# Mathematics Grade 10 P2 Gauteng June 2016 Memo (Afrikaans) > Grade 10 Mathematics Paper 2 memorandum from the Gauteng June 2016 (Afrikaans), 7 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/gr10-math-p2-afrikaans-june-2016-possible-answers/a2591f21-4c13-4562-9e50-bef4b6944976 - Updated: 2026-09-27 - Subject: Mathematics - Grade: Grade 10 - Language: Afrikaans - Document type: Memorandum - Year: 2016 - Exam period: Gauteng June - Paper: 2 - Curriculum: CAPS - Pages: 7 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 10](https://www.hlayiso.com/library/grade-10) › [Mathematics](https://www.hlayiso.com/library/grade-10/mathematics) › [Mathematics Grade 10 P2 Gauteng June 2016 Memo (Afrikaans)](https://www.hlayiso.com/library/gr10-math-p2-afrikaans-june-2016-possible-answers/a2591f21-4c13-4562-9e50-bef4b6944976) ## About this document Mathematics · Grade 10 · Gauteng June · 2016 · Afrikaans. Memorandum, 7 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com GAUTENGSE DEPARTEMENT VAN ONDERWYS PROVINSIALE EKSAMEN JUNIE 2016 GRAAD 10 WISKUNDE (VRAESTEL 2) MEMORANDUM 7 bladsye 1 ### Page 2 Downloaded from hlayiso.com MEMORANDUM Wiskunde (V2) Graad 10 GAUTENGSE DEPARTEMENT VAN ONDERWYS PROVINSIALE EKSAMEN WISKUNDE (V2) MEMORANDUM VRAAG 1 1.1 sin y x   verhouding cos r r y r   r x y vereenvoudig  x gevolgtrekking (3) 1.2.1 PQ 5 sin    antwoord PR 13 (1) 1.2.2 PR 13 sec    antwoord QR 12 (1) 1.2.3 PQ 5 tan    antwoord QR 12 (1) [6] 2 ### Page 3 Downloaded from hlayiso.com MEMORANDUM Wiskunde (V2) Graad 10 VRAAG 2 2.1 korrekte kwadrant 4 tan  3 3 y  tan    4 x r 5 r 2  x2  y r 2  (4) 2  (3) 2 r 5 5 sin   3 cot   3     3  4   5   5   3   5    3  4     3  4  7  3 7 (5) 2.2 25 cos  2 2 4 vervanging  25  5  16   25   25   16 antwoord (2) [7] 3 ### Page 4 Downloaded from hlayiso.com MEMORANDUM Wiskunde (V2) Graad 10 VRAAG 3 3.1.1 sin x  2 cos 3 y Geen  sin( 42 )  2 cos( 3  68 ) penaliseer vir afronding  sin( 42 )  2 cos 204   1,16 antwoord (2) 3.1.2 3 tan 2 ( x  y ) Geen penaliseer vir  3 tan 2 (42   68 ) afronding  3 tan 2 110   22,65 antwoord (2) 3.2.1 2 sin  1,432  sin  0,716 2   45,725 antwoord (2) 3.2.2 tan 3  6,345 Penaliseer vir 3  81,044 afronding   27,015  3  81,044  antwoord (3) Penaliseer [9] slegs in 3.2.1 of 3.2.2 vir afronding 4 ### Page 5 Downloaded from hlayiso.com MEMORANDUM Wiskunde (V2) Graad 10 VRAAG 4 4.2 sin2 45  cos 60  tan10. cot 10  sin2 45  1  2 2 2 1     1   2  2  tan 10. cot 10  1 1 1   1 1 2 2  cos 60  1 2 antwoord = 1 (4) [9] 5 ### Page 6 Downloaded from hlayiso.com MEMORANDUM Wiskunde (V2) Graad 10 VRAAG 5 5.1 Pˆ1  Qˆ  Rˆ 2 (buitehoek = som van teenoorstaande binnehoeke) rede Pˆ  30   110  1 Pˆ1  110   30   80 antwoord (2) 5.2 Pˆ2  Sˆ1 ( e teenoor gelyke sye is gelyk) stelling met rede Pˆ  Rˆ  Sˆ  180  (Som van e van ʼn driehoek  180 ) 2 2 1  stelling met rede  Pˆ2  110   Pˆ2  180  (Gegee : Rˆ 2  110  en Pˆ2  Sˆ1 )  2 Pˆ  180   110  vereenvoudiging 2  2 Pˆ2  70  Pˆ  35 2 OF stelling met rede Pˆ2  Sˆ1 ( e teenoor gelyke sye is gelyk) Rˆ1  Pˆ2  Sˆ1 (buitehoek = som van teenoorstaande binnehoeke)  stelling met rede  Pˆ  35 2 vereenvoudiging (3) [5] VRAAG 6 In ABC en CDA Bˆ  Dˆ (gegee) Stelling Cˆ1  Â 2 AC is gemeenskaplik Cˆ 1  Aˆ 2 (verwisselende e ; AD // BC ) Rede  ABC  CDA ( ; ; S ) (AD // BC) S + R  AD BC  ( ABC  CDA ) AD = BC ABCD is ʼn parallelogram (een sy = // ) rede OF ( een sy = // ) In ABC en CDA Bˆ  Dˆ (gegee) Stelling Cˆ1  Â 2 AC is gemeenskaplik Cˆ 1  Aˆ 2 (verwisselende e ; AD // BC ) Rede  ABC  CDA ( ; ; S ) (AD // BC)  AD BC  ( ABC  CDA ) S + R AD = BC AB = DC  ( ABC  CDA ) rede CD is ʼn parallelogram teenoorstaande sy = teenoorstaande sy = [5] 6 ### Page 7 Downloaded from hlayiso.com MEMORANDUM Wiskunde (V2) Graad 10 VRAAG 7 7.1 AO + OC = 4 xy ( gegee – diagonale halveer) OC = 2 xy  OC = 2 xy BO + OD = 2x 2  2 y 2 ( gegee – diagonale halveer)  BO = x 2  y 2 BO = x 2  y 2 LHS = BC2 RHS = BO2 + OC2  = x2  y2  2  2 = x 2  y 2  (2xy) 2  LK OF = x4  2x2 y2  y4 = x 4  2x 2 y 2  y 4  4x 2 y 2 RK = x 4  2x 2 y 2  y 4 rede  OF = x 2  y 2  2 BOC is a reghoekige driehoek OF bewys AOD is n reghoekige driehoek Diagonale halveer by 90 AOD is n reghoekige driejhoek (5) 7.2 Rˆ1  120  (oorstaande hoek van a // ) m  Rˆ1  120   T̂  60 Rˆ 2  60 (hoeke op ʼn reguit lyn)  Sˆ 2  60   x  15 T̂  60 (hoeke teenoor gelyke sye) (4) Sˆ 2  60  (som van hoeke van ʼn driehoek)  4 x  60 x  15 [9] TOTAAL: 45 7 ## Related documents - [Gr10 Math P1 (Afrikaans) June 2016 Possible Answers](https://www.hlayiso.com/library/gr10-math-p1-afrikaans-june-2016-possible-answers/137f30ce-23ec-4e03-a749-7c6b6defb0b9) — Mathematics · Memo · 2016 · Afr - [Gr10 Math P2 (Afrikaans) June 2017 Possible Answers](https://www.hlayiso.com/library/gr10-math-p2-afrikaans-june-2017-possible-answers/80ad79a2-f1ee-463d-8abe-4c256f21b7de) — Mathematics · Memo · 2017 · Afr - [Gr10 Math P1 (Afrikaans) June 2016 Question Papers](https://www.hlayiso.com/library/gr10-math-p1-afrikaans-june-2016-question-papers/bc064649-cbd2-48d4-a47d-a2a730f07000) — Mathematics · QP · 2016 · Afr - [Gr10 Math P2 (Afrikaans) November 2016 Question Paper](https://www.hlayiso.com/library/gr10-math-p2-afrikaans-november-2016-question-paper/8510a1e4-a4d0-46c1-8b6b-bb9e31e93e91) — Mathematics · QP · 2016 · Afr - [Gr10 Math P2 (Afrikaans) June 2019 Question Paper](https://www.hlayiso.com/library/gr10-math-p2-afrikaans-june-2019-question-paper/263631af-e143-4e33-ac4f-f9901208b72e) — Mathematics · QP · 2019 · Afr - [Gr10 Math P2 (Afrikaans) June 2018 Question Paper](https://www.hlayiso.com/library/gr10-math-p2-afrikaans-june-2018-question-paper/8eca90bd-adf7-477d-8f55-fbd705a35b52) — Mathematics · QP · 2018 · Afr ## More from Grade 10 Mathematics - [Gr 10 Maths ATP 2023-24](https://www.hlayiso.com/library/gr-10-maths-atp-2023-24/80c1c337-e011-4b8b-a37b-d2e0df9daaf6) — ATP - [KZN Maths Grade 10 June 2025 P1 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-june-2025-p1-and-memo/dc5ae33f-46ec-4eae-b577-25a82956eaec) — QP + Memo · 2025 - [KZN Maths Grade 10 March 2025 QP and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-march-2025-qp-and-memo/bc27cbbf-ec6d-4c60-bf7e-25a154d363e4) — QP + Memo · 2025 - [KZN Maths Grade 10 November 2025 P1 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-november-2025-p1-and-memo/ece9abee-2009-4e22-8de3-34ccb229e5cb) — QP + Memo · 2025 - [KZN Maths Grade 10 November 2025 P2 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-november-2025-p2-and-memo/417e9b18-c39d-4fb2-9e32-c089e8fbfd22) — QP + Memo · 2025 - [Gr 10 Mathematics P1 (Afrikaans) June 2024 Question Paper](https://www.hlayiso.com/library/gr-10-mathematics-p1-afrikaans-june-2024-question-paper/f7a97f78-e0a1-47a0-9585-d048fbb9a0b0) — QP · 2024 · Afr ## Collection - [Grade 10 past papers](https://www.hlayiso.com/grade-10/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. 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