# Mathematics Grade 10 P2 Gauteng June 2023 Memo (Afrikaans)

> Grade 10 Mathematics Paper 2 memorandum from the Gauteng June Exam 2023 (Afrikaans), 6 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr-10-math-p2-english-and-afrikaans-june-2023-possible-answers/d63885dd-69c9-41cb-8af5-07217074feba
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 10
- Language: Afrikaans
- Document type: Memorandum
- Year: 2023
- Exam period: Gauteng June Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 6

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## About this document

Mathematics · Grade 10 · Gauteng June Exam · 2023 · Afrikaans. Memorandum, 6 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

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### Page 1

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              PROVINCIAL EXAMINATION
                  PROVINSIALE EKSAMEN
                      JUNE/JUNIE 2023
                      GRADE/GRAAD 10
                  MARKING GUIDELINES
                    NASIENRIGLYNE

            MATHEMATICS/WISKUNDE (PAPER/VRAESTEL 2)

6 pages/bladsye

### Page 2

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                            MARKING GUIDELINES/ MATHEMATICS/WISKUNDE
                            NASIENRIGLYNE       (PAPER/VRAESTEL 2) GRADE/GRAAD 11

QUESTION/VRAAG 1

1.1   cos 2A – sin( 12 B)
                         
      cos 2(38,6) – sin  1  141,4)
                         2                          0,2215  0,9438
      = 0,2215 ... – 0,9438 ...                        Answer/Antwoord
      = – 0,72                                                                  (3)

1.2   1.2.1    sin 2 = 0,4                            2 = 23,178
               2 = 23,178
               = 23,2                                 Answer/Antwoord         (2)

      1.2.2    3sin( 2 – 20) = 0,85
               sin( 2 – 20) = 0,28333333
                                                       0,28333333
                2 – 20 = 16,459 ...
                
                                                       16,459 ... 
                                                       36,459 .. 
                2 = 36,459
                

                                                       Answer/Antwoord
                = 72,9                                                        (4)

1.3   1.3.1    sin245 – cos 60                       Substitution/Vervang
               = 1   1
                 2 – 2                                 Substitution/Vervang
               =0                                      Answer/Antwoord         (3)

      1.3.2    (sin30)tan45
               = ( 12 )1                               Substitution/Vervang
                                                       Substitution/Vervang
               = 1
                 2                                     Answer/Antwoord         (3)
                                                                               [15]

                                             2

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                                   MARKING GUIDELINES/ MATHEMATICS/WISKUNDE
                                   NASIENRIGLYNE       (PAPER/VRAESTEL 2) GRADE/GRAAD 11

QUESTION/VRAAG 2

2.1        2
               y                                                   f(x) – shape/vorm
                   y=
                         1
                         2
                           cos                                    g(x) – shape/vorm
           1
                                                                   (90 ; 0)
                         90             180   270       360
                                                                   (180 ; – 12 )
       –1
                                                                   (0 ; 0)
                           y = –sin                               (0 ; 12 )
       –2

                                                                                                   (6)

2.2    11                                                         Max. – Min/Maks – Min
        2
       =1                                                          Answer/Antwoord                (2)
2.3    360                                                        Answer/Antwoord                (1)

2.4    1                                                           Answer/Antwoord                (1)
                                                                                                  [10]

QUESTION/VRAAG 3

3.1.      x x     y  y2                                          Correct sub into formula/
       M( 1 2 ; 1         )
              2       2                                             Korrekte vervang in formule
          3  1 9  (5)
       M(       ;       )
                                                                  x=2
            2      2
       M (2 ; 2)                                                  y=2                             (3)

3.2    3.2.1                   y1  y2                             Substitution/Vervang
                   m AC 
                               x2  x1
                                                                             3
                       93                                         M AC 
                                                                            4
                     3  ( 5)
                               3
                   m AC 
                               4                                                                   (2)

       3.2.2                   y2  y1                             Substitution/Vervang
                   mBC 
                               x2  x1
                        53
                   
                       1  ( 5)                                            4
                                                                   mBC 
                               4                                            3
                   mBC 
                               3                                                                   (2)

                                                       3

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                         MARKING GUIDELINES/ MATHEMATICS/WISKUNDE
                         NASIENRIGLYNE       (PAPER/VRAESTEL 2) GRADE/GRAAD 11

3.3       3    4                                             product of gradients/
              1
          4    3                                              produk van gradiënte     (1)

3.4   3.4.1   AC =     ( 5  3) 2  (3  9) 2               Substitution/Vervang

              AC = 100                                       AC
              AC = 10 cm                                                               (2)

      3.4.2   CB =     ( x2  x1 ) 2  ( y 2  y1 ) 2        Substitution/Vervang

              CB =     (1  ( 5)) 2  ( 5  3) 2           BC

              CB = 100 = 10 cm                                                         (2)

                           1
3.5   Area of ABC =         base/basis  height/hoogte
                           2
                                                             Substitution/Vervang
                    1
      Area of ABC =  10  10
                    2                                        Answer/Antwoord
      Area of ABC = 50 cm2                                                            (2)
                                                                                      [14]

                                                        4

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                        MARKING GUIDELINES/ MATHEMATICS/WISKUNDE
                        NASIENRIGLYNE       (PAPER/VRAESTEL 2) GRADE/GRAAD 11

QUESTION/VRAAG 4

4.1   BÂP = 90 diagonals of a rhombus bisect at 90/            S R
                 hoeklyne van ŉ ruit halveer op 90                                            (2)

4.2   BP2 = BA2 + AP2     Pythagoras                              S R
      BP2 = 82 + 62
      BP = 10 cm                                                   Answer/Antwoord            (3)

           1
4.3   AC =    BP line drawn from midpoint parallel to 2nd side/   S R
           2
                 lyn getrek vanaf middelpunt parallel met die
                 2de sy
      AC = 5 cm                                                                                (2)

4.4                              1
      Area of/Oppv van BAP =       AB  AP                       sub into area formula/
                                 2
         1                                                          vervang in oppv formule
      =    86
         2
      = 24 cm2
       Area of/Oppv van BHSP = 4  Area of/Oppv van BAP  Area of a triangle/
                                                             Oppv van driehoek
      = 4  24                                              method/metode
      = 96 cm2                                              Answer/Antwoord                   (4)
                                                                                              [11]
                                                                        TOTAL/TOTAAL:           50

                                                5

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                 MARKING GUIDELINES/ MATHEMATICS/WISKUNDE
                 NASIENRIGLYNE       (PAPER/VRAESTEL 2) GRADE/GRAAD 11

                         TAXONOMY LEVELS
                             GRADE 10
                           MATHEMATICS
                              June 2023
                          ROUTINE       COMPLEX    PROBLEM
            KNOWLEDGE                                         TOTAL
QUESTION                PROCEDURES PROCEDURES      SOLVING
 DESIRED
     %         20%         35%           30%          15%      100%
    1.1          3
   1.2.1                     2
   1.2.2                                   4
   1.3.1                     3
   1.3.2                     3
    2.1.                                   6
    2.2                      2
    2.3                      1
    2.4                      1
    3.1                      3
    3.2                      5
    3.3                      6
    4.1                      2
    4.2                      3
    4.3                      2
    4.4                                    3           4
   Total         3          33            14                    50
 Actual %       18          66            26                   100
Desired %      20%         35%           30%          15%      100

                                 6

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