# Mathematics Grade 9 P1 Gauteng June 2023 Memo (Afrikaans)

> Grade 9 Mathematics Paper 1 memorandum from the Gauteng June Exam 2023 (Afrikaans), 8 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr-9-math-p1-english-and-afrikaans-june-2023-memo/64da2fd8-8c05-4874-ad59-cd3d93c2508f
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 9
- Language: Afrikaans
- Document type: Memorandum
- Year: 2023
- Exam period: Gauteng June Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 8

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## About this document

Mathematics · Grade 9 · Gauteng June Exam · 2023 · Afrikaans. Memorandum, 8 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

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### Page 1

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       PROVINCIAL EXAMINATION
             PROVINSIALE EKSAMEN
                       JUNE/JUNIE 2023
                       GRADE/GRAAD 9
            MARKING GUIDELINES/
                       NASIENRIGLYNE

                             MATHEMATICS/
                               WISKUNDE

           Keywords to consider/Sleutelwoorde om in ag te neem:
                  M      = Method/Metode
                  CA     = Consistent accuracy/Aaneenlopende akkuraatheid
                  A      = Answer/Antwoord

8 pages/bladsye

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                              MARKING GUIDELINES/      MATHEMATICS/WISKUNDE
                              NASIENRIGLYNE                           GRADE/GRAAD 9

SECTION/AFDELING A

QUESTION/VRAAG 1

1.1           1.2            1.3     1.4         1.5
B            B             D      D          C                                        [5]

SECTION/AFDELING B
QUESTION/VRAAG 2
2.1   2.1.1 20A                                            1 mark for the HCF.
                                                            1 punt vir GGF.                (1)

      2.1.2 2 100A                                         1 mark for the LCM.
                                                            1 punt vir KGV.                (1)

2.2   A rational numberA                                   1 mark for correct answer.
      ŉ Rasionale getalA                                   1 punt vir regte antwoord.     (1)

2.3   2.3.1 73,33% A                                       1 mark for correct answer.
                                                            1 punt vir regte antwoord.
              OR/OF

              73 13 % A                                                                   (1)

      2.3.2 27 A                                           1 mark for the answer.
            OR/OF                                           1 punt vir die antwoord.
            27
            30 A                                                                          (1)

2.4   2.4.1   60
              3
                    480
                      x M
                                                            1 mark for ratio/proportion.
                                                            1 punt vir verhouding/
              60x = 480 × 3                                 eweredigheid
                                                            1 mark for the final answer
                    1 440                                   1 punt vir finale antwoord.
              x                                            OR/OF
                      60                                    2 marks if table or number
                                                            line is used.
              x = 24 CA                                    2 punte as tabel of getallyn
                                                            gebruik is
              OR/OF
                                                            OR/OF
              0 60 120 180 240 300 360 420 480
                                                            Consider alternative
              0 3 6    9   12 15 18 21 24A                mathematically correct
                                                            responses which lead to
                                                            the correct answer.
                                                            Oorweeg alternatiewe
                                                            wiskundig korrekte
                                                            redenasies wat na die regte
                                                            antwoord lei.                  (2)

                                             2

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                                       MARKING GUIDELINES/   MATHEMATICS/WISKUNDE
                                       NASIENRIGLYNE                        GRADE/GRAAD 9

      2.4.2 Direct proportion CA                                 1 mark for correct answer.
            Direkte eweredigheidCA                               1 punt vir regte antwoord.    (1)

2.5             r 
                        n                                         1 mark for correct
      A  P 1                                                  substitution of p, r and n.
             100 
                                                                  1 punt vir korrekte
      A = 3 030,05 1  100  A
                        4,5        5
                                                                  substitusie van p, r en n.

      A = 3 030,05 104     M                                   1 mark for simplifying.
                        ,5     5
                     100
                                                                  1 punt vir vereenvoudiging.
      A = R3 775,993 … CA                                        1 mark for correct answer.
      A ≈ R3 776 CA                                              1 punt vir regte antwoord.
      OR/OF                                                       1 mark for rounding-off
                                                                  correctly.
      A = P(1 + i)n where i = 100
                              4,5
                                  = 0,045                         1 punt vir korrekte
      A = R3 030,05(1 + 0,045)5 A                                afronding.
      A = R3 775,993 … CA
      A ≈ R3 776 CA                                                                             (4)
                                                                                                [12]

QUESTION/VRAAG 3

3.1   –13 A                                                      1 mark for answer.
                                                                  1 punt vir antwoord.           (1)

3.2   2 – (–1) A                                                 1 mark for the expression./
      =2+1                                                        1 punt vir uitdrukking
      = 3 �
                                                                  1 mark for the correct
                                                                  answer./
                                                                  1 punt vir regte antwoord.
                                                                  OR/OF
                                                                  1 mark for answer only.
                                                                  1 punt vir slegs antwoord.     (2)

3.3   3.3.1        36
               ( 1) 3  2 3
                                                                  1 mark for −6
                                                                  1 punt vir −6
              = 168 M                                        1 mark for −1
                                                                  1 punt vir −1
                  6                                              1 mark for answer.
              =
                  9                                              1 punt vir antwoord.

              = 23 C�                                            0 mark for answer only./
                                                                  0 punt vir slegs antwoord.     (3)

                                                      3

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                                 MARKING GUIDELINES/   MATHEMATICS/WISKUNDE
                                 NASIENRIGLYNE                        GRADE/GRAAD 9

      3.3.2      3  6  ( 6  4)  5  7                  1 mark for simplifying/
                                                           1 punt vir vereenvoudiging.
                 = 3  6  10  5  7 M
                                                                                   60
                                                           1 mark for dividing 5 .
                 = 3 + 12 – 7 M                                             60
                                                           1 punt vir deling 5 .
                 = 15 – 7
                                                           1 mark for answer.
                                                           1 punt vir antwoord.
                 = 8 C�
                                                           0 mark for answer only.
                                                           0 punte vir slegs antwoord.   (3)
                                                                                         [9]

QUESTION/VRAAG 4

4.1   9; 25; 92 ; 3 64; 1; 0,8 �                         1 mark for 1st 3 correct
                                                           numbers.
                                                           1 punt vir 1ste 3 korrekte
                                                           getalle.

                                                           1 mark for last 3 correct
                                                           numbers./1 punt vir laaste
                                                           3 korrekte getalle.           (2)

4.2   3
          64     64 �                                    1 mark for answer.
                                                           1 punt vir antwoord.          (1)

4.3   4.3.1      5 1  511 �                             1 mark for answer.
                                                           1 punt vir antwoord.
                 OR/OF

                 5 1  15 �                                                            (1)

      4.3.2 (pq)0 = 1 �                                   1 mark for answer.
                                                           1 punt vir antwoord.          (1)

                                                4

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                                MARKING GUIDELINES/   MATHEMATICS/WISKUNDE
                                NASIENRIGLYNE                        GRADE/GRAAD 9

4.4   16a 2b    8 a 3b
                                                          1 mark for multiplying by
      3a 3b 2 9a 4b
                                                           the multiplicative inverse of
                                                           the divisor./1 punt vir
      16a 2b 9a 4b
                    M                                    vermenigvuldiging met die
      3a 3b 2 8a 3b                                       vermenigvuldigingsinverse
                6 2
                                                           van die deler.
      = (16(39)a
               8)b 3
                    b
                       M
                                                           1 mark for product law
          6
                                                           application./1 punt vir
      = 6ba C�                                            toepassing van die produk-
                                     OR/OF                 wet.

      16a 2b    8 a 3b                                     1 mark for quotient law
                                                          application./1 punt vir
      3a 3b 2 9a 4b
                                                           toepassing van die kwosient-
       16�2 �             9�4 �                            wet.
                      ×         M
      3�−3 �2             8�3 �                            1 mark for the answer
                                                           1 punt vir antwoord.
      = (2 × 3)a 2+4 – (–3) –3b1+1 –2 –1 M

      = 6a6b–1M
          6
      = 6ba C�                                                                            (4)
                                                                                           [9]

QUESTION/VRAAG 5

5.1   216 �                                           1 mark for 216./1 punt vir 216.     (1)

      5.2.1 2; 6; 10 ……A                              1 mark for all 3 terms.
                                                       1 punt vir al 3 terme.              (1)

      5.2.2 Tn = 4n – 2 CA                           1 mark for 4n./1 punt vir 4n.
                                                       1 mark for –2./1 punt vir –2.       (2)

      5.2.3 Tn = 4n – 2
            T15 = 4(15) – 2 M                         1 mark for substitution./
            T15 = 58 hearts/harte CA                  1 punt vir vervanging.
                                                       1 mark for answer.
                                                       1 punt vir antwoord.                (2)

                                               5

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                         MARKING GUIDELINES/   MATHEMATICS/WISKUNDE
                         NASIENRIGLYNE                        GRADE/GRAAD 9

      5.2.4 39 × 2 = 78 hearts/harte A         1 mark for 78./1 punt vir 78.
            Tn = 4n – 2                         1 mark substitution./
            78 = 4n – 2 M                      1 punt vir vervanging.
            80 = 4n                             1 mark for answer.
            ∴ n = 20 CA                        1 punt vir antwoord.

            OR/OF
                                                1 mark for formula./
            Tn = 2n – 1 M                      1 punt vir formule.
            39 = 2n – 1 M                      1 mark substitution./
            40 = 2n                             1 punt vir vervanging.
            n = 20 CA
                                                1 mark for answer.
                                                1 punt vir antwoord.                   (3)

5.3   12 cm A                                 2 marks for the answer.
                                                2 punte vir antwoord.                  (2)
                                                                                      [11]

QUESTION/VRAAG 6

6.1   Variable/Veranderlike �                  1 mark for answer.
                                                1 punt vir antwoord.                   (1)

6.2   False/Vals �                             1 mark for answer.
                                                1 punt vir antwoord.                   (1)

6.3   (–12p + 12pq) – (2p+ pq)                  1 mark for −pq./1 punt vir −��
      = –12p + 12pq – 2p – pq�                 1 mark for answer.
      = –14p + 11pq ��                         1 punt vir antwoord.
                                                                                       (2)
6.4   (ab + b)
        2        2
                                                1 mark for a b ./1 punt vir a b .
                                                             2 4                2 4

                                                1 mark for 2ab3./1 punt vir 2ab3.
      = (ab2 + b) (ab2 + b)
      = a2b4 + 2ab3 + b2 �                                                           (2)

6.5   3x2 + 9 – 12x                             1 mark for standardisation of the
                                                expression./1 punt vir
      = 3x2 – 12x + 9 �                        standaardvorm van uitdrukking.
                                                1 mark for taking out the
      = 3(x2 – 4x + 3) �                       common factor./1 punt vir
      = 3(x – 3) (x – 1) �                    uithaal van gemene factor.
                                                1 mark for each factor./1 punt
                                                vir elke faktor (x – 3) (x – 1).       (4)

                                          6

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                                        MARKING GUIDELINES/   MATHEMATICS/WISKUNDE
                                        NASIENRIGLYNE                        GRADE/GRAAD 9

6.6   6.6.1 6p – 4 + 2(2p + 3)                                 1 mark for removing the
                                                               brackets./1 punt vir verwydering
              = 6p –4 + 4p + 6�                               van hakies.

              = 10p + 2C�                                     1 mark for the answer.
                                                               1 punt vir antwoord.                (2)

      6.6.2   b 2  5b        2
                          3b b2 15b
              b 2  25
                                                               1 mark for (b + 5) (b – 5)./1
                                                               punt vir (b + 5) (b – 5).
                     b(b  5)      3b(b  5)                   1 mark for b(b + 5)./1 punt vir
              =                             �
                  (b  5)(b  5)      6b                       b (b – 5).

                  3b 2                                         1 mark for 3b(b – 5)./1 punt
              =                                                vir 3b (b – 5).
                   6b

                  b
              =     ��                                        1 mark for the answer.
                  2                                            1 punt vir antwoord.                (4)
                                                                                                  [16]

QUESTION/VRAAG 7

7.1   4(2d + 6) = 32�                                         1 mark for answer.
                                                               1 punt vir antwoord.                (1)

7.2   d(d – 2) = (d + 4) (d – 3)                               1 mark for removing the
                                                               brackets./1 punt vir verwydering
      d2 – 2d = d2 + d – 12 �                                 van hakies.
                                                               1 mark for adding like terms.
      –3d = –12M                                              1 punt vir bymekaartel van
                                                               gelyksoortige terme.
      d = 4 �                                                 1 mark for the value of d.
                                                               1 punt vir waarde van d.
      Mary is correct/���� �� ��� �
                                                               1 mark for the final judgement.
                                                               1 punt vir finale slotsom.

                                                               NB. correct judgement without
                                                               calculations, NO Marks/
                                                               LW. korrekte slotsom sonder
                                                               berekening verdien GEEN
                                                               punte.                              (4)

                                                       7

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                            MARKING GUIDELINES/               MATHEMATICS/WISKUNDE
                            NASIENRIGLYNE                                    GRADE/GRAAD 9

          x2                                                  1 mark for multiplying all terms
7.3   x       2
            3                                                  by the LCD./1 punt vir
      3x – (x – 2) = 6 �                                      vermenigvuldiging met KGV.
      3x – x + 2 = 6 �
      2x = 4                                                   1 mark simplification./1 punt vir
      x = 2 C�                                                vereenvoudiging.

                                                               1 mark for answer.
                                                               1 punt vir antwoord.                 (3)

7.4   Let the number of first type of chocolate equal �./      2 marks for setting up the
      Stel die 1ste soort sjokolade gelyk aan �.               equation correctly./2 punte vir
                                                               korrekte opstel van vergelyking.
      Number of first type of chocolate = x                    1 mark for simplification./1 punt
      Number of second type of chocolate = 22 – x.             vir vereenvoudiging.

      Aantal 1ste soort sjokolade= �                           1 mark for answer.
      Aantal 2de soort sjokolade = 22 −�                       1 punt vir antwoord.

      First kind is R8: Total amount for 1st kind = R8 × �.    1 mark for 13./1 punt vir 13.
      2nd kind is R6: Total amount for 2nd kind is
      R6 (22 – x).

      1ste soort kos R8: Totale bedrag vir 1ste soort
      = R8 × x.
      2de soort kos R6: Totale bedrag vir 2de soort =
      R6 (22 – x)

      The total amount spent for both types of chocolates      NB:
      is R150.                                                 Accept any variable (does not
      Die totale bedrag gespandeer op beide soorte is          have to be �)./Aanvaar enige
      R150.                                                    veranderlike (hoef nie � te wees
                                                               nie).
      ∴ 8x + 6 (22 – x) = 150 �                              Accept any reasonable and
         8x + 132 – 6x = 150 �                                logical method to arrive at the
                       2x = 18                                 answer as correct./Aanvaar
                         x = 9 �                              enige redelike en logiese metode
      ∴ there were 9 chocolates that cost R8/daar was 9        om die regte antwoord te verkry,
      sjokolade vir R8 and there were/en daar was              as korrek.
      22 – 9 = 13 �� chocolates that cost R6/
      sjokolades vir R6.                                                                            (5)
                                                                                                   [13]

                                                              TOTAL/TOTAAL: 75 MARKS/PUNTE

                                                    8

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