# Physical Sciences Grade 10 P1 Gauteng November 2020 Memo

> Grade 10 Physical Sciences Paper 1 memorandum from the Gauteng November 2020 (Afrikaans), 6 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr10-phy-p1-afrikaans-2020-exemplars-possible-answers/0aae7846-6dfc-4047-8bce-3303081e22ed
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 10
- Language: Afrikaans
- Document type: Memorandum
- Year: 2020
- Exam period: Gauteng November
- Paper: 1
- Curriculum: CAPS
- Pages: 6

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## About this document

Physical Sciences · Grade 10 · Gauteng November · 2020 · Afrikaans. Memorandum, 6 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

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### Page 1

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            GAUTENGSE DEPARTEMENT VAN ONDERWYS
                    PROVINSIALE EKSAMEN
                      NOVEMBER 2020
                          GRAAD 10

                 FISIESE WETENSKAPPE (FISIKA)
                         VRAESTEL 1

                        MEMORANDUM

6 bladsye

                              1

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                                                             FISIESE WETENSKAPPE
                                    MEMORANDUM
                                                         (VRAESTEL 1)       GRAAD 10

VRAAG 1: MEERVOUDIGEKEUSE VRAE

1.1   C              
1.2   D              
1.3   B              
1.4   C              
1.5   C                                                                      [10]

VRAAG 2

2.1   NEGATIEWE NASIEN
      TRANSVERSALE

      Die versteuring van die deeltjies van die medium is loodreg op die
      voortplantingsrigting.                                                 (3)

2.2   P                                                                       (1)

2.3   2.3.1 Golflengte = 100 mm = 10 cm = 0,1 m                               (1)

      2.3.2 T = 1,5 s                                                         (1)

      2.3.3 f = 1 / T = 1 / 1,5 = 0,67 Hz

             v = f x golflengte 
             v = (0,67) (0,1)
             v = 0,067 m·s-1                                                  (3)
                                                                               [9]
VRAAG 3

3.1   150 m + 25 m = 175 m                                                    (1)

3.2   ∆x = 125 m oos                                                          (1)

3.3   3.3.1 Verplasing is die verandering in posisie van die voorwerp        (2)

      3.3.2 Fisiese hoeveelheid wat grootte en rigting het                   (2)

3.4                                    Puntetoekenning vir skaaltekening

             5 cm           1 cm 
                                       kriteria                         Punt
                                       Korrekte metings vir 50 m en     
      Verplasing = 125 m 
      reg oos                         25 m
                                       Korrekte meting vir verplasing   
                                                                               (4)
                                                                               [10]

                                                  2

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                                                             FISIESE WETENSKAPPE
                                       MEMORANDUM
                                                         (VRAESTEL 1)       GRAAD 10

VRAAG 4

                Δx 6
4.1.1   VAB         3 m.s 1  
                Δt  2                                                               (3)

                ΔX        18
4.1.2   VCD                 9 m.s1  
                Δt         2                                                        (2)

             Δv  9  3                   
4.2     a                   1,5 m.s-2
             Δt   5 1 

        OF
                          
                          
                           
             = 1,5 m.s-2       
                                                                                    (4)

4.3     Die verandering (toename) in verplasing in elke (opeenvolgende) interval
        is konstant (6 m)                                                          (2)

4.4.1 Die motor beweeg met 'n konstante/eenvormige snelheid/ versnelling is
      nul                                                                         (1)

                     Δv  4,8  0              2
      gradient 
4.4.2 gradiënt                    0,192 m.s                                  (3)
                     Δt  25  0 

4.4.3   Tydinterval: 0 tot 25 s en 450 s tot 510 s                                (2)
                                                                                    [17]

                                               3

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                                                             FISIESE WETENSKAPPE
                                  MEMORANDUM
                                                         (VRAESTEL 1)       GRAAD 10

VRAAG 5

5.1   Die energie wat 'n voorwerp het as gevolg van sy vertikale hoogte bo die
      aarde.                                                                   (2)

5.2   Ep = mgh
      Ep = 1 (9,8) 35
      Ep = 343 J                                                                (3)

5.3   In 'n geslote/geïsoleerde stelsel bly die totale meganiese energie
      konstant/word dit behou                                                  (2)

5.4   Emec (x) = Emec (y)

      (Ep + Ek) x = (Ep + Ek) y                                     

      (mgh + ½ mv2) x = (mgh + ½ mv2) y

      343 + 0  = 0 + ½ (1) v2

      v = 26,19 m.s-1
                                                                                 (4)
                                                                                 [11]

                                              4

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                                                                 FISIESE WETENSKAPPE
                                    MEMORANDUM
                                                             (VRAESTEL 1)       GRAAD 10

VRAAG 6

6.1   NEGATIEWE NASIEN

      Verwyder 
      Dit het 'n positiewe lading.                                                (3)

6.2   6.2.1 Elke lading in die heelal is 'n heelgetal veelvoud van die elementêre
            lading.                                                               (2)

      6.2.2           𝑄𝑛𝑒𝑡
              QNuut = 2 

              QNuut = (9 x 10-9 + 0) / 2 

              QNuut = 4,5 x 10-9 C                                                 (3)

      6.2.3 n = ∆𝑄 
                 𝑒

              n = (4,5 x 10-9 - 0)  / 1,6 x 10-19

              n = 2,8125 x 1010 elektrone

              OF
                  ∆𝑄
              n= 𝑒 
              n = (4,5 x 10-9 - 9 x 10-9)  / 1,6 x 10-19

              n = 2, 8125 x 1010 elektrone                                         (4)
                                                                                    [12]

                                                 5

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                                                           FISIESE WETENSKAPPE
                                   MEMORANDUM
                                                       (VRAESTEL 1)       GRAAD 10

VRAAG 7

7.1   'n Lading van 5 C gaan deur 'n punt per tydseenheid of in een
      sekonde.                                                                (2)

7.2   1         1       1
         = 𝑅1 + 𝑅2
      𝑅𝑝

      1      1      1
           = 4 + 6
      𝑅𝑝

      1      12
           = 5
      𝑅𝑝

      Rp = 2,4 Ω
                                                                                (3)

7.3   IT = I 2 + I 3 

      5 = 3 - I3

      I3 = 2 A                                                                 (3)

7.4         𝑊
      V= 𝑄 
      12 = W / 1 
      W = 12 J                                                                 (3)
                                                                                [11]

                                                                      TOTAAL:   80

                                            6

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