# Mathematics Grade 10 P1 November Mock 2026 Memo (English)

> Grade 10 Mathematics Paper 1 memorandum from the November Mock Exam 2026 (English), 9 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-10-mathematics-2026-november-mock-exam-memorandum-paper-1/4285dfec-47d7-4d13-86c3-d23b9d84fca8
- Updated: 2026-10-29
- Subject: Mathematics
- Grade: Grade 10
- Language: English
- Document type: Memorandum
- Year: 2026
- Exam period: November Mock Exam
- Paper: 1
- Publisher: Hlayiso
- Curriculum: CAPS
- Pages: 9

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## About this document

Mathematics · Grade 10 · November Mock Exam · 2026 · English. Memorandum, 9 pages. Read online or download the PDF.

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## Document text

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### Page 1

hlayiso mock exams
                             Practice Series:
                             Grade 10 Exam Preparation
                             WWW.HLAYISO.COM

                                  NATIONAL
                             SENIOR CERTIFICATE

                                     GRADE 10

                                 MATHEMATICS P1
                     NOVEMBER EXAMINATION 2026 (MOCK)
                              MARKING GUIDELINES

  MARKS: 100

                       These marking guidelines consist of 9 pages.

Copyright reserved                                                    Please turn over

### Page 2

Mathematics/P1                                  2                                   Hlayiso/Mock 2026
                                      NSC – Marking Guidelines

NOTE:

    • If a candidate answers a question TWICE, only mark the FIRST attempt.
    • If a candidate has crossed out an attempt of a question and not redone the question, mark the
      crossed-out version.
    • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines. Stop marking at the
      second calculation error.
    • Assuming answers/values in order to solve a problem is NOT acceptable.
    • The mark for substitution is awarded for substitution into the correct formula.

QUESTION 1

             √       √      √                                            √       √
 1.1           49 < 58 < 64                                            ✓ 49 and 64
                 √
             7√< 58 < 8                                                ✓ 7 and 8                   (2)
               58 lies between 7 and 8.

 1.2.1       = 2x3 + 2x2 − 8x − 3x2 − 3x + 12                          ✓ 2x3 + 2x2 − 8x
             = 2x3 − x2 − 11x + 12                                     ✓ −3x2 − 3x + 12
                                                                       ✓ answer                    (3)

              (x − 3)(x + 3) 2(x − 2)
 1.2.2       =               ×                                         ✓ (x − 3)(x + 3)
              (x + 3)(x − 2)   x−3
                                                                       ✓ (x + 3)(x − 2)
             =2                                                        ✓ 2(x − 2)
                                                                       ✓ answer                    (4)

               3x .32 − 3x
 1.2.3       =                                                         ✓ splitting the powers
               4 . 3x .3−1
                                                                       ✓ common factor 3x (9 − 1)
               3x (9 − 1)
             =                                                         ✓ answer                 (3)
                4 . 3x . 13
               8
             = 4 =6
                 3

 1.3.1       (2x − 5)(x + 3)                                           ✓ (2x − 5)
                                                                       ✓ (x + 3)                   (2)

 1.3.2       = (x − 3)(x2 + 3x + 9) + 2(x − 3)                         ✓ (x − 3)(x2 + 3x + 9)
             = (x − 3)(x2 + 3x + 9 + 2)                                ✓ +2(x − 3)
             = (x − 3)(x2 + 3x + 11)                                   ✓ answer                    (3)

                                                                                                  [17]

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### Page 3

Mathematics/P1                                   3                             Hlayiso/Mock 2026
                                       NSC – Marking Guidelines

QUESTION 2

 2.1.1       3x2 − 5x − 2 = 0                                     ✓ standard form
             (3x + 1)(x − 2) = 0                                  ✓ factors
                   1                                              ✓ both answers               (3)
             x=−       or x = 2
                   3
                      4   1
 2.1.2       5x+1 =     =   = 5−2                                 ✓ 25
                                                                     1
                     100 25
             x + 1 = −2                                           ✓ 5−2 / equating exponents
             x = −3                                               ✓ answer                 (3)

 2.2         −4 − 2 < −3x ≤ 11 − 2                                ✓ subtracting 2
             −6 < −3x ≤ 9                                         ✓ dividing by −3 and
             2 > x ≥ −3                                           reversing signs
             −3 ≤ x < 2                                           ✓ −3 ≤ x < 2

                 −4 −3 −2 −1       0    1   2   3                 ✓ number line (closed dot at
                                                                  −3, open dot at 2)        (4)

 2.3         x = 14 + 4y …(1)                                     ✓ x the subject
             3(14 + 4y) + 2y = 7                                  ✓ substitution
             42 + 12y + 2y = 7
             14y = −35
                   5                                              ✓ y = − 25
             y=−
                   2 ( )                                          ✓x=4                         (4)
                            5
             x = 14 + 4 −      =4
                            2
             OR (elimination): (1) × 2: 6x + 4y = 14; add to
             x − 4y = 14: 7x = 28 …

                                                                                              [14]

QUESTION 3

 3.1.1       21 ; 25                                              ✓ both terms                 (1)

 3.1.2       d=4                                                  ✓ 4n
             Tn = 4n + 1                                          ✓ +1                         (2)

 3.1.3       T40 = 4(40) + 1 = 161                                ✓ substitution
                                                                  ✓ answer                     (2)

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### Page 4

Mathematics/P1                                  4                              Hlayiso/Mock 2026
                                      NSC – Marking Guidelines

 3.1.4       4n + 1 = 297                                        ✓ equating
             4n = 296                                            ✓ answer                    (2)
             n = 74 ∴ the 74th term

 3.2.1       4 ; 7 ; 10 ; 13 ; 16                                ✓ answer                    (1)
             Diagram 5 needs 16 matches.

 3.2.2       d=3                                                 ✓ 3n
             Tn = 3n + 1                                         ✓ +1                        (2)

 3.2.3       3n + 1 ≤ 150                                        ✓ 3n + 1 ≤ 150 (or = 150)
                 149
             n≤       = 49,67
                   3                                             ✓ Diagram 49
             Largest diagram: Diagram 49
             T49 = 3(49) + 1 = 148 matches                       ✓ 2 matches                 (3)
             150 − 148 = 2 matches left over

                                                                                            [13]

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### Page 5

Mathematics/P1                                  5                                Hlayiso/Mock 2026
                                      NSC – Marking Guidelines

QUESTION 4

 4.1.1       A = P(1 + ni)                                           ✓ substitution
             A = 12 000(1 + 4 × 0,085)                               ✓ answer                    (2)
             A = R16 080

 4.1.2       A = P(1 + i)n                                           ✓ substitution
             A = 12 000(1 + 0,078)4                                  ✓ answer                    (2)
             A = R16 205,27

 4.1.3       Option B, because it gives the greater amount after 4   ✓ option with reason        (1)
             years (R125,27 more).

 4.2         Deposit = 10% × 9 600 = R960
             Balance = 9 600 − 960 = R8 640                          ✓ R8 640
             A = 8 640(1 + 3 × 0,14) = R12 268,80                    ✓ substitution
                                   12 268,80                         ✓ R12 268,80
             Monthly instalment =            = R340,80               ✓ answer                    (4)
                                       36

 4.3         A = 32,99(1 + 0,052)4                                   ✓ substitution
             A = R40,41                                              ✓ answer                    (2)

                                                                                                [11]

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### Page 6

Mathematics/P1                                 6                             Hlayiso/Mock 2026
                                     NSC – Marking Guidelines

QUESTION 5

 5.1         TP B(0 ; 8): q = 8                                 ✓q=8
             f (x) = ax2 + 8
             Subst. A(4 ; 0): 0 = a(4)2 + 8                     ✓ substitution of A
             16a = −8
                    1                                           ✓ 16a = −8                 (3)
             a=−
                    2
                  4−0
 5.2         m=        = −1;       c=4                          ✓ m = −1
                  0−4
                                                                ✓ c = 4 / equation         (2)
             g(x) = −x + 4

               1
 5.3         − x2 + 8 = −x + 4                                  ✓ equating
               2
                                                                ✓ standard form
             x2 − 2x − 8 = 0
                                                                ✓ x = −2
             (x − 4)(x + 2) = 0
             x = −2 (x = 4 at A)
                                                                ✓y=6                       (4)
             y = −(−2) + 4 = 6      E(−2 ; 6)

 5.4         y ≤ 8 OR     y ∈ (−∞ ; 8]                          ✓ answer                   (1)

 5.5         x<0     OR   x ∈ (−∞ ; 0)                          ✓ answer                   (1)

 5.6         −2 ≤ x ≤ 4                                         ✓ critical values
                                                                ✓ notation                 (2)

                     1
 5.7.1       h(x) = − x2 + 5                                    ✓ answer                   (1)
                     2

 5.7.2       y ≤ 5 OR     y ∈ (−∞ ; 5]                          ✓ answer                   (1)

                                                                                          [15]

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### Page 7

Mathematics/P1                                  7                               Hlayiso/Mock 2026
                                      NSC – Marking Guidelines

QUESTION 6

 6.1         x=0       and y = 2                                  ✓x=0
                                                                  ✓y=2                        (2)

                 6
 6.2         0=    +2                                             ✓ f (x) = 0
                 x
             −2x = 6
                                                                  ✓ (−3 ; 0)                  (2)
             x = −3   (−3 ; 0)

 6.3                             y                                ✓ horizontal asymptote y = 2
                                                                  ✓ x-intercept (−3 ; 0)
                                                                  ✓ shape (both branches in
                                                                  correct quadrants relative to
                                                                  asymptotes)                 (3)

                 y=2

                                                x
              (−3 ; 0)       O

             No y-intercept: the graph does not cut the y-axis.

 6.4         x ∈ R, x ̸= 0                                        ✓ answer                    (1)

                                                                                              [8]

QUESTION 7

 7.1         q = −3                                               ✓ answer                    (1)

 7.2         Subst. P(2 ; 6): 6 = b2 − 3                          ✓ substitution
             b2 = 9                                               ✓ b2 = 9                    (2)
             b = 3 (b > 0)

 7.3         0 = 3x − 3                                           ✓ 3x = 3
             3x = 31                                              ✓ (1 ; 0)                   (2)
             x=1        (1 ; 0)

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### Page 8

Mathematics/P1                                     8                            Hlayiso/Mock 2026
                                         NSC – Marking Guidelines

 7.4         y > −3      OR   y ∈ (−3 ; ∞)                          ✓ answer                    (1)
                                               ( )x
                                                1
 7.5         h(x) = 3−x − 3       OR    h(x) =      −3              ✓ answer                    (1)
                                                3

                                                                                                [7]

QUESTION 8

 8.1.1       P(A or B) = P(A) + P(B) − P(A and B)                   ✓ substitution
             0,75 = 0,35 + 0,4 − P(A and B)
             P(A and B) = 0                                         ✓ P(A and B) = 0            (2)
             ∴ A and B are mutually exclusive.

 8.1.2       No.                                                    ✓ No
             P(A) + P(B) = 0,75 ̸= 1 (the events are not            ✓ reason                    (2)
             exhaustive)

 8.2.1        S                                                     ✓ x in the intersection
                     T                   C                          ✓ 70 − x and 45 − x
                                                                    ✓ 25 outside the circles    (3)
                     70 − x   x    45 − x

                                             25

 8.2.2       (70 − x) + x + (45 − x) + 25 = 120                     ✓ sum of regions = 120
             140 − x = 120                                          ✓ 140 − x = 120        (2)
             x = 20

 8.2.3(a)    n(T only) = 70 − 20 = 50                               ✓ 50
                          50     5                                  ✓ answer                    (2)
             P(T only) =      =     (or 0,42)
                         120 12

 8.2.3(b)    n(not choir) = 120 − 45 = 75                           ✓ 75
                             75    5                                ✓ answer                    (2)
             P(not choir) =      = (or 0,625)
                            120 8
                                       28
 8.3.1       Relative frequency =         = 0,35                    ✓ answer                    (1)
                                       80

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### Page 9

Mathematics/P1                                 9                           Hlayiso/Mock 2026
                                     NSC – Marking Guidelines

 8.3.2       0,35 × 200 = 70 times                              ✓ answer                (1)

                                                                                      [15]

                                                                            TOTAL:      100

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