# Physical Sciences Grade 10 Paper 1 November Mock Exam 2 2026 Memo

> Grade 10 Physical Sciences Paper 1 memorandum from the November Mock Exam 2 2026, 7 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/grade-10-physical-sciences-2026-november-mock-exam-2-memorandum-paper-1/6e08281f-9f46-4daa-bcf2-517b76c3c9e9
- Updated: 2026-10-23
- Subject: Physical Sciences
- Grade: Grade 10
- Document type: Memorandum
- Year: 2026
- Exam period: November Mock Exam 2
- Paper: 1
- Publisher: Hlayiso
- Curriculum: CAPS
- Pages: 7

Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 10](https://www.hlayiso.com/library/grade-10) › [Physical Sciences](https://www.hlayiso.com/library/grade-10/physical-sciences) › [Physical Sciences Grade 10 Paper 1 November Mock Exam 2 2026 Memo](https://www.hlayiso.com/library/grade-10-physical-sciences-2026-november-mock-exam-2-memorandum-paper-1/6e08281f-9f46-4daa-bcf2-517b76c3c9e9)

## About this document

Physical Sciences · Grade 10 · November Mock Exam 2 · 2026. Memorandum, 7 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

Text extracted from the PDF. Layout, diagrams and tables may not survive extraction.

### Page 1

Copyright reserved
Please turn over
Mock
hlayiso mock exams
Practice Series:
Grade 10 Exam Preparation
WWW.HLAYISO.COM
NATIONAL
SENIOR CERTIFICATE
GRADE 10
PHYSICAL SCIENCES: PHYSICS (P1)
NOVEMBER EXAMINATION 2026 (MOCK)
MARKING GUIDELINES
MARKS: 100
These marking guidelines consist of 7 pages.

### Page 2

Physical Sciences/P1
2
NSC – Marking Guidelines
Hlayiso/Mock 2026
GENERAL MARKING GUIDELINES
1. Calculations: Marks are awarded for the correct formula, correct substitution and the
correct final answer WITH the correct unit, as indicated by the ticks (✓). A formula is not
awarded a mark if it is not followed by a substitution. If an incorrect formula is used, no
further marks are awarded for that calculation.
2. Units: The final-answer mark is only awarded if the correct unit is given. Penalise an
omitted or incorrect unit only ONCE per question.
3. Rounding: Accept final answers rounded to a minimum of TWO decimal places. Small
differences caused by rounding of intermediate values are accepted.
4. Positive marking: Where an incorrect answer to a previous question is used correctly
in a later calculation, the later calculation is marked positively.
5. Negative marking: If a candidate must choose (e.g. INCREASES/DECREASES) and
then explain, and the choice is incorrect, no marks are awarded for the explanation.
6. Definitions/laws: Where key words are underlined, deduct 1 mark for EACH key word
or phrase that is omitted or used in an incorrect context. Accept equivalent wording.
7. Vectors: A direction must be given wherever a vector quantity (displacement, velocity,
acceleration) is asked for; candidates may choose either direction as positive if applied
consistently.
Copyright reserved
Please turn over

### Page 3

Physical Sciences/P1
3
NSC – Marking Guidelines
Hlayiso/Mock 2026
QUESTION 1
1.1
D ✓✓
(2)
1.2
C ✓✓
(2)
1.3
C ✓✓
(2)
1.4
A ✓✓
(2)
1.5
A ✓✓
(2)
1.6
B ✓✓
(2)
1.7
B ✓✓
(2)
1.8
A ✓✓
(2)
[16]
Notes for teachers: 1.2: Ek,P = 1
2mv2; Ek,Q = 1
2(2m)(1
2v)2 = 1
4mv2, so the ratio is 2. 1.3: moving west
gives negative velocity; slowing down means the acceleration is opposite to the velocity, i.e. positive.
1.4: λ = v/f and T = 1/f, so both are halved. 1.7: the parallel pair has resistance 1
2R, so the 12 V divides
2 : 1 (8 V and 4 V).
QUESTION 2
2.1
A wave in which the particles of the medium vibrate parallel to the direction of
motion of the wave. ✓✓
(2)
2.2
A: compression ✓
B: rarefaction ✓
(2)
2.3
The distance from the centre of a compression (A) to the centre of the next
rarefaction (B) is half a wavelength. ✓
λ = 2×0,2 = 0,4 m ✓
(2)
2.4
f = 12
3 = 4 Hz ✓
v = fλ ✓
= (4)(0,4) = 1,6 m·s–1 ✓
Accept: T = 3
12 = 0,25 s; v = λ
T = 0,4
0,25 = 1,6 m·s–1. POSITIVE MARKING FROM 2.3.
(3)
2.5
v = ∆x
∆t ✓
1,6 = 2,4
∆t ✓
∆t = 1,5 s ✓
OR: 2,4 m = 6 wavelengths; 6×T = 6×0,25 = 1,5 s. POSITIVE MARKING FROM 2.4.
(3)
[12]
Copyright reserved
Please turn over

### Page 4

Physical Sciences/P1
4
NSC – Marking Guidelines
Hlayiso/Mock 2026
QUESTION 3
3.1.1
Light travels much faster (3× 108 m·s–1) than sound (340 m·s–1). ✓
(1)
3.1.2
v = ∆x
∆t ✓
340 = ∆x
4,2 ✓
∆x = 1428 m ✓
(3)
3.2.1
Electromagnetic waves are produced by accelerating (oscillating) charges. ✓
The oscillating charge produces electric and magnetic fields that oscillate at
right angles to each other (and to the direction of motion of the wave). ✓
(2)
3.2.2
E = hf ✓
E = (6,63×10–34)(2,45×109) ✓
E = 1,62×10–24 J ✓
(3)
3.2.3
c = fλ
3×108 = (2,45×109)λ ✓
λ = 0,12 m (0,122 m) ✓
OR: E = h c
λ ⇒λ = (6,63×10–34)(3×108)
1,62×10–24
= 0,12 m. POSITIVE MARKING FROM 3.2.2.
(2)
[11]
QUESTION 4
4.1
Every charge in the universe consists of an integer multiple of the charge of
one electron (e = 1,6×10–19 C). ✓✓
(2)
4.2
Q = QP +QQ
2
+2,5×10–9 = (–3×10–9)+QQ
2
✓
QQ = +8×10–9 C (+8 nC) ✓
(2)
4.3
P LOST electrons. ✓
Change in charge on P: ∆Q = (+2,5)–(–3) = +5,5 nC ✓
n = Q
e
= 5,5×10–9
1,6×10–19 ✓
n = 3,44×1010 electrons ✓
Accept ∆Q for Q: 2,5–8 = –5,5 nC. POSITIVE MARKING FROM 4.2.
(4)
[8]
Copyright reserved
Please turn over

### Page 5

Physical Sciences/P1
5
NSC – Marking Guidelines
Hlayiso/Mock 2026
QUESTION 5
5.1
The energy transferred per unit (coulomb of) charge between two points in a
circuit (OR the work done per unit charge). ✓✓
(2)
5.2
V15Ω= IR = (0,4)(15) = 6 V ✓
Ix = 1,0–0,4 = 0,6 A ✓
R = V
I ✓
= 6
0,6
Rx = 10 Ω✓
OR: Rp =
6
1,0 = 6 Ω; 1
6 = 1
15 + 1
Rx ; Rx = 10 Ω.
(4)
5.3
V1 = IR = (1,0)(5) = 5 V ✓
emf = V1 +Vp = 5+6 = 11 V ✓
emf of each cell = 11
5 = 2,2 V ✓
OR: Rtotal = 5 + 6 = 11 Ω; emf = IR = (1)(11) = 11 V; each cell 2,2 V. POSITIVE
MARKING FROM 5.2.
(3)
5.4
W = VQ = VI∆t ✓
W = (6)(0,6)(90) ✓
W = 324 J ✓
OR: Q = I∆t = (0,6)(90) = 54 C; W = VQ = (6)(54) = 324 J. POSITIVE MARKING FROM
5.2.
(3)
5.5
DECREASES ✓
The total resistance of the circuit INCREASES (from 11 Ωto 20 Ω), so the
current through the 5 Ωresistor DECREASES and V1 = IR decreases (5 V to
2,75 V). ✓
(2)
[14]
Copyright reserved
Please turn over

### Page 6

Physical Sciences/P1
6
NSC – Marking Guidelines
Hlayiso/Mock 2026
QUESTION 6
6.1
The rate of change of position (displacement per unit time) ✓✓
Accept: speed in a specified direction.
(2)
6.2
∆x = v∆t = (12)(6) ✓
∆x = 72 m ✓
(2)
6.3
vf = vi +a∆t ✓
vf = 0+(1,5)(6) ✓
vf = 9 m·s–1 east ✓
(3)
6.4
Car: ∆x = vi∆t+ 1
2a∆t2 = 0+ 1
2(1,5)(6)2 = 27 m ✓
Position of car from the starting point of the motorbike: 40+27 = 67 m ✓
Motorbike: 72 m > 67 m, so the MOTORBIKE is in front, by 5 m. ✓
Accept ∆x =
(vf+vi
2
)
∆t =
(
9+0
2
)
(6) = 27 m. POSITIVE MARKING FROM 6.2 AND 6.3.
(3)
6.5
t (s)
v (m·s–1)
motorbike
car
12
8
Marking criteria
Motorbike: horizontal line at 12 m·s–1, labelled ✓
Car: straight line through the origin with positive gradient, labelled ✓
The two graphs intersect where the car reaches 12 m·s–1 ✓
Values 12 m·s–1 (velocity axis) and 8 s (time axis) shown ✓
Time: vf = vi +a∆t: 12 = 0+1,5∆t, ∆t = 8 s.
(4)
[14]
Copyright reserved
Please turn over

### Page 7

Physical Sciences/P1
7
NSC – Marking Guidelines
Hlayiso/Mock 2026
QUESTION 7
7.1
At t = 9 s ✓
The velocity changes from POSITIVE to NEGATIVE (the graph crosses the
time axis), so the boat starts moving west. ✓
(2)
7.2
a = ∆v
∆t ✓
= –3–6
10–7 ✓
a = –3 m·s–2, i.e. 3 m·s–2 west ✓
(3)
7.3
∆x = area between the graph and the time axis ✓
Area above the axis (0–9 s): 1
2(3)(6)+(4)(6)+ 1
2(2)(6) = 39 m ✓
Area below the axis (9–12 s): 1
2(1)(–3)+(2)(–3) = –7,5 m ✓
∆x = 39–7,5 = 31,5 m east ✓
OR area above the axis as trapezium 1
2(9 + 4)(6) = 39 m and below the axis as
trapezium 1
2(3+2)(3) = 7,5 m.
(4)
7.4
GREATER THAN ✓
The boat changes direction (moves back west), so the total distance travelled
is greater than the magnitude of the displacement (in the same time). ✓
(2)
7.5
vave = ∆x
∆t ✓
= 31,5
12 ✓
vave = 2,63 m·s–1 east ✓
Accept 2,62 or 2,63 m·s–1 east (exact value 2,625).
POSITIVE MARKING FROM 7.3.
(3)
[14]
QUESTION 8
8.1
The energy an object possesses as a result of its motion. ✓✓
(2)
8.2
EM = EP +Ek = mgh+ 1
2mv2 ✓
EM = (70)(9,8)(12) ✓+ 1
2(70)(6)2 ✓
EM = 8232+1260 = 9492 J ✓
(4)
8.3
EM(P) = EM(Q)
9492 = (70)(9,8)(2)+ 1
2(70)v2 ✓✓
v = 15,23 m·s–1 ✓
One mark for EP at Q, one mark for Ek at Q equated to 9 492 J. POSITIVE MARKING
FROM 8.2.
(3)
8.4
EP needed at R = mgh = (70)(9,8)(15) = 10290 J ✓
10290 J > 9492 J, so the biker cannot reach R. ✓
OR: maximum height h =
9492
(70)(9,8) = 13,84 m < 15 m. POSITIVE MARKING FROM 8.2.
(2)
[11]
TOTAL: 100
Copyright reserved

## Related documents

- [KZN Physical Science Grade 10 June 2023 P1 and Memo](https://www.hlayiso.com/library/kzn-physical-science-grade-10-june-2023-p1-and-memo/facea770-5fd1-4b31-8193-6fc17e11d5bf) — Physical Sciences · Memo · 2023
- [Physical Science Grade 10 November 2023 P1 and Memo](https://www.hlayiso.com/library/physical-science-grade-10-november-2023-p1-and-memo/f6cf5c0b-5796-47b3-bbce-d96df96e92f6) — Physical Sciences · Memo · 2023
- [EC Physical Science Grade 10 November 2022 P1 and Memo](https://www.hlayiso.com/library/ec-physical-science-grade-10-november-2022-p1-and-memo/8b8511dc-4ea9-409c-8ccc-7958a60f2474) — Physical Sciences · Memo · 2022
- [Gr 10 Physical Sciences P1 (English) November 2022 Possible Answers](https://www.hlayiso.com/library/gr-10-physical-sciences-p1-english-november-2022-possible-answers/910ac2af-b1bb-42b6-9f5a-973f4e4bdcea) — Physical Sciences · Memo · 2022 · Eng
- [2021 November Assessment Paper 1 QP MEMO](https://www.hlayiso.com/library/2021-november-assessment-paper-1-qp-memo/007b9a2a-f77a-420a-a7c6-985fcef42ad5) — Physical Sciences · Memo · 2021
- [PHSC SCIENCES P1 GR10 MEMO NOV2020 Afr+Engl](https://www.hlayiso.com/library/phsc-sciences-p1-gr10-memo-nov2020-afr-engl/a05e859c-7058-4ca4-b792-56d56729108e) — Physical Sciences · Memo · 2020 · Afr

## More from Grade 10 Physical Sciences

- [Gr 10 Phys Sci ATP 2023-24](https://www.hlayiso.com/library/gr-10-phys-sci-atp-2023-24/f162614c-9eea-46bf-b61a-5a5dc6360c7b) — ATP
- [EC AW Physical Sciences Grade 10 June 2025 QP and Memo](https://www.hlayiso.com/library/ec-aw-physical-sciences-grade-10-june-2025-qp-and-memo/55c5e457-737d-42d8-a3e9-d141082f89d3) — QP + Memo · 2025
- [2025 EC - Physical Sciences Grade 10 March QP](https://www.hlayiso.com/library/2025-ec-physical-sciences-grade-10-march-qp/bd09640b-cf56-4333-b958-01ad4331ee25) — QP · 2025
- [FS Physical Sciences Grade10 June 2025 QP and Memo](https://www.hlayiso.com/library/fs-physical-sciences-grade10-june-2025-qp-and-memo/4bbbc06c-f9d3-4d47-9bd5-7421512cd012) — QP + Memo · 2025
- [KZN Physical Sciences Grade 10 November 2025 P1 and Memo](https://www.hlayiso.com/library/kzn-physical-sciences-grade-10-november-2025-p1-and-memo/c5bea2ed-3318-4f7d-b1f6-2ac68a9d3399) — QP + Memo · 2025
- [LP Physical Sciences Grade 10 March 2025 QP and Memo](https://www.hlayiso.com/library/lp-physical-sciences-grade-10-march-2025-qp-and-memo/5aedbc3d-3f59-4693-b4ab-7c19bfd618f5) — QP + Memo · 2025

## Collection

- [Grade 10 past papers](https://www.hlayiso.com/grade-10/past-papers)

---

Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.