# Mathematical Literacy Grade 10 P1 2026 Memo (Eng)

> Grade 10 Mathematical Literacy Paper 1 memorandum from the November Mock Exam 2 2026 (English), 7 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-10-mathematical-literacy-2026-november-mock-exam-2-memorandum-paper-1/6adfc418-ff0f-4518-b7e8-1aac04808f22
- Updated: 2026-10-29
- Subject: Mathematical Literacy
- Grade: Grade 10
- Language: English
- Document type: Memorandum
- Year: 2026
- Exam period: November Mock Exam 2
- Paper: 1
- Publisher: Hlayiso
- Curriculum: CAPS
- Pages: 7

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## About this document

Mathematical Literacy · Grade 10 · November Mock Exam 2 · 2026 · English. Memorandum, 7 pages. Read online or download the PDF.

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## Document text

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### Page 1

Mock

                             hlayiso mock exams
                             Practice Series:
                             Grade 10 Exam Preparation
                             WWW.HLAYISO.COM

                                  NATIONAL
                             SENIOR CERTIFICATE

                                     GRADE 10

                         MATHEMATICAL LITERACY P1
                     NOVEMBER EXAMINATION 2026 (MOCK)
                              MARKING GUIDELINES

MARKS: 75

                       These marking guidelines consist of 7 pages.

Copyright reserved                                                    Please turn over

### Page 2

Mathematical Literacy/P1                         2                                     Hlayiso/Mock 2026
                                       NSC – Marking Guidelines

SYMBOL AND EXPLANATION
 Symbol Explanation                                        Symbol      Explanation
 M      Method                                             A           Accuracy
 MA     Method with accuracy                               CA          Consistent accuracy
 C      Conversion                                         D           Definition
 F      Choosing the correct formula                       SF          Substitution in a formula
 J      Justification                                      O           Opinion/Reason/Example
 P      Penalty (e.g. no units, incorrect rounding)        R           Rounding
 RT/RG Reading from a table/graph                          S           Simplification
 NPR    No penalty for rounding                            AO          Answer only, full marks
KEY TO TOPIC AND LEVEL: F = Finance; M = Measurement; DH = Data handling; P = Probability;
L1–L4 = cognitive levels 1 to 4
NOTE:

    • If a candidate answers a question TWICE, only mark the FIRST attempt.
    • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at
      the second calculation error.
    • Answers only, without working, are awarded full marks unless stated otherwise.
    • In opinion or verification questions, marks are only awarded if the relevant calculations are
      shown.

QUESTION 1

 1.1.1       Fixed: rent / funeral policy / school fees / cellphone        ✓A ONE fixed expense
             contract / savings                                            ✓A ONE variable expense
             Variable: groceries / prepaid electricity / transport (taxi   (Accept clothing account as
             fares) / clothing account / entertainment                     either fixed or variable)
                                                                           F L1                      (2)

 1.1.2       Twenty-one thousand six hundred rand                          ✓✓A correct words
                                                                           (1 mark if “rand” is omitted)
                                                                           F L1                       (2)

 1.1.3       A = R4 200 ÷ 12                                               ✓M dividing by 12
             = R350                                                        ✓A answer
                                                                           F   L1                     (2)

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### Page 3

Mathematical Literacy/P1                      3                            Hlayiso/Mock 2026
                                    NSC – Marking Guidelines

 1.1.4       B = R4 950 + R4 380 + R1 246 + R1 640 + R385 +    ✓M adding ALL ten
             R350 + R399 + R600 + R1 000 + R650                expenses
             = R15 600                                         ✓CA answer from 1.1.3
                                                               F   L1                    (2)

 1.1.5       Surplus = R21 600 − R15 600                       ✓M income − expenditure
             = R6 000                                          ✓CA answer from 1.1.4
                                                               F L2                  (2)

 1.1.6       Rent + groceries = R4 950 + R4 380 = R9 330       ✓M adding rent and
                   R9 330                                      groceries
             %=            × 100%
                  R21 600                                      ✓M % of total income
             = 43,19%
                                                               ✓A/O 43,19% and
             43,19% < 50%, so her statement is VALID.          conclusion
             OR                                                (Alternative: ✓M adding
             Half of R21 600 = R10 800                         ✓M half of R21 600 ✓A/O
             R9 330 < R10 800, so her statement is VALID.      R10 800 and conclusion)
                                                               (Conclusion mark only if
                                                               calculations are shown)
                                                               F L3                     (3)

                                 2
 1.2         Emergency fund = × R6 000                         ✓M total parts = 5
                                 5
             = R2 400                                          ✓M 52 × surplus
             (Holiday fund = 35 × R6 000 = R3 600)             ✓CA answer from 1.1.5
                                                               F   L2                    (3)

                                                                                        [16]

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### Page 4

Mathematical Literacy/P1                       4                                   Hlayiso/Mock 2026
                                     NSC – Marking Guidelines

QUESTION 2

 2.1.1       15 September 2026     (15/09/2026)                       ✓✓RT correct date
                                                                      F   L1                      (2)

 2.1.2       It is the payment of R1 862,40 that Ms Mokoena made      ✓✓O explanation (payment
             (on 30/07/2026) to pay off the previous balance. It is   made / amount paid in /
             subtracted, so the balance brought forward is R0,00.     credit)
                                                                      F L2                    (2)

 2.1.3       Water used = 4 541 kℓ − 4 518 kℓ                         ✓RT both readings
             = 23 kℓ                                                  ✓M subtracting
                                                                      F   L1                      (2)

 2.1.4       First 6 kℓ: R0,00                                        ✓RT correct tariffs from the
             Next 9 kℓ: 9× R18,60 = R167,40                           table
             Remaining 23 − 15 = 8 kℓ: 8× R26,40 = R211,20            ✓M 9 kℓ × R18,60
             A = R0 + R167,40 + R211,20 = R378,60                     ✓M 8 kℓ × R26,40
                                                                      ✓CA total
                                                                      (Max 2 marks if 23 kℓ is
                                                                      multiplied by one tariff only)
                                                                      F L3                        (4)

 2.1.5       VAT = 15%× R185,00                                       ✓M 15% of R185,00
             = 0,15× R185,00 = R27,75                                 ✓A simplification
                                                                      F   L2                      (2)

 2.1.6       B = 15%× R378,60 = R56,79                                ✓CA value of B from 2.1.4
             C = R0,00 + R412,50 + R378,60 + R56,79 +                 ✓M adding ALL the current
             R185,00 + R27,75 + R238,00 + R35,70                      charges
             = R1 334,34                                              ✓CA value of C
                                                                      F L3                    (3)

 2.1.7       New tariff = R26,40 ×1,075                               ✓M increasing by 7,5%
               OR R26,40 + (7,5% × R26,40) = R26,40 + R1,98           ✓A new tariff
             = R28,38 per kℓ                                          ✓O conclusion
             R28,38 > R28,00, so her claim is VALID.                  F   L3                      (3)

Copyright reserved                                                                     Please turn over

### Page 5

Mathematical Literacy/P1                         5                                Hlayiso/Mock 2026
                                       NSC – Marking Guidelines

 2.2         n = 18 ÷ 12 = 1,5 years                                 ✓C converting 18 months to
             A = R7 800 (1 + 0,068 × 1,5)                            1,5 years
             = R7 800 × 1,102 = R8 595,60                            ✓SF substitution
             Interest = R8 595,60 − R7 800 = R795,60                 ✓CA final amount
             OR                                                      ✓CA interest
             Interest = R7 800 ×0,068 × 1,5 = R795,60                (Alternative I = P × i × n:
                                                                     ✓C 1,5 years ✓SF ✓M
                                                                     P × i × n ✓CA R795,60 – full
                                                                     marks)
                                                                     (If n = 18 is used: max 2
                                                                     marks)
                                                                     F L2                        (4)

                                                                                                [22]

QUESTION 3

 3.1.1       Discrete                                                ✓✓A
                                                                     DH   L1                     (2)

 3.1.2       9; 12; 14; 16; 18; 20; 22; 25; 25; 25; 28; 31; 35; 42   ✓✓A all 14 values in correct
                                                                     order
                                                                     (1 mark if one value is
                                                                     missing or out of order)
                                                                     DH L1                    (2)

                       22 + 25
 3.1.3       Median =                                                ✓M average of the 7th and
                           2
             = 23,5 bottles                                          8th values
                                                                     ✓CA answer from 3.1.2
                                                                     DH L2                    (2)

 3.1.4       Mode = 25 bottles                                       ✓✓A
                                                                     DH   L1                     (2)

 3.1.5       Sum = 9 + 12 + 14 + 16 + 18 + 20 + 22 + 25 + 25 +       ✓M adding the values
             25 + 28 + 31 + 35 + 42 = 322                            ✓M dividing by 14
                      322
             Mean =                                                  ✓CA answer
                      14
             = 23 bottles                                            DH   L2                     (3)

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### Page 6

Mathematical Literacy/P1                      6                                Hlayiso/Mock 2026
                                    NSC – Marking Guidelines

 3.1.6       More than 30 bottles: 31; 35; 42 ⇒ 3 members           ✓A 3 members
                                   3                                ✓M dividing by 14
             P(more than 30) =
                                  14                                ✓R decimal rounded to 2
             = 0,214 . . . ≈ 0,21
                                                                    decimal places
                                                                    P    L2                   (3)

 3.2.1       Paper = 100% − (35% + 20% + 15% + 8%)                  ✓M subtracting from 100%
             = 22%                                                  ✓A answer
                                                                    DH L2                  (2)

 3.2.2       Glass and cans = 20% + 15% = 35%                       ✓RG 20% and 15%
             Mass = 35% × 160 kg                                    ✓M percentage of 160 kg
             = 56 kg                                                ✓A answer with unit
             OR                                                     DH    L2                  (3)
             Glass = 0,2 × 160 = 32 kg; Cans = 0,15 × 160 = 24 kg
             Total = 32 + 24 = 56 kg

                                                                                            [19]

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### Page 7

Mathematical Literacy/P1                       7                                Hlayiso/Mock 2026
                                     NSC – Marking Guidelines

QUESTION 4

 4.1.1       Distance (in km)                                       ✓✓A
                                                                    F   L1                     (2)

 4.1.2       B = R650 + R8,50 ×150                                  ✓M R650 + R8,50 × 150
             = R650 + R1 275 = R1 925                               ✓A value of B
             A: R2 350 − R650 = R1 700                              ✓M subtracting R650 and
             A = R1 700 ÷ R8,50 = 200 km                            dividing by R8,50
             (Pattern: distance increases by 50 km, cost by R425)   ✓A value of A
                                                                    (AO: full marks)
                                                                    F   L2                     (4)

 4.1.3       Cost = R650 + R8,50 ×136                               ✓M substituting 136 km
             = R650 + R1 156 = R1 806,00                            ✓A total cost
             Per learner = R1 806 ÷22                               ✓M dividing by 22
             = R82,09                                               ✓O conclusion based on
             R82,09 < R85,00, so his statement is CORRECT.          R82,09
                                                                    (accept R82,10 / R82; NPR)
                                                                    F L4                     (4)

                            R1 199 − R899
 4.2.1       % discount =                 × 100%                    ✓SF substitution
                                R1 199
                R300                                                ✓S R300 discount
             =        × 100%                                        ✓CA percentage
               R1 199
             = 25,02% (accept 25%)                                  F   L2                     (3)

 4.2.2       Profit = R899 − R620                                   ✓M selling price − cost
             = R279,00                                              price
                                                                    ✓A answer
                                                                    F   L1                     (2)

 4.2.3       Total profit = 46× R279                                ✓M multiplying by 46
             = R12 834,00                                           ✓CA total profit from 4.2.2
             R12 834 > R12 500, so the manager’s claim is VALID.    ✓O conclusion
                                                                    F L3                      (3)

                                                                                              [18]

                                                                                   TOTAL:       75

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