1)
 4.2.1      H2SO4 / H3PO4                                                                             (1)
                                              Marking criteria/nasienriglyne
 4.2.2        H H H                           Functional group correct/
              I I   I                         Funksionele groep korrek 
            H—C—C—C—H                        Whole molecule correct/ Molekuul korrek
              I I   I                         Note: Accept OH. Line (bond) must be from C to O
              H O-H H                         Aanvaar OH. Lyn (binding) moet vanaf C na O wees
                                                                                                      (2)
                                                    Marking criteria/nasienriglyne
 4.2.3      2-propanol / propan-2-ol              propanol                                          (2)
                                                    Everything correct / Alles reg
 4.3.1      Hydrogenation /hidrogenasie/hidrogenering                                                 (1)
 4.3.2
              H H H                                  H H H
              I I     I                              I I I
            H—C = C—C—H + H - H             →      H—C—C—C—H
                      I                              I I I               
                     H                                H H H
              Accept/aanvaar H2                                                                        (3)
 4.4.1      2-chloropropane / 2-chloropropaan                                                        (2)
 4.4.2       Sodium hydroxide /potassium hydroxide 
             Natriumhidroksied/ kaliumhidroksied                                                       (1)

 4.4.3      Dilute base OR adding of water /verdunde basis OF byvoeging van water
            (Mild) heat/(Matige) hitte                                                                (2)
                                                                                                       [18]

 QUESTION 5/VRAAG 5

 5.1.1       Endothermic reaction /endotermiese reaksie                                              (1)

 5.1.2      Energy is absorbed  OR Energy is required for reaction to take place OR
            Energy is absorbed from the surroundings
            Energie is geabsorbeer OF Energie word benodig vir die reaksie om plaas te
            vind OF Energie word geabsorbeer uit die omgewing.                         (1)

 5.2.1      NO/gas escapes OR it is not a closed system
            NO/ gas ontsnap OF dit is nie ŉ geslote sisteem nie                                       (1)

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Physical Sciences P2 / Fisiese Wetenskappe V2           5                  LIMPOPO September 2020
                                     NSC Marking Guideline / NSS Nasienriglyn

 5.2.2                             ∆m
            Rate/tempo = -
                                   ∆t
                                   6,3-0
                              =-            = 0,06 g∙s-1 
                                   0-105

            (accept/aanvaar -0,06 g∙s-1)                                                              (3)

 5.2.3      Reaction is completed/all Cu(reactant) is used up(NOT equilibrium)
            Reaksie is voltooi/al die Cu(reaktante) is opgebruik (NIE ewewig nie)                     (1)

 5.2.4      Temperature increased/heat is given off /exothermic reaction
            Accept: HNO3 removes CuO from Cu surface/ cleans copper surface
            Temperatuur neem toe/ hitte word vrygestel/ eksotermiese reaksie
            Aanvaar HNO3 verwyder CuO vanaf Cu oppervlak/ maak Cu oppervlak skoon (1)

 5.2.5      Concentration of HNO3 decreased/ reactants are being used up
  _         Konsentrasie van HNO3 neem af /reaktanse opgebruik                                        (1)

 5.2.6      The number of particles has decreased Thus fewer/less effective collisions
            occur per second
            Die aantal deeltjies neem af Minder effektiewe botsings vind per sekonde
            plaas                                                                      (2)

 5.2.7                m        6,3 
            NO: n =       =        = 0,21 mol (Accept / Aanvaar 6,2 - 6,4)
                      M        30
             nCu : nNO
                              0,21
              1 : 4       ∴        = 0,052 mol (Using ratio / toepassing van verhouding)
                               4

            Cu: m = nM = 0,052 x 63,5 = 3,30 g                                                      (4)

 5.2.8      Increase the concentration of HNO3
            Increase the temperature of the solution
            Use Cu powder / smaller pieces of Cu/increase the surface area of Cu 
            Verhoog die konsentrasie van die HNO3
            Verhoog die temperatuur van die oplossing
            Gebruik Cu-poeier kleiner Cu stukkies/ vergroot die reaksie oppervlak van Cu              (3)

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Physical Sciences P2 / Fisiese Wetenskappe V2           6                  LIMPOPO September 2020
                                     NSC Marking Guideline / NSS Nasienriglyn

 5.3
               Marking guidelines/Nasienriglyne
                 • Substitution of/vervanging van: 0,25x0,1 
                 • Use mol raio/ gebruik molverhouding: 1:2 ; 0,025:0,0125 
                                           m
                 • Formula/formule: n =      
                                           M
                 • Substitute/vervang: 32
                                         0,0075          0,24
                 • Substitute/vervang:          OR/OF         
                                        0,0125            0,4
                 • Final answer/finale antwoord: 60 %

            n = cV
             = 0,25x0,1
             = 0,025 mol
              HCℓ : S
               2 : 1
            0,025 : 0,0125 
               Option 1/opsie 1                          Option 2/opsie 2

                     m        0,24                       m = nM
               n=        =          = 0,0075 mol
                     M        32                           = 0,0125 x 32
                                                            = 0,4 g
                                     0,0075                           0,24
               % opbrengs =                   x 100     % opbrengs =      x 100
                                     0,0125                            0,4

                                = 60 %                                = 60 %
                                                                                                      (6)
                                                                                                      [19]

 QUESTION 6/VRAAG 6
 6.1        When an external stress (change in pressure, temperature or concentration) is
            applied to a closed system in chemical equalibrium, the equilibrium point will
            change in such a way as to counteract the stress.
            Wanneer die ewewig in ŉ geslote sisteem versteur word (verandering in
            druk,temperatuur of konsentrasie) stel die sisteem ŉ nuwe ewewig in deur die
            reaksie wat die versteuring teëwerk te bevoordeel.                              (2)

 6.2        Reaction producing fewer moles/ less volume of gas favoured
            The reverse reaction is favoured
            The amount of ozone will increase
            Die reaksie wat minder gas vorm/ kleinervolume gas vorm word bevoordeel
            Die terugwaatse reaksie word bevoordeel
            Dus sal die hoeveelheid osoon vermeerder                                                  (3)
 6.3.1      Reverse /terugwaarts                                                                     (1)

 6.3.2      Exothermic  /eksotermies                                                                 (1)

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Physical Sciences P2 / Fisiese Wetenskappe V2           7                  LIMPOPO September 2020
                                     NSC Marking Guideline / NSS Nasienriglyn

 6.3.3      Decreases/verlaag                                                                        (1)
 6.4        A catalyst is a chemical substance which increases the rate of a
            reactionwithout undergoing a permanent change itself //
            ŉ Katalisator is ŉ chemiese stof wat die tempo van ŉ chemiese reaksie verhoog
            sonder om self ŉ permanente verandering te ondergaan.
            OR/OF
            A catalyst increases the rate of a reaction by providing an alternative route
            with lower activation energy. //
            ŉ Katalisator verhoog die tempo van ‘n reaksie deur ‘n alternatiewe roete van (2)
            laer aktiveringsenergie te verskaf.

 6.5        Amount of oxygen remains the same
            A catalyst speeds up the rate of the forward and reverse reactions equally
            Die hoeveelheid van suurstof bly dieselfde.
            ŉ Katalisator verhoog die tempo van die voorwaarte en terugwaartse reaksies
            ewe vee                                                                     (2)

 6.6        Mark allocation/Puntetoekenning
            • Substitution of 0,72 mol NO at equilibrium or 0,36 mol.dm 3 if using
               concentrations/ vervanging van 0,72 mol by ewewig of 0,36 mol∙dm -3 as
               konsentrasie gebruik word.
            • Change in NO (0,54/ 1,08)/verandering in NO(0,54/ 1,08) 
            • USING ratio/GEBRUIK verhouding: 1:1:1 
            • Divide or multiply by volume/Gedeel deur of vermenigvuldig met volume
              (2 dm3) 
            • Correct Kc expression (formulae in square brackets). 
               Korrekte Kc -uitdrukking (formules tussen vierkanthakies).
            • Substitution of reactant and product concentrations/ Vervanging van (7)
               reaktans- en produkkonsentrasies. 
            • Correct final answer/Korrekte finale antwoord: 20,25
            Moles/mol:

                                          O3           NO             O2          NO2
             Initial moles            0,6X2=1,2     0,9X2=1,8     0,73X2=1,46 0,55X2=1,10
             Aanvanklik mol
             Change             1,08       (-) 1,08                 (+) 1,08          1,08
             /verandering
                                                                                                     Ratio
             Equilibrium        0,12     0,36X2=0,72                   2,54            2,18          
             Ewewig                                 
             (moles / mol)                                                                           ÷2
             Concentration     C=n/v           0,36                    1,27            1,09
             Konsentrasie   =0,12/2=0,06

                   [O2 ][NO2 ]        (1,27)(1,09)
            Kc =                 =                = 64,09  (64,0-64,2)
                     [O2 ][NO]        (0,06)(0,36)

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Physical Sciences P2 / Fisiese Wetenskappe V2           8                  LIMPOPO September 2020
                                     NSC Marking Guideline / NSS Nasienriglyn

                                         O3             NO              O2             NO2
             Initial moles               0,6            0,9            0,73            0,55
             Aanvanklik mol
             Change            0,54                  (-) 0,54       (+) 0,54          0,54
             Verandering
             Concentration     0,06                   0,36            1,27            1,09          ratio
             Konsentrasie
            Concentration/konsentrasie
                                                                                                     x2
                   [O2 ][NO2 ]        (1,27)(1,09)
            Kc =                 =                = 64,09  (64,0-64,2)                            (7)
                     [O2 ][NO]        (0,06)(0,36)

 6.7.1      Increases/ neem toe                                                                      (1)

 6.7.2      Remains the same/ bly dieselfde                                                          (1)

 6.7.3      Increases/ neem toe                                                                      (1)

 6.7.4      Decreases/ neem af                                                                       (1)

 6.7.5      Remains the same / bly dieselfde                                                         (1)
                                                                                                      [24]

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Physical Sciences P2 / Fisiese Wetenskappe V2           9                  LIMPOPO September 2020
                                     NSC Marking Guideline / NSS Nasienriglyn

 QUESTION 7/VRAAG 7

 7.1        Burette / Buret                                                                           (1)

 7.2 _      C
            Titration of a weak acid and strong base OR
       _    CH3COOH is a weak acid and NaOH a strong base
            Titrasie van ‘n swak suur en sterk basis OF
            CH3COOH is ‘n swak suur en NaOH “n sterk basis.                                            (2)

 7.3        Weak acids ionizes incompletely in water to form a low concentration of
            H3O+ ions.
                                                                             +
            Swak sure ioniseer onvolledig in water om 'n lae konsentrasie H3O -ione te
            vorm                                                                                       (2)

 7.4        NaOH → Na+(aq) + OH-(aq)
            [OH-] = 0,11mol∙dm-3
                                                        (1 mark for 0,11/ 1 punt vir 0,11))
                        -14         +      -
            Kw = 1x10 = [H3O ][OH ] 
            1x10-14 = [H3O+](0,11)
            [H3O+] = 9,09x10-14 
                 pH = -log[H3O+] 
                    = - log (9,09x10-14)
                    = 13,04
            OR
            [OH-] = 0,11 mol∙dm-3 
            pOH = -log[OH-] 
                = - log 0,11
                = 0,06 
            pH = 14 – pOH = 14 – 0,06 = 13,04                                                        (5)

 7.5        n=cxV
             = 0,11 x 0,0285 
             = 0,0031 mol  (0,003135 )                                                                (2)

 7.6        Positive marking from QUESTION 7.5/ Positiewe nasien vanaf VRAAG 7.5
            n acid/suur : n base/basis = 1:1
            n acid/suur = 0,0031 mol
            m acid/suur in 25cm3 = nxM = 0,0031 x 60 = 0,186g 
            m acid/suur in 100 cm3 = 0,186 x 4 = 0,744g
                                               0,744
             % etanoic acid/ etanoёsuur =               x 100 = 9,9 % (9,8 – 10)                     (5)
                                                7,5
                                                                                                       [17]

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Physical Sciences P2 / Fisiese Wetenskappe V2           10                  LIMPOPO September 2020
                                     NSC Marking Guideline / NSS Nasienriglyn

 QUESTION 8/VRAAG 8

 8.1        Diprotic /Diproties                                                                      (1)

 8.2        pH = -log[H3O+]
            1,6 = -log[H3O+] 
            [H3O+] = 0,025 
            [H2SO4] = 0,0125 mol∙dm-3                                                                (3)

 8.3.1      Reaction of a salt with water / Die reaksie van ‘n sout met water                       (2)

 8.3.2      Acidic / Suur
            NH+4 (aq) + H2O → NH3 + H3O (aq)
                                          +

            [H3O ] increases  /[H3O ] neem toe
                 +                  +                                                         (4)
                                                                                              [10]
                                                                               TOTAL/ TOTAAL: 150

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## Collection

- [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers)

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