# Mathematics Grade 10 Paper 2 Gauteng November 2021 Memo

> Grade 10 Mathematics Paper 2 memorandum from the Gauteng November 2021, 10 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr10-mathematics-p2-eng-afr-nov-possible-answers/d072580e-848a-447d-9a3b-b14f86133ba1
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 10
- Document type: Memorandum
- Year: 2021
- Exam period: Gauteng November
- Paper: 2
- Curriculum: CAPS
- Pages: 10

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## About this document

Mathematics · Grade 10 · Gauteng November · 2021. Memorandum, 10 pages. Read online or download the PDF.

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## Document text

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### Page 1

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              PROVINCIAL EXAMINATION/
               PROVINSIALE EKSAMEN
                      NOVEMBER 2021
                    GRADE 10/GRAAD 10
   MARKING GUIDELINES/NASIENRIGLYNE

                       MATHEMATICS/WISKUNDE
                        (PAPER/VRAESTEL 2)

10 pages/bladsye

### Page 2

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                                                           MATHEMATICS (PAPER 2)/
                                     MARKING GUIDELINES/   WISKUNDE (VRAESTEL 2)
                                     NASIENRIGLYNE
                                                                  GRADE/GRAAD 10

1.          SUGGESTED SOLUTIONS/VOORGESTELDE                EXPLANATION    MARKS
                       OPLOSSINGS                           VERDUIDELIKING PUNTE

1.1   30                                                    ✓ Answer/Antwoord    (1)

1.2   1.2.1 35                                              ✓ Answer/Antwoord    (1)

      1.2.2 30                                              ✓ Answer/Antwoord    (1)

      1.2.3 38,5                                              Answer/Antwoord
                                                            ✓ Accept 38 or
                                                              39/Aanvaar 38 of
                                                              39                 (1)

1.3   Range = Max. – Min./ Omvang = Maks. – Min.            ✓ Method/Metode
      = 44 – 24                                             ✓ Answer/Antwoord
      = 20                                                                       (2)

1.4   No. of packets of sweets above upper quartile/        ✓ Method/Metode
      Aantal pakkies lekkers bo die boonste kwartiel        ✓ Answer/Antwoord
         6
      =      100%
        25
      = 24%                                                                      (2)
                                                                                 [8]

                                                   2

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                                                                                    MATHEMATICS (PAPER 2)/
                                                 MARKING GUIDELINES/                WISKUNDE (VRAESTEL 2)
                                                 NASIENRIGLYNE
                                                                                           GRADE/GRAAD 10

2.
2.1   200 < x ≤ 250                                                                      ✓ Answer/
                                                                                           Antwoord      (1)

2.2                                              HISTOGRAM
                                              Histogram
                             Amount spent by 120 motorists at KG petrol garage
                             Bedrag gespandeer deur 120 motoriste by KG vulstasie
                                                                                         ✓ 1st & 2nd
                                                                                          columns/
                                                                                          1ste en 2de

      Number of Motorists/
                                                                                          kolomme

                                                                                         ✓ Last three

      Aantal motoriste
                                                                                          columns/
                                                                                          Laaste drie
                                                                                          kolomme

                                              Amount spent in Rands
                                              Bedrag gespandeer in Rand
                                                                                                         (2)

2.3    30                                                                                ✓ 36
           120 = 36th value/36ste waarde
      100

      ∴ interval is/interval is 50 < x ≤ 100                                             ✓ Answer/
                                                                                           Antwoord      (2)

2.4    42                                                                                ✓ 42
           360 = 126                                                                  ✓ Answer/
      120
                                                                                           Antwoord      (2)
                                                                                                         [7]

                                                                  3

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                                                                 MATHEMATICS (PAPER 2)/
                                           MARKING GUIDELINES/   WISKUNDE (VRAESTEL 2)
                                           NASIENRIGLYNE
                                                                        GRADE/GRAAD 10

3.

       𝑥 +𝑥     𝑦 +𝑦                                             Wrong Formula
3.1   ( 1 2 2 ; 1 2 2)
                                                                 NO Marks/
         −7+1       1+(−7)
                                                                 Verkeerde Formule
      𝑆( 2 ; 2 )                                                 GEEN punte nie
      ∴ 𝑆(−3 ; −3)                                               ✓ Formula/Formule
                                                                 ✓ x = –3;
                                                                 ✓ y = –3                 (3)
               𝑦 −𝑦
3.2   𝑚𝐴𝐶 = 𝑥2−𝑥1                                                Wrong Formula
                2     1
                                                                 NO Marks/
           5−(−7)                                                Verkeerde Fomule
       =                                                         GEEN punte nie
              5−1
           = 3                                                   ✓ Formula/Formule
                                                                 ✓ Answer/Antwoord
                                                                                          (2)

3.3   BC = ( x1 − x2 ) 2 + ( y1 − y2 ) 2                         ✓ Formula/Formule

                                                                 ✓ Correct
      BC = (−7 − 1) 2 + (1 − (−7)) 2                              substitution/Korrekte
                                                                  vervanging
      BC = 8 2
      AS = (5 − (−3) 2 + (5 − (−3)) 2                            ✓ BC

      AS = 8 2                                                                            (3)

                                                   4

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                                                                      MATHEMATICS (PAPER 2)/
                                                MARKING GUIDELINES/   WISKUNDE (VRAESTEL 2)
                                                NASIENRIGLYNE
                                                                             GRADE/GRAAD 10

3.4   BC = 8 2
                                                                      ✓ BC
      AS = (5 − (−3) 2 + (5 − (−3)) 2
                                                                      ✓ Formula/Formule
      AS = 8 2                                                        ✓ AS
                                                                      ✓ Method/Metode
                                    1
      Area of/area ∆ABC = 2 ∙base height/                             ✓ Answer/Antwoord
                                            1
      Area van/Area ∆𝐴𝐵𝐶 = 2 basis hoogte
                            1
                      = 2 ∙ 8√2 ∙ 8√2
      AS = 64 unit /eenheid2
                  2

                                            OR/OF

      BS = ( x1 − x2 ) 2 + ( y1 − y2 ) 2                              ✓ Formula/Formule

                                                                      ✓ BS
      BS = (−7 + 3) 2 + (1 + 3) 2
                                                                      ✓ AS

      BS = 4 2                                                        ✓ Method/Metode

      AS = (5 − (−3) 2 + (5 − (−3)) 2
                                                                      ✓ Answer/Antwoord

      AS = 8 2
                                1
      Area of ∆ABC = 2 × 2 ∙ base height/
                                        1
      Area van ∆𝐴𝐵𝐶 = 2 × 2 ∙ basis hoogte
            1
      = 2     4 2 8 2
            2

      AS = 64 unit2/eenheid2                                                               (5)
                                                                                          [13]

                                                        5

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                                                               MATHEMATICS (PAPER 2)/
                                        MARKING GUIDELINES/    WISKUNDE (VRAESTEL 2)
                                        NASIENRIGLYNE
                                                                      GRADE/GRAAD 10

4.
4.1   4.1.1                      ( )
                    y 2 = (2) 2 − 3 2                         ✓ sub in Pythagoras/
                                                                vervang in
                        =4–3
                   ∴ y=1                                        Pythagoras
                             1                                ✓y=1
                   sin  = 2
                                                              ✓ 1/2

                                                              ✓ diagram/diagram

                                   2

                                                                                        (3)

      4.1.2       sin  . cos
                      1   √3
                  = (2) ( 2 )
                                                              ✓ Sub.into cos/
                    √3
                  = 4                                           Vervang in cos
                                                                  √3
                                                              ✓ 4                       (2)

4.2   1                   𝑥                                   ✓ Correct substitution/
        𝑠𝑖𝑛 2𝑦 −[2 𝑡𝑎𝑛2 ( )]cos 𝑥
      2                   2                                     Korrekte vervanging
      1                      60°
        sin 2(45°) −[2 𝑡𝑎𝑛2 ( 2 )]cos 60°
      2                                                           1
          1       √3      1                                   ✓ 2 (1)
      = 2 (1) −[2( 2 )2 ](2 )
                                                                           √3
          3−2√3                                               ✓ [2( 2 )2
      =                                                           1
              6
                                                              ✓2
                                                                  3−2√3
                                                              ✓                         (6)
                                                                       6

                                                6

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                                                                  MATHEMATICS (PAPER 2)/
                                           MARKING GUIDELINES/    WISKUNDE (VRAESTEL 2)
                                           NASIENRIGLYNE
                                                                         GRADE/GRAAD 10

4.3   4.3.1             sin(𝛽 − 17.8°) = 0.215

                        𝛽 − 17.8° = 12.4155°                     ✓ 12,4155°
                                                                 ✓ +17,8°
                        𝛽 = 12.4155° + 17.8°                     ✓Answer/Antwoord

                        𝛽 = 30.22°                                                     (3)

      4.3.2             𝑡𝑎𝑛 3𝛽 = √3
                        3𝛽 = 60°                                 ✓60°
                        𝛽 = 20°                                  ✓ Answer/Antwoord     (2)

      4.3.3                       𝛽
                        3𝑠𝑖𝑛 2 = 2.012
                                                                          𝛽
                              𝛽                                  ✓ 𝑠𝑖𝑛 2 = 0,670666
                        𝑠𝑖𝑛 2 = 0.670666
                                                                     𝛽
                        𝛽                                        ✓ = 41,11848°
                          = 41.11848°                              2
                        2                                        ✓ Answer/Antwoord
                        𝛽 = 84.24°                                                     (3)

4.4   tan 30𝑐𝑜𝑠𝑒𝑐 60°
       𝑐𝑜𝑡45°𝑠𝑖𝑛45°                                                  √3
                                                                 ✓ 3
        √3 2                                                          2
           .                                                     ✓
      = 3 √2
          √3
                                                                     √3
        1.
           2                                                     ✓1
        4
      =3
                                                                 ✓ Answer/Antwoord     (4)
                                                                                      [23]

5.
5.1                                                              ✓ diagram/diagram

                                  y
                    7
                                      4

                𝑥
                         33

                4
      sin 𝑥 =                                                                 4
                7                                                ✓ sin 𝑥 = 7
                                                                              √33
      tan 𝑦 = 4
                √33                                              ✓ tan 𝑦 = 4
      But/Maar: tan 𝑦 = 𝑡                                        ✓ tan 𝑦 = 𝑡
                                                                          √33
                √33
      ∴ 𝑡 2 = ( 4 )2                                             ✓𝑡 2 = ( 4 ) 2
           33                                                    ✓ Answer/Antwoord
      𝑡 = 16                                                                           (6)

                                                   7

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                                                                MATHEMATICS (PAPER 2)/
                                         MARKING GUIDELINES/    WISKUNDE (VRAESTEL 2)
                                         NASIENRIGLYNE
                                                                       GRADE/GRAAD 10

5.2   5.2.1
               1 − 𝑐𝑜𝑠 2 𝑥 − 𝑠𝑖𝑛2 𝑥
               1 − (𝑠𝑖𝑛2 𝑥 + 𝑐𝑜𝑠 2 𝑥 )                         ✓ −(𝑠𝑖𝑛2 𝑥 + 𝑐𝑜𝑠 2 𝑥 )
               =1−1                                            ✓ Simplification/
               = 0                                             Vereenvoudiging

                                                               ✓ Answer/Antwoord
                                                                                            (3)

      5.2.2 𝑐𝑜𝑠 2 𝑥 +tan 𝑥. 𝑐𝑜𝑡𝑥 + 𝑠𝑖𝑛2 𝑥
                                                               ✓rearrangement and
                   2      2     𝑠𝑖𝑛𝑥 cos 𝑥                     identity/
               𝑐𝑜𝑠 + 𝑠𝑖𝑛 𝑥 + 𝑐𝑜𝑠𝑥 . sin 𝑥
                                                               herrangskikking en
               =1+1
                                                               identiteit
               =2
                                                               ✓ Simplification/
                                                               Vereenvoudig
                                                               ✓ Answer/Antwoord
                                                                                            (3)

5.3   ∠𝑆𝑀𝐸 = 34.4°                   (𝑎𝑙𝑡./𝑣𝑒𝑟𝑤. 𝑏𝑖𝑛𝑛𝑒 . ∠𝑠)   ✓ Deductions/ Aftrekkings
      ∠𝑆𝐻𝐸 = 26.2°                   (𝑎𝑙𝑡./𝑣𝑒𝑟𝑤. 𝑏𝑖𝑛𝑛𝑒 . ∠𝑠)
                                                                              55
                                                               ✓ 𝑡𝑎𝑛34.4° = 𝑆𝑀
                                             55
      Disance/Afstand SM: 𝑡𝑎𝑛34.4° = 𝑆𝑀
                                                               ✓ 𝑆𝑀 = 80.3254 𝑚
                     𝑆𝑀 = 80.3254 𝑚
                                        55
       Distance/Afstand SH:tan 26.2 ° = 𝑆𝐻
                                                               ✓ 𝑆𝐻 = 111.77 𝑚
                       𝑆𝐻 = 111.77 𝑚
                                                               ✓ Answer/Antwoord
                  ∴ 80.3254 𝑚 + 111.77𝑚 − 80.3254 𝑚
                           = 31.45 𝑚                                                        (5)
                                                                                           [17]

6.
6.1   a = −2                                                   ✓ a = −2

      b =1                                                     ✓b =1                        (2)

6.2   0  x  180                                            ✓Inequality signs/
      OR/OF                                                    Ongelykheidstekens
      x  (0 ;180  )                                         ✓Critical points/Kritieke
                                                               punte                        (2)

6.3   2                                                        ✓2                           (1)

                                                   8

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                                                                 MATHEMATICS (PAPER 2)/
                                    MARKING GUIDELINES/          WISKUNDE (VRAESTEL 2)
                                    NASIENRIGLYNE
                                                                        GRADE/GRAAD 10

6.4   −1  y  1                                                ✓ Inequality signs/
      OR/OF                                                     Ongelykheidstekens
      y  [−1;1]                                                ✓ Critical points/
                                                                Kritieke punte
                                                                                               (2)

6.5   𝑥 = 270°                                                  ✓ Inequality signs/
                                                                Ongelykheidstekens
                                                                ✓ Critical points/ Kritieke
                                                                punte                          (2)
                                                                                               [9]

7.

7.1   𝑅𝑄̂ 𝑇 + 𝑄𝑇̂𝑆 = 180°    ̂
                             [ Cointerior < s ; RQ II ST ]/     ✓✓ S/R
                             [ko-binnehoeke ; RQ || ST]
      2𝑥 + 2𝑦 = 180°
      𝑥 + 𝑦 = 90°                                               ✓S
      𝑉̂2 + 𝑄̂2 + 𝑇̂1 = 180° [sum of int/𝑠𝑜𝑚 𝑣𝑎𝑛 𝑏𝑖𝑛𝑛𝑒          ✓ S/R
                                                                ✓S
      e van ]/
      𝑥 + 𝑦 + 𝑉̂2 = 180°
      90° + 𝑉̂2 = 180°
      𝑉̂2 = 90°                                                                                (5)

7.2
       𝑉̂1 = 𝑥   [Alt < s ; RS II QT//Verw binne e 𝑅𝑆 𝐼𝐼 𝑄𝑇]   ✓S
      𝑅𝑄 = 𝑅𝑉 [sides opp equal angles/sye teenoor gelyke        ✓ S/R
                  hoeke]
      𝑅𝑄 = 𝑆𝑇 [opp sides of a parallelogram/teenoorst. sye      ✓ S/R
                  van ||m]
      𝑉̂3 = 𝑇̂1 [Alt < s ; RS II QT/                            ✓S
                Verw binne e 𝑅𝑆 𝐼𝐼 𝑄𝑇]
                                                                ✓S
      𝑉𝑆 = 𝑆𝑇 [sides opp equal angles/sye teenoor gelyke
                hoeke]
                                                                ✓S
      𝑅𝑄 = 𝑅𝑉 [sides opp equal angles/sye teenoor gelyke
                hoeke]
      𝑉𝑆 = 𝑅𝑄 = 𝑅𝑉
      𝑅𝑆 = 2𝑅𝑄                                                                                 (6)
                                                                                              [11]

                                                 9

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                                                                   MATHEMATICS (PAPER 2)/
                                    MARKING GUIDELINES/            WISKUNDE (VRAESTEL 2)
                                    NASIENRIGLYNE
                                                                          GRADE/GRAAD 10

8.
8.1                                                                       ✓
                                                                          construction/
                                                                            konstruksie

                                                                          /

      MN = NP    {construction/konstruksie]
      ̂1 = 𝑁
      𝑁    ̂2      Vertically opposite angles/ Regoorst e
      AN=AC        given/gegee
      ∆𝑀𝑁𝐴 ≡ ∆𝑃𝑁𝐶         𝑆𝐴𝑆 / s  s
                                                                          ✓S
      MA = CP    (≡ ∆𝑠) /e                                              ✓ S/R
      MP = BC and MB = PC                                                 ✓S
            ∴ MPCB is a parallelogram      [both pairs of opp side =]     ✓ S/R
          MPCB is ‘n ||m     [beide pare teenoorst sye = ]                ✓S
      MN // BC   [opp sides of //gm/teenoorst sye van ||m ]               ✓R               (6)

8.2   TS // UR    [midpoint theorem/middelpuntt stelling]                 ✓ S/R
      UR=2TS                                                              ✓S
      TS=2𝑥 [Converse midpoint theorem/omgekeerde midpt stelling]         ✓ S/R
      UR=2TS=4𝑥                                                           ✓S
      UR=UV+VR                                                            ✓S
      VR=3𝑥                                                                                (6)
      OR/OF
                                  given                                   ✓S
      UT = TQ and QS = SR [
                                 gegee ]
                       1
      TS||UR and TS = UR [midpt theorem/midpt stelling]                   ✓ S/R
                       2
      In ΔPTS
      TU = UP        [given/gegee]
      TS||UV       [proven/bewys]                                         ✓S
                          1
      PV = VS and UV = TS [converse; midpt theorem/                       ✓ S/R
                          2
                                 omgekeerde midpt stelling]
      TS = 2𝑥
      UR = 4𝑥                                                             ✓S
      VR = 3𝑥                                                             ✓S
                                                                                          [12]
                                                                        TOTAL/TOTAAL:      100

                                                10

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