# Mathematics Grade 10 Paper 1 National November 2019 Memo

> Grade 10 Mathematics Paper 1 memorandum from the National November 2019, 11 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr10-math-p1-eng-afr-november-2019-possible-answers/573cc001-10bc-4b72-b4d9-1054c8866836
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 10
- Document type: Memorandum
- Year: 2019
- Exam period: National November
- Paper: 1
- Curriculum: CAPS
- Pages: 11

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## About this document

Mathematics · Grade 10 · National November · 2019. Memorandum, 11 pages. Read online or download the PDF.

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## Document text

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### Page 1

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                                         NATIONAL
                                    SENIOR CERTIFICATE/
                                         NASIONALE
                                     SENIOR SERTIFIKAAT

                                        GRADE/GRAAD 10

                               MATHEMATICS P1/WISKUNDE V1

                                         NOVEMBER 2019

                         MARKING GUIDELINES/NASIENRIGLYNE

MARKS/PUNTE: 100

                           These marking guidelines consist of 11 pages./
                            Hierdie nasienriglyne bestaan uit 11 bladsye.

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Mathematics/P1/Wiskunde/V1                          2                                    DBE/November 2019
                        CAPS/KABV – Grade/Graad 10 – Marking Guidelines/Nasienriglyne

 NOTE:
  If a candidate answered a QUESTION/VRAAG TWICE, mark only the FIRST attempt.
  If a candidate crossed out an answer and did not redo it, mark the crossed-out answer.
  Consistent accuracy applies to ALL aspects of the marking guidelines.
  Assuming values/answer in order to solve a problem is unacceptable.

 LET WEL:
  As 'n kandidaat 'n vraag TWEE keer beantwoord het, sien slegs die EERSTE poging na.
  As 'n kandidaat 'n antwoord deurgehaal en nie oorgedoen het nie, sien die deurgehaalde
    antwoord na.
  Volgehoue akkuraatheid is op ALLE aspekte van die nasienriglyne van toepassing.
  Dit is onaanvaarbaar om waardes/antwoorde te veronderstel om 'n probleem op te los.

 QUESTION/VRAAG 1
 1.1.1 3y 2  y                                                            answer/antwoord           (1)
        y (3 y  1)

 1.1.2      x 2  10 x  24                                                 ( x  12)
             ( x  12)( x  2)                                             ( x  2)                  (2)
 1.1.3      9 x 2  y 2  10 y  25
                                                                           grouping/groepering
             9 x 2  ( y 2  10 y  25)
             9 y 2  ( y  5) 2                                           factorising/faktorisering
             (3 x  y  5)(3 x  y  5)                                   answer/antwoord       (3)
 1.2.1           1    3
             4   2  
                 x    x
                                                                            answer/antwoord (2)
                   10 3
             8  2
                    x x
 1.2.2         5x  5
                 5x
               5( x  1)
                                                                          factorising/faktorisering
                  5x
               x 1                                                        answer/antwoord           (2)
            
                 x

           OR/OF

            5x 5
                                                                          separation/skeiding
            5x 5x
                 1                                                         answer/antwoord
             1                                                                                      (2)
                 x

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Mathematics/P1/Wiskunde/V1                          3                                    DBE/November 2019
                        CAPS/KABV – Grade/Graad 10 – Marking Guidelines/Nasienriglyne

 1.2.3      3 x 1  3 x
            27.3 1 x
                3 x .3  3 x                                                separating bases/skei
            
               27.3 1.3 x                                                 basisse
               3 x (3  1)                                                 common factor/
                                                                          gemeenskalike faktor
                       27
                  3 x.
                        3
               4
                                                                          answer/antwoord           (3)
               9

           OR/OF

            3 x 1  3 x
            27.3 1 x
                3 x .3  3 x                                                separating bases/skei
                                                                          basiss
               27.3 1.3 x
                 4.3 x
            
                     27                                                    addition/optelling
               3 x.
                      3
               4
                                                                          answer/antwoord           (3)
               9
                                                                                                  [13]

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Mathematics/P1/Wiskunde/V1                          4                                    DBE/November 2019
                        CAPS/KABV – Grade/Graad 10 – Marking Guidelines/Nasienriglyne
 QUESTION/VRAAG 2
 2.1.1 2 x 2  10 x  0
                                                                           common factor/
            2 x( x  5)  0
                                                                           gemeenskaplike faktor
            x  0 or x  5                                                 both values of/beide
                                                                           waardes van x         (2)
 2.1.2      px  kx  k  p
            x( p  k )  k  p                                             common factor/
                                                                           gemeenskaplike faktor
                   kp
            x                                                            change of sign/verander
                   kp                                                     teken
            x  1                                                          answer/antwoord (3)
 2.1.3       x
                   1
            23                                                                1
                  128                                                          7
                                                                                  or/of 2 7
             x                                                                2
            2  2 7
             3
                                                                           equating exponents/
            x                                                              gelykstelling van
               7                                                         eksponente
            3
                                                                           answer/antwoord     (3)
            x  21
 2.2.1      x5
                   2                                                     simplification/
              2
            x  5  4                                                     vereenvoudiging
                                                                           answer/antwoord           (2)
            x  9
 2.2.2
                                         x                                 number line/getallelyn
                        –9
                                                                                                 (1)
 2.3        x( x  3)  y (3  x)  0
            x( x  3)  y ( x  3)  0                                     change of sign/verander
                                                                           teken
            ( x  3)( x  y )  0                                          common factor/
            x  3 or y  x  3                                             gemeenskaplike faktor
                                                                           x-value/-waarde
                                                                           y-value/-waarde      (4)
 2.4       Let the number of R50 notes be x/
           Laat die getal R50-note x wees.
                          Number of notes       Total value of
                          Getal note            money/Totale
                                                warade van geld
            R10           x + 15                10(x+15)
                                                                           setting up
            R20           2x                    20(2x)
                                                                           equation/vergelyking/
            R50           x                     50(x)                      opstel van vergelyking
           10( x  15)  20(2 x)  50 x  10150                            simplification/
           100 x  10000                                                   vereenvoudiging
           x  100                                                         x-value/-waarde
                                                                           answer/antwoord
           R10 Notes :100  15  115                                       R10 notes = 115
           R 20 Notes : 2(100)  200                                       R20 notes = 200
           R50 Notes :100  100                                            R50 notes = 100        (4)
                                                                                              [19]

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Mathematics/P1/Wiskunde/V1                          5                                    DBE/November 2019
                        CAPS/KABV – Grade/Graad 10 – Marking Guidelines/Nasienriglyne

 QUESTION/VRAAG 3
 3.1.1 5x  7                                                                 answer/antwoord            (1)
 3.1.2 Tn  mn  c
          Tn  ( x  2)n  q                                                  substitution/vervanging/
                                                                              vervanging
          4 x  5  xn  2n  q                                               simplification/
          4 x  5  3x  6  q                                                vereenvoudiging
          x 1  q
                                                                              answer/antwoord            (3)
           Tn  ( x  2)n  ( x  1)
          Tn  xn  2n  x  1
          OR/OF
          For n  1: ( 1  1 )  ( 2( 1 )  1 )
                                                                              investigating/onderso
               n  2: ( 2  1 )  ( 2( 2 )  1 )
                                                                              ek
               n  3: ( 3  1 )  ( 2( 3 )  1 )
              Tn  (n  1) x  (2n  1)                                       answer/antwoord
              Tn  xn  2n  x  1                                                                        (3)
 3.1.3    T13  95
          95  13 x  2(13)  x  1                                           substitution/vervanging/
                                                                              vervanging
          95  13 x  26  x  1
          14 x  70
          x5                                                                 answer/antwoord           (2)
 3.1.4    Tn  5n  2n  5  1
          Tn  7 n  4                                                         7n  4  158
          7n  4  158
          7n  154
          n  22                                                                n  22
           T21 is the first term less than 158./is die eerste term minder as 158
                                                                                conclusion/gevolg-
                                                                              trekking                   (3)

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Mathematics/P1/Wiskunde/V1                          6                                    DBE/November 2019
                        CAPS/KABV – Grade/Graad 10 – Marking Guidelines/Nasienriglyne

 3.2.1    Height/ Hoogte  50  44                                            answer/antwoord            (1)
                          2200 cm
 3.2.2    Tn  0,1n  c
          T1  7,9                                                            constant difference/
                                                                              konstante verskil

          7 ,9  0 ,1  c
          c  8
                                                                               Tn
          Tn  0,1n  8
          T45  0,1(45)  8
          T45  3,5m                                                          answer/antwoord
                                                                                                         (3)
          OR/OF

          7,9 ; 7,8 ; 7,7 ; ....
          7,9  0,1  1  8 ............(1)
          7,8  0,1  2  8 ...........(2)
          7,7  0,1  3  8 ...........(3)
          Tn  0,1  n  8                                                   equation/vergelykings
          Tn  0,1n  8
          T45  0,1  45  8                                                 substitution/vervanging
                                                                              answer/antwoord      (3)
          T45  3,5m
 3.2.3                                                         1
           Area of Trapezium / Oppervlakte van trapesium        ( AB  CD) Hformula/formule
                                                               2
                                     1
                                    (3,5  7,9)22                            substitution/vervanging
                                     2
                                    125,4 m 2                                answer/antwoord            (3)

                                                                                                     [16]

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Mathematics/P1/Wiskunde/V1                          7                                    DBE/November 2019
                        CAPS/KABV – Grade/Graad 10 – Marking Guidelines/Nasienriglyne

 QUESTION/VRAAG 4
 4.1.1             25
       Deposit        R 7950  R1987,50                                      deposit/deposito
                  100
       Balance  R7950  R1987,50
                                                                               balance/balans           (2)
                R5962,50
       OR/OF
                   75                                                          75%
       Balance        R 7950  R5962,50
                  100                                                           answer/antwoord ¶(2)
 4.1.2 A  P(1  in )
                           15    
           A  R5962,501      2                                            substitution/vervanging
                         100     
           A  R7751,25

                                R7751,25                                       dividing by/deel deur
          Monthly payment                R70,75                              24
                                   24                                          adding insurance/voeg
                               R393,72                                        versekering by
                                                                               answer/antwoord      (4)
 4.2.1      £55  R23,43
                                                                               answer/antwoord          (1)
           R1288,65
 4.2.2                                              5 500                          5 500
             Cost of a car/ Koste van ' n motor           14,58                       14,58
                                                    23,43                          23,43

                                                                               £3 422,54
                           £3 422,54
            Car is more expensive in England /Motor is duurder                conclusion/gevolg-
          in Engeland                                                          trekking

          OR/OF
                                                23,43                              23,43
             Cost of a car/ Koste van motor           3500                             3500
                                                14,58                              14,58

                                                                                $5624,49
                           $5624,49
            Car is more expensive in England /Motor is duurder                conclusion/
           in Engeland                                                         gevolgtrekking           (3)
                                                                                                      [10]

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Mathematics/P1/Wiskunde/V1                          8                                    DBE/November 2019
                        CAPS/KABV – Grade/Graad 10 – Marking Guidelines/Nasienriglyne

 QUESTION/VRAAG 5
 5.1.1 q 1                                                                   answer/antwoord            (1)
 5.1.2 x  ; x  0                                                            x 
                                                                              x0                       (2)
          OR/OF
          x    ; 0  0 ;                                              answer/antwoord (2)
 5.2.1    y  x 1                                                           negative gradient/
                                                                              negatiewe gradiënt
                                                                              the value of/die waarde
                                                                              van c                 (2)
 5.2.2    x20
          x  2                                                               x  2
                k
          0       1                                                          substitution (2 ; 0)
              2
          k2                                                                 k  2
                    2
           f ( x)   1                                                      equation/vergelyking
                    x
                                                                                                          (4)
 5.2.3    f ( x)  g ( x)
          2                                                                   equating/vergelyking
             1  x  2
          x
          2  x  x 2  2x                                                    standard form/
          x x20
            2                                                                 standaardvorm
                                                                              factorising/
          ( x  2)( x  1)  0
                                                                              faktorisering
           x  2 or x  1                                                   x-values/-waardes

          at A : x  1 ; y  3                                                answer/antwoord           (5)
          A(1; 3)
                                                                                                     [14]

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Mathematics/P1/Wiskunde/V1                          9                                    DBE/November 2019
                        CAPS/KABV – Grade/Graad 10 – Marking Guidelines/Nasienriglyne

 QUESTION/VRAAG 6
 6.1.1  y  4                                                                answer/antwoord            (1)
 6.1.2 q  5                                                                 answer/antwoord            (1)
 6.1.3 (2 ; 0)                                                                answer/antwoord            (1)
 6.2.1  g ( x)  ax 2  5
            (2 ; 0) : 0  a (2) 2  5
                       0  4a  5
                            5                                                 value of a
                       a
                            4
                                                                              equation/vergelyking/
                        5
             g ( x)  x 2  5                                                waarde van 'n
                        4                                                     vergelyking         (2)
 6.2.2       f ( x)  k x  4
            (2 ; 0) : 0  k  2  4                                           substitution (2 ; 0)
                             1
                       0 2 4
                            k
                      4k  1
                          2

                               1
                        k2 
                               4
                             1                                                value of/waarde van k
                        k
                             2
                                x
                       1
             f ( x)     4                                                equation/vergelyking
                       2                                                                                (3)
 6.3           1
                      0

            y   4                                                         substitution/vervanging
               2

            y  3                                                            answer/antwoord            (2)

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Mathematics/P1/Wiskunde/V1                          10                                   DBE/November 2019
                        CAPS/KABV – Grade/Graad 10 – Marking Guidelines/Nasienriglyne

 6.4
                                                                              f:
                                                                              asymptotes of/asimptote
                                                                              van f
                                                                              y-intercept of/y-afsnitte
                                                                              van f
                                                                               shape of/vorm van f

                                                                              g:
                                                                              x-intercepts/x-afsnitte
                                                                              turning point
                                                                              of/draaipunt van g
                                                                              shape of/vorm van g
                                                                                                      (6)

                                                                                                        [16]

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Mathematics/P1/Wiskunde/V1                          11                                  DBE/November 2019
                        CAPS/KABV – Grade/Graad 10 – Marking Guidelines/Nasienriglyne

 QUESTION/VRAAG 7
 7.1.1 P( A or B)  P( A)  P( B)  P( A and B)
            0,74  0,30  0,65  P( A and B )                              substitution/vervanging
           P ( A and B )  0,21                                            answer/antwoord         (2)

 7.1.2
                          A                          B                     0,09
                                                                           0,21
                           0,09    0,21       0,44                         0,44
                                                                           0,26

                                                0,26                                              (4)

 7.1.3     No ; P( A and B )  0          .                                No/Nee
           OR/OF                                                           reason/rede     (2)

           No. There is an intesection
 7.2.1     n( S )  12
           n( square no.)  3 (i.e 1 ; 4 ; 9)
                               3                                           answer/antwoord
            P( square no.)                                                                         (1)
                              12
                              1
                            
                              4
 7.2.2                                            1                             1
            P(sum of the 2 numbers  2)                                   
                                                 144                           144
                                                                   1
            P(sum of the 2 numbers greater th an 2)  1                   Complementary rule/
                                                                  144
                                                                           Komplementêre reël
                                                           143
                                                         
                                                           144
                                                          0,99            answer/antwoord         (3)

                                                                                                   [12]
                                                         TOTAL/TOTAAL:                            [100]

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- [KZN Maths Grade 10 November 2025 P1 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-november-2025-p1-and-memo/ece9abee-2009-4e22-8de3-34ccb229e5cb) — QP + Memo · 2025
- [KZN Maths Grade 10 November 2025 P2 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-november-2025-p2-and-memo/417e9b18-c39d-4fb2-9e32-c089e8fbfd22) — QP + Memo · 2025
- [Gr 10 Mathematics P1 (Afrikaans) June 2024 Question Paper](https://www.hlayiso.com/library/gr-10-mathematics-p1-afrikaans-june-2024-question-paper/f7a97f78-e0a1-47a0-9585-d048fbb9a0b0) — QP · 2024 · Afr

## Collection

- [Grade 10 past papers](https://www.hlayiso.com/grade-10/past-papers)

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Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.
