# Mathematics Grade 10 P1 Gauteng June 2017 Memo (English)

> Grade 10 Mathematics Paper 1 memorandum from the Gauteng June 2017 (English), 6 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr10-math-p1-english-june-2017-possible-answers/f0410453-7885-46f5-8a4d-6521771a981d
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 10
- Language: English
- Document type: Memorandum
- Year: 2017
- Exam period: Gauteng June
- Paper: 1
- Curriculum: CAPS
- Pages: 6

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## About this document

Mathematics · Grade 10 · Gauteng June · 2017 · English. Memorandum, 6 pages. Read online or download the PDF.

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## Document text

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### Page 1

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          GAUTENG DEPARTMENT OF EDUCATION
              PROVINCIAL EXAMINATION
                    JUNE 2017
                     GRADE 10

                   MATHEMATICS

                      PAPER 1

                  MEMORANDUM

6 pages

                         1

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                                                                  MATHEMATICS
                                           MEMORANDUM
                                                            (PAPER 1)      GRADE 10

                              GAUTENG DEPARTMENT OF EDUCATION
                                       PROVINCIAL EXAMINATION

QUESTION 1

1.1   Rational                                                  ✓                  (1)

1.2   Irrational                                                ✓                  (1)

1.3   Rational                                                  ✓                  (1)
                                                                                         [3]

QUESTION 2

2.1   5
               0

                                                              ✓answer
       12 
      1                                                        (1)

2.2    1
       x 1                                                    ✓answer
      x                                                        (1)

2.3   9 x 1.5 x  2
        45 x 1

      
        3  .5
            2 x 1      x2

         3 . 5
               2       x 1

        32 x  2.5 x  2                                        ✓ 32 x  2
       2 x  2 x 1                                            ✓ 32 x2 . 5 x1
        3 .5
       32 x2( 2 x2).5 x2( x1)                            ✓answer
                                                                (3)
       51
                                                                                         [5]

QUESTION 3

3.1   2 x 2  14 x  60                                         ✓common factor
       2 x  10  x  3                                     ✓ ( x 10)
                                                                ✓ ( x  3)
                                                                (3)

3.2   1 3 9
        x b
      8                                                         ✓first factor
                                                                ✓second factor
        1         1    1            
        x  b 3  x 2  b 3 x  b 6                         (2)
        2         4    2            
                                                                                         [5]
                                                 2

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                                                              MATHEMATICS
                                           MEMORANDUM
                                                        (PAPER 1)      GRADE 10

QUESTION 4

4.1   2  3x  6  4 x
      4 x  3x  6  2                                      ✓transposing
      x4                                                   ✓answer
                                                            (2)

4.2      x        x        3x  2
                       2
      2  x 3 x x  x  6                                  ✓change sign 
                                                                              x
         x        x           3x  2                                        x 3
                      
      x  2 x  3 x  3x  2                            ✓common denominator
      x  x  3  x  x  2   3 x  2
                                                            x  2 x  3
                                                            ✓simplify x 2  3x  x 2  2 x
        x 2  3x  x 2  2 x  3x  2
                                                            ✓  8x   2
                        8x   2
                                                            ✓answer
                               1
                           x
                               4                            (5)

4.3   3 x . 92 x1  81
       3 x . 34 x  2  34
             35 x2  34                                    ✓same bases
           5x  2  4                                       ✓equating indices
                       2                                    ✓answer
                   x                                       (3)
                       5

4.4                4  3x  1  5
                   4  1  3x  5  1                      ✓add 1 to both sides
                      3  3x  6                           ✓  3 : on both sides
      3:             1  x  2                            ✓answer
                                                            (3)
                                                                                      [13]

                                               3

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                                                           MATHEMATICS
                                        MEMORANDUM
                                                     (PAPER 1)      GRADE 10

QUESTION 5
                        Pattern 1

                            Pattern 2

                                Pattern 3

5.1     Tn  7n  3                                      ✓ 7n
                                                         ✓3
                                                         (2)

5.2     Tn  2n                                          ✓ 2n
                                                         (1)

5.3.1   T12  2(12)                                      ✓answer
            24                                          (1)

5.3.2   Tn  7 n  3
        150  7 n  3                                    ✓ = 150
                                                         ✓ n  21
           n  21
                                                         (2)
                                                                          [6]

                                            4

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                                                                     MATHEMATICS
                                            MEMORANDUM
                                                               (PAPER 1)      GRADE 10

QUESTION 6

                                      y
                    f
                                          D(3; 4)

                              B
                        C
                                                          xx
           h        D             0

6.1   y  ax 2              (3;4)
      4  a.32
                                                                   ✓substitution (3; 4)
      4  9a
                                                                        4
          4                                                        ✓a 
      a                                                                9
          9
          4
      y  x2                                                       (2)
          9

6.2        2                                    4 2
      y     x2              and          y     x
           3                                    9
                    4 2 2
                       x  x2                                     ✓equating
                    9        3
      9:          4 x  6 x  18
                       2
                                                                   ✓simplification
      2:           2 x 2  3x  9  0
                     (2 x  3)( x  3)  0
                            3
      x  0:      xC  
                            2                                      ✓correct x co-ordinate
                           2 3
                   yC      2                                  ✓substitute
                           3 2
                           1 2
                                                                   ✓ y co-ordinate
                          1

                    3 
                 C   ; 1
                    2                                            (5)

                                                      5

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                                                         MATHEMATICS
                                     MEMORANDUM
                                                   (PAPER 1)      GRADE 10

6.3    x -intercept: y  0
                 2
            0 x2
                 3
        3 : 0  2x  6                                ✓sub y  0
              2 x  6
        2 : x  3
                                                       ✓answer (+)
       WO = 3 units                                    (2)

6.4      T 4 ; 3                                     ✓answer
                                                       (1)
                                                                               [10]

QUESTION 7
                                                       y  3. 2 x  1
                              y                        ✓ asymptote
                                                       ✓shape
                                                       ✓ y -intercept
                                  (1; 7)
                              4                            6
                                                       y  1
                                                           x
                              1                        ✓shape
                      -6      0                x       ✓ x -intercept
                                                       ✓any other coordinate

Point of intersection (1;7)                            ✓✓ answer (1; 7)
                                                       (8)

                                                                               [8]
                                                                        TOTAL: 50

                                           6

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