# Physical Sciences Grade 10 P1 Gauteng November 2022 Memo

> Grade 10 Physical Sciences Paper 1 memorandum from the Gauteng November 2022 (Afrikaans), 8 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr-10-physical-sciences-p1-afrikaans-november-2022-possible-answers/2fa0afaf-a61f-436e-bc07-740a6430749e
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 10
- Language: Afrikaans
- Document type: Memorandum
- Year: 2022
- Exam period: Gauteng November
- Paper: 1
- Curriculum: CAPS
- Pages: 8

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## About this document

Physical Sciences · Grade 10 · Gauteng November · 2022 · Afrikaans. Memorandum, 8 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Matching paper and memo

- [Gr 10 Physical Sciences P1 (Afrikaans) November 2022 Question Paper](https://www.hlayiso.com/library/gr-10-physical-sciences-p1-afrikaans-november-2022-question-paper/ba98b1a9-c6ac-4e3c-90f8-1db72f96a634) — QP · 2022 · Afr

## Document text

Text extracted from the PDF. Layout, diagrams and tables may not survive extraction.

### Page 1

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            PROVINSIALE EKSAMEN
                NOVEMBER 2022
                     GRAAD 10
                NASIENRIGLYNE
            FISIESE WETENSKAPPE (VRAESTEL 1)

8 bladsye

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                                                             FISIESE WETENSKAPPE
                                  NASIENRIGLYNE
                                                             (VRAESTEL 1)   GRAAD 10

VRAAG 1

1.1   A ✓✓                                                                         (2)

1.2   D ✓✓                                                                         (2)

1.3   B ✓✓                                                                         (2)

1.4   C ✓✓                                                                         (2)

1.5   B ✓✓                                                                         (2)

1.6   B ✓✓                                                                         (2)

1.7   C ✓✓                                                                         (2)

1.8   D ✓✓                                                                         (2)
                                                                                  [16]

VRAAG 2

2.1   Fisiese hoeveelheid met beide grootte en rigting. ✓✓                         (2)

2.2   2.2.1   50 m ✓✓                                                              (2)

      2.2.2   0 m ✓✓                                                               (2)

      2.2.3   Vektor ✓– Dit het grootte, eenheid en rigting. ✓                     (2)
                                                                                   [8]

                                              2

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                                                  FISIESE WETENSKAPPE
                                  NASIENRIGLYNE
                                                  (VRAESTEL 1)   GRAAD 10

VRAAG 3

3.1   135 km.h −1
                  ✓
         3,6

      37,5 m·s–1 ✓                                                     (2)

3.2   vf = vi+ at ✓
      = 0 ✓+ (1,5)(11,5) ✓
      17,25 m·s–1 ✓                                                    (4)

3.3   x = vit + 12 at2 ✓
      = 0 ✓ + 12 (1,5)(11,5)2 ✓
      = 99,19 m ✓                                                      (4)

3.4   x = vit + 12 at2 ✓
      40 = (37,5)(4) ✓+ 12 (a)(4)2 ✓
      a = –13,75 m·s–2 ✓                                               (4)
                                                                      [14]

                                         3

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                                                               FISIESE WETENSKAPPE
                                   NASIENRIGLYNE
                                                               (VRAESTEL 1)   GRAAD 10

VRAAG 4

4.1   Die tempo van verandering in snelheid. ✓✓

                              OF

      Die verandering in snelheid per tydseenheid. ✓✓                                       (2)

4.2   4.2.1    –     Die motor begin van rus en die snelheid neem toe tot 10 m·s–1 in
                     20 sekondes. ✓
               –     Konstante positiewe versnelling of eenvormige versnelde beweging. ✓    (2)

      4.2.2    –     Snelheid is konstant (uniform). ✓
               –     Versnelling is nul. ✓                                                  (2)

      4.2.3    Motor het gestop. ✓, Versnelling is nul. ✓                                   (2)

4.3            y 2 − y1
      a = m=            ✓
               x2 − x1
                  0 − 40
              =           ✓
                  60 − 50
              =–4✓
              = 4 m·s–2, in die teenoorgestelde rigting of wes (versnelling in
              teenoorgestelde rigtings) ✓

                                                OF

      vf = vi + a. t ✓
      0 = 40✓+ a  10 ✓
      a=–4
      = 4 m·s–2, in die teenoorgestelde rigting of wes (vertraging) ✓                       (4)

4.4   BC ✓, Steiler helling. ✓                                                              (2)
                                                                                           [14]

                                               4

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                                                           FISIESE WETENSKAPPE
                                     NASIENRIGLYNE
                                                           (VRAESTEL 1)   GRAAD 10

VRAAG 5

5.1   Energie van ʼn voorwerp as gevolg van sy posisie/hoogte bo die oppervlak van die
      Aarde. ✓✓                                                                            (2)

5.2   EMA = mgh + mv2 ✓
           = (2 x 9,8 x 30) +   1
                                2    2  02 ✓

           = 588 + 0
           = 588 J ✓                                                                       (3)

5.3   Totale meganiese energie word in ʼn geïsoleerde sisteem bewaar. ✓✓

                                                 OF

      Meganiese energie aan die bokant is gelyk aan meganiese energie aan die onderkant
      in die afwesigheid van wrywing. ✓✓                                                   (2)

5.4   POSITIEWE NASIEN VANUIT VRAAG 5.2

      EMA = EMB

      588 ✓ = mgh + 21 + mv2

      588 = 2  9,8  10 + 21  2 v2 ✓

      588 – 196 = v2

      v=     392

      = 19,80 m·s–1 ✓                                                                      (4)

5.5   GELYK AAN ✓. Meganiese energie word bewaar. ✓                                        (2)
                                                                                          [13]

                                                 5

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                                                            FISIESE WETENSKAPPE
                                 NASIENRIGLYNE
                                                            (VRAESTEL 1)   GRAAD 10

VRAAG 6

6.1   ʼn Golf waar die beweging van deeltjies van die medium loodreg is op die
      voortplantingsrigting van die golf. ✓✓                                                (2)

6.2   A – Trog ✓

      B – Golflengte ✓

      C – Kruin ✓                                                                           (3)

6.3   T = 1f

          2
      T = 30 ✓

      = 0,06 s ✓                                                                            (2)

6.4   Nee, ✓ twee punte in fase word geskei deur ʼn heelgetal veelvoud van ʼn hele golf se
      siklusse of golflengtes. ✓                                                            (2)

6.5   v=f✓

      v = 30  4 ✓

      = 120 m·s–1 ✓                                                                         (3)
                                                                                           [12]

                                             6

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                                                              FISIESE WETENSKAPPE
                                        NASIENRIGLYNE
                                                              (VRAESTEL 1)   GRAAD 10

VRAAG 7

7.1   Neutrale lading – ʼn atoom wat gelyke aantal elektrone en protone het. ✓✓              (2)

7.2   Die netto lading van ʼn geïsoleerde sisteem bly konstant tydens enige fisiese
      proses. ✓✓                                                                            (2)

7.3   As gevolg van polarisasie word ʼn negatiewe lading ontwikkel aan die kant van
      sfeer B naby sfeer A en ʼn positiewe lading word ontwikkel aan die kant van sfeer B
      wat weg is van sfeer A ✓. Sfeer B beweeg na sfeer A (aantrekking) aangesien
      teenoorgestelde ladings aantrek. ✓                                                    (2)

7.4   Q = n.e ✓

      Q = 20  1,6  10–19 ✓

      Q = 3,2  10–19 C ✓                                                                   (3)

7.5   Qnet = Q1 +2 Q 2 ✓

                      −9 + 3,2  10−9
      Qnet = 2  10       2             ✓

      Qnet = 1  10–19 C ✓                                                                  (3)
                                                                                           [12]

                                               7

### Page 8

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                                                  FISIESE WETENSKAPPE
                                  NASIENRIGLYNE
                                                  (VRAESTEL 1)   GRAAD 10

VRAAG 8

8.1   7,5 v ✓                                                            (1)

8.2   8.2.1    1 = 1 + 1 + 1
              R p R1 R 2 R3

               1 =1 +1 +1 ✓
              Rp 6 4 3

              Rp = 1,3 
              RT = R s + Rp

              RT = 2,67 + 1,3 ✓

              RT = 3,97                                                 (3)

      8.2.2   I = VR

                    7 ,5
              I=         ✓
                   3,97

              I = 1,88 A ✓                                               (2)

      8.2.3   I = VR

              1,88 = 2,V67 ✓

              V = 5,01 v ✓                                               (2)

8.3       Q
      I= t

              Q
      1,88 = 360 ✓

      Q = 676,8 C ✓                                                      (3)
                                                                        [11]

                                                              TOTAAL:   100

                                         8

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