# Physical Sciences Grade 10 P2 November Mock Exam 2 2026 Memo

> Grade 10 Physical Sciences Paper 2 memorandum from the November Mock Exam 2 2026 (English), 9 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-10-physical-sciences-2026-november-mock-exam-2-memorandum-paper-2/b69c6bb9-e0db-46d8-8cfb-187285d7b8b3
- Updated: 2026-10-29
- Subject: Physical Sciences
- Grade: Grade 10
- Language: English
- Document type: Memorandum
- Year: 2026
- Exam period: November Mock Exam 2
- Paper: 2
- Publisher: Hlayiso
- Curriculum: CAPS
- Pages: 9

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## About this document

Physical Sciences · Grade 10 · November Mock Exam 2 · 2026 · English. Memorandum, 9 pages. Read online or download the PDF.

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## Matching paper and memo

- [Grade 10 Physical Sciences P2 November 2026 Mock 2](https://www.hlayiso.com/library/grade-10-physical-sciences-2026-november-mock-exam-2-question-paper-paper-2/5bd7a947-8dcc-4f45-a4e1-7d600246d8f7) — QP · 2026 · Eng

## Document text

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### Page 1

Mock

                             hlayiso mock exams
                             Practice Series:
                             Grade 10 Exam Preparation
                             WWW.HLAYISO.COM

                                  NATIONAL
                             SENIOR CERTIFICATE

                                    GRADE 10

                     PHYSICAL SCIENCES: CHEMISTRY (P2)
                     NOVEMBER EXAMINATION 2026 (MOCK)
                              MARKING GUIDELINES

MARKS: 100

                     These marking guidelines consist of 9 pages.

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### Page 2

Physical Sciences/P2                         2                              Hlayiso/Mock 2026
                                  NSC – Marking Guidelines

GENERAL MARKING GUIDELINES

  1. Calculations: Marks are awarded for the correct formula, correct substitution and the
     correct final answer WITH the correct unit, as indicated by the ticks (✓). If an incorrect
     formula is used, no further marks are awarded for that calculation.
  2. Units: Penalise an omitted or incorrect unit in a final answer only ONCE per question.
  3. Rounding: Accept final answers rounded to a minimum of TWO decimal places.
  4. Positive marking: Where an incorrect answer to a previous question is used correctly
     in a later calculation, the later calculation is marked positively.
  5. Equations: Reactants ✓, products ✓, balancing ✓ (the balancing mark requires correct
     phases where phases are asked for), unless otherwise indicated.
  6. Definitions: Where key words are underlined, deduct 1 mark for EACH key word or
     phrase omitted or used in an incorrect context.
  7. Names and formulae: If a FORMULA is asked for, a name is not accepted, and
     vice versa. If a LETTER is asked for, accept the correct name/formula only if it is
     unambiguous.

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### Page 3

Physical Sciences/P2                                3                                   Hlayiso/Mock 2026
                                         NSC – Marking Guidelines

QUESTION 1
 1.1         C ✓✓                  (2)
 1.2         A ✓✓                  (2)
 1.3         B ✓✓                  (2)
 1.4         D ✓✓                  (2)
 1.5         C ✓✓                  (2)
 1.6         C ✓✓                  (2)
 1.7         A ✓✓                  (2)
 1.8         B ✓✓                  (2)
                                                                                                        [16]
Notes for teachers: 1.2 – P has the lowest boiling point (hydrogen), so the least energy is needed to
overcome the forces between its particles. 1.6 – total moles of atoms: A 1; B 0,5 × 4 = 2; C 0,4 × 8 = 3,2;
D 1,5 × 2 = 3. 1.7 – V(NH3 ) = 23 × 30 = 20 cm3 (volume ratio = mole ratio). 1.8 – n = cV = 0,25 × 0,2 = 0,05
mol; m = nM = 0,05 × 40 = 2 g.

QUESTION 2
2.1      A pure substance consisting of one type of atom (that cannot be broken down
         into simpler substances by chemical means). ✓✓                                                  (2)
2.2.1    C✓                                                                                              (1)
2.2.2    D✓                                                                                              (1)
2.2.3    B✓                                                                                              (1)
2.3      Steel (metal) is a GOOD conductor of heat, so heat is transferred quickly to
         the food. ✓
         Plastic/wood is a POOR conductor of heat (thermal insulator), so the handle
         stays cool enough to hold. ✓
         Accept for steel: high melting point / strong / does not rust / malleable (does not melt on
         the stove). Accept for plastic/wood: poor conductor of heat (thermal insulator) ONLY,
         since that is the reason the handle is safe to hold.                                            (2)
2.4.1    Cu(OH)2 ✓✓        (Cu2+ and OH– ✓; correct ratio with brackets ✓)                               (2)
2.4.2    Potassium permanganate ✓                                                                        (1)
                                                                                                        [10]

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### Page 4

Physical Sciences/P2                          4                               Hlayiso/Mock 2026
                                   NSC – Marking Guidelines

QUESTION 3
3.1     The temperature at which a liquid changes to a solid (at a given pressure). ✓✓
        Accept: the temperature at which the solid and liquid phases of a substance are in
        equilibrium.                                                                          (2)
3.2     69 ◦ C ✓                                                                              (1)
3.3     Energy is released as the particles move closer together and forces of
        attraction between the particles form / become stronger (potential energy
        decreases). ✓
        The average KINETIC energy of the particles remains constant. ✓
        Temperature is a measure of the average kinetic energy of the particles, so the
        temperature remains constant. ✓                                                       (3)
3.4     Solid ✓                                                                               (1)
3.5     Beaker 2 ✓
        At the higher temperature the water particles (and permanganate particles)
        have a HIGHER average kinetic energy. ✓
        The particles move faster, so the permanganate particles spread out (diffuse)
        through the water faster. ✓                                                           (3)
                                                                                             [10]

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### Page 5

Physical Sciences/P2                            5                                 Hlayiso/Mock 2026
                                     NSC – Marking Guidelines

QUESTION 4
4.1.1   The mass of a particle on a scale where an atom of carbon-12 has a mass of
        12. ✓✓                                                                                    (2)
4.1.2   36 ✓    (65 – 29)                                                                         (1)
4.1.3   Let the percentage of copper-63 be x; then copper-65 is (100 – x). ✓
             63x + 65(100 – x)
        Ar =                   ✓
                    100
               63x + 65(100 – x)
        63,5 =                    ✓
                      100
        6 350 = 6 500 – 2x     x = 75% ✓
        Accept any correct method, e.g. using fractions x and (1 – x): 63x + 65(1 – x) = 63,5,
        x = 0,75.                                                                                 (4)
4.2
                                2p

         2s

         1s
        Marking criteria
        1s and 2s orbitals each with a pair of electrons with opposite spins ✓
        THREE 2p orbitals, each with ONE electron (Hund’s rule), arrows in the same
        direction ✓                                                                               (2)
4.3.1   18 ✓                                                                                      (1)
4.3.2   16 ✓                                                                                      (1)
                                                                                                 [11]

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### Page 6

Physical Sciences/P2                             6                                   Hlayiso/Mock 2026
                                      NSC – Marking Guidelines

QUESTION 5
5.1     The first ionisation energy INCREASES (generally) from sodium to argon /
        across the period. ✓                                                                         (1)
5.2     From Na to Ar the number of protons / nuclear charge INCREASES. ✓
        The valence electrons are in the SAME energy level (3), so the atomic radius
        DECREASES. ✓
        The attraction between the nucleus and the valence electrons INCREASES,
        so MORE energy is needed to remove an electron. ✓                                            (3)
5.3     Mg: 1s2 2s2 2p6 3s2 ; Aℓ: 1s2 2s2 2p6 3s2 3p1 ✓
        The electron removed from aluminium is in the 3p sub-level, which has a
        HIGHER energy than the 3s sub-level (it is further from the nucleus). ✓
        The 3p electron is therefore LESS strongly attracted by the nucleus, so LESS
        energy is needed to remove it. ✓
        Accept for the 2nd mark: the 3p electron is in a higher-energy sub-level / is further
        from the nucleus. Reference to shielding by the 3s electrons may be credited but is
        NOT required.
        Both configurations must be correct for the first mark. Accept [Ne] 3s2 and [Ne] 3s2 3p1 .   (3)
5.4     Sodium ✓                                                                                     (1)
                                                                                                     [8]

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### Page 7

Physical Sciences/P2                               7                          Hlayiso/Mock 2026
                                        NSC – Marking Guidelines

QUESTION 6
6.1     The transfer of electrons (from a metal to a non-metal) to form oppositely
        charged ions that attract each other (electrostatically). ✓✓                         (2)
6.2.1
         H× N ×H
                ×

                H
        Marking criteria
        Three N–H bonding pairs ✓
        ONE lone pair on N ✓
                                                                                             (2)
6.2.2
                                                                 2–

         Na +
            ×          O     +   × Na          [Na]+    ×   O×        [Na]+

        OR: 2[Na]+ [O]2– with 8 electrons shown around O.
        Marking criteria
        Lewis diagrams of TWO Na atoms (1 valence electron each) and O (6 valence
        electrons) ✓
        Transfer of electrons shown: TWO Na+ ions with charges ✓
        O2– ion with 8 electrons, brackets and charge ✓
                                                                                             (3)
6.3     (a) Metallic ✓     (b) Covalent ✓     (c) Ionic ✓                                    (3)
6.4     Mg3 N2 ✓         Ionic ✓                                                            (2)
                                                                                           [12]

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### Page 8

Physical Sciences/P2                           8                                Hlayiso/Mock 2026
                                    NSC – Marking Guidelines

QUESTION 7
7.1.1   Decomposition ✓                                                                         (1)
7.1.2   Chemical ✓
        NEW substances (CuO and CO2 ) with different properties are formed / bonds
        are broken and new bonds are formed. ✓
        Accept: a new black substance and a gas are formed. A colour change ALONE is not
        accepted.                                                                               (2)
7.2.1   C3 H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2 O(g)
        Marking criteria
        Reactants ✓ Products ✓ Balancing and phases ✓
        Accept H2 O(ℓ). Phases are required for the third mark.
                                                                                                (3)
7.2.2   Mass of reactants = 1(44) + 5(32) = 44 + 160 = 204 g ✓
        Mass of products = 3(44) + 4(18) = 132 + 72 = 204 g ✓
        Mass of reactants = mass of products, therefore mass is conserved. ✓
        POSITIVE MARKING FROM 7.2.1 if the equation used is balanced.                           (3)
7.3
                                C              H                  O

         Mass in 100 g       62,1 g          10,3 g         27,6 g

              m            62,1           10,3           27,6
         n=                     = 5,18         = 10,3         = 1,73
              M             12             1              16

         Ratio                  3              6                  1
        Dividing by the moles in 100 g (any one correct) ✓            all three n correct ✓
        simplest ratio 3 : 6 : 1 ✓
        Empirical formula: C3 H6 O (M = 58 g·mol–1 )
        116
             =2✓
         58
        Molecular formula: C6 H12 O2 ✓
        Accept the ratio method directly from masses. POSITIVE MARKING from an incorrect
        empirical formula.                                                                     (5)
                                                                                              [14]

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### Page 9

Physical Sciences/P2                            9                              Hlayiso/Mock 2026
                                     NSC – Marking Guidelines

QUESTION 8
8.1.1   M(NaHCO3 ) = 23 + 1 + 12 + 3(16) = 84 g·mol–1
            m        8,4
        n=     ✓ =       ✓
            M        84
        n = 0,1 mol ✓                                                                        (3)
8.1.2   n(Na2 CO3 ) = 12 n(NaHCO3 ) = 0,05 mol      (mol ratio 2 : 1) ✓
        m = nM = 0,05 × 106 ✓
        m = 5,3 g ✓
        POSITIVE MARKING FROM 8.1.1.                                                         (3)
8.1.3   n(CO2 ) = 21 n(NaHCO3 ) = 0,05 mol ✓
             V            V
        n=       0,05 =       ✓
            Vm           22,4
        V = 1,12 dm3 ✓
        POSITIVE MARKING FROM 8.1.1.                                                         (3)
8.1.4   n(H2 O) = 21 n(NaHCO3 ) = 12 (0,1) = 0,05 mol ✓
        m = nM = 0,05 × 18 ✓
        m = 0,9 g ✓
        POSITIVE MARKING FROM 8.1.1.                                                         (3)
            n           n
8.2.1   c=      0,1 =      ✓ n = 0,025 mol ✓
            V         0,25
             m    7,15
        M= =            = 286 g·mol–1 ✓
             n 0,025
        106 + 18x = 286 ✓
        x = 10 ✓
                  m           7,15
        OR: c =      : 0,1 =         ✓✓; M = 286 g·mol–1 ✓; 106 + 18x = 286 ✓; x = 10 ✓
                  MV         M(0,25)                                                         (5)
                 10(18)
8.2.2   % H2 O =        × 100 ✓
                  286
        = 62,94% ✓
        POSITIVE MARKING FROM 8.2.1.                                                         (2)
                                                                                            [19]
                                                                                     TOTAL: 100

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