# Physical Sciences Grade 11 Gauteng March Test 2025 QP & Memo

> Grade 11 Physical Sciences question paper and memo from the Gauteng March Test 2025, 17 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/gp-en-physical-sciences-grade-11-march-2025-qp-and-memo/0a3b4dc5-9a75-4761-8f7a-0fe300165a9a
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 11
- Document type: Question paper and memo
- Year: 2025
- Exam period: Gauteng March Test
- Curriculum: CAPS
- Pages: 17

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## About this document

Physical Sciences · Grade 11 · Gauteng March Test · 2025. Question paper and memorandum, 17 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

Text extracted from the PDF. Layout, diagrams and tables may not survive extraction.

### Page 1

Testpapers.co.za

Ekurhuleni North D6

DISTRICT COMMON TEST

2025
GRADE 11

PHYSICAL SCIENCES
March Test

MARKS: 100

TIME: 2 hours

This question paper consists of 12 pages including 2 data sheets

### Page 2

Testpapers.co.za

Downloaden)sezosrichtartnacein lnsaiesTéaiimarch 2025

INSTRUCTIONS AND INFORMATION

1. Write your NAME at the TOP of every ANSWER BOOK.

2. Answer ALL the questions in the ANSWER BOOK.

~~

3. You may use a no mmable' calculator.

tical instruments.

5. YOU ARE ADVISED 4E ATTACHED DATA SHEETS.

6. Number the answe' re according to the numbering system used in this
question paper.

Bs Give brief motivations, discussions, et cetera where required.

8. Round off your final numerical answers to a minimum of TWO decimal places.

9. Write neatly and legibly

### Page 3

Testpapers.co.za . ich 2025

Question 1 — Multiple choice
Four options are provided as possible answers to the following questions.

Each question has only ONE correct answer. Choose the answer and write
only the letter (A— D) next to the question number (1.1-1.5) in the ANSWER
BOOK

44 Which one of the following statements is true:

(i) A vector is a gust gnitude and direction.
(ii) Displaceme

ent | id direction of the straight line drawn
from the starting

of the motion.

(iii) Displacement and e are vectors.
A (i) and (ii)

B (ii) and (iii)

C (i) and (iii)

D (i), (ii) and (iii)

4.2 Four forces act on a body as shown in the diagram:

a
3N
4N 4N

5N

v

What is the magnitude and direction of the resultant force?

16N south
2N south
8N east
8N south

0a DPY

### Page 4

Testpapers.co.za ; irch 2025

4.3..Three objects X, Y and Z hang from strings knotted together at O, as
shown in the diagram.

Fy Fe

Fy

Which vector diagram best represents the relationship of the forces
acting on the kni -

Fs
Fa. 5
F,

1.4. The magnitude of a force A is 60N at an angle of 50° to the vertical as
shown in the diagram.

Ss

so

Wa

The vertical component of force A is...

45,95N
38,57N
21,43N
14,03N

00OWOD>

### Page 5

Testpapers.co.za ; irch 2025

Which of the following statements correctly explains why a passenger
in a car who is not restrained by a seat belt, continues to move
forward when the brakes are applied suddenly?

A The braking force applied to the car exerts an equal and opposite
force on the passenger.

B_ The braking force (called inertia) acts on the passenger.
C Aresultant forward force acts on the passenger.
DA zero resultant force acts on the passenger.

0,7kg

What is the magnitude of the force in string P?

15N
42N
27N
35N

0QWD>

According to Newton’s Third law, when a rocket is launched vertically
upwards, the “action force” is represented by...

the gravitational force of the earth on the rocket downwards.
the force of the rocket on the exploding gases, downwards.
the force of the exploding gas on the rocket downwards.
The gravitational force of the rocket on the earth upwards.

0OQODPY

### Page 6

1.8

1.9

1.10

Testpapers.co.za irch 2025

A 2,5 kg object weighs 24,5 N on Earth. What would be the object’s
mass (in Kg) on planet Mars if the acceleration due to gravity on
Mars is 3,71 m-s.

9,28

7,42

2,5

6,6 2

00ND >

The distance bet

by the spher« n
without chang
new electrosta

s, Qi and Qzis r. The force exerted
Both charges are now doubled
een them. The magnitude of the
e:

4F
Ya F
2F
hF 2

0aOoWP,Y

The figure below shows the electric field around a point charge q,
placed at a distance of 0,3m away from another charge Q. The
electric field strength measured is 800N.C™.

If the distance of the point
Q, the electric field strength v

away from
1600N.C*

200N.C*

400N.C*1

800N.C* 2
[10 x 2 = 20]

0OWDD>

### Page 7

Testpapers.co.za a irch 2025

Question 2

The figure below represents a weight W (50N), hanging from a cable, attached to a
horizontal beam. A force (F) is applied at 90° to the weight. The angle between
the cable and the beam is 25°.

Beam

25°

2.1 Using the triangle draw a fully labelled vector diagram (not to

scale). agimorep

2.2 Calculate the magnitude of the applied force F. 3

4

2.3 Calculate the tension force of the cable. 3
[10]
Question 3
A crate is connected to two ropes as shown in the diagram. Rope A

exerts a force of 100N at an angle of 20° to the horizontal. Rope B
exerts a force of 120N at an angle of 35° to the horizontal.

3.1. Define the term vector component.

3.2 Calculate the x component for rope A and rope B.

FB DN

3.3. Calculate the y component for rope A and rope B.

3.4. Calculate the magnitude of the resultant force of Rope A and Rope B. 5
[15]

### Page 8

Testpapers.co.za . ich 2025

Question 4

44

4.2

The graph was obtained in an investigation of the relationship between
force and acceleration, on a surface which is friction-compensated.

1,0 a(ms”*)

4.1.1 Whatis the accelerat V en a force of 2,5 N is applied? 1

4.1.2 What is the relationship between the two quantities plotted? 1

4.1.3 What force must be applied to obtain an acceleration of 1
0,5ms??

4.1.4 Howwill the graph differ if the same surface was used, but 2

friction is not compensated for?
4.1.5 State Newton's second law of motion in words. 2
Two masses of 1kg and 4kg are attached to a light string AB that
passes over a pulley as shown. The 1kg mass rests on a frictionless
table. A constant horizontal force P is applied to the 1kg mass to
accelerate in the direction of force P.
A P

kdl >
B )

If the tension in string AB is 48N, calculate:

4.2.1. The acceleration of the 4kg mass. 4
4.2.2 The magnitude of force P. 4
{15}

### Page 9

Testpapers.co.za ; irch 2025

Question 5

A 5kg block is being pulled up a rough incline plane of angle 40° to the
horizontal by a constant force F. the block moves up the plane at a constant

speed. B

5.1 State Newton’s { 2
a 4
5.2 Draw a labelled free m for the 5 kg mass. 4
5.3 The kinetic frictio ce | he block and the inclined surface is
19,78N.
Calculate the magnitude of force F.
5
[11]
Question 6
Two identical spheres with unequal masses m1 and ma, which are released
simultaneously from rest, fall freely from a height h above the surface of the
earth. The two spheres reach the ground at the same time.
6.1 State Newton’s Law of Gravitation in words. 2
6.2 Use formulae to show that the gravitational acceleration of any object
near the earth’s surface irrespective of its mass, can be given by
g=GM
r2
Where M = mass of the earth 3
r = radius of the earth
6.3. An object undergoing free fall on the planet Mars, experiences a
gravitational acceleration of magnitude 3,8 m.s*. The mass of Mars is
6,4 x 10*°kg. Calculate the radius of the planet Mars in metres. 4
[9]

### Page 10

Testpapers.co.za ich 2025

Question 7

7.1 Charges A, B and C are placed in a straight line, as shown in the
diagram below.

© ® ©

Qe 6mm Qa 12mm Qc
=12nC +8nC -10nC
2
2
4
4
7.2 Apoint charge Q has an electric field surrounding it.
7.2.1. Explain what is meant by the term electric field strength at a 2
point.
7.2.2 Calculate the magnitude of the electric field strength 0,1m from
Q if the charge of Q is -3 x 10°C. 3
7.2.3 If asmall point charge q (+6,4 x 10°'9 C) is placed in the field of
Q, calculate the force exerted on q by Q. 3
[20]

END OF PAPER
TOTAL = 100 Marks

10

### Page 11

Testpapers.co.za

irch 2025

DATA FOR PHYSICAL SCIENCES GRADE 12

PAPER 1 (PHYSICS)

GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12

VRAESTEL 1 (FISIKA)

TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES

NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE

11

### Page 12

Testpapers.co.za

reh 2025

TABLE 2: FORMULAE/TABEL 2: FORMULES

MOTION/BEWEGING

Vpsvyjraat Ax =v,At+4adt? orlof Ay = v,At+4adt?

vy =v, +2adx orlof v,’ =v,’ + 2aay ax= (“Sa or/of Ay -(4 —. Ja

FORCE/KRAG

Fret = ma

ELECTROSTATICS/ELE

Aimn-)|

12

### Page 13

Testpapers.co.za

Ekurhuleni North D6

DISTRICT COMMON TEST

2025

GRADE 11

PHYSICAL SCIENCES
March Test

Marking Memorandum

P.T.O.

### Page 14

Testpapers.co.za irch 2025

Question 1 — Multiple choice

ana” ;
i a dale ;
4.3—D vv ;
14 ByYv 2
15 Dvv ;
16 Cvv 2
17) AVY :
18 Cvv
19 Avv .
110 BYY .
[10x 2=20]

Question 2
a4 ‘

WwW T v

v

F

2.2 Tan 25°v = 50v oF Tan Gah Be

E 50 a

F = 107,23NV F = 107,23NY
23 T2=W2 + Fv or Sin 25°v = 50 v 3
= (50)? + (107,23)? v T
T = 118,31N v T= 118,31N v

[10]

P.T.O.

### Page 15

Testpapers.co.za ich 2025

Question 3

3.1 The components of a vector are vectors that together have the same 2
effect as the original vector. vv

3.2. RopeA Rope B 4
Cos 20° = X Cos 35° = X
100 v 120 v
X=93,97N ¥ X = 98,30N v
3.3. RopeA y . 4
sin 20° =X | =X
100 , 120 v
X =34,20N = 68,83N v
3.4. X component =- 8,30 = 4,33N v
Y component = -34 =34,63N v F: Y
P 2= x2 + Y2
aay
F 2 = (4,33)? + (34,63)? v X 5
4
rp 34,89N v
[15]
Question 4
4.1.1 1ms?v 1
4.1.2 a Fnetv 1
4.1.3 1,25N ¥ 1
4.1.4 It will not pass through the origin. vv 2
4.1.5 An object will accelerate in the direction of a net force. The 2
acceleration is directly proportional the net force and inversely
proportional to the mass. vv
4.2.1 T-—W=Fnet (ma) ¥
48 — (4)(9,8) v =4av
a=2,2m.s? v 4

P.T.O.

### Page 16

Testpapers.co.za . ich 2025

4.2.2 Fnet=mav

P-T =ma
P—48v = (1)(2,2)v 4
P=50,2NY
[15]
Question 5
5.1 A body will remain in its state of rest or continue in its state of uniform 2

motion, unless a

cted upomby an unbalance force vv

5.2

ms

5.3 Fnet =ma ¥
Fnet = 0
F -fk - Fgll=ma
F —19,78 v - (5)(9,8)sin 40° v = Ov
F- 19,78 -31,50=0 5
F = 51,28N v

(11]
Question 6
6.1 Every particle in the universe will attract every other particle with a force 2

that is directly proportional to the product of their masses and is
inversely proportional to the square of the distance between them. v ¥

6.2 W=mg...1 Fg=GmM ....2 v 3
r
(1)=(2)
mg=GinM vv g=GM
re (ie
63  g=GM v 4
r
3,8v = (6,67 x 10°") (6,4 x 1029) v
r

r= 3351668,87m v
[9]

P.T.O.

### Page 17

Testpapers.co.za irch 2025

Question 7

7.1.1, The force between two charges at rest is directly proportional to
the prroduct of the charges and inversely proportional to the
square of the distance between them. v v 2

2
4
7.14 F=KQiQ2 =(9 x 10°)(8 x 10°)(10 x 10°) v = 0,005N v
re (0,012)? v
Fnet = + 0,024-—0,005 =0,019N left v 4
7.2.1 Force exerted per unit positive charge. vv 2
7.2.2 E=KQv = (9 x 10°)(3 x10%) v = 2700N.Ctv
re (0,1)? 3
7.2.3 F=Eqv= (2700)(6,4 x 107%) v= 1,73 x 10°SNY =

THE END
TOTAL = 100 Marks

P.T.O.

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