# Mathematics Grade 10 P2 Gauteng June 2016 Memo (English) > Grade 10 Mathematics Paper 2 memorandum from the Gauteng June 2016 (English), 8 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/gr10-math-p2-english-june-2016-possible-answers/ae09e44f-f8d8-4f2e-8b02-34c5c9966c9d - Updated: 2026-09-27 - Subject: Mathematics - Grade: Grade 10 - Language: English - Document type: Memorandum - Year: 2016 - Exam period: Gauteng June - Paper: 2 - Curriculum: CAPS - Pages: 8 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 10](https://www.hlayiso.com/library/grade-10) › [Mathematics](https://www.hlayiso.com/library/grade-10/mathematics) › [Mathematics Grade 10 P2 Gauteng June 2016 Memo (English)](https://www.hlayiso.com/library/gr10-math-p2-english-june-2016-possible-answers/ae09e44f-f8d8-4f2e-8b02-34c5c9966c9d) ## About this document Mathematics · Grade 10 · Gauteng June · 2016 · English. Memorandum, 8 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Matching paper and memo - [Gr10 Math P2 (English) June 2016 Question Papers](https://www.hlayiso.com/library/gr10-math-p2-english-june-2016-question-papers/f02455ff-9acd-4b3a-9096-77e0aa2c69c0) — QP · 2016 · Eng ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com GAUTENG DEPARTMENT OF EDUCATION PROVINCIAL EXAMINATION JUNE 2016 GRADE 10 MATHEMATICS (PAPER 2) MEMORANDUM 7 pages 1 ### Page 2 Downloaded from hlayiso.com MEMORANDUM Mathematics (P2) Grade 10 GAUTENG DEPARTMENT OF EDUCATION PROVINCIAL EXAMINATION MATHEMATICS (P2) MEMORANDUM QUESTION 1 1.1 sin y x   cos r r  y y r r   x r x  y r  simplification x (3) Answer only 1/3 1.2.1 PQ 5 sin    answer PR 13 (1) 1.2.2 PR 13 sec    answer QR 12 (1) 1.2.3 PQ 5 tan    answer QR 12 (1) [6] 2 ### Page 3 Downloaded from hlayiso.com MEMORANDUM Mathematics (P2) Grade 10 QUESTION 2 2.1 correct quadrant 4 tan  3 3 y  tan    4 x r 5 r 2  x2  y r 2  (4) 2  (3) 2 r 5 5 sin   3 cot   3     3  4   5   5   3   5    3  4     3  4  7  3 7 (5) 2.2 25 cos  2 2 4 substitution  25  5  16   25   25   16 answer (2) [7] 3 ### Page 4 Downloaded from hlayiso.com MEMORANDUM Mathematics (P2) Grade 10 QUESTION 3 3.1.1 sin x  2 cos 3 y Do not penalise  sin( 42 )  2 cos( 3  68 ) for rounding off  sin( 42 )  2 cos 204   1,16 answer (2) 3.1.2 3 tan ( x  y ) 2 Do not penalise for rounding  3 tan 2 (42   68 ) off  3 tan 2 110   22,65 answer (2) 3.2.1 2 sin  1,432 Do not penalise  sin  0,716 for rounding off   45,725 answer (2) 3.2.2 tan 3  6,345 3  81,044  tan 1 3   27,015 answer (3) *penailse once [9] only for rounding off in 3.2 4 ### Page 5 Downloaded from hlayiso.com MEMORANDUM Mathematics (P2) Grade 10 QUESTION 4 4.2 sin2 45  cos 60  tan10. cot 10  cos 60  1  2 2 2 1     1  1  sin2 45   2  2 2 1 1   1 2 2  tan 10. cot 10  1 1 answer = 1 (4) [9] 5 ### Page 6 Downloaded from hlayiso.com MEMORANDUM Mathematics (P2) Grade 10 QUESTION 5 5.1 Pˆ1  Qˆ  Rˆ 2 (exterior angle = sum of interior opposite angles)  reason Pˆ  30   110  1 Pˆ1  110   30   80 answer (2) 5.2 Pˆ2  Sˆ1 (  S opposite equal sides are equal) statement and reason Pˆ  Rˆ  Sˆ  180  2 2 1 (Sum of s of a triangle  180 )  Pˆ2  110   Pˆ2  180  (Given : Rˆ 2  110  and Pˆ2  Sˆ1 ) statement and  2 Pˆ  180   110  2 reason  2 Pˆ2  70 simplification  Pˆ  35 2 (3) OR OR statement and Pˆ2  Sˆ1 (  S opposite equal sides are equal) reason Rˆ  Pˆ  Sˆ 1 2 1 (exterior angle = sum of interior opposite angles) statement and  Pˆ2  35 reason simplification (3) [5] QUESTION 6 In ABC and CDA  Cˆ 1  Aˆ 2 Bˆ  Dˆ (given) AC is common Reason Cˆ 1  Aˆ 2 (alternate angles ; AD // BC ) (AD // BC)  ABC  CDA ( ; ; S ) S + R  AD BC ( ABC  CDA ) AD = BC ABCD is a parallelogram ( one side = // ) reason ( one side = // ) OR OR In ABC and CDA Statement Bˆ  Dˆ (given) AC is common Reason Cˆ 1  Aˆ 2 (alternate angles ; AD // BC ) (AD // BC)  ABC  CDA ( ; ; S ) S + R  AD BC ( ABC  CDA ) AD = BC  AB  DC ( ABC  CDA ) reason (opposite sides =) ABCD is a parallelogram ( opposite sides = ) 6 ### Page 7 Downloaded from hlayiso.com MEMORANDUM Mathematics (P2) Grade 10 [5] 7 ### Page 8 Downloaded from hlayiso.com MEMORANDUM Mathematics (P2) Grade 10 QUESTION 7 7.1 AO + OC = 4 xy ( given – diagonals bisect) OC = 2 xy  OA = 2 xy BO + OD = 2x 2  2 y 2 ( given – diagonals bisect)  BO = x 2  y 2 BO = x 2  y 2 If rhombus – diagonals bisect at 90  LHS LHS = BC2 RHS = BO2 + OC2  = x2  y2  2   2 = x 2  y 2  (2xy) 2 RHS OR = x4  2x2 y2  y4 = x 4  2x 2 y 2  y 4  4x 2 y 2 = x 4  2x 2 y 2  y 4  OR = x 2  y 2  2 conclusion BOC is a right angled triangle OR Prove AOD as a right angled triangle Diagonals bisect each other at 90/right angles ABCD is a Rhombus (5) 7.2 Rˆ1  120  m (opposite angles of a // )  Rˆ1  120  Rˆ  60 2 (angles on a straight line) T̂  60 (angles opposite equal sides)  T̂  60 Ŝ  60 (sum of angles of a triangle)  Ŝ  60  4 x  60  x  15 x  15 (4) [9] TOTAL: 50 8 ## Related documents - [Gr10 Math P2 (English) June 2018 Possible Answer](https://www.hlayiso.com/library/gr10-math-p2-english-june-2018-possible-answer/bb750159-64b8-41c2-8174-05197986ea20) — Mathematics · Memo · 2018 · Eng - [Gr10 Math P2 (English) June 2017 Possible Answers](https://www.hlayiso.com/library/gr10-math-p2-english-june-2017-possible-answers/26dc2a6d-2c76-4c1c-a2b8-614d6e862891) — Mathematics · Memo · 2017 · Eng - [Gr10 Math P1 (English) June 2016 Question Papers](https://www.hlayiso.com/library/gr10-math-p1-english-june-2016-question-papers/12b65bdc-382b-4ad9-937b-9e61a48214d1) — Mathematics · QP · 2016 · Eng - [Gr10 Math P2 (English) June 2019 Question Paper](https://www.hlayiso.com/library/gr10-math-p2-english-june-2019-question-paper/306f487b-807d-4bdd-a26d-882dacdbe6cb) — Mathematics · QP · 2019 · Eng - [Gr10 Math P2 (English) June 2017 Question Paper](https://www.hlayiso.com/library/gr10-math-p2-english-june-2017-question-paper/b5f34c52-34e2-4402-9d23-ed733526a7b3) — Mathematics · QP · 2017 · Eng - [Gr10 Math P1 (English) June 2018 Possible Answer](https://www.hlayiso.com/library/gr10-math-p1-english-june-2018-possible-answer/c7e9b1a7-d752-4662-8fa4-b9eb6e9b2078) — Mathematics · Memo · 2018 · Eng ## More from Grade 10 Mathematics - [Gr 10 Maths ATP 2023-24](https://www.hlayiso.com/library/gr-10-maths-atp-2023-24/80c1c337-e011-4b8b-a37b-d2e0df9daaf6) — ATP - [KZN Maths Grade 10 June 2025 P1 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-june-2025-p1-and-memo/dc5ae33f-46ec-4eae-b577-25a82956eaec) — QP + Memo · 2025 - [KZN Maths Grade 10 March 2025 QP and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-march-2025-qp-and-memo/bc27cbbf-ec6d-4c60-bf7e-25a154d363e4) — QP + Memo · 2025 - [KZN Maths Grade 10 November 2025 P1 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-november-2025-p1-and-memo/ece9abee-2009-4e22-8de3-34ccb229e5cb) — QP + Memo · 2025 - [KZN Maths Grade 10 November 2025 P2 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-10-november-2025-p2-and-memo/417e9b18-c39d-4fb2-9e32-c089e8fbfd22) — QP + Memo · 2025 - [Gr 10 Mathematics P1 (English) June 2024 Question Paper](https://www.hlayiso.com/library/gr-10-mathematics-p1-english-june-2024-question-paper/f3793ce3-e07c-4539-b525-ae281a304900) — QP · 2024 · Eng ## Collection - [Grade 10 past papers](https://www.hlayiso.com/grade-10/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. 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