# Physical Sciences Grade 10 P1 2018 Memo (Afr)

> Grade 10 Physical Sciences Paper 1 memorandum from the Mpumalanga National Exemplar Exam (NSC) 2018 (Afrikaans), 12 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr10-phy-p1-english-and-afrikaans-november-2018-possible-answers/e4bf4b62-fd9c-442e-9e5d-35fa0a2b6706
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 10
- Language: Afrikaans
- Document type: Memorandum
- Year: 2018
- Exam period: Mpumalanga National Exemplar Exam (NSC)
- Paper: 1
- Curriculum: CAPS
- Pages: 12

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## About this document

Physical Sciences · Grade 10 · Mpumalanga National Exemplar Exam (NSC) · 2018 · Afrikaans. Memorandum, 12 pages. Read online or download the PDF.

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## Document text

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### Page 1

NATIONAL
                                 SENIOR CERTIFICATE/
                                     NASIONALE
                                 SENIOR SERTIFIKAAT

                                    GRADE/GRAAD 10

                        PHYSICAL SCIENCES: PHYSICS (P1)
                        FISIESE WETENSKAPPE: FISIKA (V1)

                                        NOVEMBER 2018

                      MARKING GUIDELINES/NASIENRIGLYNE

   MARKS/PUNTE: 150

                        These marking guidelines consist of 12 pages.
                         Hierdie nasienriglyne bestaan uit 12 bladsye.

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### Page 2

Physical Sciences P1/Fisiese Wetenskappe V1    2                                DBE/November 2018
                   CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne

QUESTION 1/VRAAG 1

1.1     C

1.2     C

1.3     A

1.4     A

1.5     C

1.6     A

1.7     B

1.8     B

1.9     C

1.10    C/B
                                                                                                        [20]

QUESTION 2/VRAAG 2

2.1     The difference in position (in space). /Die verskil in posisie in ruimte.

        OR/OF

        The change in position (of an object.)/Die verandering in posisie van 'n
        voorwerp.                                                                                       (2)

2.2     12 m west/wes or/of -12 m 

        IF/INDIEN
        – 12 m West/Wes                  (Award 1 mark only/Ken 1 punt toe)

        Accept/Aanvaar
        12 m left/links                                                                               (2)

2.3         ∆x
        v=
             ∆t
             5 
          =
            30 
          = 0,17 m·s-1 west/wes 

        Accept/Aanvaar
             
        0,17 m·s-1 left/links                                                                         (4)

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### Page 3

Physical Sciences P1/Fisiese Wetenskappe V1    3                                DBE/November 2018
                   CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne

2.4      POSITIVE MARKING FROM 2.2 and 2.3/POSITIEWE NASIEN VANAF
         2.2.en2.3
                   dis tan ce           afs tan d
         Speed =              / Spoed =
                     time                  tyd
                                  -1
         (0,17)(2)  = 0,34 m·s

                     12
           0,34  =      
                      ∆t
         Δt = 35,29 s                                                                                   (4)
                                                                                                        [12]

 QUESTION 3/VRAAG 3

 3.1       Motion with uniform velocity: Motion at constant velocity. / Motion with
           zero or no acceleration.
           Beweging met uniforme snelheid: Beweging teen konstante snelheid./
           Beweging met nul of geen vernselling.
           Uniform accelerated motion: Motion with constant acceleration./Velocity
           changes with the same amount during each time interval. /Motion during
           which the velocity changes with a constant amount per unit time. /
           Uniforme       versnelde    beweging:      Beweging     met     konstante
           versnelling/Snelheid verander met dieselfde hoeveelheid gedurende elke
           tydinterval/Beweging waartydens die snelheid met 'n konstante hoeveelheid
           per eenheid tyd verander.                                                                    (4)

 3.2.1     Motion with uniform velocity/Beweging met uniforme snelheid                                 (1)

 3.2.2     Uniform accelerated motion /Uniforme versnelde beweging                                     (1)

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### Page 4

Physical Sciences P1/Fisiese Wetenskappe V1    4                                DBE/November 2018
                  CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne

3.3

                                                                             ●

                         30

                                                                          3.5 
                         25

                                                                  ●

  Position/Posisie (m)
                         20

                         15

                                                        ●
                         10

                                              ●
                         5
                                    ●

                         0
                              0    1,5        3        4,5        6          7,5       9
                                                              time/tyd (s)
                         MARKING GUIDELINES/NASIENRIGLYNE
                          x-axis and units correctly labelled/x-as en eenhede korrek gemerk
                          y-axis and units correctly labelled/y-as en eenhede korrek gemerk
                          2 points correctly plotted and joined/2 punte korrek gestip en verbind
                          shape of the graph (0 – 3 s/vorm van die grafiek(0 – 3s) / straight line/reguitlyn
                          shape of graph 3 – 7,5 s curved / vorm van grafiek 3 – 7,5 s kurwe / tangent /raaklyn

                                                                                                                         (5)

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### Page 5

Physical Sciences P1/Fisiese Wetenskappe V1    5                                DBE/November 2018
                  CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne

3.4       Instantaneous velocity: rate of change in position. /Oombliklike snelheid:
          tempo van verandering in posisie.

          OR/OF
          Displacement divided by a very small time interval. /Verplasing gedeel
          deur 'n baie klein tydinterval.

          OR/OF
          Velocity at a particular time. /Snelheid op 'n spesifieke tyd.                             (2)

3.5       Refer to the graph./Verwys na die grafiek.
          (Tangent to the curve/ Raaklyn aan kurwe)                                                    (2)

3.6           ∆x
          v=
              ∆t
               6−0 
            =
               3−0 
            = 2 m·s-1 right/regs                                                                      (4)
                                                                                                       [19]

QUESTION 4/VRAAG 4

4.1       The rate of change of velocity. /Die tempo van verandering van snelheid.                   (2)

4.2.1     v f =v i + aΔt 
          0 = 15 + (-4,5)Δt 
          Δt = 3,33 s 

          OR/OF
          v f =v i + aΔt 
          0 = -15 + (4,5)Δt 
          Δt = 3,33 s                                                                                 (4)

4.2.2    OPTION 1/OPSIE 1
         v f 2 = v i 2 + 2aΔx 
         02 = 152 + 2(-4,5)Δx 
         Δx = 25 m 

         OPTION 2/OPSIE 2
         POSITIVE MARKING FROM 4.2.1/POSITIEWE NASIEN VANAF 4.2.1
               v + vi 
         Δx =  f        Δt 
               2 
               0 + 15 
            =          (3,33)
               2 
             = 24,98 m 

         OPTION 3/OPSIE 3
         POSITIVE MARKING FROM 4.2.1/POSITIEWE NASIEN VANAF 4.2.1
         Δx = v i Δt + ½ aΔt2 
            = (15)(3,33) + ½ (-4,5)(3.33)2
         Δx = 25 m                                                                                    (4)

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### Page 6

Physical Sciences P1/Fisiese Wetenskappe V1    6                                DBE/November 2018
                  CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne

4.3      OPTION 1/OPSIE 1
         v f 2 = v i 2 + 2aΔx 
         02 = 302 + 2(-4,5)Δx 
         Δx = 100 m 

         Car B has a larger stopping distance (100 m > 25 m) /Kar B het 'n groter
         stopafstand (100 m > 25 m).

         OPTION 2/OPSIE 2
         v f = v i + aΔt 
         0 = 30 + (-4,5)Δt
         Δt = 6,67 s

         Car B it takes longer to stop hence larger stopping distance / Kar B dit
         neem langer om tot stilstand te kom dus 'n groter stopafstand

         IF/INDIEN
         Car B  it has a higher velocity than car A and therefore have a larger
         stopping distance at the same acceleration  Max: (2/6)
         Kar B dit het 'n hoër snelheid as kar A en het dus 'n groter stopafstand met
         dieselfde versnelling Maks: (2/6)                                                                   (6)

4.4       The greater/larger the speed, the larger the stopping distance  if
          acceleration is constant. /Hoe groter die spoed, hoe groter die stopafstand                        (2)
          indien versnelling konstant is.                                                                    [18]

QUESTION 5/VRAAG 5

5.1       The energy an object has because of its position in the gravitational field
           relative to some reference point.  /Die energie wat 'n voorwerp het as
          gevolg van die posisie daarvan in die gravitasieveld relatief tot 'n sekere
          verwysingspunt.                                                                                    (2)

5.2       E p = mgh
              = (65)(9,8)(4,5)
              = 2 866,5 J                                                                                   (3)

5.3       The net/total mechanical energy (sum of kinetic and gravitational potential
          energy)      in an isolated/closed system remains constant/ is
          conserved./Die netto/totale meganiese energie in 'n geïsoleerde/geslote
          sisteem bly konstant/bly konstant.                                                                 (2)

5.4                (E p + E k ) top/bo = (E p + E k ) bottom/onder
                         mgh + 0 = mgh + ½mv2                      
                                                       2
               (65)(9,8)(4,5)= 0 + ½(65)v 
                                  v = 9,39 m∙s-1 
          OR/OF
          (E p + E k ) top/bo = (E p + E k ) bottom/onder
                         mgh + 0 = mgh + ½mv2                 
                                         2
          2 866,5  = 0 + ½(65)v 
                       v = 9,39 m∙s-1                                                                       (4)

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### Page 7

Physical Sciences P1/Fisiese Wetenskappe V1    7                                DBE/November 2018
                  CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne

5.5       OPTION 1/OPSIE 1
                  (E p + E k ) top/bo = (E p + E k ) bottom/onder
                   mgh + 0 = mgh + ½mv2                           
                                                             2
           (65)(9,8)h  + 0 = 0 + ½ x 65 x (9,39) 
                              637 h = 2 865,6
                                    h = 4,49 m

          No/Nee. h = 4,49 m < 6 m
          OPTION 2/OPSIE 2
          E p at Y = mgh 
                  = (65)(9,8)(6)
                  = 3 822 J

          E mech < E p at Y therefore he will not reach point Y / E meg <E p by Y daarom
          sal hy nie punt Y bereik nie                                                                       (5)
                                                                                                            [16]

QUESTION 6/VRAAG 6

6.1              Difference/Verskil                   Similarity/Ooreenkoms
           Amplitudes                             Wavelength/Golflengte
                                                   Period/Tydperk
                                                   Frequency/Frekwensie
                                                   Transverse/Transversaal
                                                   (Any one)/(Enige een)                                     (2)

6.2.1     A and/en B

          OR/OF
          C and/en D

          OR/OF
          B and/en C

          OR/OF
          A and/en D                                                                                        (1)

6.2.2     15 (mm)                                                                                          (1)

6.3       The number of waves/wave pulses passing a point per second. /Die getal
          golwe/golfpulse wat per sekonde by 'n punt verby beweeg.                                          (2)

6.4.1         1
          f=    
              T
               1
            =     
              1,5
            = 0,67 Hz                                                                                      (3)

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### Page 8

Physical Sciences P1/Fisiese Wetenskappe V1    8                                DBE/November 2018
                  CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne

6.4.2       POSITIVE MARKING FROM 6.4.1             OPTION 2/OPSIE 2
            POSITIEWE NASIEN VANAF 6.1                 ∆x                 dis tan ce
            OPTION 1/OPSIE 1                        v=      or/of speed =            
                                                        ∆t                  time
            v = fλ                                    0,1
              = (0,67)(0,1)                         =     
                                                       1,5
              = 0,067 m·s-1 
                                                     = 0,067 m·s-1                                      (3)
                                                                                                       [12]

QUESTION 7/VRAAG 7

7.1.1       What is the relationship between the speed of sound and temperature? /
            Wat is die verband tussen die spoed van klank en temperatuur?

            OR/OF
            How will the temperature affect the speed of sound? /Hoe sal die
            temperatuur die spoed van klank beïnvloed?

            OR/OF
            What is the relationship between the time taken for the sound to travel and
            temperature? / Wat is die verband tussen die spoed van klank en
            temperatuur?                                                                               (2)
            Marking criteria/Nasienriglyne:
            Dependent and independent variables correctly identified.         
            Afhanklike en onafhanklike veranderlikes korrek geïdentifiseer.
        -
            Ask a question about the relationship between the independent and
            dependent variables./Vra 'n vraag oor die verwantskap tussen die 
            afhanklike en onafhanklike veranderlikes.

7.1.2       Temperature /Temperatuur                                                                  (1)
7.1.3       Speed of sound/Time taken for the sound to travel./Spoed van klank/Tyd
            geneem vir die klank om te beweeg.                                                         (1)

7.2            ∆x                  dis tan ce
            v=       or/of speed =            
                ∆t                   time
                 50
             =       
               0,146
             = 342,47 m·s-1                                                                           (3)

7.3         The speed of sound increases / time taken for the sound to travel decreases /
            as the temperature increases. /Die spoed van klank neem toe / tyd
            geneem vir die klank om te beweeg neem af soos die temperatuur toeneem.                    (2)

7.4         Echo/Eggo                                                                                  (1)
                                                                                                       [10]
QUESTION 8/VRAAG 8

8.1         Accelerating charges /Versnelde ladings                                                   (1)

8.2         Gamma rays /Gammastrale                                                                   (1)
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Physical Sciences P1/Fisiese Wetenskappe V1    9                                DBE/November 2018
                  CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne

8.3       It has the highest frequency Energy is directly proportional to frequency /
          Eαf/
          Dit het die hoogste frekwensie. Energie is direk eweredig aan die frekwenie/
          Eαf                                                                                              (2)

8.4.1     OPTION 1/OPSIE 1                  OPTION 2/OPSIE 2
          c = fλ                               hc
                                            E=
          3 x 108 = f(600 x 10-10)              λ
          f = 5 x 1015 Hz                      (6,63 × 10 −34 )(3 × 10 8 )
                                              =                                    Any one
          Ultraviolet /Ultraviolet                   600 × 10 −10                   Enige een
                                              = 3,315 x 10-18 J

                                            E = hf
                                            3,315 x 10-18 = (6,63 x 10-34)f
                                            f = 5x 1015 Hz 

                                            Ultraviolet /Ultraviolet                                      (4)

8.4.2     POSITIVE MARKING FROM 8.4.1/POSITIEWE NASIEN VANAF 8.4.1
          Sterilisation of medical equipment./ Sterilisasie van mediese toerusting
          Suntan beds /Sonbeddens
          Security in currency/Veiligheid in valuta
          Astronomy/ Astronomie
          (Any one/Any relevant use/Enige een/Enige relevante gebruik)                                     (1)
                                                                                                           [9]

QUESTION 9/VRAAG 9

9.1       Ferromagnetic (material) /Ferromagneties (materiaal)                                            (1)

9.2       B                                                                                               (1)

9.3       South /Suid                                                                                     (1)

9.4
               N    S                   S       N              S

                X                           Y                  B
                                                      
          OR/OF
          Magnets X repels Y/ South pole /Magneet X stoot Y af / Suidpool

          Magnet Y attracts B/ South pole at B /Magneet Y trek B aan / Suidpool by B                      (2)

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### Page 10

Physical Sciences P1/Fisiese Wetenskappe V1   10                                DBE/November 2018
                  CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne

9.5

                                       Marking criteria/Nasienkriteria
                Correct direction of field lines/Korrekte rigting van veldlyne     
                Shape of the magnetic field/Vorm van die magneetveld               
                No field lines crossing each other/Geen veldlyne kruis             
                mekaar nie.                                                                            (3)

9.6.1     Less than 5 cm / Minder as 5 cm                                                             (1)

9.6.2     Magnitude of magnetic force is inversely proportional to the distance.  B, is
          no longer attracting Y to the right 
          Grootte van magnetiese krag is omgekeerd eweredig aan die afstand. B, trek
          nie meer Y na regs aan nie

          OR/OF
          A decrease in distance increases the magnetic force. B, is no longer
          attracting Y to the right 
          'n Afname in afstand laat die magnetiese krag toeneem, B, trek nie meer Y
          na regs aan nie                                                                               (2)
                                                                                                       [11]

QUESTION 10/VRAAG 10

10.1          Q            Q
          n=      or/of
               e          qe
                      Q
          30 =                 
                − 1,6 × 10 −19
          Q = -4,8 x 10-18 C 

          Accept/Aanvaar
              Q            Q
          n=      or/of
               e           qe
                     Q
          30 =               
                1,6 × 10 −19
          Q = 4,8 x 10-18 C                                                                           (3)

10.2      Unlike/opposite charges attract/Ongelyksoortige/teenoorgestelde ladings
          trek mekaar aan.                                                                             (2)

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### Page 11

Physical Sciences P1/Fisiese Wetenskappe V1   11                                DBE/November 2018
                  CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne

10.3      The net/total charge in an isolated/closed system remains constant/is
          conserved Die netto/totale lading in 'n geïsoleerde/geslote sisteem
          bly konstant.                                                                                (2)
          NOTE/LET WEL:
          If any of the underlined words/phrases are omitted in the correct context:
          minus 1 mark.)
          Indien enige van die onderstreepte woorde/frases in die korrekte konteks
          weggelaat is: minus een punt.)

10.4      POSITIVE MARKING FROM 10.1/POSITIEWE NASIEN VANAF 10.1
                        Q + Q2
          Q net/netto = 1          
                            2
                                                       
                         4 × 10 −18 + ( −4,8 × 10 −18 )
                      =
                                       2
                      = -4 x 10-19 C                                                                   (4)
                                                                                                       [11]

QUESTION 11/VRAAG 11

11.1.1    (a)   V 1 = 24 (V)                                                                          (1)

          (b)   A 1 = 0 (A)                                                                           (1)

11.1.2    OPTION 1/OPSIE 1                    OPTION 2/OPSIE 2
           1    1   1                              product / produk
             =    +                          Rp =                  
          R p R1 R 2                                   sum / som
               1 1                                 (8)(8)
             = +                                =        
               8 8                                  8+8
          Rp = 4 Ω                               =4Ω

          RT = Rs + Rp                        RT = Rs + Rp
             = 8 + 4                            = 8 + 4
             = 12 Ω                             = 12 Ω                                               (4)

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### Page 12

Physical Sciences P1/Fisiese Wetenskappe V1   12                                DBE/November 2018
                  CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne

11.1.3    OPTION 1/OPSIE 1
          V divides in a ratio 8 : 4  (series)/V verdeel in 'n verhouding 8 : 4 (serie)
                 8                      2
          V2 =     x 24 or/of V 2 = x 24
                12                      3
             = 16 V 

          OPTION2 / OPSIE 2
          POSITIVE MARKING FROM 11.1.2/POSITIEWE NASIEN VANAF 11.2.1
          V = IR
          24 = I(12)
          I=2A

          V = IR
            = (2)(8)
            = 16 V                                                                                 (3)

11.1.4    A2 = A3 .                                                                                (1)

11.2.1    Resistance is directly proportional to the length of the conducting wire. /
          Weerstand is direk eweredig aan die lengte van die geleidingsdraad.

          OR/OF

          As the length of the wire increases, the resistance increases./Soos die lengte
          van die geleidingsdraad toeneem, neem die weerstand toe                                   (1)

11.2.2    1,35 Ω        (Range/Variasiewydte: 1,3 Ω to/tot 1,4 Ω)                                   (1)
                                                                                                    [12]

                                                                          TOTAL/TOTAAL:             150

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- [Gr10 Phy P2 (English and Afrikaans) June 2018 Possible Answer](https://www.hlayiso.com/library/gr10-phy-p2-english-and-afrikaans-june-2018-possible-answer/90de8ad3-d5d4-4736-8702-c5ba535b10d1) — Physical Sciences · Memo · 2018 · Afr

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- [Grade 10 past papers](https://www.hlayiso.com/grade-10/past-papers)

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