# Mathematical Literacy Grade 12 P2 Gauteng Mock 2021 Memo > Grade 12 Mathematical Literacy Paper 2 memorandum from the Gauteng Mock Exam 2021 (English), 10 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/gr12-mathematical-literacy-p2-english-2021-preparatory-possible-answers/3403e0ff-571a-4686-8a06-2daef4821171 - Updated: 2026-09-27 - Subject: Mathematical Literacy - Grade: Grade 12 - Language: English - Document type: Memorandum - Year: 2021 - Exam period: Gauteng Mock Exam - Paper: 2 - Curriculum: CAPS - Pages: 10 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Mathematical Literacy](https://www.hlayiso.com/library/grade-12/mathematical-literacy) › [Mathematical Literacy Grade 12 P2 Gauteng Mock 2021 Memo](https://www.hlayiso.com/library/gr12-mathematical-literacy-p2-english-2021-preparatory-possible-answers/3403e0ff-571a-4686-8a06-2daef4821171) ## About this document Mathematical Literacy · Grade 12 · Gauteng Mock Exam · 2021 · English. Memorandum, 10 pages. Read online or download the PDF. 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Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com GAUTENG DEPARTMENT OF EDUCATION PREPARATORY EXAMINATION 2021 MARKING GUIDELINES MATHEMATICAL LITERACY PAPER 2 (10602) Codes Explanation M Method MA Method with Accuracy CA Consistent Accuracy A Accuracy C Conversion D Define J Justification/Reason/Explain S Simplification RT/RD/RG Reading from a table OR a graph OR a diagram OR a map OR a plan F Choosing the correct formula SF Substitution in a formula O Opinion P Penalty, e.g. for no units, incorrect rounding-off, etc. R Rounding-off NP No penalty for rounding-off OR omitting units KEY TO TOPIC SYMBOL: M = Measurement; MP = Maps, Plans and other representations; P = Probability 10 pages 1 ### Page 2 Downloaded from hlayiso.com 10602/21 QUESTION 1 Q Answer Explanation Level 1.1.1 Personal care  2A correct answer CA (2) 1.1.2 2 x 60 = 120 seconds  1M multiplying by 60 M1 1A correct answer (2) 1.1.3 236 –198 = 38 mins 1M subtraction M1 1A correct answer (2) 1.1.4 93 minutes ÷ 60 = 1 hour 33 minutes  1M dividing by 60 M1 1A correct answer (2) 1.1.5 1 : 2 1M ratio M1 1M statement 93 : 109 1 : 1,17 His claim is INCORRECT. (2) 1.1.6 They are older and more mature/more capable 2A correct answer MP4 of handling the responsibility of household maintenance.  OR Any other logical reason. (2) 1.1.7 (i) 26  1A correct answer MP1 (1) (ii) 1 437  1A correct answer MP1 (1) 2 ### Page 3 Downloaded from hlayiso.com 10602/21 Q Answer Explanation Level 1.2.1 Boom Street 1A correct answer MP1 Paul Kruger Street 1A correct answer (2) 1.2.2 2  2A correct answer MP1 (2) 1.2.3 North East  2A correct answer MP1 OR NE  (2) 1.2.4  Lion 1A correct answer MP1  Rhinoceros 1A correct answer  Leopard Any 2 correct answers  Buffalo  Elephant (2) 1.2.5 6 : 2 1A correct answer MP1 3 : 1 1 S simplification AO (2) 1.2.6 Cableway 2A correct answer MP1 (2) 1.2.7 80 1002 1C multiplying by 1002 MP1 = 800 000 m2 1A correct answer OR 80 x 10 000 = 800 000 m2 (2) 1.2.8 Western 2A correct answer MP1 OR On the left-hand side (2) [30] 3 ### Page 4 Downloaded from hlayiso.com 10602/21 QUESTION 2 Q Answer Explanation Level 2.1.1 at Buffs 1A correct answer RT1 (1) 2.1.2 Some runners may not be able to complete this 2A correct answers MP4 course of 42,2 km. To encourage aspiring long-distance runners to be competitive To encourage more people to compete To encourage fitness amongst people To encourage more participation in the event (Accept any TWO reasonable answers.) (2) 2.1.3 39 – 27 = 12 km  2A correct answer RG (2) 2.1.4 Time taken = 8,75 h – 5 h  1M time MP3 = 3,75 h  1M substraction 1M correct answer OR Time taken = 08:45 – 05:00 = 03h45 minutes = 3,75 h (3) 2.1.5 Distance = Average speed x time 1SF substitution correct MP3 values 21 = x x 0,75  1M change subject of formula 21,2 x=  1CA answer 0,75 = 5,65  = 5,7 km/h  (3) 2.1.6 Distance = Average speed x time 1M substitution MP3 1M calculation 42,2 = 5,7 x x  1M answer 42,2 1M hours and minutes x =  5,7 x = 7,406  = 7 hours and 24,36 minutes  He started at 5:00 so he should complete the marathon by 12:24 (5:00 + 7 h 34) (4) 4 ### Page 5 Downloaded from hlayiso.com 10602/21 Q Answer Explanation Level 2.1.7 Cut-off time is a time limit by which all 2A correct explanation M2 participants must cross a demarcation/line to ensure they can finish the race before the event shuts down. (2) 2.1.8 Increasing fitness levels 1M correct answer MP2 Improve camaraderie Meet new people (Any ONE) (1) 5 ### Page 6 Downloaded from hlayiso.com 10602/21 Q Answer Explanation Level 2.2.1 Gauteng  1A correct answer MP1 (1) 2.2.2 Craighall  2A correct answer MP1 (2) 2.2.3 4 cm = 30 km  2A correct answer MP2 1,6 cm = 12 km  (2) 2.2.4 Kempton Park  2A correct answer MP2 (2) 2.2.5 Randburg to Soweto is approximately 6,5 cm 1M read scale MP5 on the map.  1M measurement 1M correct answer 4 cm = 30 km  2M motivation 1 cm = 7,5 km  6 cm = 45 km  No, they will not be justified since the distance from Randburg to Soweto according to the scale bar is approximately 46,4 km. The Buffalo marathon is 42,2 km.  (5) 2.2.6 1USD = R14, 05 1M calculation MP2 2M correct answer X = R1 000  R1 000 ÷ R14,05 = USD 71, 17  (3) 2.3.1 A P2 B R (3) 2.3.2 1 1A numerator P2  1A denominator 8 (2) [38] 6 ### Page 7 Downloaded from hlayiso.com 10602/21 QUESTION 3 Q Answer Explanation Level Radius =  1M divide by 2 M2 3.1.1 1A correct answer = 50 mm AO (2) 3.1.2 Capacity is the amount of space available to 2A definition of capacity M2 hold something. 2A definition of volume whereas volume is the amount of space occupied by a geometric object.  (4) 3.1.3 2 000 mℓ = 2 000 cm3  1C conversion to cm3 M3 50 mm = 5 cm 1C conversion to cm Volume of dispenser A = 3,142 (5 cm)2 1SF correct values 1MA value of 2 000 cm3 h 1CA answer 2 000 cm3 = 78,55 cm2 h h = 25,46 cm OR OR 1C conversion to cm3 2 000 mℓ = 2 000 cm3  1C conversion to cm 50 mm = 5 cm 1MA subject of the formula Volume = xh Height =  1SF correct values =  1CA answer = 25,46 cm (5) 3.1.4 80 mm = 8 cm 1C conversion to cm M4 Capacity of dispenser B 1SF correct values = 13,7 cm 8 cm 20,8 cm 1CA answer = 2279,68 cm3  1A correct unit The claim is invalid 1O conclusion (5) 7 ### Page 8 Downloaded from hlayiso.com 10602/21 Q Answer Explanation Level 3.1.5 Volume of sensor = 13,7 cm 8 cm 2 cm  CA from 3.1.4 M4 = 219,2 cm3 1SF correct values 1MA correct answer Volume of dispenser B 1M subtracting correct = 2 279,68 cm3 – 219,2 cm3 values  1CA answer = 2 026,48 cm3 1O justification Dispenser B is bigger OR OR 2A value of 18.8 Add: V = ℓ x b x h 1SF correct values = 13,7 x 8 x 18,8 1CA answer = 2 026,48 cm3 Dispenser A = 2 000 ml and dispenser B = 2 026,48 mℓ 1O justification B is 26,48 mℓ bigger than A (5) 3.1.6  It reduces the spread of infections. 2A correct answer M4 OR  It offers a standard amount that is enough to clean both hands. Accept any other sensible advantage. (2) 3.2.1 25 ℓ = 25 000 cm3  1C conversion M3 Number of dispensers =  1A numerator 1A denominator = 12,5 1CA answer 12 1R correct value (5) 3.2.2 Volume of dispensers for 4 weeks 1A correct values M3 = 2 000 cm3 5 4 1A total volume = 40 000 cm3 1M dividing by 5 000 1A correct answer Number of 5 ℓ bottles =  = 8 bottles (4) 3.2.3 Dispensers allocated to male rest rooms CA from 3.2.2 M2 = 25  1A numerator 1A denominator = 10 dispensers 1M multiplying by 25 1A correct answer (4) [36] 8 ### Page 9 Downloaded from hlayiso.com 10602/21 QUESTION 4 Q Answer Explanation Level 4.1.1 Space inside the rooms 2A correct answer M1 (2) 4.1.2 Perimeter 1A for every 2 correct values M2 = 6 m + 8 m + 3 m + 5 m + 6,5 m + 1A correct value 5 m + 3,5 m + 8 m = 45 m (6) 4.1.3 b = 200 cm = 2 m 1C conversion to 2 m M2 Surface area of cabinets 2SF correct values = (6 m 2 m) + (3 m 2 m)  1CA answer = 12 m2 + 6 m2 = 18 m2 (4) 4.1.4 Area of room A = 8 m 6 m CA from 4.1.3 M3 = 48 m2 1MA correct values 1A correct answer Area to be tiled = 48 m2 – 18 m2 = 30 m2 1M subtracting correct values 1CA answer (4) 4.1.5 Area of a tile = 0,6 m 0,6 m CA from 4.1.4 M4 . = 0,36 m2 1MA correct values 1A correct answer Number of tiles =  1M dividing by area of tile = 83,3 1MA answer = 84 tiles  1R rounding up The claim is valid 1O for justification (6) 4.1.6 Cost of tiles = 84 R180 CA from 4.1.5. M2 = R15 120 1RT value of R180 1M multiplying correct values 1A correct answer (3) 4.1.7 Number of boxes =  CA from 4.1.5. M2 1A numerator = 14  1A denominator 1A correct answer (3) 9 ### Page 10 Downloaded from hlayiso.com 10602/21 Q Answer Explanation Level 4.2.1 Number of boxes in Room B using 2A correct values MP2 option 1 =   2A correct answers 1CA answer = 4  9 = 36 boxes (5) 4.2.2 Number of boxes in Room B using 2A correct values MP4 option 2 =   2A correct answers 1CA answer = 7  5 1J justification = 35 boxes 1O opinion Option 1 will enable packaging of more boxes The claim is invalid (7) 4.3.1 18 months old 2rt correct value M1 (2) 4.3.2 Weight = 12,6 kg 1RT value of weight M3 Length = 97 cm 1RT value of length BMI =  1SF correct values 1CA answer BMI = 0,00133914 kg/cm2 (4) [46] TOTAL: 150 10 ## Related documents - [MATHS LIT P1 GR12 MEMO SEPT 2021 English](https://www.hlayiso.com/library/maths-lit-p1-gr12-memo-sept-2021-english/9e0090b1-9cc7-4ae4-abe6-f4cf6ea5bce3) — Mathematical Literacy · Memo · 2021 · Eng - [Grade 12 NSC Mathematical Literacy P1 (English) 2020 Preparatory Possible Answers](https://www.hlayiso.com/library/grade-12-nsc-mathematical-literacy-p1-english-2020-preparatory-possible-answers/d1485a44-4dbf-41f8-bef0-0376485fcde9) — Mathematical Literacy · Memo · 2020 · Eng - [MATHS LIT P2 GR12 MEMO SEPT2022 English](https://www.hlayiso.com/library/maths-lit-p2-gr12-memo-sept2022-english/dfa5d81c-279c-4516-b124-cfc6103a3517) — Mathematical Literacy · Memo · 2022 · Eng - [MATHS LIT P1 GR12 ADDENDUM SEPT 2021 English](https://www.hlayiso.com/library/maths-lit-p1-gr12-addendum-sept-2021-english/1141e20a-9cef-43c2-9fab-b805c645f238) — Mathematical Literacy · Addendum · 2021 · Eng - [Grade 12 NSC Math Lit P2 Preparatory 2018 Possible Answer](https://www.hlayiso.com/library/grade-12-nsc-math-lit-p2-preparatory-2018-possible-answer/1a6b9c22-6d39-4799-8d55-c6d5e13736b3) — Mathematical Literacy · Memo · 2018 - [Grade 12 NSC Mathematics Literacy P1 (English) 2019 Preparatory Examination Addendum](https://www.hlayiso.com/library/grade-12-nsc-mathematics-literacy-p1-english-2019-preparatory-examination-addendum/f7fa95a2-740d-4706-983c-7cc7de284a90) — Mathematical Literacy · Addendum · 2019 · Eng ## More from Grade 12 Mathematical Literacy - [MATHS LIT P2 GR 12 SEPT 2025 ADDENDUM AFR watermark](https://www.hlayiso.com/library/maths-lit-p2-gr-12-sept-2025-addendum-afr-watermark/813c6e54-f134-474a-b01a-1260e38b4c8f) — Addendum · 2025 · Afr - [Maths LIT Grade 12 NSC P1 QP September 2025 Free State](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-qp-september-2025-free-state/45f0ab2a-afdd-46df-bf98-5505c4021e64) — QP · 2025 - [Maths LIT Grade 12 NSC P1 ANSWER BOOK September 2025 KZN](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-answer-book-september-2025-kzn/b0b358eb-c897-437a-8694-910fe61dfcbc) — Addendum · 2025 - [Maths LIT Grade 12 NSC P1 QP September 2025 Limpopo](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-qp-september-2025-limpopo/c5d7a167-2d27-4e33-80ef-fad9cde4ebd2) — QP · 2025 - [Maths LIT Grade 12 NSC P2 QP September 2025 Limpopo](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p2-qp-september-2025-limpopo/f22349c1-8dbf-420e-ae8d-13d53bcb300b) — QP · 2025 - [Maths LIT Grade 12 NSC P2 QP September 2025 North West](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p2-qp-september-2025-north-west/7ce5b7fe-941b-4148-80dc-d9cde7bdbfd7) — QP · 2025 ## Collection - [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. 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