# Mathematics Grade 10 Paper 2 KZN November 2024 Paper & Memo

> Grade 10 Mathematics Paper 2 question paper and memo from the KZN November Exam 2024, 20 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/grade-10-mathematics-2024-kzn-november-exam-question-paper-and-memorandum-paper-2/287a5196-5b77-419a-b85c-9f961a714f7f
- Updated: 2026-09-28
- Subject: Mathematics
- Grade: Grade 10
- Document type: Question paper and memo
- Year: 2024
- Exam period: KZN November Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 20

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Mathematics · Grade 10 · KZN November Exam · 2024. Question paper and memorandum, 20 pages. Read online or download the PDF.

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### Page 1

Downloaded from Stanmorephysics.com

KWAZULU-NATAL PROVINCE

EDUCATION
REPUBLIC OF SOUTH AFRICA

NATIONAL
SENIOR. CERTIBICATE

al

VLA P

anmorephisies.com

MARKS: _ 100

TIME: 2 hours

This question paper consists of 9 pages.

Copyright Reserved Please turn over

### Page 2

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INSTRUCTIONS AND INFORMATION

Read the following instructions carefully before answering the questions.

1; This question paper consists of 10 questions.
2. Answer ALL the questions.
3. Number the answers correctly according to the numbering system used in this

question paper.

4, Clearly show ALL calculations, diagrams, graphs, etc. which you have used in
determining your answers.

5; Answers only will NOT necessarily be awarded full marks.

6. You may use an approved scientific calculator (non-programmable and non-graphical),
unless stated otherwise.

Is If necessary, round off answers correct to TWO decimal places, unless stated otherwise.
8. Diagrams are NOT necessarily drawn to scale.

9. Write neatly and legibly.

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### Page 3

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QUESTION 1

Amahle recorded the amount of data (in MB) that she had used daily in the past 15 days.

[3 [10 [12 [13 [15 [15 [16 [18 [24 [26 [34 [40 [42 | 43 [45 |

1.1 Calculate the range of the data. (2)
12 Calculate the mean data usage. (2)
1.3 Write down the five number summary of the data. (3)
1.4 Draw a box and whisker diagram to represent the data. (3)
1.5 Determine the interquartile range. (3)
[13]
QUESTION 2

The compan
which

a survey at a gym in KwaZulu — Natal, to find out
health supplements.

FREQUENCY

29
28
21
15
10
2

2.1 Identify the modal class for the data. (1)
2.2 Determine the interval in which the median lies. ql)

23 Estimate the mean age of the people that use the health supplements. (4)

[6]

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### Page 4

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QUESTION 3

In the cartesian plane below, A(-3;0), B(0;2), C(2;-1) and D(-1;-3) are points on a
quadrilateral.

A(-3 ; 0)

3.1 Determine the coordinates of R , the midpoint of AC. (3)
3.2. Calculate the gradient of the line AB. (2)
3.3. Calculate the length of AC. (3)
3.4 If ABCD is a rhombus, calculate the area of ABCD. (5)
[13]

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### Page 5

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QUESTION 4

If 4tan@=-3 and cos@>0, WITHOUT using a calculator, determine the value of:

41 sin (3)

42 10cos* 6 (2)

43 3cot6+5sind (3)
[8]

QUESTION 5

5.1 In each of the following equations, solve for x where 0°<x<90'. Give your answers

correct to TWO decimal places.

S211 cosx=2 (2)
3
$12, 4 +1=3 (3)
cotx
5.2) Simplify fully, WITHOUT the use of a calculator.
tan 45°.cosec 60° (5)

cot 30°.cos’ 45

5.3 If x=56,3° and y=97,5°, evaluate the following correct to TWO decimal places.
5.3.1 cos(x+y) (2)
532 2sin” x-2
cos y (3)

[15]

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### Page 6

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QUESTION 6

The graphs of f(x)=psinx and g(x)=cosx+q for xe[0 ; 360°] are sketched below:

&
. x
270° 4
f
6.1 Determine the value of p and q. (2)
6.2 Write down the amplitude of g. (1)
6.3 Write down the range of /- (2)
64 For which value(s) of x will f(x)>02 (2)
6.5 The graph of g is reflected about the x-axis and then shifted 2 units upwards to

obtain the graph h. Write down the equation of h. (2)
19]

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### Page 7

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QUESTION 7

In the diagram below ABCD is a rectangle. DC = 155cm and DE = 800cm. The angle of elevation
from D to Eis 22° .

ald

7A Calculate the length of BE. (4)
1 Determine the distance of BC. (3)
17]

QUESTION 8

A metal marble has a diameter of 16 millimetres.

Volume of sphere = Sar

8.1 Calculate the volume of metal used to make this marble. Give your answer correct to

TWO decimal places. (3)
8.2 If the radius of the marble is doubled, write down the ratio of the new volume to the

original volume. (3)

[6]

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### Page 8

KZN/November 2024

Mathepsiwidded from Stanmorephysics.com

QUESTION 9

9.1 In quadrilater

Prove that WXYZ is a parallelogram. ()

9.2 In the sketch below, ABCD is a parallelogram. DC=DE and A =120°.

A s D
1
2
2
B C E

9.2.1 Calculate the size of:
a) B (2)
b) ¢, (2)
9.2.2 If D, =4x. Calculate the value of x. (4)

[13]

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### Page 9

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QUESTION 10

AXYZ is tight angled at Y. F and G are the midpoints of XZ and YZ respectively. H is the
midpoint of XG. E lies on XY such that FHE is a straight line.

x

Y
10.1 Prove that E is the midpoint of XY. (3)
10.2 If EH=3,5cm and the area of AHEX =9,5cm’. Calculate the length of XY. (4)
10.3 Hence, calculate the area of AXYZ. (3)
[10]

TOTAL: 100

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### Page 10

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education

Department:
Education

PROVINCE OF KWAZULU-NATAL

Stanmorephysies.com

sees 5

NATIONAL
SENIOR CERTIFICATE

(ane)

MARKS: = 100

The marking guidelines consist of 10 pages.

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### Page 11

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GRADE 10

QUESTION 1

Marking Guideline

November 2024

1 Range = Max — Min
=45-3
=42

Answer only, full marks

YA __ substitution
¥CA answer (only if
subst was shown)

(2)

Answer only, full marks

VA 356

¥CA_ answer (only if
divided by 15)
(2)

YA Min and Max

YAQ

YA Q, and Q,
(3)

1.4

Wdenree-
_

ae--

Ze--

oe

¥CA Min and Max

YCA Q,
YCA Q,and Q,

(3)

15 IQR = Q, -Q,
=40-13
=27

Answer only, full marks

YA formula
YCA substitution
¥CA answer

(3)

[13]

QUESTION 2

2.1 20<x<30

2.2 30<x<40

23 |< _ (25x29)+(35x28)+(45x21)+(55x15)+(6

_ 4275
105
= 40,71

105

(4)

*Penalise for Rounding here*

[6]

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November 2024

GRADE 10
Marking Guideline
QUESTION 3
x, $x, +
31 Mack = 2 ; 1h)
n( 22 130) YA substitution
2 2
R =l_-1 ¥CA_ x—value
2° 2 Answer only, full marks ¥CA_ y—value
On condition the coordinates of A
and C are used ONLY
QB)
32 May = VeVi
%,-%
a= 2-0 YA substitution
0-(-3)
2
ma r only, full marks ¥CA answer
Q)
43 AC= YA formula
AC= VA substitution
AC = 126 2 ? ¥CA answer
i ; ‘ G3)
3.4 BR = (x, -x,)° +(V, -yy

Area of ABCD = 2{ 4(40)(6R)]

-(v26)( 22)

2

= 13units*

YCA substitution
YCA distance of BR

YCA areaof Ax2

¥CA substitution

¥CA answer

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### Page 13

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GRADE 10
Marking Guideline

November 2024

OR OR
dy =\(-3+1) +(0+3) ¥CA length of AD
= 13 YCA length of DC
Ape = y(-1- 2y° +(-3+ ly YA formula for area
=V13
Area of ABCD = base x height YCA substitution
= diy Aye ¥CA answer
=Vi3xVi3
= 13units*
diagonal AC & BD = 26 units ¥CAYCA subst & length of DB
1 vA formula for area
Area of ABCD = 5 (duc xdyp)
1 ¥CA substitution
| (38%)
= 13units* ¥CA answer
(5)
[13]
QUESTION 4
4.1
vA tand= =
4
sin@=— vA value of r
¥CA answer
G3)

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### Page 14

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GRADE 10
Marking Guideline

November 2024

4.2 10cos*

=| of 4 ) ¥CA substitution
5
£92 Y¥CA answer
5
OR OR
10
sec’ 0 —
10 ¥CA substitution
= =
(3)
32 ¥CA answer
5 (2)
4.3 .
3cotO+5sind YCA =a
3 5
=-4-3 ¥CA simplification
mmo Answer only, max 2/3 YCA answer
See notes on last page
OR OR
3 +5sin0
tan
yl)
= +5| — —3
= V¥CA —s
2) 5 4
4
=-4-3 Answer only, max 2/3 YCA __ simplification
=7 See notes on last page YCA answer
Q)
[8]
QUESTION 5
5.1.1 2
cosx=>
5
x=cos” (2) YA __ simplification using arc cos
x=48.19° Answer only, full marks YA answer

(2)

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### Page 15

Mathenawnloaded from Stanmorephysics.com

November 2024

GRADE 10
Marking Guideline
5.1.2
4105
cotx
cotx=2. vA cotx =2
1
ee
tanx vA 1 _s4
1 tan x
tanx = =
2
x =26,57° ¥CA answer
GB)
5.2 tan 45°.cos ec60"
cot 30’.cos” 45° 5
VA —
3B
VA a/3)
2
va (2
2
See notes on last page YCA _ simplification
YCA answer
OR OR
tan 45° tan 30° oe 1
sin 60° cos” 45° 3
1 5,
1) =
BLES a 4 ale)
(2)
2\ 2
2
_ NB ae
9 3 See notes on last page ¥YCA - simplification
8
4 ¥CA answer
“3
(5)

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### Page 16

Mathemawnloaded from Stanmorephysics.com November 2024
GRADE 10

Marking Guideline

5.3.1 | coset)
= c0s(56,3’ +97,5°) VA substitution
=cos(153,6")
vi
==0,90 CA answer
(2)
5.3.2 | 2sin?x=2
cos y
2(sin 56,3" y -2 YA _ substitution in numerator
a 97,5 vA _ substitution in denominator
=4,72 ¥CA answer
(3)
[15]
QUESTION 6
6.1 p=2
q=l
2)
6.2 amplitude =\ (1)
6.3 2sys2 interval
notation
OR
ye [-2,2] A interval
¥A_ notation
(2)
6.4 0 < x<180 YA interval
YA notation
sa OR
ane (0' 5 180") YA. interval
YA. notation
Q)
6.5 h(x) =—cosx+1 YA =cosx
¥CA +1
(2)

[9]

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### Page 17

Mathemewnloaded from Stanmorephysics.com November 2024
GRADE 10
Marking Guideline

QUESTION 7
71 | fe oe
Hor vA correct trig ratio
AE = 800.sin 22°
vA AE=299,69
AE=299, 69cm
“BE = 299,69+155 ¥CA 299,69 + 155
BE = 454,69cem Y¥CA answer
(4)
7.2 AD _ 5599 vA correct trig ratio
AD = 800cos 22’
AD = 741,75 ¥CA  AD=741,75
. AD = BC (opposite sides of a rectangle)
BC = 741,75 cm YCA answer
OR OR
AD? + AE* = ED” ¥CA substitution
AD* +(299,69)° =(800)" YCA — AD=741,75
AD=741,75 YCA answer
BC =741,75cm
G3)
17]

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### Page 18

Mathemawnloaded from Stanmorephysics.com
GRADE 10

QUESTION 8

Marking Guideline

November 2024

8.1

V = 2144,66 mm’

vA r=8

vA substitution

YCA answer
(3)

8.2

r=2x8mm

=1l6mm

OR
4

57 (16) :=2(8)
(16)' :(8)
16:8

4096 : 512

8:1

VA - substitution with new r

YCA. division of volumes
¥CA answer

OR
YA $2(16)

YCA simplification
¥CA answer

3)

[6]

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### Page 19

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November 2024

GRADE 10
Marking Guideline
QUESTION 9
9.1 In AWXY and AYZW
1) WY is common vA Ss
2) ¥,=W, (Alternate angles WZ // XY ) vA SIR
3) X=Z (Given)
v
“ AWXY = AYZW (Z,2,S) “ R
XY = WZ (AWXY = AYZW) vA SIR
«. WXYZis a parallelogram (one pair of sides equal and //)_ | VA R
(5)
9.2.1(a) | B=180°-120° —_(co-interior angles AD // BC) vA SIR
B= 60° Penalise for parallel lines vA answer
here (2)
9.2.1(b) | A=C opposite sides of a parm VA S/R
C, =120°
% vA
C, =60° angles on a str. line a
OR OR
C, =180°-120° (corr. angles AB//DC)
6, =60° YASIR
vA answer
—_ (2)
9:22 E=C, angles opposite equal sides VA S/R
E+C,+ BD, =180° sumofA vA R
4x = 180° —120° vA substitution
4x = 60°
x=15° vA answer
(4)
[13]

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### Page 20

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GRADE 10
Marking Guideline

QUESTION 10

November 2024

10.1 In AXGZ F and H are midpoints (Given)
«. HE//GZ (midpoint theorem)
F 5 vA S/R
FE/YZ (same straight line) vA S
In AXYG_ H is the midpoint
EH//YG_ (Proved)
.. E is the midpoint (line through midpt // to second side) VA R
Q)
10.2 XEH =90° (corr. angles EF//YZ) vA R
Area = 5 (EHYXE)
9,5 = 5 N5xXE ¥ A Sub Corr formula
— 38_
te VA 38 5 43
76
“ XY = —=10,86
7 em YCA 2 =10,86
(4)
10.3 Y¥G=7 (midpt theorem)
YZ=14 (YG=GzZ) VAS
Area= EGG YCA sub
2 7
Area = 76cm’ ¥ CA answer
GB)
[10]
TOTAL: 100
NOTES:
QUESTION 4.3

Learners must show the simplification step to be awarded full marks.

QUESTION 5.2
Learners must show the simplification step to be awarded full marks.

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