# Physical Sciences Grade 10 KZN September Test 2024 QP & Memo

> Grade 10 Physical Sciences question paper and memo from the KZN September Test 2024, 20 pages. Read online or get the free PDF download.

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- Updated: 2026-09-28
- Subject: Physical Sciences
- Grade: Grade 10
- Document type: Question paper and memo
- Year: 2024
- Exam period: KZN September Test
- Curriculum: CAPS
- Pages: 20

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Physical Sciences · Grade 10 · KZN September Test · 2024. Question paper and memorandum, 20 pages. Read online or download the PDF.

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### Page 1

ownloaded from Stanmorephysics.com |
KWAZULU-NATAL PROVINCE

EDUCATION
REPUBLIC OF SOUTH AFRICA

NATIONAL
SENIOR CERTIFICATE

MARKS: 100

DURATION: 2 hours

This question paper consists of 10 pages and 2 data sheets.

Copyright reserved Please turn over

### Page 2

Physical Science (Grade,10) September 2024 Common Test

ownloaded from Stanmorephysics.com

INSTRUCTIONS AND INFORMATION

4. This question paper consists of SEVEN questions. Answer ALL the questions
in the ANSWER BOOK.

2 Start FACH auestion an a NEW nane in the ANSWER BOOK.

3. Number the answers correctly according to the numbering system used in this
question paper.

4. Leave ONE line between two sub-questions, for example between
QUESTION 2.1 and QUESTION 2.2.

5. You may use a non-programmable calculator.

6. You may use appropriate mathematical instruments.

te You are advised to use the attached DATA SHEETS.

8. Show ALL formulae and substitutions in ALL calculations.

9. Round off your final numerical answers to a minimum of TWO decimal places.

10. Give brief motivations, discussions et cetera where required.

11. Write neatly and legibly.

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### Page 3

Physi , 5 Ade) from Z tanmorep. hys ics. com September 2024 Common Test

QUESTION 1; MULTIPLE-CHOICE QUESTIONS

Four options are provided as possible answers to the following questions. Each
question has only ONE correct answer. Choose the answer and write only the letter
(A-D) next to the question number (1.1-1.8) in the ANSWER BOOK, for example 1.11

Eg.
41 Which ONE of the following Is a scalar quantity?

A Displacement

B Force
C Speed
D  Aceeleration . ‘i (2)

1.2 The position — time graph of an object is shown below. East is taken as the

rect description of the motion of the

asterly direction.
B The object is slowing down in the easterly direction.
C The object is speeding up in the westerly direction.

D The object is slowing down in the westerly direction. (2)

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### Page 4

September 2024 Common Test

Physical Sgence {Beryl from Stanmbd§éphysics.com

1.3 An object, starting from rest, experiences a constant acceleration a when

increasing its velocity to V.
The acceleration when increasing the velocity from V to 2V in the same time

will’be.;./

AAR

B- 2a

C ha

D 4a (2)
1.4 Consider the vector diagram below:

P
Q R

Which ONE of the following is the correct relationship between vectors P, Q

and R?

A P=Q+R

B R=P+Q

C Q=P+R

D P+Q+R=0 (2)
15 Consider the balanced chemical equation for the reaction below:

2(9) 2(g) — 2NHs(g)
ur 2 of Hydrogen (Hz) required to form 22,4 dm? of

C 1.5x 22,4 dm

D 2 :
3 x 22,4 dm (2)

Copyright reserved Please turn over

### Page 5

Pre ewiioaded from Stanmorkphysics.com —_ SePtember 2024 Common Test

1.6 Which ONE of the following contains 6,02 x 1023 ATOMS?

A -1. mole of CO2
B16 g of O2 gas
C-— 22,4 dm of Nz gas at STP

D 18g ofH20 (2)

1.7 Which ONE of the following expressions is correct for the percentage
composition of water (H2O) in NazSO4-10H20?

A 18

742 *100
B 18

322 *100

(2)
1.8 it of Avogadro's Law?
upies the same volume at the same
B One mole of any gas occupies the same volume at standard
temperature and pressure.
C One mole is the amount of substance having the same number of
particles as there are atoms in 12 g carbon-12.
D_Avagadro's number is the number of particles present in one mole. (2)
[16]

Copyright reserved Please tum over

### Page 6

Physical Dowanenacean from Stanmasephysics.com _ september 2024 Common Test
6

SECTION A: PHYSICS
QUESTION 2 (Start on a new page.)

2.1 Jack and his dog, Rex, are initially standing at point A. Jack throws a ball in
an easterly direction so that it comes to rest at point B.

Om z.

Jack thereafter runs at an average velocity of 5 m-s' due west, reaching point
Cin 10 seconds. The distance between point B and point C is 70 m

244 Calculate Jacks displacement. (3)

Rex leaves point A at the same time as Jack and runs due east to fetch the

ball at point B. He immediately turns around and runs due west, meeting Jack
at point C.

Rex takes 2 seconds more than Jack to reach point C.
212 Define the term average speed in words. (2)

2.1.3 Calculate Rex’s average speed for his motion from A to B to C. (4)

2.2 Two forces, F1 and F2 of magnitude 60 N and 20 N respectively act on a
suspended box of weight 30 N as shown in the diagram below.

Fi =60N
t F2=20N

| wean

Using the tail-to-head method and a scale of 1 cm represents 10 N, draw an

accurate vector diagram to determine the magnitude of the resultant force

acting on the box. (4)
[13]

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### Page 7

Physical Science. OPE Fro ms tanmor®fhysi ics.com September 2024 Common Test

QUESTION 3 (Start on a new page.)

3.1 The velocity-time graph below represents the motion of a car travelling EAST
over a period of 21 seconds.

N
E
Ss
Time (s)
3.1.1 Describe how the velocity of the car changes from 15 seconds to
21 seconds. (2)
3.1.2 Calculate the acceleration of the car from 15 seconds to 21
seconds. (3)
3.1.3 The displacement of the car in the 21 seconds interval is 415 m.
Calculate the magnitude of the cars initial velocity, X. (4)

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### Page 8

Physical SienogiBatdae from Stanmesephysics.com September 2024 Common Test
8

3.2 The position-time graph for a quad bike travelling NORTH along a straight
horizontal surface is shown below.

The quad bike starts from rest and moves at a constant acceleration

GRAPH OF POSITION VERSUS TIME

Tangent to the
line at 6 seconds

: ae
6
Time (s)
324 Define the term instantaneous velocity in words. (2)

3.2.2 Calculate the instantaneous velocity of the quad bike at 6 seconds. (3)

3.2.3 Determine the magnitude of the quad bikes acceleration during the
first 6 seconds. (3)

[17]
QUESTION 4 (Start on a new page.)

In the diagram below, the driver of a car travelling east, at a constant velocity of
45 ms‘, notices a speed trap 100 m away. The speed limit is 120 km-h".

The driver takes 0,5 seconds to react before applying brakes. The car slows down
uniformly at 6 m-s*.

(e)

100m WIN

—>
Speed trap
‘metres per second (m-s*) (2)

41

42 o determine if the car will exceed the speed limit at

(6)

4.3 Determine the time taken for the car to reach the speed trap after applying (4)
brakes.

[12]

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### Page 9

Physical Sci Gi 1 . September 2024 Cor Test
eSownloaded from Stanmohphysics.com — —

SECTION B: CHEMISTRY
QUESTION 5. (Start on a new page.)

Iron(IIl) oxide (Fe2O3) reacts with carbon monoxide (CO) as represented in the
balanced equation below:

3Fe20s(s) + CO(g) + 2FeaOa(s) + CO2(g)

In one such reaction, 1,2 kg iron(IIl) oxide reacts with excess carbon monoxide at
standard temperature and standard pressure (STP)

5.1 Define the term molar mass in words.
5.2 Calculate the:
5.2.1 Number of moles of Fe2O3 reacted
5.2.2 Number of FesOs formula units formed
5.2.3 Volume of CO (in dm%) required to completely react with the 1,2 kg
Fe2O03
QUESTION 6 (Start on a new page)

6.1 An organic acid made up of carbon (C), hydrogen (H) and oxygen (O) only
has the following percentage composition by mass:

Element Percentage Composition
Carbon (C) 48,65%
Hydrogen (H) 8.11%
Oxygen (O) 43,24%
6.1.1 Define the term empirical formula in words.
6.1.2 Determine the empirical formu! is compound

6.2 An unknown meta tely V Sulphuric acid (H2SOs) according

concentration 0,75 no ea

Use relevant calculations to determine the NAME of metal Y.

Copyright reserved Please tum over

(2)

(3)

(4)

(4)
[13]

(2)
(6)

(6)
[14]

### Page 10

PrysicalSSWANGEEEY from StanmoPphysics.com —_SePlember 2024 Common Test
QUESTION 7 (Start on a new page.)

tal

7.2

Propane(CsHs) reacts with oxygen (O2) to form carbon dioxide (COz) and
water (H20), as indicated in the balanced equation below.

CsHs (g) + 502 (g) » 3COz (g) + 4H20 (g)

In one such reaction 5 dm? propane(CsHs) reacts with excess oxygen at
standard temperature and standard pressure (STP).

7.1.4 Calculate the TOTAL volume of gas (in dm?) formed at the end of
the reaction. (4)

The graph below shows the volume of COz formed as the reaction above
progresses. The reaction has not reached completion.

16
me =e | il _
=e
°
a
5.6m
3 :
4
Ore p 1C5.C0
0
0) 2 4 6 8 10 12 14
Time (minutes)
E12 Determine the mass of CsHs (in grams) that reacted after 6 minutes (5)

Hydrochloric acid (HCI) reacts with magnesium (Mg), as represented in the
balanced equation below:
Mg(s) + 2HCl(aq) — MgCl2(aq) + He(g)

18 grams of magnesium (Mg) reacts completely with excess hydrochloric acid
(HCl). The percentage yield of hydrogen (H2) in the reaction is 80%.

Calculate the mass of H2 formed (in grams). (6)

[15]
TOTAL: 100

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### Page 11

rms SWAISEAED from StanmoM~physics.com September 2024 Common Test

DATA FOR PHYSICAL SCIENCES GRADE 10

PHYSICS
TABLE 1; PHYSICAL CONSTANTS
NAME SYMBOL VALUE
Acceleration due to gravity g 9,8 m-s*
Speed of light in a vacuum c 3,0 x 108 m:s
Planck's constant h 6,63 x 10% J-s
Charge on electron qe -1,6 x 1079C
Electron mass Me 9,11 x 10°31 kg
TABLE 2: FORMULAE
MOTION
1
y=v, tat AX = vAt + paat?
+V;
ve? = v;2 + 2aAx Ax= (*)at
CHEMISTRY
TABLE 1: PHYSICAL CONSTANTS
NAME SYMBOL VALUE
Standard pressure p° 1,013 x 105 Pa
Molar gas volume at STP Vn 22,4 dm*-mol*
Standard temperature T° 273 K
Avogadro's constant Na 6,02 x 1073 molt
TABLE 2: FORMULAE
N
m a
n= M 8 Ny
n _m a
c= Vv or c= Mw n Va

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### Page 12

DownlocRtestdisornsStarmorgphysics.com NSC September 2024
12
TABLE 3: THE PERIODIC TABLE OF ELEMENTS
1 2 3 4 5 6 7 8 9 10 #1 #2912 «1306 .1460¢« NS 161TH
Oo @ qm) (My) YM) vt) vm
1 Atomic number 2
KEY/SLEUTEL Atoomgetal
a H He
: 4 * 6] 7] 8] 9 =
Electronegativit Symbol 5
2 Li | Be Elektronegatiwiteit 2 Cu —Simbool = a b= solg¢ Ne
7 9 ae 41 | 12| 14] 16| 19| 20
11 12 T 13 14 15 16 17 18
2 Na/& Mg Approximate relative atomic mass 2AelZ SiS P| S /SCe| Ar
23 24 Benaderde relatiewe atoommassa 27 28 31 32 35,5 40
19 20 24 22] 23] 24] 25] 26] 27] 2] 29] 30] 31| +32| 33) 34) 35! 36
s K [2 Cal? Sci? Ti |¢ = Cr|2Mn/2 Fe |2 Co|2 Ni |2 Cu |2 Zn |2 Ga |2 Ge |S As |S Se |3 Br} Kr
39 40 45 | 48| 51| 52| 55| 56| 59| 59| 635} 65| 70| 73| 75! 79| 80| 84
37 38 39 | 40] 41/ 42] #43] 44/ 45/ 46| 47/ +48| 49| 501 51| 521 531 54
es Rb|2 Sr |= Y |= Zr} Nb/2 Mo/2 Tc|§ Ru |S Rh|s Pd |2 Ag |= Cd |= In [2 Sn|2 Sb|S Te |3 1 | Xe
86 88 89 | 91| 92| 96 101| 103/ 106} 108| 112] 115| 119| 122| 128| 127| 134
55 56 57 | 72| 73| 74] 75! 76| 77/ +78| +79! +80| 81| 82) 831 841 851 86
s Cs/3 Ba| La/2 Hf| Ta| W| Re| Os| Ir| Pt| Au| Hg|2 Te|2 Pb|2 Bi |S Pol% At| Rn
133 | 137| 139| 179] 181| 184] 186] 190| 192] 195| 197} 201| 204| 207| 209
87 88 89
s Fr |2 a Ac 58 | 59 | 60 | 61 | 62 | 63 | 64 | 65 | 66 | 67 | 68 | 69] 70] 741
Ce | Pr | Nd | Pm| Sm| Eu | Gd | Tb | Dy | Ho| Er | Tm | Yb | Lu
140 | 141 | 144 150 | 152 | 157 | 159 | 163 | 165 | 167 | 169 | 173 | 175
90 | 91 | 92 | 93 | 94 | 95 | 96 | 97 | 98 | 99 | 100 | 101 | 402 | 103
Th | Pa} U | Np! Pu | Am| Cm}! Bk | Cf | Es | Fm|Md!No/! Lr
232 238

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### Page 13

Downloaded from Stanmorephysics.com

KWAZULU-NATAL PROVINCE

EDUCATION
REPUBLIC OF SOUTH AFRICA

NATIONAL
SENIOR CERTIFICATE

MARKS: 100

DURATION: 2 hours

This marking guideline consists of 8 pages.

Copyright reserved

### Page 14

PhysicdDeneuetsaded from Stanmerephysics.com September 2024 Common Test
rade

QUESTION 1
1A Cv¥v (2)
152 Cv¥v (2)
1.3 AVY (2)
1.4 Cvv (2)
1.5 Cvv (2)
1.6 Byv (2)
LT Cvv (2)
1.8 AVY (2)
[16]
QUESTION 2
21
2.1.1
(3)
2.1 ravelled per total time vv (2)
9:43. _ distance v
speed ~ “ime
_ 20+70¥
“120
=7,5ms'v (4)

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### Page 15

PhysicdDeneuetsaded from Stanmorephysics.com September 2024 Common Test
rade

CRITERIA

1 mark — F1 and F2 drawn head-to-tail
with correct scale and direction

1 mark — F3 drawn downwards from F2
with the correct scale.

1 mark — Fr drawn with correct direction
and scale.

v_ | 1 mark — Final answer (50 N)

(4)
[13]

QUESTION 3

3.1

3.1.1 The velocity uniformly decreased from 30 m-s" east ¥ to 0 m-s1/

stop/ rest in 6 seconds ¥ (2)

3.1.2 Av OR See Va
a=— az=——

at x2 - %
_ 0-304

~ 21-15%

=-5m-s?

=5m-s*West ¥ (3)
3.1.3. OPTION4

415 v = 10x ++ x 10 x (30-x)¥ +5 x 30 ++ x 6x 304

X=5mstv
OPTION 2

1 1
Mov = x10 x (x + 30)¥ +5 x 3045 x 6X 30¥%

X=5mstv
OPTION 3
Ax (10 — 21 seconds)

Ax (0 — 10 seconds) = 415
=1

= ere

Ax At

30+X

175 v= x10V

X=5mstv (4)
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### Page 16

PhysicdDeuseuetsaded from Stanmerephysics. COM __ September 2024 Common Test
rade

3.2
3.2.1 The rate of change in position. Vv“ (2)
3.2.2 vert
X2— X41
_ 36-0¥
~ 6-34
= 12 m-s™ North ¥ (3)

3:2:3 POSITIVE MARKING FROM 3.2.2
OPTION 1
Av v

OPTION 2 OPTION 3

1
Ax = viAt + paat? v v2 = v2 + Zadx ¥

36 = 0(6) + ta(6) v (12)? = 0? + 2a(36) v

= “g2 = “s2
a=2ms?v a=2ms?*v (3)
[17]

QUESTION 4
41 120+3,6 ¥ =33,33 m-stv (2)

1
42 Ax=viAt+ saat? OR AX=v,At

aa
= 45(0,5) + 5(0)ae? ¥ = 45(05) ¥

Ax = 22,5 m

> = 100 — 22,5 Vv
=77,5m

1 mS"

The vehicle will not exceed the speed limit. ¥ (6)

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### Page 17

PhysicdDeuseuetsaded from Stanmerephysics. COM __ September 2024 Common Test
rade

4.3 POSITIVE MARKING FROM 4.2

OPTION 1 OPTION 2
Uf + Vi
Vy=vitadt ¥ ax= 2 wal
33,09 +45
33,09 v= 45 +(-6)At ¥ aes ae
At =1,99sv At =1,98s ¥
OPTION 3
1
AX = vjAt+ zaat'y
1
77,5 ¥ = 45At + 3 Cb)aty
At = 1,98 s ¥ (4)
[12]
QUESTION 5
5.1 The mass of one mole of substance. vv (2)
§2
(3)
N
=— Vv
n(FesO4) Ma
5-=_  __v
6,02 x 1023
N (FesOs) = 3,01 x 1074 FesO4 formula units “ (4)

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### Page 18

Physicdoneuttoaded from Stanmerephysics.com

5.2.3 POSITIVE MARKING FROM 5.2.1

September 2024 Common Test

Fe203: CO
3 404
n(CO) = 2,5 mol
Vv
= v
n(CO) Vn
a v
25 54
V(CO) = 56 dm? ¥ (4)
[13]
QUESTION 6
6.1.1. The simplest whole-number ratioY of atoms in a compound ¥ (2)
6.1.2
Consider 100g
Element a. n= 3
48,65
Cc 48,65 |——=
T2 4,05
8,11 modified
H 8,11 a 8.11 simplest
ratios)
fo) 43,24 | 43:24 _
16 j
Empirical Formula: Cs (6)
6.2 n
C(H,S,)= 5%
n
aad v
0,75 04
n(H2SOaz) = 0,3 mol
Y : H2SO4
2141
n(Y) = 0,6 mol
_m
nY)= Gy
v
ee 13,8
M(Y) = 23 g.molt
Y is Sodium ¥ (6)
[14]

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### Page 19

Physicdoneuttoaded from Stanmorephysics.com

QUESTION 7

7.1
TAA

OPTION 1

CsaHs : CO2

1 ca
V(CO2) = 15 dm?

CsHs : H2O

1 :4 Vv

V(H20) = 20 dm?

V(end)=15+20 v
= 35 dm3 ¥

OPTION 2

Vv
n(CsHs) = va

m
a

n(CsHe) = 224
= 0,22 mol
CsHs : CO2

1 73 4
n(COz) = 0,66 mol

Cs3Hs : H2O
1 1:4 Vv
n(H2O) = 0,88 mol

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September 2024 Common Test

(4)

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### Page 20

PhysicdDeuseuetsaded from Stanmerephysics.com September 2024 Common Test
rade

7.1.2 V(COz) = 12 dm3 ¥
Cs3Hs : CO2
1 i
V(CsHs) = 4 dm?

CsHe) = .
n(C3Hs) = Tn
a 9
22,4
= 0,18 mol
m
n(CsHs) = uM
m
-" v
0,18 44
m(CsHs) = 7,92 g ¥ (5)
7.2 m
=— Vv
n(Mg) = yj
a al
24
= 0,75 mol
Mg : H2
1 sav

n(H2) = 0,75 mol

M(H2)theoretical =1,5 g

M(H2)actual = M(Hz)theoretical X percentage yield

H = 1,5 — v
m( 2)actual = xX 100
M(Ha)actual = 1,2 g ¥ (6)
[15]
TOTAL: 100

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