# Mathematical Literacy Grade 12 P1 Gauteng Mock 2021 Memo > Grade 12 Mathematical Literacy Paper 1 memorandum from the Gauteng Mock Exam 2021 (English), 22 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/gr12-mathematical-literacy-p1-english-2021-preparatory-possible-answers/4622e602-2287-4cd3-b8fd-a7de8c4d7820 - Updated: 2026-09-27 - Subject: Mathematical Literacy - Grade: Grade 12 - Language: English - Document type: Memorandum - Year: 2021 - Exam period: Gauteng Mock Exam - Paper: 1 - Curriculum: CAPS - Pages: 22 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Mathematical Literacy](https://www.hlayiso.com/library/grade-12/mathematical-literacy) › [Mathematical Literacy Grade 12 P1 Gauteng Mock 2021 Memo](https://www.hlayiso.com/library/gr12-mathematical-literacy-p1-english-2021-preparatory-possible-answers/4622e602-2287-4cd3-b8fd-a7de8c4d7820) ## About this document Mathematical Literacy · Grade 12 · Gauteng Mock Exam · 2021 · English. Memorandum, 22 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com GAUTENG DEPARTMENT OF EDUCATION PREPARATORY EXAMINATION 2021 MARKING GUIDELINES MATHEMATICAL LITERACY P1 (10601) Codes Explanation M Method MA Method with Accuracy CA Consistent Accuracy A Accuracy C Conversion D Define J Justification/Reason/Explain/Conclusion S Simplification Reading from a table OR a graph OR a diagram RT/RD/RG OR a map OR a plan F Choosing the correct formula SF Substitution in a formula O Opinion Penalty, e.g. for no units, incorrect rounding-off, P etc. R Rounding-off NP No penalty for rounding-off OR omitting units KEY TO TOPIC SYMBOLS: F = Finance; M = Measurement; MP = Maps, Plans and other representations. DH = Data Handling; P = Probability 22 pages ### Page 2 Downloaded from hlayiso.com 10601/21 QUESTION 1 Q ANSWER EXPLANATION LEVEL 1.1 1.1.1 Multi-tank SA A 2 A Correct answer (2) F1 1.1.2 Unemployment Insurance Fund A 2A Correct answer (2) F1 1.1.3 MA 1 MA Multiplying by 1% A 1 A Answer OR F1 MA = R127,90 A (2) 1.1.4  1 MA Multiplying by 60% A 1 A Correct answer OR  1 MA Multiplying by 60% A 1 A Correct answer F1 OR 1MA Subtracting the correct amount R12 790 – R5 116  1A Correct answer = R7 674  (2) 2 ### Page 3 Downloaded from hlayiso.com 10601/21 Q ANSWER EXPLANATION LEVEL 1.1.5 He will have less money to spend. J 2J Justification OR His buying power will be reduced. F1 OR Accept any reasonable/ valid answer He will buy less goods/food/petrol. (2) 1.1.6  A 1MA Multiplying by 120% A 1A Answer OR  A 1MA Multiplying by 1,2 R21,50 × 1,2 = R25,80 A 1A Answer F1 OR 1MA Adding R4,30 R21,50 × = R4,30 1A Answer  A R21,50 + R4,30 = R25,80 A (2) 1.1.7  1MA dividing by 0,046 1A Correct answer A OR F1 = R 8 695,652 R8 695,65 (2) 1.2 1.2.1 Discrete data only consists of whole numbers 2 O Correct explanation of and continuous data consists of decimal both discrete and continuous DH1 numbers as well.  O data. (2) 1.2.2 Western Cape  A 2A Answer (2) DH1 3 ### Page 4 Downloaded from hlayiso.com 10601/21 Q ANSWER EXPLANATION LEVEL 1.2.3 Range = Maximum value – Minimum value 2RT Correct values 1A Answer 44 143 – 63  RT DH1 = 44 080  A Answer only, full marks (2) 1.2.4 205, 322, 362, 512, 1 177, 3 959, 10 597, 1M Arrangement 12 193, 44 143  M 1CA Answer Median = 1 177  CA Penalty: Penalise 1 mark if DH1 learner used all 10 provinces and got 844,5 Answer only, full marks (2) 1.2.5 205 + 322 + 362 + 512 + 1 177 + 3 959 + 1MA Addition 10 597 + 12 193 + 44 143  MA 1A Answer DH1 = 73 470  A (2) 1.3 1.3.1 Males  A 2A Answer (2) DH1 1.3.2 Bar Graph  A 2A Answer (2) DH1 1.3.3 30 – 49 years old  A 2A Answer (2) DH1 [30] 4 ### Page 5 Downloaded from hlayiso.com 10601/21 QUESTION 2 Q ANSWER EXPLANATION LEVEL 2.1 2.1.1 It means that people 65 years and younger, 2J Reason explaining less receiving an annual income of R83 100 or than R83 100 and does not F4 less, does not have to pay tax. J have to pay tax (2) 2.1.2 Income – pension – UIF = taxable income M M R60 000 (7,5% 1M Subtracting pension CA 1M Subtracting UIF M 1CA Answer 1M Multiplying by 12 CA 1CA Answer OR M 1M Multiplying by 12 R60 000 × 12 = R720 000 CA 1CA Answer 1M Subtracting pension 1M Subtracting UIF 1CA Answer R720 000 – R54 000 = R666 000 M R666 000 – (R148,72 × 12) F3 = R666 000 – R1 784,64 M = R664 215,36 CA OR M 1M Multiplying by 12 R60 000 × 12 = R720 000 CA 1CA Answer 1M Subtracting pension 1M Subtracting UIF 1CA Answer R148,72 × 12 = R1 784,64 R54 000 + R1 784,64 = R55 784,64 R720 000 – R55 784,64 MM = R664 215,36 CA (5) 5 ### Page 6 Downloaded from hlayiso.com 10601/21 Q ANSWER EXPLANATION LEVEL 2.1.3 MA ( ( 1MA Addition and per month A multiplication 1A Answer M 1M Multiplying by 12 per year  CA 1CA Answer OR MA (R319 + R319) + (R215 + R215) 1MA Addition A Answer = R638 + R430 1M Multiplying by 12 = R1 068 A 1CA Answer M per year  CA OR R319 × 12 = R3 828 1MA Multiplication by 12 R3 828 × 2 = R7 656 MA and 2 1A Both answers R215 × 12 = R2 580 A 1M Addition R2 580 × 2 = R5 160 1CA Answer R7 656 + R5 160 M F2 = R12 816 CA OR R319 × 2 = R638 1MA Multiplication by 12 R638 × 12 = R7 656 MA and 2 1A Both answers R215 × 2 = R430 A 1M Addition R430 × 12 = R5 160 1CA Answer R7 656 + R5 160 M = R12 816 CA OR 12 × 2 = 24 MA 1MA for 24 1A Both Answers R319 × 24 = R7 656 1M Addition A 1CA Answer R215 × 24 = R5 160 R7 656 + R5 160 M = R12 816 CA OR 6 ### Page 7 Downloaded from hlayiso.com 10601/21 12 × 2 = 24 MA 1MA for 24 R319 + R215 1A Total or 1M Addition of both values A 1M Multiplying by 24 = R534 × 24 M 1CA Answer = R12 816 CA (4) 2.1.4 ( CA from Q 2.1.2 and )  Q 2.1.3  1RT Correct tax bracket ( ) 1SF Substitute into formula 1CA Answer  1M Subtract rebate 1M Subtract medical tax  credits 1M Division by 12 1CA Answer M 1J Opinion/Conclusion R171 752,99 – R12 816 = R158 936,99 M CA No, her claim is NOT VALID. J F4 7 ### Page 8 Downloaded from hlayiso.com 10601/21 OR Annual Tax payable: RT R155 505 + 39% of income above R584 200 1RT Correct tax bracket R155 505 + 39% × (R664 215,36 – R584 200) 1SF Substitute in formula 1CA Answer SF 1M Subtract rebate 1M Subtract medical tax ( ) credits 1M Division by 12 = R155 505 + R312 065,99 1CA Answer = R186 710,99 CA 1J Opinion Rebate: M R186 710,99 – R14 958 = R171 752,99 Medical Tax credits: M R171 752,99 – R12 816 = R158 936,99 Monthly Tax payable: M = R13 244,75 CA No, her claim is NOT VALID. J 8 ### Page 9 Downloaded from hlayiso.com 10601/21 OR Annual Tax payable: RT R155 505 + 39% of income above R584 200 1RT Correct tax bracket R155 505 + 39% × (R664 215,36 – R584 200) 1SF Substitute in formula 1CA Answer SF 1M Subtract rebate 1M Subtract medical tax ( ) credits 1M Division by 12 = R155 505 + R312 065,99 1CA Answer = R186 710,99 CA 1J Opinion Rebate and medical tax credits: M M R186 710,99 – R14 958 – R12 816 = R158 936,99 Monthly Tax payable: M = R13 244,75 CA No, her claim is NOT VALID. J 9 ### Page 10 Downloaded from hlayiso.com 10601/21 OR Annual Tax payable: RT R155 505 + 39% of income above R584 200 RT Correct tax bracket R155 505 + 39% × (R664 215,36 – R584 200) 1SF Substitute in formula 1CA Answer SF 1M Subtract rebate 1M Division by 12 ( ) 1M Subtract medical tax credits = R155 505 + R312 065,99 1CA Answer = R186 710,99 CA 1J Opinion Rebate: M R186 710,99 – R14 958 = R171 752,99 Monthly tax before medical tax deductions: M = R14 312,75 Medical tax credits: R14 312,75 – (2 × R319) – (2 × R215) = R14 312,75 – R638 – R430 = R14 312,75 – R1 068 M = R13 244,75 CA No, her claim is NOT VALID J (8) 2.2 2.2.1 RT M 1RT Correct values from CA table 1M subtraction/concept of F1 difference 1CA answer (3) 10 ### Page 11 Downloaded from hlayiso.com 10601/21 Q ANSWER EXPLANATION LEVEL 2.2.2 MA 1MA Multiplying by 12 12 x R20 725 1A Answer = R248 700 A 1RT Reading year from table Private High School in 2025 RT OR F1 2020: 1MA Division by 12 MA 1A Answer 2025: A 1RT Reading year from table Private High School in 2025 RT (3) 2.2.3 Year 1 (2022) MA 1MA Multiplying by 6,6% ( 1A Answer for 1st year A 1CA Answer for 2nd year 1CA Answer for 3rd year Year 2 (2023) 1RT Reading University fees ( from table for 2025 CA 1CA Difference 1O Opinion Year 3 (2024) ( CA NOTE: If Compound interest formula was used: University fees for 2025 – savings = shortfall Award FULL MARKS, given RT that the answer is 100% CA correct. NO marks if answer is Joshua is correct, R250 would cover the incorrect. F4 shortfall  OR Joshua is incorrect, the amount is less than R250 OR 11 ### Page 12 Downloaded from hlayiso.com 10601/21 Year 1 (2022) R88 653,77 = R5 851,14882 MA 1MA Multiplying by 6,6% 1A Answer for 1st year A 1CA Answer for 2nd year R88 653,77 + R5 851,14882 = R94 504,91882 1CA Answer for 3rd year 1RT Reading University fees Year 2 (2023) from table for 2025 R94 504,91882 = R6 237,324642 1CA Difference 1O Opinion R94 504,91882 + R6 237,324642 = R100 742,2435 CA Year 3 (2024) R100 742,2435 = R6 648,988068 R100 742,2435 + R6 648,988068 = R107 391,2316 = R107 391,23 CA Difference: RT R107 600 – R107 391,23 = R208,77 CA Joshua is correct, R250 would cover the shortfall  OR Joshua is incorrect, the amount is less than R250 OR Year 1 (2022) MA R88 653,77 x 1,066 = R94 504,91882 A 1MA Multiplying by 1,066 1A Answer for 1st year Year 2 (2023) 1CA Answer for 2nd year R94 504,91882 x 1,066 = R100 742,2435 1CA Answer for 3rd year CA 1RT Reading University fees from table for 2025 Year 3 (2024) 1CA Difference R100 742,2435 x 1,066 = R107 391,23 CA 1O Opinion Difference: RT R107 600 – R107 391,23 = R208,77 CA Joshua is correct, R250 would cover the shortfall  OR Joshua is incorrect, the amount is less than R250 (7) 12 ### Page 13 Downloaded from hlayiso.com 10601/21 Q ANSWER EXPLANATION LEVEL 2.3 2.3.1 R200,00 RT 2RT Reading from table (2) F1 2.3.2 Conversion to rand: 1C Conversion to rand 1A Answer for 50 kWh 1A Difference C 1CA Answer 1CA Total First 50 kWh 50 × R0,6936 = R34,68 A 286 kWh – 50 kWh = 236 kWh A Next 236 kWh 236 x R0,8160 = R192,576 CA Total: R34,68 + R192,576 = R227,256 = R227,26 CA F3 OR First 50 kWh 1A Answer for 50 kWh in 50 x 69,36 = 3 468c A cents 1A Difference 286 kWh – 50 kWh = 236 kWh A 1CA Answer 1CA Total Next 236 kWh 1C Conversion to rand 236 x 81,60 = 19 257,6c CA Total: 3 468 + 19 257,6 = 22 725,6c CA Conversion to rand: C = R227,26 (5) 13 ### Page 14 Downloaded from hlayiso.com 10601/21 Q ANSWER EXPLANATION LEVEL 2.3.3 Cost excluding VAT: MA 1MA for VAT exclusive A method 1A Answer 1CA Cost excluding fixed OR monthly fee 1C Conversion MA 1CA Answer A Cost excluding fixed monthly fee: R626,0869565 – R200 = R426,0869565 CA F2 Cost per unit in Rand: C kWh used: = 601,35 kWh used CA (5) [44] 14 ### Page 15 Downloaded from hlayiso.com 10601/21 QUESTION 3 Q ANSWER EXPLANATION LEVEL 3.1 3.1.1 Range = Maximum – Minimum M 1M Range concept = 78,2% - 60,6%  MA 1MA Correct values in DH2 = 17,6%  A correct order 1A Answer (3) 3.1.2 Bi-modal = 70,2% A and 78,2% A 2A Correct Answers (2) DH2 3.1.3 Arrangement of values: 1MA Correct arrangement 60,6 ; 67,8 ; 70,2 ; 70,2 ; 72,5 ; 73,9 ; 1MA Correct values divided 75,1 ; 75,8 ; 78,2 ; 78,2 MA by 2 1CA Answer Median = MA DH3 = = 73,2  CA (3) 3.1.4 Continuous A 1A Continuous The data consists of decimal numbers. J 2J Correct definition OR DH4 Continuous A The data can be measured J (3) 3.1.5 IQR = Q3 – Q1 1A Correct Quartile 1 and 3 values Q3 = 75,8% 1M IQR method/concept Q1 = 70,2% 1CA Answer DH3 A IQR = 75,8% - 70,2% M = 5,6%  CA (3) 3.1.6 The third Quartile value (Q3) represents 75% 2J Explanation of Q3, must of the data collected.  J include 75% OR Accept any reasonable/ DH4 valid explanation The third Quartile value (Q3) represents of including 75% the data collected.  J (2) 3.1.7 Probability = MA 1MA Denominator 1MA Numerator P2 1S Simplification = S (3) 15 ### Page 16 Downloaded from hlayiso.com 10601/21 Q ANSWER EXPLANATION LEVEL 3.2 3.2.1 Ordinary pass rate: 2J Explanation of the trend The pass rate dropped/decreased/fell from of ordinary pass rate 2015 to 2016 and then increased/went up/went higher from 2016 to 2018. J 2J Explanation of the trend of university pass rate University pass rate: There is a continuous increase from 2015 to Penalise learner if years 2018. J are not used DH4 OR University pass rate: There is an increase from 2015 to 2016, and another increase from 2016 – 2017 and another increase from 2017 – 2018 J (4) 3.2.2 Biased A 1A Biased The data was only collected from one province 1J Explanation instead of all the provinces. J Accept any OR valid/reasonable answer Biased A referring to the entire The data was only collected from a small part country or only part of DH4 of the country. J the country OR Biased A The data does not represent the whole country, only one part. J (2) 3.2.3 Survey questions: 4O Four questions asked 1. Did you attend school every day? relating to the University 2. How long before the exams did you pass rate start studying? 3. Did you study every day? 9 Possible options are 4. What are you going to study next year? given – mark only the 5. What or who influenced your choice to first four answers; any study further? relevant/valid questions DH4 6. Who will finance your studies? relating to a learner 7. Will you get a part-time job to help pay who achieved a for your studies? university entrance can 8. How did COVID-19 influence your be accepted. approach to school and your studies? 9. Did any of your parents attend university? (4) [29] 16 ### Page 17 Downloaded from hlayiso.com 10601/21 QUESTION 4 Q ANSWER EXPLANATION LEVEL 4.1 4.1.1 3 days in Jan + 28 days in Feb + 31 days in 1MA Mark for adding March MA 1CA for Answer 1M for Dividing by days  1R Rounding to the nearest  million F3  (4) 4.1.2 1M Multiplying tickets by    days (CA from 4.1.1.) 1MA Multiplying tickets by $76 1CA Mark for answer F2 OR 60 tickets × $76 = $4 560 per day MA 1MA Multiplying tickets by M $76 $4 560 × 62 days = $282 720 CA 1M Mulitplying with days (CA from 4.1.1.) 1CA Answer OR 62 days × $76 = $4 712M 1M Multiplying days by $76 MA (CA from 4.1.1.) $4 712 × 60 tickets = $282 720 CA 1MA Multiplying amount by 60 1CA Answer (3) 4.1.3  (CA from 4.1.2.) 1M Multiply by 11,8321  1CA Mark for answer (2) F1 17 ### Page 18 Downloaded from hlayiso.com 10601/21 Q ANSWER EXPLANATION LEVEL 4.1.4 MA 1MA Total income per day 1CA Calculating 40% of total income CA 1M Subtracting difference  loss OR 60 people 1MA Calculating number of F2 people attending daily = 24 people allowed to attend daily CA 1CA Calculating total income per day 24 people × R120 = R2 880 1M Subtracting difference Total = 60 people × R120 = R7 200 CA M Loss = R7 200 – R2 880 = R4 320 loss (3) 4.2 4.2.1 R200 A 2A Marks for answer (2) F1 4.2.2 Minimum fee of R30 when you make a 2A Marks for answer deposit A OR When you make a deposit at FNB bank OR When you make a deposit of less than R5 000 OR F2 When you make a deposit of R5 000 or less OR Minimum fee when you make a deposit of less than R5 000 OR When you make a deposit at FNB of less than R5 000 (2) 18 ### Page 19 Downloaded from hlayiso.com 10601/21 Q ANSWER EXPLANATION LEVEL 4.2.3 1MA Multiplication by (  R11 300 and R1,49 1CA Mark for answer F2 = R8,40 + R168,37  OR 1MA Multiplying 113 by 113 × R1,49 = R168,37MA R1,49 R8,40 + R168,37 = R176,77 CA 1CA Answer (2) 4.2.4  1MA Correct percentage (a) 1A Mark for dividing by 12  1CA Mark for answer  F1 OR 1MA Calculating decimal MA 1A Division by 12 1CA Answer A = 0,002 CA (3) 19 ### Page 20 Downloaded from hlayiso.com 10601/21 Q ANSWER EXPLANATION LEVEL 4.2.4 Month 1 CA from 4.2.2 (b)  1M Multiplication by  decimal 1CA Interest for 1st month  1CA Total interest for 1st month Month 2 1CA Interest for 2nd month 1CA Total interest CA F3 CA OR Maand 1 CA from 4.2.2 M 1M Multiplying by 0,2% R11 300 = R22,60 CA 1CA Interest for 1st month 1CA Total interest for first  month 1CA Interest for 2nd month Month 2 1CA Total interest CA NOTE: If compound interest formula was used: CA Award FULL MARKS, given that the answer is 100% correct. NO marks if answer is incorrect. (5) 4.3 4.3.1  1M Division by 300  CA 1CA Answer income per 1R Rounding personR OR 1M Division by 300 1CA Answer M 1R Rounding F2 = R133,3333333... CA R (3) 20 ### Page 21 Downloaded from hlayiso.com 10601/21 Q ANSWER EXPLANATION LEVEL 4.3.2  1 RT Mark for the fixed ( )  expenses (R30 000)  1MA Mark for subtracting 1M for Dividing by 500  CA 1 CA Mark for cost per person F2 OR 2MA Calculating difference between total expense and fixed cost 1M Dividing by 500 MA 1CA Answer M = R20 per person CA (4) 4.3.3 M CA from 4.3.2  1M Difference between amounts  1M Division 1CA Percentage F2 OR 1M Difference  1M Division 1CA Percentage  = 550%  (3) 21 ### Page 22 Downloaded from hlayiso.com 10601/21 Q ANSWER EXPLANATION LEVEL 4.4 4.4.1 Grade 11s from 2014 – 2019: MA 1MA Correct order of grade 827 677, 864 618, 858 769, 869 513, 890 971 11s DH 2 Grade 12s from 2014 – 2019: 1MA Correct order of grade MA 12s 501 303, 512 735, 534 484, 610 178, 644 536 (2) 4.4.2 Median = 534 484 1A Q3 1A Q1 Quartile 3 (Q3) 1M Concept of IQR 1CA Answer If range is used, no = 627 357 A marks. CA only if other values are used and the Quartile 1 (Q1) = DH3 concept IQR is used. = 507 019 A IQR = Q3 – Q1 = 627 357 – 507 019 M = 120 338 CA (4) 4.4.3 None A 2A Answer DH 1 No mode (2) 4.4.4 1MA Addition or total 1MA Division by 5 1CA Answer MA DH2 MA = 560 647,2 CA (3) [47] TOTAL: 150 22 ## Related documents - [MATHS LIT P1 GR12 MEMO SEPT 2021 English](https://www.hlayiso.com/library/maths-lit-p1-gr12-memo-sept-2021-english/9e0090b1-9cc7-4ae4-abe6-f4cf6ea5bce3) — Mathematical Literacy · Memo · 2021 · Eng - [Grade 12 NSC Mathematical Literacy P1 (English) 2020 Preparatory Possible Answers](https://www.hlayiso.com/library/grade-12-nsc-mathematical-literacy-p1-english-2020-preparatory-possible-answers/d1485a44-4dbf-41f8-bef0-0376485fcde9) — Mathematical Literacy · Memo · 2020 · Eng - [MATHS LIT P1 GR12 ADDENDUM SEPT 2021 English](https://www.hlayiso.com/library/maths-lit-p1-gr12-addendum-sept-2021-english/1141e20a-9cef-43c2-9fab-b805c645f238) — Mathematical Literacy · Addendum · 2021 · Eng - [Grade 12 NSC Mathematics Literacy P1 (English) 2019 Preparatory Examination Addendum](https://www.hlayiso.com/library/grade-12-nsc-mathematics-literacy-p1-english-2019-preparatory-examination-addendum/f7fa95a2-740d-4706-983c-7cc7de284a90) — Mathematical Literacy · Addendum · 2019 · Eng - [Grade 12 NSC Mathematics Literacy P1 (English) X05 2019 Preparatory Examination Question Paper](https://www.hlayiso.com/library/grade-12-nsc-mathematics-literacy-p1-english-x05-2019-preparatory-examination-question-paper/b94cd72e-83d6-480c-8302-36093d2fdd3f) — Mathematical Literacy · QP · 2019 · Eng - [Grade 12 NSC Mathematical Literacy P1 (English) 2015 Preparatory Examination Question Paper](https://www.hlayiso.com/library/grade-12-nsc-mathematical-literacy-p1-english-2015-preparatory-examination-question-paper/6cb0661c-9e1c-49bb-a37b-db7f3504733d) — Mathematical Literacy · QP · 2015 · Eng ## More from Grade 12 Mathematical Literacy - [MATHS LIT P2 GR 12 SEPT 2025 ADDENDUM AFR watermark](https://www.hlayiso.com/library/maths-lit-p2-gr-12-sept-2025-addendum-afr-watermark/813c6e54-f134-474a-b01a-1260e38b4c8f) — Addendum · 2025 · Afr - [Maths LIT Grade 12 NSC P1 QP September 2025 Free State](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-qp-september-2025-free-state/45f0ab2a-afdd-46df-bf98-5505c4021e64) — QP · 2025 - [Maths LIT Grade 12 NSC P1 ANSWER BOOK September 2025 KZN](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-answer-book-september-2025-kzn/b0b358eb-c897-437a-8694-910fe61dfcbc) — Addendum · 2025 - [Maths LIT Grade 12 NSC P1 QP September 2025 Limpopo](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-qp-september-2025-limpopo/c5d7a167-2d27-4e33-80ef-fad9cde4ebd2) — QP · 2025 - [Maths LIT Grade 12 NSC P2 QP September 2025 Limpopo](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p2-qp-september-2025-limpopo/f22349c1-8dbf-420e-ae8d-13d53bcb300b) — QP · 2025 - [Maths LIT Grade 12 NSC P2 QP September 2025 North West](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p2-qp-september-2025-north-west/7ce5b7fe-941b-4148-80dc-d9cde7bdbfd7) — QP · 2025 ## Collection - [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. 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