# Life Sciences Grade 12 Paper 2 NSC June 2013 Memo

> Grade 12 Life Sciences Paper 2 memorandum from the NSC June 2013, 14 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/biology-p2-hg-2013-memo/82034e08-8dd2-48a0-80c8-ce697be5ca86
- Updated: 2026-09-27
- Subject: Life Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2013
- Exam period: NSC June
- Paper: 2
- Curriculum: CAPS
- Pages: 14

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## About this document

Life Sciences · Grade 12 · NSC June · 2013. Memorandum, 14 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

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basic educhtion““

Department:
Basic Education Hones BAG X
REPUBLIC OF S p 00

SENIOR CERTIFICATE EXAMINATION

BIOLOGY P2
HIGHER GRADE
2013

POSSIBLE ANSWERS

MARKS: 200

This memorandum consists of 14 pages.

Copyright reserved Please turn over

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Biology/HG/P2 2 DBE/2013
i ailahel DEPARTMENT OF BASIC”
EDUCATION

PRINCIPLES RELATED TO MARKING HG & SG BIOLOGY 2013

This document should be attached to ail memoranda after the question paper Ag

been written and made available to ALL Life Sciences/Biolqgy teacherssié GAG > +10
PRETORIA 0001

_ If more information than marks allocated is given PUBLIC EXAMINATIONS

Stop marking when maximum marks are reached and puf a Wavy line and max in
the right-hand margin.

2. If, for example, three reasons are required and five are given
Mark the first three irrespective of whether all or some are correct / incorrect.

3. if whole process is given when only part of it is required
Read all and credit relevant part.

4. If comparisons are asked for and descriptions are given
Accept if differences / similarities are clear.

5. If tabulation is required but paragraphs are given
Candidates will lose marks for not tabulating.

6. If diagrams are given with annotations when descriptions are required
Candidates will lose marks.

c If flow charts are given instead of descriptions
Candidates will lose marks.

8. if sequence is muddled and links do not make sense
Where sequence and links are correct, credit. Where sequence and links are
incorrect, do not credit. If sequence and links becomes correct again, resume
credit.

9. Non-recognised abbreviations
Accept if first defined in answer. If not defined, do not credit the unrecognised
abbreviation but credit the rest of answer if correct.

10. Wrong numbering
If answer fits into the correct sequence of questions but the wrong number is given,
it is acceptable.

11. If language used changes the intended meaning
Do not accept.

12. Spelling errors
If recognisable accept provided it does not mean something else in Biology or if it
is out of context.

13. If common names given in terminology
Accept provided it is accepted at this memo discussion.

Copyright reserved _ GM. Wiese Please turn over

External Moderator
malusi

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Biology/HG/P2 3 DBE/2013
ee ena DEPARTMENT OF BASIC
EQUCATION
14. If letter only is asked for and name only is given (arid vice versa)
No credit. 2013 -06- 05
15. If units are not given in measurements PRIVAIE BAG 4 11d
Candidates will lose marks. Memorandum will allocate marks-for. finite. ue
separately. PUBLIC EXAMINATIONS

16. Be sensitive to the sense of an answer, which may be stated in a different way.

17. Caption
All illustrations (diagrams, graphs, tables, etc.) must have a caption.

18. If you have doubts consult the other language memo. If you still have doubts ask
the Provincial Internal Moderator to contact the National Internal Moderator or the
External Moderator(s).

19. Code-switching of official languages (terms and concepts)
A single word or two that appears in any official language other than the learners’
assessment language used to the greatest extent in his/her answers should be
credited, if it is correct. A marker that is proficient in the relevant official language
should be consulted. This is applicable to all official languages.

20. Nochanges may be made to the marking memoranda without consulting the
Provincial Internal Moderator who in turn will consult with the External
Moderator(s).

21. | Only memoranda bearing the signatures of the UMALUSI moderators and
distributed by the National Department of Education via the Provinces may be
used.

Copyright reserved FM, Wiese Please turn over

External Moderator
Umatusi

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Biology/HG/P2
SECTION A
QUESTION 1

1.1

1.4.1 Dvv

(12) By

1.1.3 C/DV¥
1.1.4 AlCVv¥Y
115 BYY

11.6 AY

1.2

1.2.1 CapillarityY”
1.2.2 Turgor( pressure)

4.2.3 Xerophytes ~/ Succulents
1.2.4 Bicarbonate ionsv
12.5 Urethra”

1.2.6  Guttation”

1.3

13.1 Avvonly

13.2  Avvonly

1.3.3 AvVonly

1.3.4 BothAandBvYY
13.5  Bvvonly

1.3.6 BothAandBvYY
Copyright reserved

SCE — Memorandum

DBE/2013

DEPARTMENT OF GASI®”
pucaTt

2013 -06- 05

PRIVATE BAG x 110
PRETORIA 0001

PUBLIC EXAMINATIONS

(6x2) (42)

(6x1) (6)

(6x2) (12)

FM. Wiese Please turn over

Externol Moderator
nralusi

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DEPARTME! Fe BAC

Biology/HG/P2 5
SCE — Memorandum ERY
13 -115-
14 2013 -06- 05
PiiVATE BAG A isd
1: Impulse¥ PRETORIA 0001 i
PUBLIC EXAMINATIONS
2: Sensory/afferent “neuron
Central nervous system/interneuronv / spinal cord (In this sequence)
3: Motor/efferent V neuron (4)
1.5
1.5.1 - (Gain) in metabolism ¥
- (Loss) by exhalation”
- (Loss) by sweating ¥ (Any2x1) (2)
1.5.2 600+ (24x 3) ¥=8,3v cm3h ¥ (3)
1.5.3 ADH / antidiuretic hormone ¥ (compulsory mark)
- is produced when the body
is losing too much water as in exercise / produced in
order to maintain blood water potential “
- Increases permeability of collecting ducts ¥
- Thus more water is reabsorbed back into the blood
- Resulting in a smaller volume of urine Vv (5)
(10)
16
16.1 (41.0-41.5)v "Cv (2)
1.6.2 - The only difference between the two camels was the availability of
water vv Jalil other factors were the same for both (2)
1.6.3 - Take readings from more camels” under the same conditions
- Repeat “ the experiment / on more days
- Use camels of the same age Y under the same conditions (any 2x1) (2)
1.6.4 - Hydrated camel was able to sweat more v to cool down” (2)
(8)
17
4.7.1 - Auxin ¥ (1)
1.7.2. - Tip of stem / rootY (1)
1.7.3 -1,00 ~mg/t (1)
Copyright reserved PML Wiese Please turn over

External Moderator ®
Imalusi

### Page 6

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Biology/HG/P2 6 DBE/2013
SCE ~ Memorandum

1.74  -The number of adventitious roots increase “as the plant growth substance
concentration increases” up to a certain optimum”
- High concentration of the plant growth substance inhibits growth v (any 3x1) (3)

1.7.5 - Regulate leaf and fruit abscission ¥

- Responsible for apical dominance “

- Responsible for tropic movements “

- Promotion of the ripening of fruit

- Rnhibition of germination of seeds “

- Improve development of fruit ¥

- Increase the plants resistance to infections ”

- Help in growth ~/ development / cell division / cell elongation (Any 2) (2)
(8)

TOTAL SECTION A: 60

DEPARTMENT GF BASIC
WW AKBUSATION ~

2013 -06- 05
PaivAl DAG A id
PRETORIA 0691
PUBLIC EXAMINATICN 5

Copyright reserved PH, Wiieseiease turn over
External Moderator
imalysi

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Biology/HG/P2 7 DEPARTMENGIOF
SCE — Memorandum EDUGATION we
SECTION B 2013 -08- 05
PRIVATE 8
QUESTION 2 PRETORIA Ooo!”
os PUBLIC EXAMINATIONS
2.1.1 Examples of ceil that can be drawn
Cell membrane V (can be dubble) Cell membrane

OR

Elodea cell in salt water Elodea cell in salt water
Quality of diagram “

Allow a maximum of:

2 marks, for showing a cell with shrunken contents
1 mark for labelling the cell membrane.

1 mark for caption

41 mark for quality of CORRECT diagram: neat and clear (5)
2.1.2 - Plasmolysis ¥ (1)
(6)

2.2

2.2.1 Accept:
~- Passive transport
- Osmosis / endosmosis¥ (1)

2.2.2 As the sugar concentration in the beaker increasesv’, the change
in mass of the dialysis tubing decreasesv or vice versa (2)

SM. Wiese

External Moderator
Umolusi

Copyright reserved Please turn over

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Biology/HG/P2

2.2.3

8

SCE - Memorandum

DEPARTMENT OF BASIC”
EDUCATION.

DBE/2Z0TS

2013 -08- 05

PRIVATE BAG X 110

Yunit
6;

“scale

Change in mass of dialysis

Change in mass of dialysis tubing in grams in
different sugar solutions

Y
¥ plotting
v

0 5 10

<

Y label

Sugar concentration in the beakers in %

Y type of graph

15 20 25 30 “scale

¥ unit

v heading

PRETORIA 0C01

PUBLEC EXAMINATIONS

Rubric for the assessment of the graph

Correct type of graph

Title of graph

Correct label for X-axis

Correct unit for label of X-axis

Correct label for Y-axis

Correct unit for label of Y-axis

Appropriate scale for X-axis

afa}o[a}.fo]]o)

Appropriate scale for Y-axis

Plotting of points for graphs

3: plotted all six
points correctly

2: plotted three
or more of the
points correctly

0: no points
plotted

1: plotted two or
fess of the points
correctly

Wrong type of graph is drawn : marks will be lost for “correct type of graph” as well as for

“plotting of points”

“If axes are transposed : marks will be lost for labels

7
cells

- lowers the water potential of the guard cellsY”
- leading to endosmosis” from surrounding epidermal cells
- Turgor pressure of guard cells increasesY
- Thin outer wails of guard cells bulge out”
- causing thick inner walls of guard cells to be pulled apart”
- leading to an increase in the size of the stomatal pore”

- allowing more water vapour to leave Vv

Copyright reserved

Feernal Moderator

imatysi

(11)
(14)

- Glucose” formed during photosynthesis v/ K* ions enter guard

(Any 6x1)

Please turn over

(6)

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[ CRPARTIENT or sxes—
Biology/HG/P2 9 EDUanON ec

SCE — Memorandum

i 2018 -08- 95
oe pate BAG xX 110
2.4.1 Mist “/ Moisture BOR
| BLIC EXAMINATIONS
2.4.2 - The group of plants in classroom conditions’
2.4.3 (4.2 + 7.6 + 11.7) ¥ -(45+7.6+ 11.0) ¥ =04/Y ml (3)
2.4.4 - Connection between plant and tube should be air tight V to

ensure that there are no air bubbles in the apparatus v
- Cut the twig under water V to prevent air entering the xylem V
- Use sharp knife V to prevent damaging the xylem” (Any 2 x 2) (4)
(9)
(35)

Copyright reserved External Medes dulel Please turn over

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| DEPARTMENT GF exer:
NT G el
Biology/HG/P2 10 finn SUCAT Poy
SCE — Memorandum
QUESTION 3 2013 -06- 95
PRIVATE BAG x

3.1 PRETORIA dGO)
3.1.14. A-—Ciliary body/muscle ¥ PUBLIC EXAMINATIONS

B ~ Suspensory ligaments ¥ 42)

3.1.2 a) Diagram || Y— Ciliary body moves closer to the lensv resulting in slack
suspensory ligaments “ (3)

b) Diagram | ¥— Pupil is dilatedv’/bigger to allow more light to enter the eye Vv (3)

3.1.3 a)Dv¥ (1)
b)FY (1)

3.1.4 - Can change its shape: ¥
- To focus image onto the yellow spot / retina “

- Irrespective of the distance from the eye v / For near or distant vision /

accommodation (3)
(13)
3.2
3.2.1 (a) - Absence of pain receptors Vv
- thus no impulse is generated ¥
- to be interpreted by the brain Vv : (3)
(b) - Pain is a protective function ¥
- Part could be lost or damaged ¥
- and lose its function for the body “
- Because the person is unaware of the harm ¥
- Therefore, does not respond appropriately / correctly Vv
- Leading to further damage ¥ (Any 5) (5)
3.2.2 (a) A: Optic nerve ¥
C: CerebellumY (2)
(b) BY (1)
3.2.3. Vital / reflex processes” such as breathing / heartbeat” will stop W (3)
3.2.4 (a) BY (1)
(b) Cv (1)
(16)
3.3 - Layer of fat under the skin v’ insulates the penguin against the cold v
- Streamlined body Y reduces resistance from water, v / allows the penguin
to swim faster to catch fish
- Oily feathers V prevent cold water reaching skin “ (6)
Copyright reserved GM. Wiese Please turn over

External Moderator
Umatusi

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Biology/HG/P2
QUESTION 4
4.1

4.1.1

4.1.2

4.1.3
4.2

4.2.1

4.2.2
4.3

4.3.1

4.3.2

4.3.3
Copyright reserved

11
SCE - Memorandum ; ae 16, ARON. : am

2013 -05- 95

PRIVATE B&G & 47
PRETORIA 0004

3000 vem? (2000 + 300 + 100) / 2400 vomp®_ PUBLIC EXAMINATIO
= 600 v cm? a EON]

- More sweat produced on warm v day
-To cool down the body “ (2)

On a hot day more liquids taken in W
less urination V
more sweating v (Mark first two only) (2)

”

The volume of urine produced by the kidneys will be higher v in
Man A ¥

OR
The volume of urine produced by the kidneys will be less Yin Man
BY

The concentration of urine will be lower” in Man A ¥
OR
The concentration of urine will be higher “in Man B W (4)

Man A sitting under shade ~/ less active and drinking, hence less
water lost through sweat “’/ more water lost through dilute urine

Man B runningv / more active, hence more water lost through

sweating” / less water lost through urine thus urine more

concentrated. (4)
(8)

In a healthy person:

Protein not present” because

proteins are large (macromolecules) Y / cannot pass through (filter)

In person with disease:

damaged tissue Y / glomerulus / Malphighian body

allows protein to filter through ¥ (4)

- Reabsorption “and
Active transport. Vv (2)

The urea in urine comes not only from the blood through
glomerular filtration’ but it is also added from the blood in the

second capillary network during tubular excretion” 7
: : ~ Please turn over
GM.Weose

External Moderator
Umotusi

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DEPARTEN ? BASIC

Biology/HG/P2 12
SCE — Memorandum
2018 -06- 95
4.4.1 - It creates a greater surface areav PRIVATE BAG x 40
[E BAG Ri

- for the movement of waste substances” into the bathimgstawid'ogn; (2)

PUBLIC & “2
4.42 - Useful substances in the bathing liquid bechme-desiteae PAUNATIONS

- while waste substances are depositedv into the bathing liquid
- to maintain a concentration difference” for the movement of

substances (Any 2) (2)
4.4.3 This is the average body temperature V needed for optimal
enzyme functioning “ (2)
(6)
45
Afferent arteriole ¥
Efferent arteriole V
Glomerulus W
Bowman’s
capsule ¥ PodocyteY
Capsular space”
Malphighian body of a human
nephron
Marking criteria:
Diagram should show the following:
- Efferent arteriole narrower than afferent arteriole VW
- Cup shaped ¥ :
- Any four (4) correct labels (6)
(35)
Copyright reserved PM. Wiese Please turn over

External Moderator”
mabysi

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[ DEPARTHENT OF wxste—

Biofogy/HG/P2 13
SCE — Memorandum
2013 -08- 95
QUESTION 5 PRIVATE Bac
x
PRETORIA over
5.1 PUBLIC EXAMINATIONS
5.1.1 0 ¥—2 ~years / during first “two years after birth (2)
5.1.2 (5,8 - 5,9) — (1,2 -1,5) “= (4,3-4,7) ¥ (2)
5.1.3 Boys: 14 W years ¥
Girls: 13 ¥ (3)
5.14 From the 9"v — 13" vyear (2)
5.1.5 Growth hormone / STH / Thyroxin ” (1)
5.1.6 17-18v (1)
5.1.7 - Females reach the second increase in growth rate/ puberty
earlier Y than males
- Females reach their final adult sizev earlierv than males
- Females have a smallerv adult sizev than males
- Between ages 4 and 6vgrowth of the boys is higher than girls,
Between 9 and 13 ~ growth rate of girls is higher than boys, “”
Between 13 and 18 growth rate of boys is higher than that of
girls. ¥ (any 3x2) (6)
(17)
5.2 Homeostasis is the maintenance of a constant internal environment “

When the metabolic rate is low ¥

because of low thyroxin concentration

the pituitary gland is stimulated V

to secrete TSH V

which is transported by the blood ”

to the thyroid gland which is stimulated to secrete more thyroxinY
which is transported to cells Vv

to increase the metabolic rate “

If the metabolic rate increases above the normal level “
the pituitary gland is inhibited v

therefore less / no TSHY is secreted

and therefore less thyroxin Vis secreted

The metabolic rate is lowered to normal Vv

The autonomic nervous system also influences the metabolic rate through

double innervation

which functions antagonistically Vv
One section is stimulatory, “

while the other section is inhibitory ¥
A constant internal environment ”

is thus maintained through negative feedback. W any 15
Copyright reserved FeAl, Vhiese Please turn over
External Moderator

alas;

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Biology/HG/P2

14
SCE — Memorandum

Assessing the presentation of the e:

Marks

Level description

()

Did not attempt the question.

4

The key concepts are used randomly to ansWeér-tne+
question and more explanation is needed. There are
significant gaps in the logic or flow of the answers. The
answer is meaningless.

Most of the key concepts are organised in a rather
superficial way. There are minor gaps in the logic or
flow of the answer. The learner does not demonstrate
that he/she is in full control of the relevant subject
content.

The answer is phrased logically and is well structured.
The key concepts are explained in such a way that the
answer demonstrates insight and understanding of the
relevant subject content / question.

Copyright reserved

Factual content:
Synthesis:

TOTAL SECTION C:
GRAND TOTAL:

4a
EM. Vijose

tsar
Umafusi

as faoi3

15

(18)

35
200

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