# Physical Sciences Grade 12 Paper 2 Free State Mock 2018 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the Free State Mock Exam 2018, 15 pages. Read online or download the free PDF.

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- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2018
- Exam period: Free State Mock Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 15

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### Page 1

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                PREPARATORY EXAMINATION
                VOORBEREIDENDE EKSAMEN

                            GRADE/GRAAD 12

   PHYSICAL SCIENCES: CHEMISTRY (P2)
   FISIESE WETENSKAPPE: CHEMIE (V2)

                             SEPTEMBER 2018

                           MARKS/PUNTE: 150

                               MEMORANDUM

                      This memorandum consists of 15 pages.
                    Hierdie memorandum bestaan uit 15 bladsye.

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Physical Sciences P2/Fisiese Wetenskappe V2 2                           FS/VS/September 2018
Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

QUESTION 1/VRAAG 1

1.1     C                                                                                  (2)

1.2     A                                                                                  (2)

1.3     D                                                                                  (2)

1.4     D                                                                                  (2)

1.5     A                                                                                  (2)

1.6     C                                                                                  (2)

1.7     D                                                                                  (2)

1.8     B                                                                                  (2)

1.9     B                                                                                  (2)

1.10    D                                                                                  (2)
                                                                                           [20]

QUESTION 2/VRAAG 2

2.1.1 A                                                                                    (1)

2.1.2 ANY TWO/ENIGE TWEE
      B
      C
      D                                                                                    (1)

2.2
2.2.1 Compounds with the same molecular formula but different types of
      chains.
      Verbindings met dieselfde molekulêre formule, maar verskillende soort
      kettings.                                                                            (2)

2.2.2

                                        IF/INDIEN:
                                        • H atom omitted/H-atoom uitgelaat: - 1
                                        • Condensed structure/Gekondenseerde
                                           struktuur: -1

                                                                                           (2)

2.3     H2                                                                                 (1)

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Physical Sciences P2/Fisiese Wetenskappe V2 3                         FS/VS/September 2018
Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

2.4
2.4.1 Butanal/Butanaal                                                                   (1)

2.4.2 3-methyl but-1-yne /3-methyl-1-butyne
      3-metielbut-1-yn/3-metiel-1-butyn                                                  (2)

2.5

         Marking guidelines/Nasienriglyne
         • Ignore/Ignoreer ⇌
         • Accept H2O if condensed./Aanvaar H2O as gekondenseerd.
         • Any additional reactants and/or products/Enige addisionele reaktanse en/of
           produkte:                                              Max./Maks. 3/4
         • Accept coefficients that are multiples.
           Aanvaar koëffisiënte wat veelvoude is.
         • Incorrect balancing/Verkeerde balansering:             Max./Maks. 3/4
         • Condensed formulae/Gekondenseerde formules:            Max./Maks. 3/4
           Molecular formulae/Molekulêre formules:                Max./Maks. 1/4

                                                                                         (4)

2.6

        Marking criteria/Nasienriglyne:
        • At least one structural formula of ethanol as shown.
          Ten minste een struktuurformule van etanol soos aangetoon.
        • Dotted line drawn from O-atom of one molecule to H-atom bonded to an
          O-atom in the second molecule (H-atom should be between two O-
          atoms).
          Stippellyn getrek vanaf O-atoom op een molekuul na 'n H-atoom gebind
          aan 'n O-atoom in die tweede molekuul (H-atoom moet tussen twee O-
          atome wees).

                                                                                         (2)

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Physical Sciences P2/Fisiese Wetenskappe V2 4                        FS/VS/September 2018
Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

2.7
2.7.1 Addition polymerisation/Addisiepolimerisasie                                      (1)

2.7.2

          n                                              Bal.
                                                n

          Marking guidelines/Nasienriglyne
          • Ignore/Ignoreer ⇌
          • Any additional reactants and/or products/Enige addisionele reaktanse
            en/of produkte:                                        Max./Maks. 2/3
          • Incorrect balancing/Verkeerde balansering:             Max./Maks. 2/3
          • Condensed formulae/Gekondenseerde formules:            Max./Maks. 2/3
          • Molecular formulae/Molekulêre formules:                0/3
                                                                                        (3)
                                                                                        [20]

QUESTION 3/VRAAG 3

3.1     Haloalkanes/Alkyl halides/Haloalkane/Alkielhaliede                              (1)

3.2
3.2.1 London forces/dispersion forces/induced dipole forces
      Londonkragte/dispersiekragte/geïnduseerde dipoolkragte                            (1)

3.2.2 Structure/Struktuur:
      Compound B has a longer chain length/larger molecular size/molecular
      structure/molecular mass/surface area than compound A.
      Verbinding B het 'n langer kettinglengte/groter molekulêre grootte/
      molekulêre struktuur/molekulêre massa/oppervlak as verbinding A.
      Intermolecular forces/Intermolekulêre kragte:
      Stronger intermolecular forces/induced dipole forces/London forces/
      dispersion forces/Van der Waals forces.
      Sterker intermolekulêre kragte/geïnduseerde dipoolkragte/Londonkragte/
      dispersiekragte/Van der Waalskragte.
      Energy/Energie:
      More energy needed to overcome/break intermolecular forces.
      Meer energie benodig om intermolekulêre kragte te oorkom/breek.

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    Physical Sciences P2/Fisiese Wetenskappe V2 5                       FS/VS/September 2018
    Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

            OR/OF

            Structure/Struktuur:
            Compound A has a shorter chain length/smaller molecular size/molecular
            structure/molecular mass/surface area than compound B.
            Verbinding A het 'n korter kettinglengte/kleiner molekulêre grootte/
            molekulêre struktuur/molekulêre massa/oppervlak as verbinding B.
            Intermolecular forces/Intermolekulêre kragte:
            Weaker intermolecular forces/induced dipole forces/London forces/
            dispersion forces/Van der Waals forces.
            Swakker intermolekulêre kragte/geïnduseerde dipoolkragte/Londonkragte/
            dispersiekragte/Van der Waalskragte.
            Energy/Energie:
            Less energy needed to overcome/break intermolecular forces.
            Minder energie benodig om intermolekulêre kragte te oorkom/breek.      (3)

    3.3     Positional (isomers)/Posisie(-isomere)                                         (1)

    3.4.1 69 °C                                                                            (1)
-
    3.4.2
            •   Compare compound D to compound B:
                Vergelyk verbinding D met verbinding B:
                Compound D is more branched/more compact/has a smaller surface
                area than compound B.
                Verbinding D is meer vertak/meer kompak/het 'n kleiner oppervlak as
                verbinding B.
            •   Compare compound D to compound E:
                Vergelyk verbinding D met verbinding E:
                Compound D is less branched/has a longer chain length/larger surface
                area than compound E.
                Verbinding D is minder vertak/het 'n langer kettinglengte/het 'n groter
                oppervlak as verbinding E.
            •   Intermolecular forces in compound D are weaker than in compound B
                and stronger than in compound E.
                Intermolekulêre kragte in verbinding D is swakker as in verbinding B en
                sterker as in verbinding E.
            •   Less energy is needed to overcome/break intermolecular forces in
                compound D than in compound B and more energy is needed to
                overcome/break intermolecular forces in compound D than in
                compound E.
                Minder energie benodig om intermolekulêre kragte in verbinding D te
                oorkom/breek as in verbinding B en meer energie benodig om
                intermolekulêre kragte in verbinding D te oorkom/breek as in
                verbinding E.                                                           (4)
                                                                                        [11]

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Physical Sciences P2/Fisiese Wetenskappe V2 6                        FS/VS/September 2018
Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

QUESTION 4/VRAAG 4

4.1
4.1.1 Z                                                                                 (1)

4.1.2 X                                                                                 (1)

4.1.3 V                                                                                 (1)

4.1.4 Y                                                                                 (1)

4.2
4.2.1 Propan-2-ol/2-propanol                                                            (1)

4.2.2 Propane/propaan                                                                   (1)

4.3
4.3.1 Both reactions take place in the presence of a strong base/NaOH/
      KOH/LiOH.
      Beide reaksies vind plaas in teenwoordigheid van 'n sterk basis/NaOH/
      KOH/LiOH.                                                                         (1)

4.3.2 Y: concentrated base/ethanolic base & Z: dilute base/base in water/water
      Y: gekonsentreerde basis/etanoliese basis & Z: verdunde basis/basis in
         water/water

        Y: heat (strongly)/high temperature & Z: mild heat
        Y: verhit (sterk)/hoë temperatuur & Z: matige hitte                             (2)

4.3.3          H      H    H                                   H     H     H

          H     C     C     C    H + H - Br              H     C      C     C     H

                H                                              H      Br    H
          Marking guidelines/Nasienriglyne
          • Ignore/Ignoreer ⇌
          • Accept HBr if condensed./Aanvaar HBr as gekondenseerd.
          • Any additional reactants and/or products/Enige addisionele reaktanse
            en/of produkte:                                        Max./Maks. 2/3
          • Accept coefficients that are multiples.
            Aanvaar koëffisiënte wat veelvoude is.
          • Incorrect balancing/Verkeerde balansering:             Max./Maks. 2/3
          • Condensed formulae/Gekondenseerde formules:            Max./Maks. 2/3
          • Molecular formulae/Molekulêre formules:                Max./Maks. 1/3

                                                                                        (3)
                                                                                        [12]

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Physical Sciences P2/Fisiese Wetenskappe V2 7                                                  FS/VS/September 2018
Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

QUESTION 5/VRAAG 5

5.1
                                 5.1.1
                                          (a)   Concentration (of Na2S2O3)/Konsentrasie (van Na2S2O3)            (1)

                                          (b)   To dilute (the Na2S2O3)/Om Na2S2O3 te verdun.

                                                 OR/OF

                                                 Decrease concentration (of Na2S2O3.)
                                                 Verminder konsentrasie (van Na2S2O3.)                           (1)

                                 5.1.2       Graph of volume of Na2S2O3(aq) versus reaction rate
                                            Grafiek van volume Na2S2O3(aq) teenoor reaksietempo
                                 30

                                 25

      Volume Na2S2O3(aq) (cm3)
                                 20

                                 15

                                 10

                                  5

                                  0
                                      0         0,02     0,04      0,06     0,08      0,10       0,12        0,14
                                                                                          -1
                                                           Reaction rate/Reaksietempo (s )

                                  Marking criteria/Nasienriglyne
                                  Any three points plotted correctly./Enige drie punte korrek gestip.
                                  All the points plotted correctly./ Alle punte korrek gestip.
                                  Best-fit line drawn./Beste paslyn getrek.
                                                                                                                 (3)

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Physical Sciences P2/Fisiese Wetenskappe V2 8                        FS/VS/September 2018
Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

                     1              1       1
       5.1.3                 /            =     = 0,09 (s-1 )
               reaction time reaksietyd 11
               On graph: Dotted line starting from 0,09 s on x axis drawn to y axis
               as shown on graph.
               Op grafiek: Stippellyn geteken vanaf 0,09 s op x-as na y-as soos
               getoon op grafiek.

               Reading on y axis/Lesing op y-as: 17,5 cm3
               (Accept/Aanvaar: 17 – 18 cm3)

            Note/Let wel: Award mark for answer only if 0,09 s used and dotted
            lines shown on graph./Ken punt vir antwoord slegs toe indien 0,09 s
            gebruik is en stippellyn op grafiek aangetoon is.
                                                                                        (3)

       5.1.4 Higher than/Hoër as
           -
               OPTION 1/OPSIE 1
               In experiment 1/In eksperiment 1:
       •       More (Na2S2O3) particles per unit volume.
               Meer (Na2S2O3)-deeltjies per eenheidsvolume.
       •       More effective collisions per unit time.
               Meer effektiewe botsings per eenheidstyd.

               OPTION 2/OPSIE 2
               In experiment 5/In eksperiment 5:
       •       Less (Na2S2O3) particles per unit volume.
               Minder (Na2S2O3)-deeltjies per eenheidsvolume.
       •       Less effective collisions per unit time .
               Minder effektiewe botsings per eenheidstyd.                              (3)

5.2
       5.2.1 The minimum energy needed for a reaction to take place.
             Die minimum energie benodig vir 'n reaksie om plaas te vind.               (2)

       5.2.2 (a)     - 20 kJ•mol-1                                                      (1)

               (b)   185 kJ•mol-1                                                       (1)

       5.2.3 Reverse (reaction)/Terugwaartse (reaksie)                                  (1)
                                                                                        [16]

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Physical Sciences P2/Fisiese Wetenskappe V2 9                               FS/VS/September 2018
Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

QUESTION 6/VRAAG 6

6.1    Reversible reaction/Omkeerbare reaksie                                                  (1)

6.2      Marking criteria/Nasienriglyne:
         • Use M(NH4Cℓ) = 53,5 g·mol-1 to calculate n(NH4Cℓ)
            Gebruik M(NH4Cℓ) = 53,5 g·mol-1 om n(NH4Cℓ) te bereken.
         • m(NH4Cℓ)used/gebruik = m(NH4Cℓ)initial/begin - m(NH4Cℓ)equil/ewe
            OR/OF
            n(NH4Cℓ)used/gebruik = n(NH4Cℓ) initial/begin - n(NH4Cℓ) equil/ewe
         • USING ratio/GEBRUIK verhouding: NH4Cℓ : NH3 : HCℓ = 1 : 1 : 1
         • n(NH3)equil/ewe = n(NH3)form/gevorm & n(HCℓ)equil/ewe = n(HCℓ)form/gevorm
         • Divide/Deel n(NH3)equil/ewe & n(HCℓ)equil/ewe by/deur 0,5 dm3
         • Correct KC expression/Korrekte Kc-uitdrukking
         • Substitution of concentrations into KC expression.
            Vervang konsentrasies in Kc-uitdrukking.
         • Final answer/Finale antwoord: to/tot 0,01
            Range/Gebied: 0,009,447 x 10-3 to/tot 0,01

       OPTION 1/OPSIE 1

                                               NH4Cℓ(s)         NH3(g)     HCℓ(g)
       Initial quantity (mol)                 10,7
                                                   = 0,2           0          0
       Aanvanklike hoeveelheid (mol)          53,5
       Change (mol)                                                                    Ratio/
                                                  0,05           0,05       0,05
       Verandering (mol)                                                               verhouding
       Quantity at equilibrium (mol)          8,1
                                                   = 0,15        0,05       0,05
       Hoeveelheid by ewewig (mol)            53,5
       Equilibrium concentration
       Ewewigskonsentrasie                           -            0,1        0,1       Divide by/Deel
       (mol·dm-3)                                                                      deur 0,5

       Kc = [NH3][HCℓ]                No KC expression, correct substitution/Geen Kc-
          = (0,1)(0,1)                uitdrukking, korrekte vervanging: Max./Maks. 7/8
          = 0,01
                                      Wrong KC expression/Verkeerde Kc-uitdrukking:
                                      Max./Maks. 5/8
               IF/INDIEN: [NH4Cℓ] = 1 in Kc = [NH3][HCℓ]
                                               [NH4Cℓ]
               No mark for Kc expression, but continue marking substitution and answer.
               Geen punt vir Kc-uitdrukking, maar sien substitusie en antwoord na.

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Physical Sciences P2/Fisiese Wetenskappe V2 10                           FS/VS/September 2018
Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

OPTION 2/OPSIE 2:

∆m(NH4Cℓ) = 10,7 – 8,1         = 2,6 g

∆n(NH4Cℓ) = 2,6         = 0,05 mol
            53,5

∆n(NH3) = ∆n(NH4Cℓ) = 0,05 mol
∆n(HCℓ) = ∆n(NH4Cℓ) = 0,05 mol

n(NH3)equi/ewe = n(NH3)initial/begin + ∆n(NH3) = 0,05 mol
n(HCℓ) equi/ewe = ∆n(HCℓ)initial/begin + ∆n(HCℓ) = 0,05 mol

[NH3]equi/ewe = 0,05 = 0,1 mol
                0,5
                                          Divide by/Deel deur 0,5
[HCℓ]equi/ewe = 0,05
                     = 0,1 mol
                0,5

                                     No KC expression, correct substitution/Geen Kc-
          Kc = [NH3][HCℓ]            uitdrukking, korrekte vervanging: Max./Maks. 7/8
             = (0,1)(0,1)            Wrong KC expression/Verkeerde Kc-uitdrukking:
             = 0,01                  Max./Maks. 5/8
                 IF/INDIEN: [NH4Cℓ] = 1 in Kc = [NH3][HCℓ]
                                                 [NH4Cℓ]
                 No mark for Kc expression, but continue marking substitution and answer.
                 Geen punt vir Kc-uitdrukking, maar sien substitusie en antwoord na.

                                                                                            (8)

6.3       Endothermic/Endotermies
      -
          •   Increase in temperature increases concentration of products/favours
              forward reaction.
              Toename in temperatuur verhoog die konsentrasie van die
              produkte/bevoordeel die voorwaartse reaksie.
          •   Increase in temperature favours the endothermic reaction.
              Toename in temperatuur bevoordeel die endotermiese reaksie.                   (3)

6.4
6.4.1 Remains the same/Bly dieselfde                                                        (1)

6.4.2 Increases/Verhoog                                                                     (1)

6.4.3 Remains the same/Bly dieselfde                                                        (1)
                                                                                            [15]

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Physical Sciences P2/Fisiese Wetenskappe V2 11                           FS/VS/September 2018
Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

QUESTION 7/VRAAG 7

7.1
7.1.1 A dilute base contains a small amount/number of moles of base in
      proportion to the volume of water and a concentrated base contains
      a large amount/number of moles of base in proportion to the volume of
      water.
      'n Verdunde basis bevat 'n klein hoeveelheid/aantal mol basis in
      verhouding tot die volume water en 'n gekonsentreerde basis bevat 'n
      groot hoeveelheid/aantal mol basis in verhouding tot die volume water.                (2)

7.1.2 Phosphoric acid (solution)/Fosforsuur(oplossing)                                      (1)

7.1.3 (a)      Increases/Toeneem                                                            (1)

        (b)    Increases/Toeneem                                                            (1)

7.2
7.2.1
          Marking criteria/Nasienriglyne:
                                                               n
          • Formula/Formule: pH = -log [H3O+] OR/OF c =
                                                               v
          •   Substitute/Vervang pH = 2.
          •   Use mol ratio/Gebruik molverhouding: n(H3PO4) : n(H3O+) = 1:3
          •   Substitute/Vervang [H3PO4] & 0,5 dm3 in n= cV.
          •   Final answer/Finale antwoord: 1,67 x 10-3 mol / 1,665 x 10-3 mol

          pH = -log [H3O+]
           2 = -log [H3O+]
           [H3O+] = 0,01 mol·dm-3

          [H3PO4] =       [H3O+]
                                                            Any one/Enige een
                    =      x 0,01
                    = 3,33 x 10-3 mol·dm-3

          n(H3PO4)ini/aanv = cV
                           = (3,33 x 10-3)(500 x 10-3)
                           = 1,67 x 10-3 mol
                                                                                            (5)

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Physical Sciences P2/Fisiese Wetenskappe V2 12                               FS/VS/September 2018
Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

7.2.2 POSITIVE MARKING FROM QUESTION 7.2.1.
      POSITIEWE NASIEN VANAF VRAAG 7.2.1.

        Marking criteria/Nasienriglyne:
        • Use M = 58 g·mol-1 to calculate n(Mg(OH)2)reacted
          Gebruik M = 58 g·mol-1 om n(Mg(OH)2)gereageer te bereken.
        • Use mol ratio/Gebruik molverhouding: n(H3PO4) : n(Mg(OH)2) = 2:3
        • Subtraction/Aftrekking:
          n(H3PO4)excess/oormaat = n(H3PO4)initial/aanvanklik - n(H3PO4)react/reageer
        • Use Va = 14 x 10-3 dm3/14 cm3.
          Gebruik Va = 14 x 10-3 dm3/14 cm3.
        • Use mol ratio/Gebruik molverhouding: n(H3PO4) : n(NaOH) = 1:3
        • Use Vb = 25 x 10-3 dm3/25 cm3 to calculate [NaOH].
          Gebruik Vb = 25 x 10-3 dm3/25 cm3 om [NaOH] te bereken.
        • Final answer/Finale antwoord: 9,58 x 10-5 mol·dm-3
          Range/Gebied: 9,66 x 10-4 to/tot 9,76 x 10-4 mol·dm-3

                           m
        n(Mg(OH)2) =
                           M
                          0,12
                      =
                        58
                      = 2,07 x 10-3 mol

        n(H3PO4)reacted/reageer = ⅔n(Mg(OH)2)
                                = ⅔(2,07 x 10-3)
                                = 1,38 x 10-3 mol

        n(H3PO4)excess/oormaat = 1,67 x 10-3 - 1,38 x 10-3
                               = 2,9 x 10-4 mol

                                                          14
        n(H3PO4)excess/oormaat in 14 cm3 = 2,9 x 10-4 x
                                                       500
                                         = 8,12 x 10-6 mol

        n(NaOH) = 3n(H3PO4)
                = 3(8,12 x 10-6)
                = 2,44 x 10-5 mol
             n
        cb =
             V
               2,44 × 10-5
           =
               25 × 10-3
           = 9,76 x 10-4 mol·dm-3

                                                                                               (7)
                                                                                               [17]

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Physical Sciences P2/Fisiese Wetenskappe V2 13                          FS/VS/September 2018
Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

QUESTION 8/VRAAG 8

8.1    Galvanic/Galvanies                                                                  (1)

8.2    Ag                                                                                  (1)

8.3    Zn → Zn2+ + 2e-
         Marking guidelines/Nasienriglyne:
         • Zn ⇌ Zn2+ + 2e- 12                         Zn2+ + 2e- ⇌ Zn     0
                                                                              2
             Zn2+ + 2e- ← Zn      2
                                      2
                                                      Zn2+ + 2e- → Zn         0
                                                                                  2
         •   Ignore if charge omitted on electron./Ignoreer indien lading op elektron
             weggelaat word.
         •   If charge (+) omitted on Cu2+/Indien lading (+) weggelaat op Zn2+:
                                                                2       -
             Max./Maks: 1       Example/Voorbeeld: Zn → Zn + 2e
                            2
                                                                                           (2)

8.4    Increases/Verhoog                                                                   (1)

8.5

       n(Zn) = ½n(Ag)
             = ½ x 0,02
             = 0,01 mol

                                                                                           (4)

8.6
8.6.1 Pressure/Druk: 1,013 x 105 Pa/101,3 kPa/1 atm                                        (1)

8.6.2 Zn(s) | Zn2+(aq) (1 mol·dm-3)       ||   H+(aq) (1 mol·dm-3) | H2 (g) | Pt(s)

       OR/OF
       Zn(s) | Zn2+(aq)     ||   H+(aq) | H2 (g) | Pt(s)

       OR/OF
       Zn | Zn2+    ||    H+ | H2 | Pt                                                     (3)

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Physical Sciences P2/Fisiese Wetenskappe V2 14                                FS/VS/September 2018
Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

8.6.3
             OPTION 1/OPSIE 1:                      Notes/Aantekeninge
                                                     • Accept any other correct formula
                                                       from the data sheet./Aanvaar enige
                                                       ander korrekte formule vanaf
                = 0 - (-0,76)                          gegewensblad.
                = 0,76 V                             • Any other formula using
                                                       unconventional abbreviations, e.g.
                                                       E°cell = E°OA - E°RA followed by
                                                       correct substitutions:/Enige ander
                                                       formule wat onkonvensionele
                                                       afkortings gebruik bv. E°sel =
                                                       E°OM - E°RM gevolg deur korrekte
                                                       vervangings: 3/4

             Option 2:
             2H+ + 2e- → H2                 E° = 0,00 (V)
             Zn → Zn2+ + 2e-                E° = 0,76 (V)

                                                                                                 (4)
                                                                                                 [17]

QUESTION 9/VRAAG 9

9.1     The process in which electrical energy is converted to chemical energy.
        Die proses waarin elektriese energie omgeskakel word na chemiese
        energie.
        OR/OF
        The use of electrical energy to produce a chemical change.
        Die gebruik van elektriese energie om 'n chemiese verandering te weeg te
        bring.                                                                   (2)

9.2     Oxidation/Oksidasie                                                                      (1)

9.3     A substance that loses electrons/donates electrons.
        'n Stof wat elektrone verloor/skenk.                                                     (2)

9.4     Cℓ–/chloride (ion)/Chloried(ioon)
        Accept/Aanvaar: NaCℓ/sodium chloride/natriumchloried.                                    (1)

9.5     2H2O(ℓ) + 2e- → H2(g) + 2OH-(aq)
         Marking guidelines/Nasienriglyne:
         • 2H2O + 2e- ⇌ H2+ 2OH- 12                         Zn2+ + 2e- ⇌ Zn     0
                                                                                    2
                       -                -
              H2 + 2OH ← 2H2O + 2e          2
                                                2
                                                       H2 + 2OH → 2H2O + 2e- 0 2
                                                                     -

         •    Ignore if charge omitted on electron./Ignoreer indien lading op elektron
              weggelaat word.
                                         -                                   -
         •    If charge (-) omitted on OH /Indien lading (-) weggelaat op OH :
              Max./Maks: 1       Example/Voorbeeld: 2H2O + 2e- → H2 + 2OH
                             2
                                                                                                 (2)

9.6     Carbon/C/koolstof/platinum/Pt                                                            (1)
                                                                                                 [9]
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### Page 15

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    Physical Sciences P2/Fisiese Wetenskappe V2 15                       FS/VS/September 2018
    Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum

    QUESTION 10/VRAAG 10

    10.1
    10.1.1 N2(g) + 3H2(g)     → 2NH3(g)          balancing/balansering
              Marking criteria/Nasienriglyne:
              •   Reactants          Products          Balancing
                  Reaktanse          Produkte          Balansering
              • Ignore phases./Ignoreer fases.
              •   Ignore double arrows./Ignoreer dubbelpyle.
              •   Marking rule 6.3.10/Nasienreël 6.3.10.
                                                                                            (3)

    10.1.2 Contact (process)/Kontak(proses)                                                 (1)

    10.1.3 H2SO4 + 2NH3       → (NH4)2SO4        balancing/balansering

             Marking criteria/Nasienriglyne:
             •   Reactants          Products          Balancing
                 Reaktanse          Produkte          Balansering
             • Ignore phases./Ignoreer fases.
             •   Ignore double arrows./Ignoreer dubbelpyle.
             •   Marking rule 6.3.10/Nasienreël 6.3.10.
                                                                                           (3)

    10.2
    10.2.1 (Fertiliser) S                                                                   (1)
-
    10.2.2 Higher N for leaf production.
           Hoër N vir blaarproduksie.                                                       (2)

    10.2.3
              OPTION 1/OPSIE 1:             OPTION 2/OPSIE 2:

                                                                                            (3)
                                                                                            [13]

                                                                      TOTAL/TOTAAL: 150

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