# Mathematics Grade 11 P1 Gauteng June 2023 Memo (English)

> Grade 11 Mathematics Paper 1 memorandum from the Gauteng June Exam 2023 (English), 10 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr-11-math-p1-english-june-2023-possible-answers/df728d9d-98d3-4a33-90a1-47ad3e999390
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 11
- Language: English
- Document type: Memorandum
- Year: 2023
- Exam period: Gauteng June Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 10

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## About this document

Mathematics · Grade 11 · Gauteng June Exam · 2023 · English. Memorandum, 10 pages. Read online or download the PDF.

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### Page 1

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           PROVINCIAL EXAMINATION
                     JUNE 2023
                     GRADE 11
            MARKING GUIDELINES

                 MATHEMATICS (PAPER 1)

10 pages

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                                                              MATHEMATICS
                                         MARKING GUIDELINES
                                                              (PAPER 1)                         GRAD

QUESTION 1

1.1   1.1.1   x  {4 ; 5}                                       answer
                                                                answer                   (2)

      1.1.2   x  {0 ; 3}                                       answer
                                                                answer                   (2)

      1.1.3   x  {1 ; 2}                                       answer
                                                                answer                   (2)

1.2   1.2.1   3x 2  4 x  0
               x ( 3 x  4)  0                                factors
                            4
              x  0 or  x                                    answers
                            3
              NOTE: Any other valid method.                                               (3)

      1.2.2 3x – 14 = –6x2
                                                                standard form
               6x2 + 3x – 14 = 0

                       (3)  (3) 2  4(6)( 14)
              x=                                               substitution
                                2(6)

               x = 1,29 or x = –1,79                           answers                 (4)

      1.2.3    ( x  1)( x  3)  12
               x 2  2 x  3  12
                                                                standard form
               x 2  2 x  15  0
                                                   -3   5       factors
               ( x  5)( x  3)  0
                x  5or  x  3                              answers
                                                                                          (4)

      1.2.4     2 x 2 x
                2 x  x2
              ( 2  x ) 2  ( x  2) 2                          squaring both sides
              2  x  x2  4x  4
              0  x 2  3x  2                                  standard form
              0 = (x – 2)(x – 1)                                factors
               x = 2 ... or ... x = 1(NA)                      answers with rejection   (4)

                                                        2

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                                                            MATHEMATICS
                                       MARKING GUIDELINES
                                                            (PAPER 1)                             GRAD

      1.2.5       x6  0
                  x  6                                      value of x
                   x  2y  3
                  6  2y  3                                  substitution
                  2y  3
                         3
                  y                                         value of y
                         2                                                                  (3)

1.3   y – 1 = 2x
       y = 2x + 1 ………(1)                                     expression for y
      x2 + xy – 3x – y + 2 = 0 ………(2)
       x2 + x(2x + 1) – 3x – (2x + 1) + 2 = 0                substitution
      x2 + 2x2 + x – 3x – 2x – 1 + 2 = 0
       3x2 – 4x + 1 = 0                                      standard form

      (3x – 1)(x – 1) = 0
                  1
      x=           ... or ... x = 1                          x-values
                  3
                  5
      y=           ... or ... y = 3                          y-values
                  3                                                                         (5)

1.4   x 2  px  p 2  2
       x 2  px  p 2  2  0
        b 2  4ac
        ( p ) 2  4(1)( p 2  2)                          substitute into 

        p2  4 p2  8
        5 p2  8
                                                                  5 p2  8
       p 2  0 p  
       5 p 2  0 p                                          p 2  0 , 5 p 2  0 and
              2
       5 p  8  0 p                                        5 p2  8  0

       roots are real and unequal.                                                         (3)

                                                 3

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                                                               MATHEMATICS
                                     MARKING GUIDELINES
                                                               (PAPER 1)               GRAD

1.5   The 100 m fencing will make up three sides because
      the existing wall will make one side.

                            Wall

                 �                            �

                                 �

      fencing = 2x + y = 100
       y = –2x + 100
       A  xy                                              expression for y
      A = x(–2x + 100)
      A = –2x2 + 100x                                       expression for A
      A = –2(x2 – 50x)
       A = –2(x2 – 50x – 625 – 625)                        complete square
      A = –2(x – 25)2 –625)

      Maximum area: x  25                                  value of x

      A  2( 25) 2  100( 25)
                                                            value of A
       A  1 250
       1 250  25 y
       y  50                                              value of y          (7)
                                                                                [39]

                                                  4

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                                                                              MATHEMATICS
                                                        MARKING GUIDELINES
                                                                              (PAPER 1)                  GRAD

QUESTION 2

2.1   2.1.1   3n2.9n1
               27n1
              3n2.32n2
                                                                            32 n  2 and 33n 3
                33n3
              33n4
              33n3
              33n43n3                                                    33 n  4  3 n  3

              37                                                            answer                (3)

      2.1.2    x2
              1 x

                  (1  3 ) 2
                                                                        substitution
                  11 3

                  1 2 3  3
                                                                        simplification
                     2 3

                   42 3
              
                   2 3

                   2(2  3 ) 2                                           factorisation
              
                     2 3
              =2                                                         answer                   (4)

                                                    5
      2.1.3       ( a 2  b 2 )  ( a  b) 2
                                    1
                        ( a  b) 2
                                                         5
                     (a  b)(a  b)  (a  b) 2
              
                                 ( a  b) 2
                                            1
                                                                         factorisation
                             1           1                   5
                   ( a  b) 2 ( a  b) 2  ( a  b) 2
                                               1                        simplification
                                 ( a  b) 2
                         1              5
              ( a  b) 2  ( a  b) 2
                                                                         simplification
              ( a  b) 3

              a 3  3a 2b  3ab2  b3                                    answer                   (4)

                                                                  5

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                                                     MATHEMATICS
                                MARKING GUIDELINES
                                                     (PAPER 1)                           GRAD

                2    8
2.2   RTP:         –    = 2
              1 2    8
        2    8
           –
      1 2    8
            2     8                                 2 2
              –
          1 2   2 2
          2(2 2 )  8(1  2 )
                                                   2 2(1  2)
             2 2 (1  2 )

          4 2 88 2
      
           2 2 2 4

          4 2 88 2
      
            2 2 4

          4 2 8
                                               simplification
          2 2 4

          4 2 2
                                               factorisation
          2 2 2
       2                                                                         (4)

2.3

      MK  LM  2                               MK= 2

      JM 2  (2  3) 2  22 pythag              substitution

      JM 2  4  4 3  3  4                    simplification

      JM 2  4 3  3

      JM  4 3  3                              JM

         1
      A  (4) 4 3  3                           substitution into area formula
         2
      A  6,3 units2                            answer                            (6)
                                                                                  [21]

                                          6

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                                                             MATHEMATICS
                                        MARKING GUIDELINES
                                                             (PAPER 1)                             GRAD

QUESTION 3

3.1   T2  T1  T3  T2
      4 x  5  x  10 x  5  ( 4 x  5)                     method
      3x  5  10 x  5  4 x  5
      3x  5  6 x  10
       3x  15
      x  5                                                  answer                        (2)

3.2   3.2.1     3n  20  106                               equating
               3n  126
               n  42                                        answer                        (2)

      3.2.2     3n  20  0                                  Tn  0
               20  3n
               20
                 n
                3
              n  7                                          answer                        (2)

      3.2.3 Odd valued terms:
            17; 11; 5; ………..                                  sequence
            General term: Tn  6n  23                       Tn
               Tn  6( 20)  23
               Tn  97                                      answer                        (3)

3.3   3; a; 10; b; 21
                                                              1st differences
      a  3; 10  a; b  10; 21  b         1st difference

      2nd differences:

      10  a  a  3  1                                      equating 2nd difference in
       2a  13  1                                            terms of a, then b.
       2a  12
      a  6                                                  value of a
      and
      21  b  b  10  1
       2b  31  1
       2b  30
       b  15                                                value of b                    (4)
                                                                                            [13]

                                                      7

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                                                                          MATHEMATICS
                                            MARKING GUIDELINES
                                                                          (PAPER 1)                      GRAD

QUESTION 4

                                        y

                                                           D(6 ; 7)

                            C(–1 ; 0)                        B
                                                                      x
                                            O

                                                A(2 ; y)

4.1   B(5; 0)                                                          answer

      NOTE: Must be in coordinate form.                                                            (2)

4.2   y  a ( x  x1 )( x  x2 )
       7  a (6  (1))(6  5)                                        substitute roots and
      7  7a                                                            point D(6;7)
      a  1                                                           value for a
       y  1( x  1)( x  5)
      y  x 2  5x  x  5                                                 y  x 2  5x  x  5
       y  x2  4x  5                                                                            (3)

4.3    B(5 ; 0) C(0 ;  5)

            50
      mBC 
             05
            5
      mBC                                                                 mBC
            5
       mBC  1
       mh   1                                                           mh
       y  y1  m( x  x1 )
      y  (1)  1( x  0) pt (1;0)
       y  x 1                                                      answer                     (3)

                                                             8

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                                                                     MATHEMATICS
                                      MARKING GUIDELINES
                                                                     (PAPER 1)                          GRAD

4.4   1  x  0                                                      all critical values
                                                                       (independent)
      x5                                                             answers

                                    OR

      x  [–1 ; 0] or [5 ; ]                                         all critical values
      NOTE: Deduct 1 mark if brackets are incorrect in the             (independent)
                 alternative solution.                                answers                    (2)
                                                                                                 [10]

QUESTION 5

5.1

                                                                           asymptotes
                                2
                                                                           intercepts
                                                                           shape

      NOTE:        If the candidate calculates the intercepts and lists
                   the asymptotes but does not sketch the graph, award
                   2 marks.                                                                       (3)

5.2   tan 135 = –1                                                          m  1
      y – y1 = m(x – x1)
      y – (–1) = –1(x – (–2))                                              subs. point (2;–1)
      y + 1 = –x – 2
      y = –x – 3                                                             answer              (3)

5.3   x  2                                                                 answer              (1)

5.4   5.4.1 5 units right                                                    answer

               NOTE: Accept an answer of 5 units.                                                 (1)

      5.4.2 3 units up                                                       answer

               NOTE: Accept an answer of 3 units.                                                 (1)
                                                                                                  [9]

                                                       9

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                                                                 MATHEMATICS
                                            MARKING GUIDELINES
                                                                 (PAPER 1)                     GRAD

QUESTION 6

6.1   6.1.1   y  6                                                  answer            (1)

      6.1.2   h( x)  3.2 x  6

              0  3.2 x  6                                           equate to 0

              6  3.2 x
              2  2x
              x 1                                                    answer            (2)

      6.1.3   h( x )  3.2 x  6
              y = 3.2 – 6
              y = –3                                                  answer            (1)

      6.1.4   x >1                                                    answer            (1)

6.2                                    y

                                                                      x-intercept
                                                                 x
                                   O                                  asymptote

                                       –1                             shape

                                                                                         (3)
                                                                                         [8]

                                                                                TOTAL:   100

                                                     10

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