# Mathematics Grade 11 P2 National Exemplar November 2017 Memo

> Grade 11 Mathematics Paper 2 memorandum from the National Exemplar November Exam 2017 (Afrikaans), 19 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/gr11-math-p2-english-and-afrikaans-november-2017-possible-answers/32da1b44-d4a7-40a5-9c5c-f90677df6a8b
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 11
- Language: Afrikaans
- Document type: Memorandum
- Year: 2017
- Exam period: National Exemplar November Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 19

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## About this document

Mathematics · Grade 11 · National Exemplar November Exam · 2017 · Afrikaans. Memorandum, 19 pages. Read online or download the PDF.

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### Page 1

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                                             NATIONAL
                                        SENIOR CERTIFICATE
                                            NASIONALE
                                        SENIOR SERTIFIKAAT

                                         GRADE/GRAAD 11

                             MATHEMATICS P2/WISKUNDE V2

                                          NOVEMBER 2017

                       MARKING GUIDELINES/NASIENRIGLYNE

MARKS/PUNTE: 150

                            These marking guidelines consist of 19 pages.
                             Hierdie nasienriglyne bestaan uit 19 bladsye.

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Mathematics P2/Wiskunde V2                       2                                  DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

NOTE:
• If a candidate answered a question TWICE, mark only the FIRST attempt.
• If a candidate crossed out an answer and did not redo it, mark the crossed-out answer.
• Consistent accuracy applies to ALL aspects of the marking guidelines.
• Assuming values/answers in order to solve a problem is unacceptable.

LET WEL:
• As 'n kandidaat 'n vraag TWEE keer beantwoord het, sien slegs die EERSTE poging na.
• As 'n kandidaat 'n antwoord deurgehaal en nie oorgedoen het nie, sien die deurgehaalde
   antwoord na.
• Volgehoue akkuraatheid is op ALLE aspekte van die nasienriglyne van toepassing.
• Dit is onaanvaarbaar om waardes/antwoorde te veronderstel om 'n probleem op te los.

QUESTION/VRAAG 1

    10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66

 1.1.1   min = 12                                                                     min + max
         Q1 = 17                                                                      median, Q1 and/en Q3
         median / mediaan = 30                                                                          (2)
         Q3 = 38
         max = 65
 1.1.2   IQR = Q3 − Q1                                                                answer/antw
            = 38 − 17                                                                                       (1)
            = 21
 1.1.3 Skewed to the right OR positively skewed                                       answer/antw
       Skeef na regs       OF positief skeef                                                                (1)

    5     8        10     17       20    29      32      48     50     50      63       y        107

 1.2.1                         439 + y
         Mean/Gemiddeld =
                                  13
                               439 + y                                                        439 + y
                          41 =                                                        41 =
                                  13                                                            13
                     439 + y = 533
                                                                                      answer/antw
                           y = 94                                                                           (2)
 1.2.2   σ = 30,94                                                                    answer/antw
                                                                                                            (1)

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Mathematics P2/Wiskunde V2                       3                                  DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

 1.2.3       41 × 13 = 533
              6 × 18 = 108                                                           108
                                                                                      533 + 108 = 641
                                                                                      answer/antw
          533 + 108 641                                                                                   (3)
                   =    = 33,74
             19      19                                                                                  [10]

QUESTION/VRAAG 2

 2.1                                                                 CUMULATIVE
                AGE OF PERSON                                         FREQUENCY/
             SURVEYED/OUDERDOM          FREQUENCY/FREKWENSIE         KUMULATIEWE
            VAN PERSOON IN OPNAME                                     FREKWENSIE

                   20 < x ≤ 30                     7                       7
                   30 < x ≤ 40                    20                       27
                   40 < x ≤ 50                    25                       52
                   50 < x ≤ 60                    12                       64
                   60 < x ≤ 70                     8                       72                  20, 12
                   70 < x ≤ 80                     4                       76                  8, 4
                                                                                               52
                   80 < x ≤ 90                     4                       80                 76
                                                                                                            (4)
 2.2     n = 80                                                                               answ/antw
                                                                                                        (1)
 2.3     40 < x ≤ 50                                                                           answ/antw
                                                                                                        (1)

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Mathematics P2/Wiskunde V2                       4                                  DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

2.4
                                                                                     Ogive/Ogief
                                                 90                                                                                        Grounding (20; 0)
                                                                                                                                           /Geanker by (20; 0)

                                                 80                                                                                        upper limits/
                                                                                                                                           boonste limiete

                                                 70
                                                                                                                                            shape
                                                                                                                                            (smooth curve)/
                                                 60                                                                                        vorm

        Cumulative Frequency/Kumulatiewe Frekwensie
                                                                                                                                            (gladde kurwe)
                                                                                                                                                          (3)
                                                 50

                                                 40

                                                 30

                                                 20

                                                 10

                                                      0
                                                          0    10       20      30     40     50    60      70      80    90       100
                                                                    Age of person surveyed/Ouderdom van persoon in opname

 2.5   80 – 58 = 22                                                              Accept/aanvaar: 56 – 59 calls/oproepe                   58
       22                                                                                                                                calls/oproepe
          × 100 = 27,5%                                                                                                                  22
       80                                                                                                                                 27,5%
                                                                                                                                                    (3)
                                                                                                                                                  [12]

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Mathematics P2/Wiskunde V2                       5                                  DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

QUESTION/VRAAG 3

                                              y
                                                      C
                      B

                                                  T
                            15

                                                                                    x
                                         O

                                 A(−2 ; −5)                                        D

 3.1                 1                                                          Standard
         BD    y = − x+9                                                       form/vorm
                     2
                    1
         ∴ m BD = −
                    2
                                                                                answ/antw
         ∴ m AC = 2                                                                                   (2)
 3.2      y − y1 = m( x − x1 )
         y − (−5) = 2( x − (−2))                                                subst (–2 ; –5)
                                                                                answ/antw
                y = 2x −1                                                                             (2)
 3.3               1                                                                      1
         2x − 1 = − x + 9                                                       2x −1 = − x + 9
                   2                                                                      2
         5
           x = 10
         2
                                                                                x=4
         x=4

         y = 2(4) − 1
                                                                                y=7
         y=7
                                                                                                      (3)

         T (4 ; 7 )

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Mathematics P2/Wiskunde V2                       6                                  DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

 3.4.1       −2+ x
         4=
                2
         8 = −2 + x
                                                                                     x = 10
         x = 10

             −5+ y
         7=
                2
         14 = −5 + y                                                                 y = 19
         y = 19                                                                                           (2)

         C (10 ; 19 )
 3.4.2   AT =     (4 − (− 2))2 + (7 − (− 5))2                                        subst. in
                                                                                    distance/afstand
         = 180                                                                      form.
                                                                                     answer/antw
         =6 5

         BT 2 + AT 2 = AB 2          (Pythagoras )
                                                                                     subst. in pyth
         BT = 15 − 180  2
                            (    )
                                 2

                                                                                     answer/antw
         =3 5
                                                                                                          (4)
 3.4.3   BC is the diameter/ middellyn [subt. right / ondersp. reg ∠ ] or/of S
                                [conv.∠ in semi - circle/ omgk. ∠ in halfsirkel ]
                                        s                         s

                    15                                                               answ/antw
         Radius =      = 7,5 units/ eenh.
                     2                                                                                    (2)
                                                                                                         [15]

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Mathematics P2/Wiskunde V2                       7                                  DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

QUESTION/VRAAG 4

                                               B (4 ; 12)

                              E         O                                           C

                      A (–5 ; –3)

 4.1          12 − (−3) 5                                                             subst. in
        mAB =           =                                                            gradient form.
               4 − (−5) 3
                                                                                      answ/antw
        OR/OF
                                                                                                       (2)
              − 3 − 12 5
        mAB =         =
              −5−4 3

 4.2             5                                                                   equation/verg.
         y − 12 =   (x − 4)
                 3
                 5
        0 − 12 = ( x − 4 )                                                           y=0
                 3
              16
        x=−
               5
            16                                                                      answ/antw
        E −       ; 0
            5                                                                                        (3)

        OR/OF

        0 − 12 5                              0+3 5
               =                                     =                               equating/verg.
         x−4 3                                x+5 3                                  y=0
        − 36 = 5 x − 20                       9 = 5 x + 25
        − 16 = 5 x                            − 16 = 5 x
              − 16                                 − 16
         x=                                   x=                                      answ/antw
               5                                    5                                                  (3)
           16    
        E −   ; 0
           5     

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Mathematics P2/Wiskunde V2                       8                                  DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

 4.3    tan α = m AB                                                                           5
                                                                                   tan α =
                    5                                                                          3
        tan α =
                    3
                                                                                   α = 59ο
        α = 59 ο
                                                                                                          (2)

 4.4    76 ° + 59° =135° [ext ∠ of Δ]
                                                                                   135°
            BĈX =135°

         tan 135° = mBC                                                            tan 135ο = mBC
              mBC = −1 = m//                                                       answer/antw

                                                                                   subst (–3 ; –5)
          y − (− 3) = −1(x − (− 5))                                                answer/antw
                  y = −x − 8                                                                              (5)
                                                                                                         [12]

QUESTION/VRAAG 5

 5.1        sin(90o − x). cos(180o + x) + tan x. cosx. sin ( x −180o )             cos x
                                                                                   − sin x
                                sin x
            = cos x. (−cos x) +       . cos x . (− sin x)                          − cos x
                                cos x
                                                                                     sin x
                                                                                  
            = − cos 2 x − sin 2 x                                                    cos x
            = − (cos 2 x + sin 2 x)                                               common
            = −1                                                                  factor/gemene fakt.
                                                                                   identity/identiteit
                                                                                                          (6)
 5.2                                    o
                        sin 315°. tan 210 .sin190°
            LHS =                                                                  − sin45°
                             cos 100°.sin 120 o
                                                                                   tan30°
            =
                (− sin45°). (tan30o ).(− sin10°)                                   − sin10°
                      (− sin 10°).(sin 60o )                                       – sin10°
               1 1                                                                 sin 60°
                −  .                                                               subst. of special
            =   2    3                                                            angles/inverv. van
                  3                                                               sp hoeke
                 2
                2                                                                                         (6)
            =−
               3

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Mathematics P2/Wiskunde V2                       9                                  DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

                                                         y

                                                                        R

                                                     β       α
                                                         O          T          x

                                  P

 5.3.1          x2 + y2 = r 2         [Pythagoras]
                2       2     2                                                     subst in pyth
            ( x) + (3) = 5
                      x 2 = 16                                                     x=4
                        x=4
                          R (4 ; 3)
                            3                                                       answer/antw
                    tan α =
                            4                                                                           (3)
 5.3.2      sin β
            = sin (180 ο + α)                                                       β = 180° + α
                                                                                    − sinα
            = −sinα
              −3                                                                    answer/antw
            =
               5                                                                                        (3)

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Mathematics P2/Wiskunde V2                       10                                 DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

 5.3.3       y −3                                                                 y
               =                                                               
            10    5                                                              10
            y = −6                                                               −3
                                                                               
            ∴ x = −8                                                              5
                                                                                y = −6
             P(− 8 ; − 6 )
                                                                                x = −8
                                                                                                      (4)
 5.4.                                     2
                      sin θ − tan θ . cos θ
            LHS =
                       cos θ − (1 − sin 2θ)
                                                                                 sin θ
                               sinθ                                            
                     sin θ −         . cos 2θ                                    cos θ
                   =          cosθ
                                                                                cos 2 θ
                         cos θ − cos 2θ
                                                                                common fact/
                     sin θ(1 − cosθ )                                          gemene fakt.
                   =
                      cos θ(1 − cosθ )                                          common fact/
                   = tan θ                                                     gemene fakt.
                   = RHS                                                                              (4)

            OR/OF
                       sin θ − tan θ . cos 2 θ
            LHS =
                                  (
                     cos θ − 1 + 1 − cos 2 θ     )                             
                                                                                 sin θ
                                                                                 cos θ
                              sinθ
                     sin θ −        . cos 2 θ                                   1 − cos 2 θ
                              cos θ                                             common fact/
                   =
                         cos θ − cos 2 θ                                       gemene fakt.
                     sin θ(1 − cosθ )                                           common fact/
                   =                                                           gemene fakt.
                     cos θ(1 − cosθ )
                   = tan θ
                                                                                                      (4)
                   = RHS                                                                             [26]

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Mathematics P2/Wiskunde V2                       11                                 DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

QUESTION/VRAAG 6

 6.1       sin( x − 30 ο ) = cos 2 x                                                      sin(90ο − 2 x)
           sin( x − 30 ο ) = sin(90 ο − 2 x)
                                                                                          x − 30 = 90 − 2 x + 360 k
                                                                                                   ο     ο             ο

            x − 30 ο = 90 ο − 2 x + 360 ο k or x − 30 ο =180 ο − ( 90 ο − 2 x) + 360k
                        ο       ο                        ο       ο
                                                                                          x = 40ο + 120ο k
           3 x =120 + 360 k                    − x =120 + 360 k                          
                    ο       ο
            x = 40 +120 k                      x = − 120 ο + 360 ο k , k ∈ Z              x − 30ο =180ο − ( 90ο − 2 x) + 360k

                                                                                          x = − 120ο + 360ο k

                                                                                                                           (5)

           OR/OF                                                                                  (          (
                                                                                          cos 90 ο − x − 30 ο             ))
           cos(90 ο − (x − 30 ο )) = cos 2 x
               (            )
           cos 120 ο − x = cos 2 x                                                       
                                                                                         120 ο − x = 2 x + 360 ο k
                ο                   ο             ο                    ο
           120 − x = 2 x + 360 k          or 120 − x = −2 x + 360 k
                                                                                          x = 40ο + 120ο k
           − 3 x = −120 ο + 360 ο k                   x = −120° + 360 ο k                
           x = 40 ο + 120 ο k , k ∈ Z                                                    120 ο − x = −2 x + 360 ο k

           NOTE/LET WEL:                                                                  x = 240 ο + 360 ο k
            x = −120° + k .360° is equivalent to/ekwivalent aan x = 240° + k .360°                                         (5)

 6.2.1     180°                                                                              answer/antw                  (1)
 6.2.2      −1 ≤ y ≤ 1                                                                    values/waardes
                                                                                          notation/notasie
           OR/OF                                                                                                           (2)
                                                                                          values/waardes
            y ∈ [−1; 1]                                                                   notation/notasie
                                                                                                                           (2)

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Mathematics P2/Wiskunde V2                       12                                 DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

 6.2.3                                         y                                                                    f    x-
                                                                                                                    intercept
                                           1                                      f                                 at/afsnit by 30o
                                      g                                                                              shape of/
                                                                                                                    vorm van f
                                                                                                 (180° ; 0,5)
                                                                                                                    g x-
                                                                                                                x   intercepts
                −90° −60°        −30°     0        30°        60°   90°       120° 150°          180°               at/afsnitte by
                                                                                                                    45o and/
                                                                                                                    en 135o
           (−90°;−0,7)                                                                                                shape
                                          −1                                                                        of/vorm van g
                                                                                                                    TP at/DP by
                                                                                                                    (90 ο ;−1  )
                                                                                                                                 (5)
 6.2.4      x = − 80 ο ; x = 40 ο ; x = 160 ο                                                                       one
                                                                                                                    mark per
                                                                                                                    answer/een
                                                                                                                    punt per
                                                                                                                    antw.(3)
                                                                                                                                [16]

QUESTION/VRAAG 7
                                                                                             Q
                                                                                      θ

                                                         2x

                                                                          3
                                  P

                                               x

                                                         R

 7.1             x 2 = (2 x ) + (3) − 2(2 x )(3)cos θ                                                     cos rule
                           2          2

                                                                                                          subst
         12 x cos θ = 3x 2 + 9
                      3x 2 + 9
              cos θ =                                                                                     simplify/vereenv
                       12 x
                                                                                                                                   (3)
                      3( x 2 + 3)
              cos θ =
                         12 x
                       2
                      x +3
              cos θ =
                        4x

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Mathematics P2/Wiskunde V2                       13                                 DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

 7.2.1
          cosθ =
                 (2,4)2 + 3                                                        subst
                                                                                   cos θ = 0,9125
                   4(2,4)
                                                                                   answer/antw.
          cosθ = 0,9125                                                                                     (3)
                    ο
         θ = 24,15

 7.2.2                            1
          Area of/van ∆PQR =        × PQ × QR × sin Qˆ
                                  2
            1
          =   × 4,8 × 3 × sin 24,15                                                subst
            2
          = 2,95 units/eenh 2                                                      answer/antw.
                                                                                                            (2)
 7.3     For/vir x > 0 , cosθ > 0
         0° < θ < 90°
               x2 +3                                                                        x2 +3
         0<          <1                                                            0 <          <1
                4x                                                                           4x
           x 2 + 3x < 4 x
           x2 − 4x + 3 < 0
          (x −1)(x − 3) < 0
              1< x< 3                                                              1 < x < 3
                                                                                                            (4)
                                                                                                       [12]

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Mathematics P2/Wiskunde V2                       14                                 DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

QUESTION 8/VRAAG 8

 8.1         1                                                                          
         V =    Ah                                                                        Area of square/van
             3                                                                                 = (16 × 16 )
                1                                                                       vierk.
         640 = × (16 × 16 ) × h
                3                                                                       Subst in volume
         h = 7,5cm                                                                      form
                                                                                                            (2)
 8.2               slant height / skuinshoogte = 7 ,5 2 + 8 2 = 10 ,9658....            Subst in pyth
                                                                                        answer/antw
                                                                                        Subst in SA/
                                                               1                      BO form.
         Total surface / Totale buite area = (side × side ) + 4 b× ⊥ h                answer/antw
                                                               2       
                                                           1                  
                                           = (16 × 16 ) + 4 × 16 × 10,9658....                               (4)
                                                           2                                                 [6]
                                                = 606,91cm 2

QUESTION 9/VRAAG 9

                                                        O

                                                    1       2
                                        R                                S
                                                    T

 9.1        Construction/Konstr: Draw/trek radii OR and/en OS                           Constr/Konstr
            In ΔOTR and/ en ΔOTS
            OR = OS (radii )                                                            S (OT is
                                                                                        common/gemeen)
            OT = OT (common side/ gemene sy )                                           S/R
                                (
            Tˆ = Tˆ = 90 ο ∠ s on straight line/ op 'n reguit lyn
               1      2                                              )
                          (
            ∆OTR ≡ ∆OTS 90 ο HS             )                                           R
                                                                                        S
            ∴ RT = TS (≡ ∆ )        s
                                                                                                               (5)

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Mathematics P2/Wiskunde V2                       15                                 DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

                                        A        4           F       4   B

                                                         x

                                                         O

                                                             D

 9.2                         line from centre ⊥ to chord/                           S/R
            AF = FB = 4cm                                                           8− x
                             lyn van mdpt ⊥ aan koord 
            OD = OB = 8 − x (radii )
                                            2        2           2
                                                                                       (8 − x) 2 = x 2 + 4 2
                                        OB = OF + FB ( Pythagoras )
                                  ( 8 − x )2 = x 2 + 4 2
                             64 −16 x + x 2 = x 2 + 4 2                                x =3
                                        48 = 16 x
                                          x =3
            length of/ lengte van radius = 8 − x                                      Answer/antw
                                                                                                             (5)
                                         = 8−5                                                              [10]
                                         = 3 units / eenh

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Mathematics P2/Wiskunde V2                       16                                 DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

QUESTION/VRAAG 10

                                                      V
                                                              Q
                                                              2
                                                          1

                                            2
                                                  1
                                          M

                           S
                                                1
                                                    2
                                                                                        P
                                              R

 10.1          Q̂ 2 = Rˆ 2 [ tangents from common point/ rk ln e van selfde punt ]  S R
                                                                                   S
               Q̂ 2 + Rˆ 2 + 70 ο = 180 ο [sum ∠ Δ]                                 Rˆ 2 = 55ο
               2 Rˆ 2 = 110 ο
                                                                                                           (4)
               Rˆ = 55 ο
                 2

 10.2          Qˆ 2 + Qˆ 1 = 90 ο   [tan/rkl ⊥ rad]                                 R
                                                                                    Qˆ1 = 35ο
               Qˆ = 35 ο
                 1
                                                                                                           (2)
               OR/OF
                                                                                    R
               Rˆ1 + Rˆ 2 = 90 ο    [tan/rkl ⊥ rad]                                 Qˆ1 = 35ο
                      Rˆ = 35 ο
                       1                                                                                   (2)
                     Qˆ 1 = Rˆ1 == 35 ο [OR = OQ]

 10.3          Ô1 + R̂ 1 + Q̂1 = 180 ο [sum ∠ Δ]
                                                                                    Ô1 = 110 ο
               Ô1 = 180 ο − 70 ο = 110 ο
                                                                                    Ô 2 = 110ο        R
                          equal chords subtend = ∠ at the centre/ 
               Ô 2 = 110 ο
                                                                                                        (3)
                           gelyke koorde onrsp. = ∠ by mdpt                                            [9]

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Mathematics P2/Wiskunde V2                       17                                 DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

QUESTION/VRAAG 11
                                            B

                                               2
                                           O
                                               1

                                                       1 2

                                                         D

                                            A

                                                   E

 11.1          Bˆ1 = Bˆ 2 = x [BD bisect/halveer ∠ AB̂C ]                          S
               ABˆ C = 2 x
               Oˆ = 2 x [∠ at centre = 2 times ∠ at circumference/]
                 1                                                       S                 R
                      [ midpts∠ = 2 × omtreks∠]                          R
              ∴ BC OD [corresponding ∠ are equal/ooreenk. ∠ is gelyk ]                                  (4)

              OR/OF

               Bˆ1 = Bˆ 2 = x   [BD bisect/halveer ∠ AB̂C ]                        S
               Dˆ = x            [angle opp = sides/∠e to gelyke sye]              S       R
                 1
                                                                                   R
              Dˆ 1 = Bˆ 2 = x                                                                             (4)
              ∴ BC OD           [alternate angles are equal/verw ∠e gelyk]

              OR/OF                                                                S

               Bˆ1 = Bˆ 2 = x [BD bisect/halveer ∠ AB̂C ]
               ABˆ C = 2 x                                                         S       R
               Oˆ = 2 x [angle at centre = 2 times angle at circumference ]
                 1
                           [ midpts∠ = 2 × omtreks∠]
               ˆ
              O2 = 180 − 2 x [∠ on a straight line/∠ op reguit lyn ]
                         ο
                                                                                   R
              Oˆ 2 + ABˆ C = 180 ο − 2 x + 2 x = 180 ο                                                    (4)
              ∴ BC OD [ co-int angles are suppl/ko-binne ∠ is suppl]

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Mathematics P2/Wiskunde V2                       18                                 DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

 11.2          ODˆ C = 90 ο [tan/rkl ⊥ rad ]                                    S/R
                                                                                S R
                   Cˆ = 90 ο [co − int / ko-binne ∠' s OD BC]                                         (3)

              OR/OF                                                             S/R
                                                                                S R
               Dˆ 1 = x                                                                               (3)
                                                                                S/R
               Dˆ = 90 ο − x [tan/rkl ⊥ rad ]
                 2                                                              S R
                              (         )
                Cˆ = 180 ο − 90 ο − x − x [int ∠' s of / van ∆ ]                                       (3)
                     = 90 ο
                                                                                                      [7]

              OR/OF

               EDˆ C = 90 ο [tan/rkl ⊥ rad ]
               Cˆ = 90 ο [corresp. / ooreenk . ∠' s OD BC]

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Mathematics P2/Wiskunde V2                       19                                 DBE/November 2017
                      CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne

QUESTION/VRAAG 12

                                                   A                          Q

                                                       1 2
                                                         x

                                                                                           B
                                                                                                                    F
                                                                                       1
                                                                                           2

                                                                             6 5               T
                                                                                   4
                                                                            7    P3
                                                                            8 1 2

                                                                                                       2
                                                                    2                              y
                                                               1        3                              1
                           E                                        D          R                               C

 12.1          P̂1 = x         [tan − ch th/ rkl-kdst ]                                                            SR
                                                                                                                   SR
               Ĉ 2 = x        [alt / verw. ∠ s AD           BC ]                                                  SR
               Ê = x           [∠ in the same segment/dieselfde segment ]
                                   s                                                                                S/R
                                                                                                                                   (7)
               P̂5 = x          [vert opp/ reg oorst ]

 12.2        DCˆ B = x + y
                                                                                                                   S R
             E Dˆ A = Dˆ = x + y [corresp / ooreenk. ∠ s = , AD
                          1                                                            BC ]                        S R
                                           [
                   ∴ EP̂A = x + y ∠ s in the same segment/dieselfde segment                                ]                       (4)

 12.3                       Pˆ2 = y [ tan from a commom point/ rklyne v dieselfde pt ]                              S/R

                          DPˆ T = Pˆ + Pˆ + Pˆ
                                       1       2       3

                                 = x + y + ( x + y)                                                                 Ĉ = x + y
                                 = 2x + 2 y
                                                                                                                    Subst
                               Ĉ = x + y
                                                                                                                    Answ/antw
                   DPˆ T + Ĉ =180 ο [opp ∠ s of a cyclic quad/ teenoorst. ∠ s van kvhk]
                                                                                                                                   (4)
             2 x + 2 y + x + y =180 ο
                                                                                                                                  [15]
                     3 x + 3 y =180 ο
                                 ∴ x + y = 60 ο

                                                                                                           TOTAL/TOTAAL: 150

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