# Mathematics Grade 10 KZN September Test 2024 Paper & Memo

> Grade 10 Mathematics question paper and memo from the KZN September Test 2024, 12 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/grade-10-mathematics-2024-kzn-september-test-question-paper-and-memorandum/f18a23a8-6723-494b-a8e3-06d14a152a1a
- Updated: 2026-09-28
- Subject: Mathematics
- Grade: Grade 10
- Document type: Question paper and memo
- Year: 2024
- Exam period: KZN September Test
- Curriculum: CAPS
- Pages: 12

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Mathematics · Grade 10 · KZN September Test · 2024. Question paper and memorandum, 12 pages. Read online or download the PDF.

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### Page 1

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                                     NATIONAL
                                SENIOR CERTIFICATE

                                          GRADE 10

                                     MATHEMATICS

                                     COMMON TEST

                                    SEPTEMBER 2024

MARKS: 75

TIME: 1 hour 30 minutes

              This question paper consists of 6 pages and 1 separate diagram sheet

Copyright Reserved                                                             Please Turn Over

### Page 2

Mathematics                                            2                    September 2024 Common Test
      Downloaded f rom St anmorephysics.
                              NSC –Grade 10 com
INSTRUCTIONS AND INFORMATION

Read the following instructions carefully before answering the questions.

1.      This question paper consists of 6 questions.

2.      Answer ALL the questions.

3.      Number the answers correctly according to the numbering system used in this
        question paper.

4.      Clearly show ALL calculations, diagrams, graphs, etc. which you have used in
        determining your answers.

5.      Answers only will NOT necessarily be awarded full marks.

6.      You may use an approved scientific calculator (non-programmable and non-graphical),
        unless stated otherwise.

7.      If necessary, round off answers correct to TWO decimal places, unless stated otherwise.

8.      Write neatly and legibly.

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### Page 3

Mathematics                                              3                      September 2024 Common Test
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                               NSC –Grade 10 com
QUESTION 1

 An advertisement in a local newspaper reads as follows:
                     Buy an iPhone 14 Pro Max cell phone for only R1 029 per month.
                     You have 36 months to pay.
                     No deposit is required.

 1.1          Calculate the total amount to be paid over a period of 36 months.                              (1)

 1.2          The monthly instalment quoted in the advertisement, is calculated on a hire purchase
              agreement which charges interest of 8,2% p.a. on the cash price of the cell phone.
              Calculate the cash price of the cell phone.                                                    (3)

 1.3          The cost of the cell phone is subject to inflation and increases to a cash price of
              R31 968, 11 after 3 years. Calculate the annual inflation rate.                                (4)
                                                                                                             [8]

QUESTION 2

 2.1          On a trip to America, Charity booked into a hotel for five days. The exchange rate at
              that time was $1=R18,73. The cost of the hotel per day was $104.
              How much did she spend, in rands, for five days?                                               (3)

 2.2          Mr Zungu from Sparks Estate Secondary takes out a loan to buy furniture for his
              office. The loan is repaid in ONE payment of R189 389,80 at the end of 4 years. The
              interest paid on the loan is 10% p.a. compounded annually. Calculate the amount of
              money borrowed from the bank to buy furniture.                                                 (4)
                                                                                                             [7]

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Mathematics                                             4                      September 2024 Common Test
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                               NSC –Grade 10 com
QUESTION 3

 3.1          Given: P  A  0,4 ; P  B   0,5 and P  A and B   0,25 . Determine the:

              3.1.1       P  not B                                                                        (1)

              3.1.2       P  A or B                                                                       (2)

              3.1.3       P  not A and B                                                                  (3)

 3.2          In a school of 70 Grade 10 learners, 32 learners take Economics (E), 43 take
              Mathematics (M) and 15 learners take neither of these two subjects.
              Let the number of learners who take both subjects be x .

              3.2.1       Show that x  20 .                                                                (3)

              3.2.2       Draw a Venn diagram to illustrate the above information.                          (3)

              3.2.3       Determine the probability of a learner taking:

                              (a) Economics and Mathematics.                                                (2)

                              (b) at least ONE of the two subjects.                                         (2)

                              (c) taking EXACTLY ONE subject.                                               (2)

              3.2.4       The probability that a Mathematics learner is also a Physical Sciences
                          learner is 79%. Determine the number of learners that take Physical               (3)
                          Sciences.
                                                                                                            [21]

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Mathematics                                                5                       September 2024 Common Test
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                               NSC –Grade 10 com
QUESTION 4

 At a School Athletics Day, a stopwatch was used to find the time it took a group of athletes to
 run the 200m event. The results were recorded in a frequency table below.

              Class intervals (time in seconds)                Frequency (number of athletes)
                         20  x  30                                         6
                         30  x  40                                        16
                         40  x  50                                        21
                         50  x  60                                         8

 4.1           How many athletes ran the 200m event?                                                             (1)
 4.2           Calculate the estimated mean.                                                                     (4)
 4.3           What is the modal class interval                                                                  (1)
 4.4                                                                
               Identify in which class interval the thirtieth 30th percentile lies.                              (2)
 4.5           Represent the data on a histogram, using the attached DIAGRAM SHEET.                              (3)

                                                                                                                 [11]

QUESTION 5

 The following Life Sciences marks, for a test out of 50, were recorded from 15 grade 10
 learners at a certain school.

       10      13     15    17    18    20    23      24   26       28   28   29    39   48     49

 5.1          Write down the median.                                                                            (1)

 5.2          Determine:
              5.2.1        The mean of the data.                                                                (2)
              5.2.2        The range.                                                                           (1)
              5.2.3        The interquartile range.                                                             (3)

 5.3          Draw a box and whisker diagram to represent the data above.                                       (3)

 5.4          The pass mark for the Life Sciences test was 30%. How many learners passed?                       (2)

                                                                                                                [12]

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Mathematics                                                6                       September 2024 Common Test
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                               NSC –Grade 10 com
QUESTION 6

 6.1          Given: f  x   2sin x  1 and g  x   tan x , where x  [0 ;270 ]

              6.1.1       Write down the:
                              (a) period of g .                                                                 (1)
                              (b) range of 𝒇 .                                                                  (2)

              6.1.2       On the same set of axes provided on the DIAGRAM SHEET, sketch the
                          graphs of f and g . Clearly indicate all intercepts with the axes, as well as
                          turning points and end points of the graphs.                                          (4)

              6.1.3       Determine the value(s) of x where g  x   0 .                                       (2)

 6.2          A handy man attempts to reach the roof of a hall with a ladder 5 metres in length.
              Unfortunately, the ladder is too short, and a new ladder will be required. Suppose that
              the length of the ladder needed to reach the top has to be double the distance from the
              foot of the ladder to the wall. Also, the angle between his current ladder and the
              ground will need to be equal to the angle between the two ladders.

              The above situation is depicted in the diagram below.

                                                     x

               6.2.1        Calculate the value of  .                                                           (3)

               6.2.2        If   30 , determine what the length of the ladder should be, to get the            (4)
                            handy man to the roof.
                                                                                                                 [16]
                                                                                                TOTAL:           [75]

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### Page 7

Mathematics                                 7      September 2024 Common Test
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                              NSC –Grade 10 com
                                   DIAGRAM SHEET

Learner’s Name : _____________________________

QUESTION 4.5

QUESTION 6.1.2

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### Page 8

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                                MATHEMATICS

                               COMMON TEST

                              SE PT E M BE R 202 4

                            M AR K I NG G U I D E L INE

                                NATIONAL
                            SENIOR CERTIFICATE

                                    GRADE 10

 MA R K S:   75

                     This marking guideline consists of 5 pages.

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Mathematics                                                    2             September 2024 Common Test
                                                          NSC-GRADE 10
                                                         Marking Guideline

QUESTION 1

 1.1     T otal am ou n t  R 1 0 2 9  3 6
                                 = R 37 044                                   Answer                             (1)
 1.2     A  P 1  i  n                                                   formula
                                                                             substitution
         3 7 0 4 4  P  1  0, 0 8 2  3 

         P  R 2 9 7 3 0, 3 4                                                answer
                                                                                                                 (3)
 1.3     A  P 1  i 
                             n
                                                                             formula
                                                     3
         3 1 9 6 8, 1 1  2 9 7 3 0, 3 4  1  i 
                                                                             substitution
                   3 1 9 6 8, 1 1
         i    3                    1                                                 3 1 9 6 8, 1 1
                   2 9 7 3 0, 3 4                                            i3                       1
                                                                                      2 9 7 3 0, 3 4
         i  2, 4 5 % p .a

                                                                             answer                             (4)
                                                                                                                 [8]
QUESTION 2

 2.1     $1  R 18, 73
         $104 = x
                                                                              R 1 9 4 7 , 9 2
         x  R 1 9 4 7 , 9 2 p er d ay
         total sp en d i n g = R 9 7 3 9 , 6                                 answer
                                                                                                                 (3)
 2.2     A  P 1  i 
                             n
                                                                             formula
                                               4
          1 8 9 3 8 9 .8 0  P  1  0, 1                                    substitution
            P  R 129 355, 78
                                                                             answer

                                                                                                                 (4)
                                                                                                                 [7]

QUESTION 3

 3.1.1    P  n ot B   0, 5                                                answer
                                                                                                                 (1)
 3.1.2    P  A or B   P  A   P  B   P  A an d B                   formula
                           = 0, 4 + 0, 5       0, 2 5
                                                                             answer
                           = 0, 65                                                                               (2)
 3.1.3    P  n ot A an d B   0, 5  0, 2 5                                 0, 5  0, 2 5
                                                                             answer
                                    = 0, 25                                                                      (3)
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Mathematics                                                                  3      September 2024 Common Test
                                                                 NSC-GRADE 10
                                                                Marking Guideline

 3.2     32  x  x  43  x 15  70                                                32  x  x  43  x 15
          x  20                                                                    equating to 70
                                                                                    answer                             (3)
 3.2.2                                                                              12

                                                                                    20

                                                                                    23

                                                                                    15

                                                                                                                        (4)
 3.2.3                             20        2                                      answer
         (a) P  E an d M                      0, 2 9
                                   70        7                                                                          (2)
 3.2.3                                  55        11                                answer
         (b) P  A t l east on e                     0, 7 9
                                        70        14                                                                    (2)
 3.2.3                                  12  23            35       1               answer
         (c) P  E x actl y on e                                     0, 5
                                             70            70       2                                                   (2)
 3.2.4    P h y si cal sci en ce  4 3  7 9 %                                       4 3  7 9 %
                                 3 3, 9 7
                                                                                    answer
                                 3 4 l earn ers
                                                                                    Answer only: full marks
                                                                                                                         (3)
                                                                                                                        [21]

QUESTION 4

 4.1.    51 athletes                                                                answer                             (1)
 4.2                     ( 6  2 5)  (1 6  3 5)  ( 4 5  2 1)  (5 5  8)        numerator
         M ean  x  
                                                       51                           denominator
                                                                                     2095
                         2095
                     =
                          51
                                                                                    answer
                     = 41, 08                                                                                           (4)
 4.3     40  x  50                                                                answer
                                                                                                                        (1)
 4.4     30  x  40                                                                answer
                                                                                                                        (2)

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Mathematics                              4              September 2024 Common Test
                                    NSC-GRADE 10
                                   Marking Guideline

 4.5
                                                        20-40

                                                       40-50

                                                       50-60

                                                                                          (3)
                                                                                         [11]

QUESTION 5

 5.1   Median = 24                                      answer                          (1)
 5.2.1        387                                          387
          M ean =                                      
                       15                                  15
                 = 25, 8                               answer
                                                       Answer only: full marks           (2)
 5.2.2    ran g e = 4 9  1 0                          answer
                 = 39                                                                    (1)
 5.2.3    I Q R = 29  17                               2 9  1 7
                = 12
                                                       answer

                                                                                         (3)
 5.3
                                                        10 and 49
                                                       24
                                                       17 and 29

                                                                                         (3)
 5.4      15                                           pass mark
               is the pass mark.                       answer
          50
         ∴13 learners passed.                          Answer only: full marks           (2)
                                                                                         [12]

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Mathematics                                                5             September 2024 Common Test
                                                      NSC-GRADE 10
                                                     Marking Guideline

QUESTION 6

 6.1.1 a) P er i od = 1 8 0                                                answer                    (1)
 6.1.1 b) Range : y   1; 3                                              notation
         OR                                                                 values
         Range: 1  y  3                                                                             (2)
 6.1.2

                                                                            shape of f

                                                                            shape of g

                                                                            asymptotes of g

                                                                            turning point of f

                                                                                                       (4)
 6.1.3    0   x  9 0  OR 1 8 0   x  2 7 0                            0  x  90
                                                                             180  x  270          (2)
 6.2.1                  x        1                                                       x        1
          cos 2                                                           cos 2         
                        2x       2                                                       2x       2
              2  60
                                                                             2  60
                = 30
                                                                            answer                    (3)
 6.2.2                  x                                                                     x
          cos 3 0                                                          cos 3 0  
                        5                                                                     5
          x  4, 3 3                                                        value of x
                                                                            answer
          L en g th of th e l ad d er = 8 , 6 6 m                                                      (4)

                                                                                                       [15]

                                                                            TOTAL:                     [75]

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