# Electrical Technology Grade 12 NSC November 2013 Memo (Eng)

> Grade 12 Electrical Technology memorandum from the NSC November Exam 2013 (English), 15 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/electrical-technology-nov-2013-memo-eng/bfddc3bc-e5b8-440e-ab87-54e4e0ff5d2e
- Updated: 2026-09-27
- Subject: Electrical Technology
- Grade: Grade 12
- Document type: Memorandum
- Year: 2013
- Exam period: NSC November Exam
- Curriculum: CAPS
- Pages: 15

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Electrical Technology · Grade 12 · NSC November Exam · 2013. Memorandum, 15 pages. Read online or download the PDF.

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                                   GRAAD 12

                                  NATIONAL
                             SENIOR CERTIFICATE

                                   GRADE 12

                          ELECTRICAL TECHNOLOGY

                                 NOVEMBER 2013

                                 MEMORANDUM

MARKS: 200

                       This memorandum consists of 15 pages.

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Elektriese Tegnologie                           2                           DBE/November 2013
                                        NSS – Memorandum

INSTRUCTIONS TO MARKERS

1.        All questions with multiple answers imply that any relevant, acceptable
          answer should be considered.

2.        Calculations:

          2.1           All calculations must show the formula.

          2.2           All answers must show the correct unit.

          2.3           Alternative methods must be marked.

          2.4           Where an erroneous answer is to be carried over to the next step,
                        the first answer will be marked incorrect. However, should the
                        incorrect answer be carried over correctly, the marker has to re-
                        calculate the values, using the incorrect answer from the first
                        calculation. If correctly used, the learner should receive the full
                        marks for subsequent calculations.

3.        The memorandum is only a guide with model answers. Alternative
          interpretations must be considered, and marked on merit. However, this
          principle should be applied consistently throughout the marking session at
          ALL marking centres.

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Elektriese Tegnologie                             3                           DBE/November 2013
                                          NSS – Memorandum

QUESTION 1: TECHNOLOGY, SOCIETY AND THE ENVIRONMENT

1.1       1.1.1      Wind power 
                     Solar power 
                     Hydro power
                     Wave power
                     Geothermal Energy
                                                                                  (any two)      (2)

          1.1.2      Coal has a huge negative impact on the environment and coal is
                     also not a renewable source of energy, at some stage there will be
                     no more coal to burn in SA. 
                     Coal pollution may also have a negative impact on the health of
                     individuals / society                                                       (2)

1.2       1.2.1      Without electricity a person will not have the opportunity to make
                     use of all the electrical and electronic devices that are educational
                     and allow for communication therefore retarding a person's
                     progress in education and life.                                            (2)

          1.2.2      The cost of petrol increases which increase the cost of
                     transporting coal to the power station
                     The cost of mining coal increases which increases the cost of
                     generating electricity
                     Water resources are becoming scarce and therefore will become
                     expensive increasing cost of generation of electricity
                     (This does not only limit the answer to Coal, could include any
                     reference to generation of electricity)
                     Archaic energy systems and ineffective energy designs waste
                     energy.                                                                     (2)

          1.2.3      Without electricity people will have to rely on an alternative source
                     of energy  like wood and other inconvenient and polluting fuels
                     such as coal, paraffin or candles.                                         (2)
                                                                                                 [10]
QUESTION 2: TECHNOLOGICAL PROCESS
Consider all possible types of answers related to the answers OR related to the
Technological Process as an interpretation thereof.

2.1       2.1.1         The input receives the electrical instruction and feeds into the CPU
                        (central processing unit)                                                   (2)

          2.1.2         The processing unit will receive the input and interpret it and
                        execute it and deliver it to the output                                     (2)

          2.1.3         The output receives the executed instructions and delivers it to the
                        external devices                                                            (2)

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Elektriese Tegnologie                           4                         DBE/November 2013
                                        NSS – Memorandum

          2.1.4         The power supply supplies the processing unit with the power to
                        execute the instructions                                                (2)

2.2       To establish that the design specification has been met
          To establish the correct operation of the artefact
                                                                  (Any relevant answer)          (2)
                                                                                                 [10]

QUESTION 3: OCCUPATIONAL HEALTH AND SAFETY

3.1       Horseplay in the workshop.
          Working on a machine which does not have the correct guards or protective
          devices.
          Working with live, open terminals.
          Touching live conductors exposed in the workshop.
          Using incorrect tools in the workshop.
          Using correct tools incorrectly.
          Not using safety equipment/uniform.
                                                                         (Any two)               (2)

3.2       Earth leakage protective devices.
          Emergency stop button. 
          Overload relay. 
          Fuses
          Circuit breakers
          Stop Button
          Emergency Disconnect Button
          Isolator Switch
                                                                             (Any three)         (3)

3.3       Any fire extinguisher that uses a non-conductive material such as CO 2 type or
          powder type. 
          Fire bucket with Sand
          Type C Fire Extinguisher
          ABC Dry Chemical (popular)
          Carbon Dioxide (CO2)
          Halotron
          Halotron 1211
          High Performance Dry Chemical
          Regular Dry Chemical                                                                   (1)

3.4       Before connecting the meter make sure the power is switched off.
          Set the meter to the highest current scale. 
          Make sure that the meter is connected in series in the circuit.
          Make sure the leads of the meter are plugged into the correct sockets of the
          meter.
          Make sure correct scale is used for AC or DC.
          After connecting the meter correctly proceed with the line test.
          Mention of a clamp meter as ammeter is acceptable          (Any two)                   (2)

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Elektriese Tegnologie                                     5                   DBE/November 2013
                                                  NSS – Memorandum

3.5       The workshop must be well ventilated to prevent drowsiness which may
          lead to an accident and possible injuries.
          Some work processes may lead to fumes being released which, if not
          extracted, will cause health problems.                       (Any one)                     (2)
                                                                                                     [10]

QUESTION 4: THREE-PHASE AC GENERATION

4.1       For high power generation the three-phase system is more functional and
          efficient.
          For generators with the same size frame three-phase machines produce more
          power than single-phase machines.
          Three-phase generators may be connected in parallel to obtain an increased
          supply.
          Three-phase systems can deliver both three-phase and single-phase power.
                                                                          (Any one)                  (1)
          If candidate speaks of motor- no penalisation

4.2                                    IL 
                                     IP 
                 VPh                     VPh
                                                      VL=VPh
                     IP                                         
                                                            VL=VPh

                                      IP
                              VPh                      VL=VPh
                                                                                                     (4)
          Marks not allocated for Direction of arrows but for the labels.

4.3      4.3.1               P = 3VL I L cos θ
                                            P
                              IL =
                                       3VL cos θ 
                                           60 x 10 3
                                 =                        
                                     3 x 380 x 0.85
                                             
                                 = 107.25 A                                                      (3)

         4.3.2            If the power factor of the load was improved the current drawn by
                          the load will be reduced  while the load and the voltage across
                          the load remains constant.                                            (2)
                          The load and the voltage across the load will remain constant;
                          therefore the current drawn by the load will decrease with an
                          improved power factor.
                          The circuit Impedance changes.
                                                                                                 [10]

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Elektriese Tegnologie                             6                          DBE/November 2013
                                          NSS – Memorandum

QUESTION 5: RLC CIRCUITS

5.1       The frequency of the supply
          Capacitance of the capacitor 
          Size of the capacitor                                                                 (2)
          If physical characteristics as well as capacitance are mentioned – Only one
          mark as these refer to the same component /factor

5.2       Inductive reactance is the opposition offered by the inductor to the flow of
          current in a coil when the coil is connected across an alternating-voltage
          supply and it is measured in ohms.                                                   (2)
          If mention is made of resistance – The learner will get 1 Mark Maximum

5.3       If the number of turns of the coil are increased the inductance of the coil will
          increase therefore the inductive reactance of the coil will increase.               (2)

5.4       5.4.1
                                 VR
                                 IR 
                                   

                                                                                                (2)

                     (Must show that V and I are in phase)

          5.4.2
                            VL
                                      
                                 IL
                                            

                                                                                                (2)

                     Must show that I lags V
                     Labelling is important to show lag of the current with respect to the
                     applied voltage.

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Elektriese Tegnologie                                               7                    DBE/November 2013
                                                            NSS – Memorandum

5.5       5.5.1       X L = 2πfL            
                                  = 2 x π x 50 x 180 x 10− 3 
                                  = 56.55 Ω                                                               (3)

          5.5.2                         1
                      XC =
                                      2πfC 
                                               1
                                  =                                
                                      2πx50 x 200 x 10 − 6
                               = 15.92 Ω                                                                  (3)

          5.5.3       Z =             R 2 + ( X L − X C )2     

                              =                (
                                      102 + 56.55 − 15.92) 2       )
                              = 41.84 Ω 
                                                                                                           (3)

          5.5.4                 V
                      I =            
                                Z
                                 220 
                              =
                                41.84                                                                      (3)
                              = 5.26 A 
          5.5.5                                VL 

                                                                               VS   
                                      VL- VC

                                                               ᶱ
                                                                           IS   VR 

                                               VC
                                                        
                                                                                                           (5)
                      One mark per correct label (maximum 5)

5.6       IS =       I R + ( IC − I L )2
                          2
                                                    
              = 1 + (2 − 1.5)
                      2                    2
                                                   
              = 1.12 A 
                                                                                                           (3)
                                                                                                           [30]

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Elektriese Tegnologie                             8                             DBE/November 2013
                                          NSS – Memorandum

QUESTION 6: SWITCHING AND CONTROL CIRCUITS

6.1
             A                    C
                                  G
                                              (one mark for correct drawing without labels)            (3)

6.2       Speed control of electrical motors 
          Lamp dimming of incandescent lamps
          Temperature control of furnaces
          Inverters                                                         (Any two)                  (2)

6.3       A voltage must be applied across the two main terminals of the SCR with
          the anode made positive and the cathode negative. It can now be
          triggered into conduction by a positive pulse to the gate. 
                                                                                                       (3)

6.4       The physical size of an SCR is determined by the supply voltage it will be
          connected across and the maximum current that will flow through the
          device.
          The higher the current, the larger the device should be.
          External environmental heat factors                                                          (2)

6.5       A voltage in any direction (of any polarity)  must be applied across the
          DIAC  this voltage must now be increased to the break-over voltage of
          the DIAC, about 30 V to 50 V. The DIAC will now switch on and allow
          current to flow through it.                                                                  (3)

6.6       6.6.1         To allow a specific gate voltage to the gate of the TRIAC to fire it
                        into conduction. OR to prevent transient signals to the gate of the
                        TRIAC and therefore triggering the TRIAC.                                      (2)

          6.6.2         The time it takes for the capacitor to fully charge depends upon the
                        value of R 2  and the value of the capacitor.  The time constant
                        is calculated by T=5RC. Therefore if R 2 is increased the capacitor
                        will take longer to charge to the required voltage to trigger the
                        TRIAC into conduction. The current will therefore flow through
                        the lamp for a shorter period reducing its brightness.                        (5)

6.7       6.7.1         When the TRIAC begins to conduct its internal resistance falls
                        this will result in the voltage drop across the TRIAC dropping to a
                        lower voltage (almost Zero). 
                        (The reduction /fall /drop / lowering / decrease of internal
                        resistance is the crux of the question – If no mention is made
                        thereof – only award 2 marks maximum)                                          (3)

          6.7.2         I H is the holding current which is the minimum current that must
                        flow through the TRIAC to maintain conduction. 
                        If the current drops below I H the TRIAC will stop conducting.                 (2)
                                                                                                       [25]
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Elektriese Tegnologie                             9                           DBE/November 2013
                                          NSS – Memorandum

QUESTION 7: AMPLIFIERS

7.1      7.1.1          Positive feedback: the output signal is fed back into the input and
                        added in phase to the input signal resulting an increased input            (3)
                        signal therefore leading to an increased gain.

         7.1.2          Leads to instability in circuits. 
                        Causes ring feed (shock oscillation)
                        Renders the output therefore unpredictable               (Any one)           (1)

         7.1.3          Design of oscillator circuits to overcome losses of natural
                        oscillation                                                                 (1)

7.2      1 - Inverting input 
         2 - Non-inverting input 
         3 - Output                                                                                 (3)

7.3      7.3.1          Inverting comparator op-amp                                                 (1)

         7.3.2

                          Vref
                                               

                         +Vc              

                          

                         -Vcc         
                                                                                                     (5)

         7.3.3          V ref determines when the output voltage is switched due to a
                        change in the input voltage above or below V ref .                         (3)

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Elektriese Tegnologie                       10                             DBE/November 2013
                                     NSS – Memorandum

7.4

                                            _

                                                 

                                           +
                                                                    Rf               
                               VIN                                                    Vout

                                                                
                                                                     Rin

                                                                                                    (5)

7.5      By making R f small (zero or short-circuited)  and R in very large                      (3)
                                                                                                    [25]

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Elektriese Tegnologie                                      11            DBE/November 2013
                                                    NSS – Memorandum

QUESTION 8: THREE-PHASE TRANSFORMERS

8.1     To step down the mains voltage in a domestic supply for use in a cellphone
        charger. 
        Any practical application.                                                              (1)

8.2     An alternating voltage is connected to the primary winding of the transformer. 
        This sets up an alternating current in the primary. 
        This sets up a magnetic field that is linked to the secondary winding via a
        laminated iron core. 
        The magnetic field expands outwards and collapses inwards cutting the
        secondary winding.
        The relative movement between the magnetic field and the secondary winding
        results in an EMF being induced across the secondary winding. 
        Lenz's law.
        The process is due to mutual induction.                                                (5)

8.3     8.3.1        The input power doubles (increase 100% -same amount)

        8.3.2        The current will also double (increase 100% -same amount)

        8.3.3        The voltage stays the same

8.4     8.4.1
                  POUT = 3VL ( S ) I L ( S ) cos θ
                                 POUT
                  I L( s) =                     
                              3VL ( S ) cos θ
                              66 x103
                         =                  
                            3 x 380 x 0.85
                         = 117.97 A                                                            (3)

        8.4.2     POUT = PIN
                  PIN = 3VL ( P ) I L ( P ) cos θ
                                  PIN
                  I L( s) =                     
                              3VL ( P ) cos θ
                             66 x103
                        =                 
                         3 x 11000 x 0.85
                                                                                                (3)
                      = 4.08 A 
                 Alternative method using Ratios and Phase Values is acceptable
                                                                                                [15]

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Elektriese Tegnologie                          12                             DBE/November 2013
                                        NSS – Memorandum

QUESTION 9: LOGIC CONCEPTS AND PLCs

9.1       Sequencing of robots
          Control of machinery in factories
          Automation of machinery in assembly lines
                                                                       (Any relevant answer)         (2)

9.2       9.2.1      The program is written to memory from a device
                     ( PC )  OR The programme is stored here                                        (2)
                     OR
                     (Function of the memory is to store the information it receives
                     during programming process)

          9.2.2      Execute the tasks (instructions program) that were written into               (2)
                     memory.
                     OR
                     Process the information

          9.2.3      Connecting the input  devices from the electrical circuits to the PLC.         (2)
                     
                     OR
                     (The function of the input interface is to accept the input signal and
                     feed it into the PLC)

9.3       Ladder logic ( LL) 
          Instruction list (IL) 
          Logic block diagram ( LBD)                                                                (3)
          Flow Diagram
          Function Blocks
          Structured Text

9.4       9.4.1      NOT function                                                                   (1)

          9.4.2

                                        
                                                             
                                 X              =1                 F

                     Alternative symbols acceptable
                     Any two correct labels                                                          (2)

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Elektriese Tegnologie                           13                        DBE/November 2013
                                         NSS – Memorandum

          9.4.3      X F
                     0 1
                                                                              
                     1 0                                       C1       F

                                                                                                     (2)
          9.4.4      Start = I1
                     Relay Coil = C
                     Relay Contact =C1                                     
                     Lamp = F                                            C
                                                                                     
                     Can be interpreted either way
                     Different labelling techniques
                     Acceptable
                                                                   I1
                     Correct answer will receive full credit

                                                                                                     (5)

9.5       9.5.1      Direct online starter control circuit                                          (1)
                     Holding Circuit

          9.5.2
                                       
                            Overload Xo

                            Stop X1 

                            Start X3                     N/O contacts

                        

                            Coil Yo 

                                                                                                     (6)

9.6       9.6.1      The design effort is simpler owing to fewer components and easy
                     sequence planning.                                                              (2)

          9.6.2      Relay and timer problems are reduced.                                         (2)
                     Fewer Moving Parts
                     Solid State

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Elektriese Tegnologie                              14                       DBE/November 2013
                                            NSS – Memorandum

          9.6.3      They are much more compact than a relay panel. Mass production
                     is possible by repeat of programs.                                           (2)
                     (Compact – The device takes up less physical space – This has
                     many advantages, reducing cost of manufacturing, using surface
                     mount devices with automated manufacturing)
                     Standardised programming approaches and inter product
                     compatablility. Industry standards such as profibus etc.

9.7       Counter 
          PLC                                                  (any other relevant answer)         (1)
                                                                                                   [35]

QUESTION 10: THREE-PHASE MOTORS AND CONTROL

10.1      Star connection
          Delta connection                                                                        (2)

10.2      Insulation resistance between windings test.
          Insulation resistance to earth test.
          Short-circuit or
          open-circuit test.                                                                       (3)
          continuity test of the windings

10.3      Is the cooling fan intact and turning freely but mounted securely on the motor
          shaft? 
          Does the frame have any cracks or missing parts? 
          Are the bearings noisy or feel rough when turning?
          Is the motor mounted securely and are the bolts tightened properly?
          End plates fastened properly?
                                                                               (Any two)           (2)

10.4      By reversing/swapping the connections of any two of the supply lines to the
          stator.                                                                                 (1)

10.5      Large power range available 
          Self-starting 
          Higher starting torque
          More efficient than single-phase motors
          Physically smaller than single-phase motors for the same output
                                                                                (Any two)          (2)

10.6      10.6.1        P = 3VL I L cos θ
                                  P
                        IL =             
                               3VL cos θ
                                 17000
                           =                 
                               3 x 380 x 0.8
                           = 32.29 A                                                              (3)

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Elektriese Tegnologie                             15                        DBE/November 2013
                                           NSS – Memorandum

          10.6.2              P 
                        S=
                            Cosθ
                            17000 
                          =
                             0.8
                          = 21.25 kVA

                        OR

                        S = 3 × VL × I L
                          = 3 × 380 × 32.29
                          = 21.25 kVA
                                                                                                (3)
10.7      The casing of the motor is made from a conducting material, earthing it will
          activate protection under fault conditions preventing electric shock.               (2)

10.8      Overload unit
          No-volt coil
          Emergency stop buttons
          Circuit breakers
          Isolator switch
          MCB                                                                                   (3)
          Fuse
                                                                              (Any three)

10.9      Excessive current to the motor. 
          Motor not running on all three phases. 
          Motor used over long periods without switching and cooling off.
          Overloading the motor
          Insufficient ventilation                                                              (2)
          Over and under voltage condition
                                                                            (Any two)

10.10     Normally open contacts are contacts open in the de-energised state and
          closed in the energised state.                                                       (2)

10.11     Protect the fan from damage 
          Protect users from injuries 
          Force the air over the motor fins for cooling.                                        (2)
          Take note that the Afrikaans version can be interpreted as an endplate!

10.12     The purpose of electrical switchgear is to safely distribute and control
          electrical energy and provide electrical protection as well protect the
          operator of the equipment.                                                           (3)
                                                                                                [30]

                                                                                 TOTAL:         200

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- [ELEC TECH GR12 QP SEPT2024 Power Systems Afrikaans](https://www.hlayiso.com/library/elec-tech-gr12-qp-sept2024-power-systems-afrikaans/928e510b-68c2-4670-a7c7-fe20b388befb) — QP · 2024 · Afr
- [ELEC TECH GR12 QP SEPT2024 Digital English](https://www.hlayiso.com/library/elec-tech-gr12-qp-sept2024-digital-english/9fcfef2b-6d5e-4601-853a-24a2a3993617) — QP · 2024 · Eng

## Collection

- [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers)

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Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.
