# Mathematics Grade 11 P2 Gauteng June 2023 Memo (Afrikaans)

> Grade 11 Mathematics Paper 2 memorandum from the Gauteng June Exam 2023 (Afrikaans), 10 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr-11-math-p2-afrikaans-june-2023-possible-answers/63afec40-2b96-4cba-a190-b1602c35bc7d
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 11
- Language: Afrikaans
- Document type: Memorandum
- Year: 2023
- Exam period: Gauteng June Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 10

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## About this document

Mathematics · Grade 11 · Gauteng June Exam · 2023 · Afrikaans. Memorandum, 10 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

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             PROVINSIALE EKSAMEN
                     JUNIE 2023
                     GRAAD 11
                 NASIENRIGLYNE

                  WISKUNDE (VRAESTEL 2)

10 bladsye

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                                                                 WISKUNDE
                                    NASIENRIGLYNE
                                                                 (VRAESTEL 2)                GRAAD 11

INSTRUKSIES EN INLIGTING:

A – AKKURAATHEID
CA – KONTINUE AKKURAATHEID
S – BEWERING
 R – REDE
S & R – BEWERING met REDE

NOTAS:

   Indien ŉ kandidaat ŉ vraag TWEE keer beantwoord het, merk slegs die EERSTE poging.
   Indien ŉ kandidaat ŉ antwoord doodgetrek het, en dit nie weer gedoen het nie, merk die
    doodgetrekte antwoord.
   Deurlopende akkuraatheid moet op ALLE aspekte van die nasienriglyne toegepas word.
   Dit is onaanvaarbaar om waardes/antwoorde aan te neem om probleme op te los.

                                               2

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                                                                       WISKUNDE
                                           NASIENRIGLYNE
                                                                       (VRAESTEL 2)            GRAAD 11

VRAAG 1

1.1   10; 13; 17; 21; 21; 23; 27; 29; 31; 34; 37; 38; 42; 43; 46; 48      Korrekte Min.
                                                                           Q1 en Maks.
      Min. =10 ;   Q1 = 21 ;     Maks. = 48
                                                                          Korrekte Q 2
           29  31                38  42
      Q2           30 ;    Q3           40
              2                      2                                    Korrekte Q 3         (3)

1.2                                                                         Korrekte Min./
                                                                             onderste punt
        Graad 11A
                                                                            Korrekte Maks./
                                                                             boonste punt
                            10       21        30         40    48
                                                                            Korrekte houer
        Graad 11B

                                                                                                (3)

1.3       480                                                               Breuk
      x                                                                    Antwoord
           16
      x  30                                                             NB: Antwoord alleen
                                                                             volpunte           (2)

1.4   σ = 11,46                                                           Antwoord            (2)

1.5   1σ interval: (30 – 11,46 ; 30 + 11,46)                                Interval
                   (18,54 ; 41,46)                                          Antwoord

      4 leerders het meer as 41,46 punte behaal.                                                (2)

1.6   Daar is geen verskil in die IKO nie. IKO = 19 vir albei klasse.       Opmerking
      Alhoewel, die middel 50% van Graad 11B tussen 21 en 40 was in         IKO waarde
      vergelyking met Graad 11A waar 50% tussen 11 en 30 was. Die
      houer vir 11B het na regs geskuif. Dus het Graad 11B oor die
      algemeen beter gevaar.                                                                    (2)

1.7   75%                                                                   Antwoord           (1)
                                                                                               [15]

                                                      3

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                                                          WISKUNDE
                                         NASIENRIGLYNE
                                                          (VRAESTEL 2)           GRAAD 11

VRAAG 2

2.1   Vergelyking van EG:                                    Gradiënt
                                                             Antwoord
      3x – y + 6 = 0
      y = 3x + 6

      dan m EG = 3

      tan β = 3
      β = 71,57°                                                                  (2)

2.2   x + 3(0) = 8                                           x=0
                                                             Koördinaat vorm
      x=8
       (8 ; 0)                                                                   (2)

2.3   M DF  M GE      hoeklyne halveer mekaar               M DE  M GE
        10  8) 6  0                                     Koördinate van K
      K          ;                                         x-waarde
             2     2 
                                                             y-waarde
      K(  1 ; 3)
           x 1            y9
      1              3
             2              2
      x  3           y  3
       E(3 ;  3)                                                               (4)

2.4   mDF  mGE                                            mDF
                                                           DF  GE
          1                                                Rede
      =  3
          3
      = –1
      DF  GE

      DGFE is ŉ ruit. (hoeklyne halveer mekaar loodreg)                           (3)
                                                                                 [11]

                                                  4

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                                                                 WISKUNDE
                                               NASIENRIGLYNE
                                                                 (VRAESTEL 2)            GRAAD 11

VRAAG 3

3.1                                                             Substitusie
      d      x  x )  ( y  y )
               2     1
                          2
                                   2   1
                                           2

      AC      1  (2) 2  5  (1) 2                      Antwoord

      AC  3 5                                                                            (2)

3.2            54                                              Substitusie
      m BC                                                     Antwoord
             1  ( 3)
             1
      m BC 
             4                                                                            (2)

3.3   m BC  m BD  mCD                                         Gelyke gradiënte
      1 y 5                     1   y4                        Substitusie
                        of                                    y=6
      4 5 1                     4 5  ( 3)
      y6                                                                                 (3)

3.4   m AH  4            (AH  BC)                            m AH
      y  (1)  4 x  (2)                                  Vervang A
                                                                Vergelyking
      y  4 x  9                                                                        (3)
                                                                                         [10]

VRAAG 4

4.1   4.1.1    x 2  ( 24) 2  25 2                            Vervang in Pythagoras
                                                                Antwoord
               x  7                                                                     (2)

      4.1.2 (a)          sin                                   Antwoord
                              24
                         
                              25                                                          (1)

               (b)       cos(180   )                         Reduseer
                           cos                               Vereenvoudigde
                                                                 antwoord
                            7
                              
                             25 
                            7
                         
                           25                                                             (2)

                                                      5

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                                                           WISKUNDE
                                         NASIENRIGLYNE
                                                           (VRAESTEL 2)            GRAAD 11

        (c)   tan 2 (  )                                Reduseer
                                                          Vereenvoudigde
               tan 2 
                                                           antwoord
                           2
                  24 
                     
                 7 
                576
              
                 49                                                                (2)

4.1.3   (a)            24                                           y
              sin                                       sin  
                       25                                           15
               y  24                                     Stel sin verhoudings
                                                          gelyk
              15     25
                                                                     x
                   72                                    cos  
              y                                                    15
                    5
                                                          Stel cos verhoudings
                       7
              cos                                        gelyk
                       25
               x 7
                 
              15 25
                   21
              x
                    5                                                              (4)

        (b)                     1       72              Formule vir oppervlak
              OppΔROT            (12)                   van Δ
                                2       5 
                                                          Basis = 12
              OppΔROT  86, 4 units 2                                72
                                                          Hoogte =
                                                                      5
              ALTERNATIEF                                 Oppervlak

              OT  15          OF  12                    OT lengte
                253,7397...                            106,26°
                          1                               Vervang in sin
              OppROT  (15) (12) sin (106,26)            oppervlak formule
                          2
                                                          Oppervlakte
              OppROT  86,4 units 2                                               (4)

                                                6

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                                                                          WISKUNDE
                                              NASIENRIGLYNE
                                                                          (VRAESTEL 2)             GRAAD 11

4.2     tan 225  sin (180   ) cos (90   )                        tan 225° = 1
             cos (90   ) sin (  540)                              sin (180° – θ) = sin θ
                                                                         cos (90° + θ) = –sin θ
          1  sin  .  sin
                                                                        sin (–θ –540°) = sin θ
             sin  .sin                                                 1 – sin2 θ = cos2 θ
          1  sin 2                                                       cos 2 
                                                                                  tan 2 
            sin 2                                                         sin 
                                                                              2

          cos 2 
        
          sin 2 
         tan 2                                                                                    (6)
                                                                                                   [21]

VRAAG 5

                                                    y
                                                    2

                                                    1

                                                                                             x
                                                     O
      −240º       −180º    −120º      −60º                   60º   120º        180º       240º
              f

                                                    -1

          g
                                                    -2

5.1    A=2                                                                      Antwoord           (1)

5.2    Periode = 720°                                                           Antwoord           (1)

5.3    a = –1                                                                   Waarde van a
       p = –60°                                                                 Waarde van p       (2)

5.4    –120° ≤ x ≤ 60°     of   x = –240°    of x = 240°                        Interval
                                                                                –240°; 240°        (2)

5.5    p = 30°                                                                Waarde van p        (2)
                                                                                                    [8]

                                                         7

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                                                                          WISKUNDE
                                                    NASIENRIGLYNE
                                                                          (VRAESTEL 2)            GRAAD 11

VRAAG 6

6.1         r                                                       Substitusie
      tan                                                           Manipulasie
          2 R
              
      R. tan    r
             2                                                                                  (2)

6.2                1 4                                                   1
      Vhemisfeer    . R 3                                               Volume Sfeer
                   2 3                                                   2
                   2                                                   Vervang r uit 6.1
      Vhemisfeer   R 3                                               Trek volumes af
                   3
                                                                        (Metode)
                 1
      Vkeël   r 2R                                                   Faktore
                 3
                                        2
                1          
      Vkeël      R.tan    R
                3         2 
                  2               
      Vkeël         .R 3 tan 2  
                  3              2 
                        2        1              
      Voorblywende        R 3   .R 3 tan 2  
                        3        3             2 
                      R3             
      Voorblywende        2  tan 2   
                       3              2                                                       (4)

6.3                  1                                                     1             
        Vkeël          .R 3 tan 2                                  Vkeël  π.R3 tan 2  
                     3              2                                       3            2
                     1               36                             Vervang
                        11 tan 2 
                             3
        Vkeël                                                         R  11 en   36
                     3               2 
                                                                       Volume van kerswas
        Vkeël  147,15 cm 3                                                                       (3)
                                                                                                  [9]

VRAAG 7

7.1   7.1.1     Ĉ 2  40                  raaklyn koord stelling     S      R
                                                                                                  (2)

      7.1.2     K̂ 1  90                   in 'n halwe sirkel       S      R                 (2)

      7.1.3     P̂1  25                      buite  van 'n Δ        S      R                 (2)

7.2   T̂1  65                                buite  van Δ           R
                                                                       R
      TC  QC                                  sye teen gelyke e                                 (2)
                                                                                                  [8]

                                                                  8

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                                                                        WISKUNDE
                                                  NASIENRIGLYNE
                                                                        (VRAESTEL 2)     GRAAD 11

VRAAG 8

                   T

                                                                  U

                                            1    O
                                           2

                           V

8.1   Konstrueer UO en verleng.                                        Konstruksie

      In ΔTOU
      Oˆ  Tˆ  U
                ˆ                    buite  van 
        1          1                                                   SR
      Tˆ  U
           ˆ
             1                        e teen gelyke radii             SR
      O ˆ  2Uˆ
            1     1

      Net so in TOU
       Ô 2  2Û 2                                                   S
       Ô1  Ô 2  2Û 1  2Û 2
                       
       Ô1  Ô 2  2 Û 1  Û 2                                    Gevolgtrekking
      TÔV  2TÛV
                                                                                         (5)

                                                             9

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                                                                            WISKUNDE
                                                        NASIENRIGLYNE
                                                                            (VRAESTEL 2)           GRAAD 11

                    A

                                                                   B
                                                           1
                                                               2   3
                                          O
                              2               2x                                       C
                          F       1

                                                          1 2
                                      2                        M
                                          1

                                      D

8.2   8.2.1 Twee pare aangrensende sye gelyk.                                    R                 (1)

      8.2.2 (a)         midpts = 2  omtreks                                   R                 (1)

              (b)       buite  van koordevierhoek                               R                 (1)

              (c)       ooreenkomstige  e, OD MB                                R
                                                                                                    (1)

              (d)       teenoorst e, ruit                                       R

                                                    ALTERNATIEF

                        verw  e, OB DM                                                             (1)

      8.2.3   D̂ 2  x  90                       raaklyn  rad                 R
              D̂ 2  90  x
              B̂ 3  90                           raaklyn  rad                 S
              Ĉ  90  x                         binne e van                 SR
               D̂ 2  Ĉ                          albei 90  x                 Gevolgtrekking    (4)

      8.2.4   F̂2  90                            ooreenk e, FB DM             SR
                                                                                 S
              AF  FD                              lyn van midpt  koord
                                                                                 R
              AB  BC                              lyn deur midpt 2 de sy        R                 (4)
                                                                                                   [18]

                                                                                       TOTAAL:     100

                                                                       10

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