# Mathematics Grade 10 P1 Gauteng June 2018 Memo (Afrikaans)

> Grade 10 Mathematics Paper 1 memorandum from the Gauteng June 2018 (Afrikaans), 6 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr10-math-p1-afrikaans-june-2018-possible-answer/9c19cefa-04fc-4803-8dc1-ac68f0106dd1
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 10
- Language: Afrikaans
- Document type: Memorandum
- Year: 2018
- Exam period: Gauteng June
- Paper: 1
- Curriculum: CAPS
- Pages: 6

Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 10](https://www.hlayiso.com/library/grade-10) › [Mathematics](https://www.hlayiso.com/library/grade-10/mathematics) › [Mathematics Grade 10 P1 Gauteng June 2018 Memo (Afrikaans)](https://www.hlayiso.com/library/gr10-math-p1-afrikaans-june-2018-possible-answer/9c19cefa-04fc-4803-8dc1-ac68f0106dd1)

## About this document

Mathematics · Grade 10 · Gauteng June · 2018 · Afrikaans. Memorandum, 6 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Matching paper and memo

- [Gr10 Math P1 (Afrikaans) June 2018 Question Paper](https://www.hlayiso.com/library/gr10-math-p1-afrikaans-june-2018-question-paper/521b2294-1c34-488d-ae4e-e2863fffef72) — QP · 2018 · Afr

## Document text

Text extracted from the PDF. Layout, diagrams and tables may not survive extraction.

### Page 1

Downloaded from hlayiso.com

            GAUTENGSE DEPARTEMENT VAN ONDERWYS
                   PROVINSIALE EKSAMEN
                        JUNIE 2018
                         GRAAD 10

                        WISKUNDE

                        VRAESTEL 1

                      MEMORANDUM

6 bladsye

                            1

### Page 2

Downloaded from hlayiso.com
                                                           WISKUNDE
                                 MEMORANDUM
                                                    (VRAESTEL 1)  GRAAD 10

                       GAUTENGSE DEPARTEMENT VAN ONDERWYS
                              PROVINSIALE EKSAMEN

VRAAG 1
1.1 25  33  36
                        .
       25  33  36                                          25 ; 36
                                                            antwoord
      5  33  6
                                                                                (2)
        33 lê tussen 5 en 6
1.2   x  0, 4545454545
      100 x  45, 45454545                                   100 x  45, 45454545
      x  0, 4545454545
                                                             99 x  45
      99 x  45
           45
      x                                                     x
                                                                    5
           99                                                      11
            5                                                                   (3)
         
           11

                                                                                [5]

                                       2

### Page 3

Downloaded from hlayiso.com
                                                               WISKUNDE
                                           MEMORANDUM
                                                        (VRAESTEL 1)  GRAAD 10

VRAAG 2
2.1   2.1.1   (3x) 2 ( 2 xy ) 3
                  2x5 y 4
                                                                 9 x 2 .  8 x3 y 3
                  9 x .  8x y
                     2         3   3
              
                     2 x5 y 4
                  72 x5 y 3
              
                   2 x5 y 4                                      36y 1
               36 x55 y 3 4                                 
                                                                   36
               36 y 1                                            y
                                                                                       (3)
                 36
              
                 y

      2.1.2   1     1       q 1    2
                q   q   2   qp 
              p     p       p q     
                                                                     1      
                 1        q    q p 
                                   2 2                             2  q2 
                2  q2    2  2                               p       
                p        pq     p 
                                                                  q     q p 
                                                                          2 2

                 1        1                                  2  2 
                2  q2    2  q2                           pq      p 
                p        p         
                 1         1
               2  q2  2  q2                                 
                                                                   1         1
                                                                       q2  2  q2
                 p         p                                      p 2
                                                                            p
               2q 2                                            2q 2
                                                                                  (3)
2.2   2.2.1   6 p  40  p 2
                                                                 ( p 2  6 p  40)
               ( p 2  6 p  40)
               ( p  10)( p  4)                               ( p  10)
                                                                 ( p  4)
                                                                                    (3)
      2.2.2    xy  ( y  x)b  b2
                xy  by  bx  b2                               xy  by  bx  b2
                y ( x  b)  b( x  b)                        groepeer
                                                                 ( x  b)
               ( x  b)( y  b)
                                                                 ( y  b)
                                                                                    (4)
                                                                                  [13]

                                               3

### Page 4

Downloaded from hlayiso.com
                                                                          WISKUNDE
                                              MEMORANDUM
                                                                   (VRAESTEL 1)  GRAAD 10

VRAAG 3
3.1       x2           3      1
                          
      x  3x  4 x  4 2  2 x
        2

                                                                          korrekte faktore
           x2            3        1
                            
       x  4  x  1 x  4 2  x  1                                   2  x  2
      KGV: 2  x  4  x  1                    Beperking:   ;           6  x  1
      2  x  2   6  x  1  1 x  4                                 x  4
       2x  4  6x  6  x  4                                            antwoord
      2 x  5 x  10  4                                                                      (5)
             3x  6
           x  2
3.2        x
      2   1  3
           2                                                                       x
                                                                           3      2
           x                                                                       2
      3   2
           2
      6  x  4                                                           6  x  4
                                                                          getallelyn
                                                                                              (3)
      -6                                      4
                                                                                              [8]

                                                         4

### Page 5

Downloaded from hlayiso.com
                                                               WISKUNDE
                                           MEMORANDUM
                                                        (VRAESTEL 1)  GRAAD 10

VRAAG 4

4.1   4.1.1   T1  3(1)  2  5
              T2  3(2)  2  8                                metode
              T3  3(3)  2  11                               
              T4  3(4)  2  14                               2
              Tn  3n  2                                                         (3)
4.2   4.2.1   3x  7; 2 x; 3x  1;....                          waardes
              2 x   3x  7   3x  1  2 x                  gelyk stel
                                                               vereenvoudig
                2 x  3x  7  x  1                           antwoord
                         2x   6                                                (4)
                          x3
      4.2.2   2; 6; 10; …
              Tn  4n  2                                       4n  2  31
                   4n  2  31
                       4n  33                                  n  8, 25
                        n  8, 25                              gevolgtrekking
                                                                                  (3)
              n  9

                                                                                 [10]

                                                5

### Page 6

Downloaded from hlayiso.com
                                                                   WISKUNDE
                                             MEMORANDUM
                                                            (VRAESTEL 1)  GRAAD 10

VRAAG 5
5.1           q 1                                                  q 1
              y  b 1
                     x

                                                                   vervang koördinaat
              5  b2  1                                           b  2
              b2  4                                                                (3)
              b2
5.2   5.2.1   y   x  2........(1)
                   3
              y  ..............(2)
                    x
              Vervang (1) in (2):
                                                                   vervanging
                         3
              x  2                                              vereenvoudig
                          x                                        faktore
              x  2x  3  0
                 2
                                                                    waardes
                x  3 x  1  0                                waardes
                                                                   koördinaat vorm
              x  3 OF x   1                                                         (6)

              y   (3)  2 OF         y   (1)  2
              y  1                   y3
              Q(3;  1)            P(1; 3)
      5.2.2   B(2; 0)                                              2
                                                                   0
                                                                                       (2)
      5.2.3   y   (6)  2                                        GE  8
              GE  8

                                                                            1
                 3                                                 EF 
              y                                                            2
                 6
                   1
              EF 
                   2                                                    1
                                                                   7
                                                                        2
                              1                                                        (3)
               GF  8 
                              2
                          1
                     7
                          2
                                                                                      [14]

                                                                            TOTAAL : 50

                                                        6

## Related documents

- [Gr10 Math P1 (Afrikaans and English) June 2019 Possible Answers](https://www.hlayiso.com/library/gr10-math-p1-afrikaans-and-english-june-2019-possible-answers/ce0cbf93-1614-4c22-8b6e-72953c486036) — Mathematics · Memo · 2019 · Afr
- [Gr10 Math P1 (Afrikaans) June 2017 Possible Answers](https://www.hlayiso.com/library/gr10-math-p1-afrikaans-june-2017-possible-answers/ed628e40-c132-422b-8d08-3f73add812ad) — Mathematics · Memo · 2017 · Afr
- [Gr10 Math P1 (Afrikaans) June 2016 Possible Answers](https://www.hlayiso.com/library/gr10-math-p1-afrikaans-june-2016-possible-answers/137f30ce-23ec-4e03-a749-7c6b6defb0b9) — Mathematics · Memo · 2016 · Afr
- [Gr10 Math P2 (Afrikaans) June 2018 Question Paper](https://www.hlayiso.com/library/gr10-math-p2-afrikaans-june-2018-question-paper/8eca90bd-adf7-477d-8f55-fbd705a35b52) — Mathematics · QP · 2018 · Afr
- [Gr10 Math P1 (Afrikaans) June 2016 Question Papers](https://www.hlayiso.com/library/gr10-math-p1-afrikaans-june-2016-question-papers/bc064649-cbd2-48d4-a47d-a2a730f07000) — Mathematics · QP · 2016 · Afr
- [Gr10 Math P2 (Afrikaans) June 2017 Possible Answers](https://www.hlayiso.com/library/gr10-math-p2-afrikaans-june-2017-possible-answers/80ad79a2-f1ee-463d-8abe-4c256f21b7de) — Mathematics · Memo · 2017 · Afr

## More from Grade 10 Mathematics

- [Gr 10 Maths ATP 2023-24](https://www.hlayiso.com/library/gr-10-maths-atp-2023-24/80c1c337-e011-4b8b-a37b-d2e0df9daaf6) — ATP
- [KZN Maths Grade 10 June 2025 P1 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-june-2025-p1-and-memo/dc5ae33f-46ec-4eae-b577-25a82956eaec) — QP + Memo · 2025
- [KZN Maths Grade 10 March 2025 QP and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-march-2025-qp-and-memo/bc27cbbf-ec6d-4c60-bf7e-25a154d363e4) — QP + Memo · 2025
- [KZN Maths Grade 10 November 2025 P1 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-november-2025-p1-and-memo/ece9abee-2009-4e22-8de3-34ccb229e5cb) — QP + Memo · 2025
- [KZN Maths Grade 10 November 2025 P2 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-november-2025-p2-and-memo/417e9b18-c39d-4fb2-9e32-c089e8fbfd22) — QP + Memo · 2025
- [Gr 10 Mathematics P1 (Afrikaans) June 2024 Question Paper](https://www.hlayiso.com/library/gr-10-mathematics-p1-afrikaans-june-2024-question-paper/f7a97f78-e0a1-47a0-9585-d048fbb9a0b0) — QP · 2024 · Afr

## Collection

- [Grade 10 past papers](https://www.hlayiso.com/grade-10/past-papers)

---

Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.
