# Mathematics Grade 10 Paper 1 North West November 2024 Memo

> Grade 10 Mathematics Paper 1 memorandum from the North West November Exam 2024, 7 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-10-mathematics-2024-north-west-november-exam-question-paper-paper-1/056a97f6-b59a-4d1b-9ae3-94ac6091961a
- Updated: 2026-10-29
- Subject: Mathematics
- Grade: Grade 10
- Document type: Memorandum
- Year: 2024
- Exam period: North West November Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 7

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Mathematics · Grade 10 · North West November Exam · 2024. Memorandum. Read online or download the PDF.

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### Page 1

PROVINCIAL ASSESSMENT
                           PROVINSIALE ASSESSERING

                                   GRADE/GRAAD 10

                                            G

                             MATHEMATICS P1/WISKUNDE V1

                                        NOVEMBER 2024

                           MARKING GUIDELINES/NASIENRIGLYNE

MARKS/PUNTE: 100

TIME/TYD: 2 hours/uur

                      These marking guidelines consists of 7 pages.
                       Hierdie nasienriglyne bestaan uit 7 bladsye.

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### Page 2

Mathematics P1/Wiskunde V1                                2                        NW/November 2024
                                Grade 10/Graad 10 – Marking Guidelines/Nasienriglyne

 QUESTION/VRAAG 1
 1.1.1 𝑥 2 − 16𝑥 + 15
       = (𝑥 − 1)(𝑥 − 15)                                                   answer/antwoord
                                                                                                        (1)
 1.1.2 𝑎(6𝑎 + 2𝑏) − 3(3𝑎 + 𝑏)
                                                                           common factor/
         = 2𝑎(3𝑎 + 𝑏) − 3(3𝑎 + 𝑏)
                                                                            gemeenskaplike faktor
         = (3𝑎 + 𝑏)(2𝑎 − 3)                                                answer/antwoord
                                                                                                        (2)
                2                                                             3
               3
 1.2.1 (33 ) / √(33 )2
                3                                                          √(33 )2
       = 32
       =9                                                                  9
         OR / OF
                                                                                  3
          3
         ( √27)2                                                           ( √27)2

         = 32
         =9                                                                9
                                                                                                        (2)
 1.2.2 𝑥 + 3 𝑥 3 − 27     𝑥−3
            × 2       × 2                                                             𝑥−3
       𝑥 − 3 𝑥 − 9 𝑥 + 3𝑥 + 9                                              × 𝑥 2 +3𝑥+9

           𝑥 + 3 (𝑥 − 3)(𝑥 2 + 3𝑥 + 9)     𝑥−3                             (𝑥 − 3)(𝑥 2 + 3𝑥 + 9)
         =      ×                      × 2
           𝑥−3      (𝑥 − 3)(𝑥 + 3)      𝑥 + 3𝑥 + 9                         (𝑥 − 3)(𝑥 + 3)

         =1                                                                answer/antwoord
                                                                                                       (4)
         3𝑥+1 (1−3)           3𝑥 (3−32 )                                     common factor numerator/
 1.2.3                    /
         3𝑥 (32 +1)           3𝑥 (32 +1)                                      gemeenskaplike faktor teller
              31 (−2)                                                        common factor denominator
         =      10                                                            gemeenskaplike faktor
          (−6)                                                                noemer
         =                                                                   simplifying/vereenvoudig
           10
            3                                                                answer/antwoord
         =−
            5

         OR/OF
         3𝑥 .3 − 3𝑥 .32
                                                                           common factor numerator/
          3𝑥 .32 + 3𝑥
                                                                            gemeenskaplike faktor teller
          3𝑥 (3−32 )                                                       common factor denominator
         =3𝑥 (32 +1)                                                        gemeenskaplike faktor
           −6                                                               noemer
         =                                                                 simplifying/vereenvoudig
            10
               3                                                           answer/antwoord
         = −5
                                                                                                        (4)
                                                                                                       [13]

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### Page 3

Mathematics P1/Wiskunde V1                             3                        NW/November 2024
                             Grade 10/Graad 10 – Marking Guidelines/Nasienriglyne

 QUESTION/VRAAG 2
 2.1.1 2. 32𝑥 = 2. 32                                                     factorising/faktoriseer
       32𝑥 = 32                                                           simplifying/vereenvoudig
       2𝑥 = 2                                                             simplifying/vereenvoudig
        𝑥=1                                                               answer/antwoord
                                                                                                   (4)
 2.1.2 2𝑥 − 1 ≥ 3(2𝑥 + 1)                                                 simplifying /vereenvoudig
       2𝑥 − 1 ≥ 6𝑥 + 3                                                    multiplication brackets
       −4𝑥 ≥ 4                                                            simplifying/vereenvoudig
          𝑥 ≤ −1                                                          answer/antwoord
                                                                                                   (4)
 2.1.3    2𝑥 2 − 𝑥 − 10 = 0
         (2𝑥 − 5)(𝑥 + 2) = 0                                            factorising/faktoriseer
         2𝑥 – 5 = 0 of 𝑥 + 2 = 0                                        equal to 0/stel gelyk aan 0
              5   1
         𝑥 = 2 /2 2 / 2,5 or / of 𝑥 = −2                               answers/antwoorde
                                                                                                    (4)
 2.2     (𝑥 + 5)(𝑥 − 5) = 𝑥 2 − 25                                      𝑥 2 − 25
                                                                        𝑥2 − 25
         (𝑥 + 1)(𝑥 − 25) = 𝑥 2 − 24𝑥 − 25                               −24𝑥
         −24𝑥 must be added at (𝑥 + 5)(𝑥 − 5)
         −24𝑥 moet by (𝑥 + 5)(𝑥 − 5) bygetel word                         answer/antwoord
                                                                                                      (4)
 2.3     𝑦 = 3𝑥 − 2………………...................... (1)                     3𝑥 − 2
         7𝑥 – 2𝑦 = 8 ………………………………. (2)
         7𝑥 – 2(3𝑥 – 2) = 8                                             substitution/vervanging
         7𝑥 – 6𝑥 + 4 = 8
         𝑥 = 4                                                          𝑥 = 4
         𝑦 = 3(4) − 2
         𝑦 = 10                                                         𝑦 = 10
                                                                                                     (4)
                                                                                                    [20]

 QUESTION/VRAAG 3
 3.1.1 𝑇𝑛 = 3𝑛                                                          3n
                                                                                                     (1)
 3.1.2 𝑇300 = 3(300)                                                    substitution/vervanging
       𝑇300 = 900                                                       answer/antwoord
                                                                       CA from/van 3.1.1
                                                                                                     (2)
 3.1.3 1500 = 3𝑛                                                        substitution/vervanging
       𝑛 = 500                                                          answer/antwoord
                                                                       CA from /van 3.1.1
                                                                                                     (2)

 3.2     TERMSTERMS..repeat after the fifth letter.                     see pattern/sien patroon

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### Page 4

Mathematics P1/Wiskunde V1                             4                        NW/November 2024
                             Grade 10/Graad 10 – Marking Guidelines/Nasienriglyne

        TERMSTERMS..herhaal na die vyfde letter.
        383
            = 76 𝑟𝑒𝑚𝑎𝑖𝑛𝑑𝑒𝑟 3                                            ÷5
         5
                                                                        answer/antwoord
        The 383rd letter will be a R / Die 383ste letter sal ‘n R
        wees.
                                                                                                     (3)
 3.3.1 36 ; 43                                                         answers/antwoorde
                                                                                                     (2)
 3.3.2 Add 7 to the previous term / Tel 7 by die vorige term.          answer/antwoord
                                                                                                     (2)
                                                                                                    [12]

 QUESTION/VRAAG 4
 4.1    3 x $ 450 = $ 1 350                                             3 x $ 450 = $ 1 350
        $ 1 350 x R 9,10                                                $ 1 350 x R 9,10
        = R 12 285                                                      answer/antwoord
                                                                                                     (3)
 4.2.1 Balance/Balance = R20 000 – R3000 – R2000                        20 000 – 3000 – 2000
                = R15 000                                               answer/antwoord
       Total installments/Totale paaiemente = 24 x R900                 24 x R900
                                              = R21600                  Total installments/Totale
       Total interest paid = Total installments – Balance                paaiemente
        Totale rente betaal= Totale paaiemente - Balans
                                = R21 600 – R15 000                     R21 600 – R15 000
                                = R6 600                                answer/antwoord
                                                                                                     (6)
 4.2.2 𝐴 = 𝑃(1 + 𝑛𝑖)                                                    formula/formule
       21 600 = 15 000(1 + 2𝑖)                                          substitution/invervanging
                                                                        simplification/vereenvoudig
        21 600
                 − 1 = 2𝑖
        15 000
        0,22 = i                                                        answer/antwoord
        r = 22 %                                                                                     (4)
                                                                                                    [13]

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### Page 5

Mathematics P1/Wiskunde V1                             5                        NW/November 2024
                             Grade 10/Graad 10 – Marking Guidelines/Nasienriglyne

 QUESTION/VRAAG 5
 5.1
                                                                        𝑓(𝑥): intercepts/afsnitte
                                                                        𝑓(𝑥): shape & turning point
                                                                                vorm en draaipunt
                                                                        𝑔(𝑥): intercept/afsnit
                                                                        𝑔(𝑥): shape/vorm
                                                                        𝑔(𝑥): asymptote/asimptote

                                                                                                     (5)

 5.2    TP (0;4)                                                        answer/antwoord             (1)

 5.3    The graph of 𝑓 is reflected in the 𝑥 – axis /                   reflected/refleksie
                                                                        𝑥-axis/as
        OR
        𝑓 is reflected in the line 𝑦 = 0.                               reflected/refleksie
                                                                        𝑦=0

                                                                                                     (2)
                                                                                                     [8]

 QUESTION/VRAAG 6
 6.1    𝑐 = −4                                                          𝑐 = −4
             −8
        𝑚=      =2                                                      𝑚=2
             −4
        OR /OF
        Substitute/Vervang A (4;4)
        𝑔(𝑥) = 𝑚𝑥 − 4                                                   substitution/vervanging
             4 = 𝑚(4) − 4
            8 = 4𝑚
            𝑚=2
                                                                        𝑚=2
        OR / OF
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### Page 6

Mathematics P1/Wiskunde V1                             6                        NW/November 2024
                             Grade 10/Graad 10 – Marking Guidelines/Nasienriglyne

               Δ𝑦
        𝑚=
               Δ𝑥
               4 − (−4)
           =                                                            substitution/vervanging
                 4−0
               8
            =4

            =2                                                          𝑚=2
                                                                                                     (2)
 6.2    𝑦 ∈ 𝑅; 𝑦 ≠ −2                                                   𝑦∈𝑅
                                                                        𝑦 ≠ −2
                                                                                                     (2)

 6.3    4                                                                  4
          − 2 = 2𝑥 − 4                                                        − 2 = 2𝑥 − 4
        𝑥                                                                  𝑥

        4 − 2𝑥 = 2𝑥 2 − 4𝑥
               0 = 2𝑥 2 − 2𝑥 − 4                                        0 = 2𝑥 2 − 2𝑥 − 4
             B (2; 0) E (−1; −6)                                        B (2; 0)
                                                                        E (−1; −6)
                                                                                                     (4)
 6.4    −1 ≤ 𝑥 < 0 or 𝑥 ≥ 2                                             −1 ≤ 𝑥 < 0
                                                                        𝑥≥2
                                                                         CA from/van 6.3
                                                                                                     (2)
 6.5           4                                                                    4
        𝑓(4) = − 2                                                      𝑓(4) = 4 − 2
               4
             = −1                                                       −1
        𝐴𝐶 = 4 + 1                                                      𝐴𝐶 = 4 + 1
           = 5 units/eenhede                                                =5
                                                                                                     (3)
                                                                                                    [13]

 QUESTION/VRAAG 7
 7.1    𝑦 = −2                                                          𝑦 = −2
                                                                                                     (1)

 7.2    𝑎=1                                                             𝑎=1
        𝑞 = −2                                                          𝑞 = −2

        0 = (1)𝑏1 − 2
        ∴𝑏=2                                                            𝑏=2

        ∴ ℎ(𝑥) = 2𝑥 − 2                                                 ℎ(𝑥) = 2𝑥 − 2
                                                                       CA from/van 7.1
                                                                                                     (4)

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### Page 7

Mathematics P1/Wiskunde V1                             7                        NW/November 2024
                             Grade 10/Graad 10 – Marking Guidelines/Nasienriglyne

 7.3    𝑦 = −1                                                          𝑦 = −1
        OR / OF
        20 − 2
        = −1                                                                                         (1)
                                                                                                     [6]
 QUESTION/VRAAG 8
 8.1    𝑃(𝐴) + 𝑃(𝐵) = 0,43 + 0,37                                       0,43 + 0,37
                     = 0,80
                 Not complementary events /                             conclusion/gevolgtrekking
                 Nie komplimentêre gebeurtenisse.
                     𝑃(𝐴) + 𝑃(𝐵) ≠ 1                                                                 (2)
 8.2    𝑃(𝐴 𝑎𝑛𝑑 𝐵) ≠ 0                                                  𝑃(𝐴 𝑎𝑛𝑑 𝐵) ≠ 0
        Not mutually exclusive events/                                  conclusion/gevolgtrekking
        Nie onderling uitsluitende gebeurtenisse.                                                    (2)
 8.3                                                                    0,2709
                                                     𝑩                  0,1591
                      𝑨                                                 0,2109
                                                                        0,3591
                          0,2709    0,1591     0,2109

                                                      0,3591
                                                                                                     (4)
                                                                                                     [8]

 QUESTION/VRAAG 9
 9.1    𝑃(𝑁𝑜𝑡 𝐴) = 1 − 𝑃(𝐴) / 𝑃(𝑁𝑖𝑒 𝐴) = 1 − 𝑃(𝐴)
             2
        =1−                                                                    2
             3                                                          1−3
          1                                                               1
        =                                                               3
          3
                                                                                                     (2)
                             1
 9.2    𝑃(𝐵) = 1 − 𝑃(𝐵 )
             3
        =1−                                                                   3
             5                                                          1−5
          2                                                               2
        =                                                               5
          5
                                                                                                     (2)
 9.3    𝑃(𝐴 𝑜𝑟/𝑜𝑓 𝐵) = 𝑃(𝐴) + 𝑃(𝐵) − 𝑃(𝐴 and/𝑒𝑛 𝐵)                      formula/formule
               4    2   2
                  = 3 + 5 − 𝑃(𝐴 and/𝑒𝑛 𝐵)                               substitution/substitusie
               7
                             52                                         answer/antwoord
        𝑃(𝐴 and/𝑒𝑛 𝐵) = 105

                                                                                                     (3)
                                                                                                     [7]
                                                                              TOTAL/TOTAAL: 100

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