# Mathematics Grade 10 P1 Gauteng June 2018 Memo (English)

> Grade 10 Mathematics Paper 1 memorandum from the Gauteng June 2018 (English), 6 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr10-math-p1-english-june-2018-possible-answer/c7e9b1a7-d752-4662-8fa4-b9eb6e9b2078
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 10
- Language: English
- Document type: Memorandum
- Year: 2018
- Exam period: Gauteng June
- Paper: 1
- Curriculum: CAPS
- Pages: 6

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## About this document

Mathematics · Grade 10 · Gauteng June · 2018 · English. Memorandum, 6 pages. Read online or download the PDF.

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## Document text

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### Page 1

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          GAUTENG DEPARTMENT OF EDUCATION
              PROVINCIAL EXAMINATION
                    JUNE 2018
                     GRADE 10

                   MATHEMATICS

                      PAPER 1

                  MEMORANDUM

6 pages

                         1

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                                                             MATHEMATICS
                                      MEMORANDUM
                                                       (PAPER 1)      GRADE 10

                            GAUTENG DEPARTMENT OF EDUCATION
                                  PROVINCIAL EXAMINATION

QUESTION 1
1.1  25  33  36
                        .
        25  33  36                                            25 ; 36
                                                               answer
      5  33  6
                                                                                   (2)
        33 lies between 5 and 6
1.2   x  0, 4545454545
      100 x  45, 45454545                                      100 x  45, 45454545
      x  0, 4545454545
                                                                99 x  45
      99 x  45
           45
      x                                                        x
                                                                       5
           99                                                         11
            5                                                                      (3)
         
           11

                                                                                   [5]

                                            2

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                                                              MATHEMATICS
                                           MEMORANDUM
                                                        (PAPER 1)      GRADE 10

QUESTION 2
2.1   2.1.1   (3x) 2 ( 2 xy ) 3
                  2x5 y 4
                                                                 9 x 2 .  8 x3 y 3
                  9 x .  8x y
                     2         3   3
              
                     2 x5 y 4
                  72 x5 y 3
              
                   2 x5 y 4                                      36y 1
               36 x55 y 3 4                                 
                                                                   36
               36 y 1                                            y
                                                                                       (3)
                 36
              
                 y

      2.1.2   1     1       q 1    2
                q   q   2   qp 
              p     p       p q     
                                                                     1      
                 1        q    q p 
                                   2 2                             2  q2 
                2  q2    2  2                               p       
                p        pq     p 
                                                                  q     q p 
                                                                          2 2

                 1        1                                  2  2 
                2  q2    2  q2                           pq      p 
                p        p         
                 1         1
               2  q2  2  q2                                 
                                                                   1         1
                                                                       q2  2  q2
                 p         p                                      p 2
                                                                            p
               2q 2                                            2q 2
                                                                                  (3)
2.2   2.2.1   6 p  40  p 2
                                                                 ( p 2  6 p  40)
               ( p 2  6 p  40)
               ( p  10)( p  4)                               ( p  10)
                                                                 ( p  4)
                                                                                    (3)
      2.2.2    xy  ( y  x)b  b2
                xy  by  bx  b2                               xy  by  bx  b2
                y ( x  b)  b( x  b)                        grouping
                                                                 ( x  b)
               ( x  b)( y  b)
                                                                 ( y  b)
                                                                                    (4)
                                                                                  [13]

                                               3

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                                                                       MATHEMATICS
                                               MEMORANDUM
                                                                 (PAPER 1)      GRADE 10

QUESTION 3
3.1       x2           3      1
                          
      x  3x  4 x  4 2  2 x
        2

                                                                        correct factors
           x2            3        1
                            
       x  4  x  1 x  4 2  x  1                                 2  x  2
      CD: 2  x  4  x  1                 Restriction:   ;           6  x  1
      2  x  2   6  x  1  1 x  4                               x  4
       2x  4  6x  6  x  4                                          answer
      2 x  5 x  10  4                                                                   (5)
             3x  6
           x  2
3.2        x
      2   1  3
           2                                                                     x
                                                                         3      2
           x                                                                     2
      3   2
           2
      6  x  4                                                         6  x  4
                                                                        number line
                                                                                           (3)
      -6                                       4
                                                                                           [8]

                                                         4

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                                                              MATHEMATICS
                                           MEMORANDUM
                                                        (PAPER 1)      GRADE 10

QUESTION 4

4.1   4.1.1   T1  3(1)  2  5
              T2  3(2)  2  8                                method
              T3  3(3)  2  11                               
              T4  3(4)  2  14                               2
              Tn  3n  2                                                       (3)
4.2   4.2.1   3x  7; 2 x; 3x  1;....                          values
              2 x   3x  7   3x  1  2 x                  equate
                                                               simplify
                2 x  3x  7  x  1                           answer
                         2x   6                                              (4)
                          x3
      4.2.2   2; 6; 10; …
              Tn  4n  2                                       4n  2  31
                   4n  2  31
                       4n  33                                  n  8, 25
                        n  8, 25                              conclusion
                                                                                (3)
              n  9

                                                                               [10]

                                                5

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                                                                  MATHEMATICS
                                             MEMORANDUM
                                                            (PAPER 1)      GRADE 10

QUESTION 5
5.1           q 1                                                  q 1
              y  b 1
                     x

                                                                   substitute coordinate
              5  b2  1                                           b  2
              b2  4                                                                  (3)
              b2
5.2   5.2.1   y   x  2........(1)
                   3
              y  ..............(2)
                    x
              Substitute (1) in (2):
                                                                   substitute
                         3
              x  2                                              simplification
                          x                                        factors
              x  2x  3  0
                 2
                                                                    values
                x  3 x  1  0                                values
                                                                   coordinate form
              x  3 OR x   1                                                         (6)

              y   (3)  2 OR         y   (1)  2
              y  1                   y3
              Q(3;  1)            P(1; 3)
      5.2.2   B(2; 0)                                              2
                                                                   0
                                                                                       (2)
      5.2.3   y   (6)  2                                        GE  8
              GE  8

                                                                            1
                 3                                                 EF 
              y                                                            2
                 6
                   1
              EF 
                   2                                                    1
                                                                   7
                                                                        2
                              1                                                        (3)
               GF  8 
                              2
                          1
                     7
                          2
                                                                                      [14]

                                                                              TOTAL : 50

                                                        6

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