# Mathematics Grade 11 P2 Gauteng June 2018 Memo (Afrikaans)

> Grade 11 Mathematics Paper 2 memorandum from the Gauteng June 2018 (Afrikaans), 9 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr11-math-p2-afrikaans-june-2018-possible-answers/01135fce-dccc-4b5d-ad21-e3d5045563e4
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 11
- Language: Afrikaans
- Document type: Memorandum
- Year: 2018
- Exam period: Gauteng June
- Paper: 2
- Curriculum: CAPS
- Pages: 9

Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 11](https://www.hlayiso.com/library/grade-11) › [Mathematics](https://www.hlayiso.com/library/grade-11/mathematics) › [Mathematics Grade 11 P2 Gauteng June 2018 Memo (Afrikaans)](https://www.hlayiso.com/library/gr11-math-p2-afrikaans-june-2018-possible-answers/01135fce-dccc-4b5d-ad21-e3d5045563e4)

## About this document

Mathematics · Grade 11 · Gauteng June · 2018 · Afrikaans. Memorandum, 9 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

Text extracted from the PDF. Layout, diagrams and tables may not survive extraction.

### Page 1

Downloaded from hlayiso.com

            GAUTENGSE DEPARTMENT VAN ONDERWYS
                   PROVINSIALE EKSAMEN
                        JUNIE 2018
                        GRAAD 11

                        WISKUNDE

                       VRAESTEL 2

                     MEMORANDUM

9 bladsye

                            1

### Page 2

Downloaded from hlayiso.com
                                               MEMORANDUM                 WISKUNDE Vraestel 2
                                                                               Graad 11

                        GAUTENGSE DEPARTEMENT VAN ONDERWY
                                     PROVINSIALE EKSAMEN

                                                                WISKUNDE Vraestel 2

                                         MEMORANDUM

INSTRUKSIES EN INLIGTING:

A      – Akkuraatheid
C.A.   – Deurlopernde Akkuraatheid
S      – Stelling
R      – Rede
SR     – Stelling en Rede

NOTA:

      Indien ŉ kandidaat ŉ vraag TWEE MAAL beantwoord het, merk slegs die eerste poging.

      Indien ŉ kandidaat ŉ antwoord DOODGETREK het, maar dit nie oorgedoen het nie, merk die
       doodgetrekte antwoord.

      Volgehoue akkuraatheid word in ALLE aspekte van die memorandum toegepas.

      Om antwoorde / waardes om ŉ probleem op te los, te veronderstel, word NIE toegelaat NIE.

                                                 2

### Page 3

Downloaded from hlayiso.com
                                                  MEMORANDUM       WISKUNDE Vraestel 2
                                                                        Graad 11

      VRAAG 1                                                                  [25]
1.1

                                                                vervang in korrekte formule
              =
              =-4                                               antwoord
                                                                                               (2)

1.2

                                                                vervang in korrekte formule
      F(
      F( 3; -2)                                                 antwoord

                                                                                               (2)
1.3

                  =
                                                                      =

                                                                korrek vervang in reguitlyn verg.

                                                                antwoord
                                                                                               (3)

1.4
                                                               

                                                               

      Verw.           = 75,9                                    Verw.      = 75,9

                  =                                               =

      ̂                   ........buite   van ∆
          =                                                     antwoord
                                                                                               (5)

                                                   3

### Page 4

Downloaded from hlayiso.com
                                    MEMORANDUM       WISKUNDE Vraestel 2
                                                          Graad 11

1.5

                                                 

                                                 

                                                 

                                                 antwoord
                                                                             (4)

1.6
      T(1 ; – 7)                                 x=1
                                                 y = – 7
                                                                             (2)

1.7
      Midpt. van BT (                             korrekte vervanging
                     (3 ; -2)
      Ook die midpt. van AC                      gevolgtrekking
                                                                             (2)

1.8                                               korrekte vervanging
      AB  √                                       AB = √
        = √
      BC √                                        BC = √
        = √
                                                  omtrek van ABCT = 29,14
      Omtrek van ABCT = 2( √    √
                       = 29,14
      Omtrek van LMNO = 2 29,14                  antwoord
                  = 58,28                                                    (5)

                                     4

### Page 5

Downloaded from hlayiso.com
                                                  MEMORANDUM       WISKUNDE Vraestel 2
                                                                        Graad 11

        VRAAG 2                                                                [26]

2.1.1
        k= √                 ..... Teorie van Pyth.            enige relevante weergawe van
        k=–4                                                    Pythagoras
                                                               antwoord
                                                                                          (2)
2.1.2                                                           antwoord
                                                                                          (1)

2.1.3                                                          
        =
        =                                                       antwoord
                                                                                          (2)

2.1.4                                                           Verw.       = 36,87

        Verw.          = 36,87                                 143,13
                                                                                          (2)

2.2

                   √      ...Teorie van Pyth.                           √

        B( √       ; 3)                                         B( √    ; 3)

                                                                korrekte vervanging.

                                                                antwoord
                                                                                          (4)
               √                 √
        = (        )         (       )

        =0

                                                      5

### Page 6

Downloaded from hlayiso.com
                              MEMORANDUM       WISKUNDE Vraestel 2
                                                    Graad 11

2.3

                                           
                                           
                                           

                                           
                  √

          √
      –
                                            antwoord
                                                                     (5)
2.4   LK =

                                           
      =

      =                                    

      =                                    
      =
      = tan x = RK                         
                                                                     (4)

2.5

                                           
                                   Z            Z

                                           

                                           
              {                        }
                                            alle waardes korrek
                                           OF
                                            3 of 4 waardes korrek

                                                                     (6)

                               6

### Page 7

Downloaded from hlayiso.com
                              MEMORANDUM          WISKUNDE Vraestel 2
                                                       Graad 11

        VRAAG 3                                            [14]

3.1
                                            vorm van f
                        𝑦                   korrekte draaipunte van f

                                             korr. x en y afsnitte van f

                                            vorm van g

                                            korrekte draaipunte van g
                                        𝑥
                                            korr. x en y afsnitte van g
                                      180

                                                                            (6)

3.2.1                                       –1
              [    ]                        1
                                                                            (2)
3.2.2   360                                 antwoord
                                                                            (1)
3.2.3   3                                   antwoord
                                                                            (1)
3.3                                         45
                                             korr.hakies / ongelykhede
                                                                            (2)
3.4                                         
                                            +1
                                                                            (2)

                               7

### Page 8

Downloaded from hlayiso.com
                                                MEMORANDUM          WISKUNDE Vraestel 2
                                                                         Graad 11

        VRAAG 4                                                           [12]

4.1.1   Loodreg                                               antwoord                (1)

4.1.2   Twee maal                                             antwoord                (1)

4.2.1   B ̂ A = 90°               (∠ in ŉ semi-sirkel)        S
                                                              R                       (2)
(a)        AC = √              (Pythagoras Teorie)            middellyn =10
           AC = √
           AC = 6                                             AC = 6
              AM = 3                                          AM = 3
            (lyn vananf middel van sirkel  tot koord
        die koord halveer OF middelpunt stelling)             Stelling (lyn vananf middel
                                                               van sirkel  tot koord
                                                               die koord halveer OF
                                                               middelpunt stelling)

                                                                                       (4)
(b)     OM = √           (Phyth. OF Midpt.St.)
        OM = 4                                                OM = 4
        Oppvl  AOM : Oppvl  ABC
                                                              vervang oppvl van  AOM
               . 4. 3 :        . 8. 6                          en  ABC
                      6 : 24                                  oppvl  AOM = 6 en oppvl
                      1:4                                       ABC = 24
                                                              beide korrekte
                                                               vereenvoudigde antwe.
                                                                                     (4)

                                                   8

### Page 9

Downloaded from hlayiso.com
                                                  MEMORANDUM             WISKUNDE Vraestel 2
                                                                              Graad 11

         VRAAG 5                                                               [4]

5.1      ̂    ̂          ̂ (hoeke in selfde segment)              R
         Maar ̂           ̂                                       R

             ̂       ̂     ̂ hoeke teenoor = sye)

                                                                                              (2)
5.2      ̂       ̂       ̂ (hoeke in selfde segment)              R

             ̂       ̂     ̂      ̂                                     ̂     ̂      ̂   ̂

                     gelykbenig                                                               (2)

         VRAAG 6                                                               [19]

6.1      A ̂ C = 104°          (Ko-binne ∠’e OC || AB )           A ̂ C = 104°
         Refleks AÔC = 2B
                      = 208° (middpts∠ =2x ∠ op omtrek)
                                                                  refleks AÔC = 208°
         Stomp ∠ A ̂ C = 152°
                         x = 28° (ko-binne ∠’e OC || AB)
                                                                  stomp L AÔC = 152°
                                                                  x = 28
                                                                  rede
                                                                                              (5)
6.2.1.   ̂1=x                     (∠’ e teenoor = sye/ radii)       S( ̂ 1 = x)
                                                                    R (∠’ e teenoor =sye)
         ̂ 1 = 180° - 2x          (som van∠e in QRO)               S( ̂ 1 = 180° - 2x )
                                                                    R(som van∠ s in QRO)
         ̂ 1 = 90° - x            (mdpts ∠ = 2 x ∠ op omtrek.)      ̂ 1 = 90° - x
                                                                     S
                                                                    R(mdpts ∠ = 2 x ∠ op
                                                                     omtrek.)
                                                                                              (7)

6.2.2.     PQ = QR              (gegee)
         Q ̂ P = 90° - x         (∠ teenoor = sye in  )              S (PQ = QR)
         P ̂ R = 2x              (∠ som in PQR )                     S (Q ̂ P = 90° - x )
         x + ̂ 2 = 2x                                              R (∠ teenoor = sye in  )
           ̂2 = x                                                    S (P ̂ R = 2x )
         TQ halveer PQR                                               (∠ som van PQR)
                                                                      x + ̂ 2 = 2x
                                                                       ̂2 = x
                                                                                              (7)
                                                                                   TOTAAL : 100

                                                    9

## Related documents

- [Gr11 Math P2 (Afrikaans) June 2018 Question Paper Errata](https://www.hlayiso.com/library/gr11-math-p2-afrikaans-june-2018-question-paper-errata/f8b25236-b390-468d-a38e-7bca697a99b0) — Mathematics · Errata · 2018 · Afr
- [Gr11 Math P2 June 2018 Possible Answers](https://www.hlayiso.com/library/gr11-math-p2-june-2018-possible-answers/c2aaf619-cabd-4c3b-9635-b0b14fdfcb00) — Mathematics · Memo · 2018
- [Gr11 Math P1 (Afrikaans) November 2017 Question Paper](https://www.hlayiso.com/library/gr11-math-p1-afrikaans-november-2017-question-paper/b933e467-3a29-4cbf-8117-6b05a4fc5378) — Mathematics · QP · 2018 · Afr
- [Gr11 Math P2 (English and Afrikaans) November 2018 Answer Book](https://www.hlayiso.com/library/gr11-math-p2-english-and-afrikaans-november-2018-answer-book/fbd125bb-cb12-4a9d-b0ad-c96a47b5e035) — Mathematics · Addendum · 2018 · Afr
- [Gr11 Math P2 June 2018 Question Paper Errata](https://www.hlayiso.com/library/gr11-math-p2-june-2018-question-paper-errata/c33250f1-b917-4589-ae55-a60bdee9309d) — Mathematics · Errata · 2018
- [Gr11 Math P1 (Afrikaans) June 2017 Possible Answers](https://www.hlayiso.com/library/gr11-math-p1-afrikaans-june-2017-possible-answers/b8504619-0cb6-476d-944d-f53d2ea22f72) — Mathematics · Memo · 2017 · Afr

## More from Grade 11 Mathematics

- [FS Maths Grade 11 June 2025 P1 only](https://www.hlayiso.com/library/fs-maths-grade-11-june-2025-p1-only/82015d8f-bcc0-478e-ad47-d3b295dabb01) — QP · 2025
- [FS Maths Grade 11 June 2025 P2 only](https://www.hlayiso.com/library/fs-maths-grade-11-june-2025-p2-only/5d0e7dd8-cb37-419c-8fe2-0aee27fbdc84) — QP · 2025
- [KZN Maths Grade 11 November 2025 P2 and Memo](https://www.hlayiso.com/library/kzn-maths-grade-11-november-2025-p2-and-memo/a2aac931-a969-41c8-bde2-85d23035d042) — QP + Memo · 2025
- [MATHS P2 ANSWER BOOK GR11 2024 ENG AFR D watermark](https://www.hlayiso.com/library/maths-p2-answer-book-gr11-2024-eng-afr-d-watermark/91fd4f6b-a252-4d30-b6b1-f8f546015336) — Addendum · 2024 · Afr
- [Gr 11 Mathematics P1 (Afrikaans) June 2024 Question Paper](https://www.hlayiso.com/library/gr-11-mathematics-p1-afrikaans-june-2024-question-paper/1a0f4a9d-f18a-4aca-af77-5a81acfb8e0c) — QP · 2024 · Afr
- [Gr 11 Mathematics P2 (Afrikaans) June 2024 Question Paper](https://www.hlayiso.com/library/gr-11-mathematics-p2-afrikaans-june-2024-question-paper/4934c5d3-e2a1-4d6b-acf6-d00e0623d46d) — QP · 2024 · Afr

## Collection

- [Grade 11 past papers](https://www.hlayiso.com/grade-11/past-papers)

---

Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.
