# Physical Sciences Grade 10 P2 National November 2016 Memo

> Grade 10 Physical Sciences Paper 2 memorandum from the National November 2016, 14 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-10-physical-sciences-p2-memo/5c79d2a0-fb11-498c-ae8a-37ee9cbca43c
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 10
- Document type: Memorandum
- Year: 2016
- Exam period: National November
- Paper: 2
- Curriculum: CAPS
- Pages: 14

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## About this document

Physical Sciences · Grade 10 · National November · 2016. Memorandum, 14 pages. Read online or download the PDF.

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### Page 1

ale basic education

REPUBLIC OF SOUTH AFRICA

NATIONAL
SENIOR CERTIFICATE/

NASIONALE
SENIOR SERTIFIKAAT

GRADE/GRAAD 10
i PHYSICAL SCIENCES: CHEMISTRY (P2) +
7 FISIESE WETENSKAPPE: CHEMIE (V2)
ty a
7 NOVEMBER 2016 :
i un
i il
N MEMORANDUM n
MARKS/PUNTE: 147
This memorandum consists of 12 pages.
Hierdie memorandum bestaan uit 12 bladsye.
DEPARTMENT OF BASIC
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Physical Sciences/P2/Fisiese Wetenskappe/V2 DBE/November 2016
CAPS/KABV — GradelGread 10- Memorandum

QUESTION 1/VRAAG 1
1.4 CvY (2)
1.2 AvvY (2)
1.3 Cvv (2)
14 Dvv (2)
1.5 Cvv (2)
1.6 Avv (2)
1.7 ByYY (2)
1.8 Byv (2)
1.9 Cv¥v (2)
1.10 Dvv (2)
[20]
QUESTION 2/VRAAG 2
2.1 A pure substance is a substance that cannot be separated into simpler
components by physical methods. “
OR
A pure substance is made up of one (same) type of element or molecule. “
‘n Suiwer stof is 'n stof wat nie deur fisiese metodes in eenvoudiger
komponente opgebreek kan word nie.
OF
‘n Suiwer stof bestaan siegs uit een (dieselfde) tipe element of molekule. (1)
2.2 2.2.1 Element ¥ (1)
2.2.2 Consist of only one type of atom.”
Besiaan uit net een tipe atoom (1)
2.2.3 Mixtures ¥/Mengsel (1)
o¢ 2.2.4 It is a combination of many gases. “
Dit is 'n kombinasie van baie gasse (1)
2.3 Pots and pans are made of metal, because metal is a good conductor “that
allows heat to be transferred so that the food can cook. The handles are
insulators (poor conductor of heat) VW so that you do not burn your hands
when you pick up a hot pot.
Potte en panne word van metaal gemaak, omdat metaal 'n goeie geleier van
hitte is wat toelaat dat hitte oorgedra word, sodat die kos kan gaar word. Die
handvaisels is isolators (swak geleiers van hitte) sodat jou hande nie brand
as jy 'n warm pot optel nie. (2)
2.4 2.4.1 NaCt DEPARTMENT OF BASIC (2)
2.42 alas 7 2) SSS q00t Me

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Physical Sciences/P2/Fisiese Wetenskappe/V2 3 DBE/November 2016

CAPS/KABV — Grade/Graad 10 - Memorandum

QUESTION 3/VRAAG 3

3.1

3.2

3.3
3.4
3.5

3.6
3.7

3.8

3.9

3.1.1 Temperature V/Temperatuur
3.1.2 Time ¥ Also accept phase change
Tyd. Aanvaar ook faseverandering

What is the relationship between an increase in temperature over a period

of time and/or phase change? Vv”

Wat is die verwantskap tussen 'n toename in temperatuuir vir 'n tydperk en/of

faseverandering?

NOTE: -YThe dependent and independent variable must be mentioned.

¥The relationship between the variables must be identified.

The question should not be answered with a YES or NO.

LET WEL: Die onafhanklike en afhanklike veranderlike moet genoem
word.
Die verwantskap tussen die veranderlikes moet ook genoem
word.
Die vraag moet nie kan beantwoord word deur 'n JA of NEE
antwoord nie.

Solid “/Vaste stof
-24°Cv

Boiling point is the temperature of a liquid at_which its vapour pressure is
equal to the external (atmospheric) pressure. es

Kookpunt is die temperatuur van 'n vioeistof waar sy dampdruk gelyk is aan
die eksterne (atmosferiese) druk.

Liquid changes to gas. v/Vioeistof na gas

The kinetic energy of the particles remains the same’, the energy is used to
overcome/break/weaken the intermolecular forces (forces of attraction)
between the particles’, particles move further away from each other
(increase in potential energy)“ resulting in a phase changew’.

Die kinetiese energie bly dieselfdew, die energie word gebruik om die
intermolekulére kragte (aantrekkingskragte) tussen die deeitjies te oorkom
/oreek/verswak v{die deeltjies beweeg verder uit mekaar uit, dus neem die
potensiéle energie toe.“ en sodoende vind 'n faseverandering piaas. “”

Substance 2.V

Substance 2 has a lower meiting and/or boiling point than substance 1. “
Stof 2.

Stof 2 het 'n laer smelt- en/of kookpunt as stof.

Thermometer “/Termometer

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Physical Sciences/P2/Fisiese Wetenskappe/V2 4 DBE/November 2016
CAPS/KABV - Grade/Graad 10 - Memorandum
3.10 Gi TO.”
O\ substance 1 and 2 are at the same temperature. Therefore they will have the

same average kinetic energy.”
GELYK AAN.
Stof 1 en 2 is by dieselfde temperatuur. Dus sal hulle oor dieselfde

gemiddelde kinetiese energie beskik.

QUESTION 4/VRAAG 4

41

4.2

4.3

lonisation energy is the energy needed to remove an electron from (one mole)
of an atomv v in a gaseous phase.

lonisasie-energie is die energie benodig om 'n elektron uit (een mol) van ‘n
atoom in 'n gasfase te verwyder.

4.2.1 Metals_have_lower_first_ionisation energy than _non-metalsvv,
therefore metals would rather lose electrons to form a positive ion
(cation).
Metale het laer eerste ionisasie-energie as nie-metale, daarom sal
metale eerder elekirone verloor om 'n positiewe ioon (katioon)
fe vorm.

4.2.2 Non-metals have higher first ionisation energy than _metalsv v,
therefore non-metals would rather gain electrons to form the
negative ions (anions).

Nie-metale het hoér eerste ionisasie-energie as metale, daarom sal
nie-metale eerder elektrone opneem om die negatiewe ione
(anione) te vorm.

The second electron is removed from the energy level very close to the
nucleus (atomic radius decreases), therefore the force of attraction between
the electron and the nucleus is stronger” hence more energy is needed to
remove the second electron”.

OR

When lithium loses its first electron, it attains a stable electron configuration’,
hence more energy is needed to remove the second electron’.

Die tweede elektron word verwyder van die energieviak wat naby aan die
kem is (atoomradius verminder), dus is die aantrekkingskrag tussen die
elektron en die kern sterker. Daarom word meer energie benodig om die
tweede elektron te verwyder.

OF

Wanneer fitium die eerste elektron verloor, verkry dit ‘n meer stabiele
elektronkonfigurasie. Daarom word meer energie benodig om die tweede
elektron te verwyder.

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Physical Sciences/P2/Fisiese Wetenskappe/V2 DBE/November 2016
CAPS/KABV — Grede/Groed 10 - Memorandum
QUESTION 5/VRAAG 5
5.1 Isotopes are atoms of the same element having the same number of protons
but different numbers of neutrons. a)
OR

different atomic mass (mass number).
Isotope is afome van dieselfde element Wat dieselfde getal protone het, maar
verskillende getalle neutrone.

Isotopes are atoms of the same ber having the same atomic number but

OF
isotope is atome van dieselfde element wat dieselfde atoomgetal het, maar
verskillende atoommassas (massagetal) het. (2)
5.2 5.24 18x and/en 29x v
OR/OF
A and/en CY (1)
5.2.2 Fluorine” /Fluoor (1)
5.3 69 % Wn”
Ar(Cu — x63 — x65
(Cu)= (a Js (io
=63.62¥v (4)

5.4 5.4.1 19 Vv
5.4.2 10v
5.4.3 Mg (isotope) OR magnesium (isotope) “
Mg (isotoop) OF magnesium (isotoop)”

5.4.4 12Vv
5.4.5 138Vv (5)
55 (NHz)2S0, “ (1)

5.6 Covalent bond’.
lectrons are shared” between the atoms of hydrogen and nitrogen.
Kovalente binding.

Elektrone word gedee! tussen die atome van waterstof en stikstof. (2)
5.7
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Physical Sciences/P2/Fisiese Wetenskappe/V2 6 DBE/November 2016
CAPS/KABV — Grade/Graad 10- Memorandum

5.9 ee

H
Ww 2

QUESTION 6/VRAAG 6
6.1 6.1.1 Reaction (ii) v/Reaksie (ii) (1)
6.1.2 Reaction (i) ~/Reaksie (i) (1)
6.2 Gas phase Vv
Gasfase (1)
6.3 6.3.1 aluminium carbonate: Atz(COs)3 7)
aluminiumkarbonaat. Ato(COs)3 (2)
6.3.2 aluminium oxide: Af,O3 ”)
aluminiumoksied: AtO3 (2)
6.4 Cle «+ He > 2HC&g) “Reactants/ Reagense ~ Products/ Produkte (2)
6.5 Reactants/Reaktante: M (Cf2) + M (H2)
= (2)(35,5) + (2)(1)
= 73 g.moltv

Products/Produkte: M (2 HC2)
= (2)(1 + 35,5)
= 73 g.molt ”

Thus the mass of the reactants = mass of the products ¥
Dus die massa van die reaktante = massa van die produkte. (3)

6.6 M(HCE) = 1 + 35,5
= 36,5 (g.mol") v

*H= 100
or 36.5
=2,74% ¥
ic
35 5 DEPARTMENT ON
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Physical Sciences/P2/Fisiese Wetenskappe/V2 DBE/November 2016

CAPS/KABV — Grade/Gred 10 - Memorandum

QUESTION 7/VRAAG 7
7.1 An electrolyte is a solution that conducts electricity Vv’ through the movement

7.2

7.3

7.4

7.5

70

of ions.

‘n Elektroliet is 'n oplossing wat elektrisiteit gelei deur die beweging van ione.

KCLY —K*v +CErv

KCe: K*

1:1

Thus 2 mol of KC£ dissolves. vv
Dus 2 mol KC£ los op.

39
%K =
745

x100 v

=52,35% ¥
Increase V/Toeneem

NEGATIVE MARKING FROM QUESTION 7.5.

NEGATIEWE NASIEN VAN VRAAG 7.5.

With an increase in concentration of the metal salt, potassium chloride, more
ions are released v into the solution. Thus, more free ions are available to

conduct electricity. “
Met 'n toename in die konsentrasie van die metaalsout, kaliumchloried, word

meer jone in die oplossing vrygelaat. Dus is meer ione beskikbaar om
elektrisiteit te gelei.

Ic
TMENT CF BAS
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Physical Sciences/P2/Fisiese Weftenskappe/V2 8 DBE/November 2016
CAPS/KABV ~ Grade/Graad 10 - Memorandum

QUESTION 8/VRAAG 8

8.1 8.1.1 The empirical formula is the simplest whole number ratio of atoms

in a compound.
Die empiriese formule is die eenvoudigste heelgetalverhouding van

atome in 'n verbinding. (2)

8.1.2 If 100 g of the compound is available then:
Indien 100 g van die verbinding beskikbaar is, dan is daar:

53,3g 0 40gC 6,6 gH
M(©) = 16 g:‘mol"* = M(C) = 12 g:mol™? M(H) = 4 g-mol"*
n=m/M n=m/M n=m/M
n= §3,3/16 n= 40/12 n=6,6/1
n=3,33125 mol“ n=3,3mol” n=6,6 mol”
Thus/Dus: O:C :H

3.33125: 3.3 :6.6
33 33 33”
1:1 :2
Emiprical formula/Empiriese formule = C Hz OV
ACCEPT TABLE METHOD
AANVAAR TABEL METODE (5)

8.1.3 M(CH20)
= 12 + 2(1)+ 16
= 30 g-mor' v

Formule mass/Formulemassa 60 =2v
Empirical mass/Empiriese massa 30

Thus the molecular formula
Dus is die molekulére formule = (CH20) x 2

al C2H.02 v (3)
8.2 M (Na2COs) = 106 g-‘mol! ¥
M (x H2O) = 268 — 106
~ ssimer OF BASIC
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Physical Sciences/P2/Fisiese Wetenskappe/V2 9
CAPS/KABV — Grade/Graad 10 - Memorandum

QUESTION 9/VRAAG 9

9.1

9.2

9.2.1

DBE/November 2016

Temperature/Temperatuur. 273 K or/of 0 °C ¥
Pressure/Druk: 1,013 x 10° Pa (101,3 kPa) or/of 1 atm ”

MARK OPTION 1 AND 2 IF 10g | MARK OPTION 3 IF 2dm*
Na IS USED. WATER IS USED
MERK OPSIE 1 EN 2 INDIEN MERK OPSIE 3 INDIEN 2dm’
10g Na GEBRUIK IS. WATER GEBRUIK IS.
OPTION 4/OPSIE 7: OPTION 3/OPSIE 3:

m
n(Na)=Y 2 mol H2O : 1 mol He ”

40 (2)(18) Vv :2v

“33 v 2000 g : xv
= v
= 0,43 mol Na x= 111,11g
Na: He.
2:1v%

Thus 0,22 mol H2 produced ¥
Dus 0,22 mol H2 word
geproduseer.

m
n(H2) = —

(He) M

m
0,22 =—

2

m=0,43gv Hz
produced/gevorm
OPTION 2/OPSIE 2:
2 mol Na produces 1 mol H2 “”
(2)(23g) V produces (1)(2g) “
10g produces x¥
x =0,43g”
—SSNENT GF BASIC |

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Physical Sciences/P2/Fisiese Wetenskappe/V2 DBE/November 2016
CAPS/KABV — Grade/Greed 10- Memorandum

9.2.2 POSITIVE MARKING FROM 8.2.1
POSITIEWE NASIEN VAN 9.2.1

MARK OPTION 1 AND 2 IF 10 g Na IS USED.
MERK OPSIE 1 EN 2 INDIEN 10g Na GEBRUIK IS.

OPTION 1/OPSIET:

n(H:) =< ¥

m

0,22 = v
22,4

V=4,93 dm? v
Accept 4,82 dm®
OPTION 2/OPSIE 2:
4 mol: 22,4dm? v

2g : 22,4 dmv

0,439 : x
x= 4, 82 dm°v

MARK OPTION 3 IF 2dm® WATER IS USED
MERK OPSIE 3 INDIEN 2dm’ WATER GEBRUIK IS.

OPTION 3/OPSIE 3:

1 mol: 22,4dm> v
2g : 22,4 dmv

111,119 : x
X = 1244,43 dm? (3)

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Physical Sciences/P2/Fisiese Wetenskappe/V2 11 DBE/November 2016
CAPS/KABV — Grade/Graad 10 - Memorandum

9.2.3 POSITIVE MARKING FROM 9.2.1
POSITIEWE NASIEN VAN 9.2.1

MARK OPTION 1 AND 2 IF 10 g Na IS USED.
MERK OPSIE 1 EN 2 INDIEN 10g Na GEBRUIK IS.

OPTION 1/OPSIE 1:

n(Na) : n(NaOH)

2:2V
Thus mol NaOH = 0,43 mol
Dus mol NaQH = 0,43 mol

n(NaOH) = M v

m

—___—___-v
(23+16+1)
m=17,2 g VY of NaOH produced/gevorm

0,43 =

OPTION 2/OPSIE 2:

1 mol Na produces/produseer 1 mol NaOH ¥
23g produces/produseer 40g v

10g produces/produseer xv

x= 17,399”

MARK OPTION 3 IF 2dm* WATER IS USED
MERK OPSIE 3 INDIEN 2dm* WATER GEBRUIK IS.

OPTION 3/OPSIE 3:

1 mol H2O : 1 mol NaOH ~
18g : 40g ¥
2000g : x”
x = 4444 44gv

(4)

POSITIVE MARKING FROM 9.2.3
OSITIEWE NASIEN VAN 9.2.3

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Physical Sciences/P2/Fisiese Wetenskappe/V2 12 DBE/November 2016

CAPS/KABV — Grade/Graad 10 - Memorandum

QUESTION 10/VRAAG 10
10.1. Precipitate v/Presipitaat/Neersiag (1)
10.2 10.2.1 Step |: BaCl, ¥

10.3

10.4

10.5

Step Il: no reaction ¥

Stap I: BaCl,

Stap Il: geen reaksie V (2)
10.2.2 Step I: AgNO; ~

Step Il: HNO3

Stap I: AgNO3

Stap Il: HNO3 (2)
10.2.3. White “/Wit (1)
10.3.1 Cv (1)
1032 Dv (1)
103.3 Av (1)

Precipitation v/Presipitasie (neerslag)
Evaporation v/Verdamping
Condensation V/Kondensasie (3)

Building dams that store drinking water and water for household needs
or agriculture.

Boreholes are used to tap ground water for use.

Any applicable answer. “”

Bou damme vir drinkwaier en huishoudelike gebruik of landbou.
Boorgate word gebruik om grondwater te gebruik.

Enige aanvaarbare antwoord. VV (2)
[14]

TOTALITOTAAL: 147

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basic education

Department:
Basic Education
REPUBLIC OF SOUTH AFRICA

Private Bag X895, Pretoria, 0001, Sol Plaatie House, 222 Struben Street, Pretoria, 0002, South Africa
Tel.: (012)357 3000, Fax: (012) 323 0601, www.education.gov.za

HEADS OF EXAMINATION SECTIONS
HEADS OF CURRICULUM SECTIONS

| EXAMINATION INSTRUCTION NO 35 OF 2016

AMENDMENTS TO THE MARKING GUIDELINE OF THE 2016 COMMON EXAMINATION FOR GRADE 10:
PHYSICAL SCIENCES P2

Error on both English and Afrikaans versions: Question 9.

An etror was identified in sub question 9.2.4. Information required to calculate the
concentration of NaOH was omitted.
This sub question which carried 3 marks must not be marked, and, these 3 marks must be

excluded.

Consequently the total marks for the question paper must be reduced to 147 marks, then
scaled up to 150 marks.

Refer to Annexure A that provides the conversion table that must be used to calculate the

learner's total marks.
her information please contact ihe Director: Examinations and Assessment,

se pgaaneno at 012 357 3909 or email: Oqunbanjo.o@dbe.gov.za

Ow
=
DR RR POLIAH
CHIEF DIRECTOR: NATIONAL ASSESSMENT AND PUBLIC EXAMINATIOS
DATE: =
IS- Nth, DEPARTMENT OF BASIC
EDUCATION
PRIVATE BAG X95, PRETORIA 0001
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Basic Education» Basiese Onderwys » Imfundve Lesisekelo « Ifundosisekelo » IMfundo Eyisieckelo= IMfundo esiSissko « Dyondze yale Hansi
Pfunzo ya Mutheo® Thuto ya Matheo* Thuto ya Mctheos Thutoe Pottana

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Annexure A: GRADE 10 PHYSICAL SCIENCES P2:; ENGLISH AND AFRIKAANS VERSIONS- M

JARKS CONVERTED FROM 147 TO 150

pis Converted Wald Converted Mars Converted (REE Converted
out of | to 150 out of | to 450 out of | to 150 out of | to 150
147 147 147 147
1 1 45 46 89 91 133 136
2 2 46 47 90 92 134 137
3 3 47 48 91 93 135 138
4 4 48 49 92 94 136 139
5 5 49 50 93 95 137 140
6 6 50 51 94 96 138 141
7 7 51 52 95 97 139 142
8 8 52 53 96 98 140 143
9 9 53 54 97 99 141 144
10 10 54 55 98 100 142 145
11 41 55 56 99 101 143 146
12 12 56 57 100 102 144 147
13 13 S7 58 101 103 145 148
14 14 58 59 102 104 146 149
15 15 59 60 103 105 147 150
16 16 60 61 104 106
17 17 61 62 105 107
18 18 62 63 106 108
19 19 63 64 107 109
20 20 64 65 108 110
21 21 65 66 109 111
22 22 66 67 110 112
23 23 67 68 111 113
24 24 68 69 112 114
25 26 69 70 113 115
26 27 70 71 114 116
27 28 71 72 115 117
28 29 72 73 116 118
29 30 73 74 117 119
30 31 74 76 118 120
31 32 75 77 119 121
32 33 76 78 120 122
33 34 7 79 121 123
34 35 78 80 122 124
35 36 79 81 123 126
36 37 80 82 124 127
37 38 81 83 125 128
38 39 82 84 126 129
39 40 83 85 127 130
40 41 84 86 128 131
41 42 8&5 87 129 132
42 43 86 8&3 130 133
43 44 87 89 131 134 ry
44 4S 88 90 132 135 = DURATION Easle
PRIVATE B&G X595, PRETORIA CQUT
2016 -11- 41
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PLIFRI tes rw a neine mri

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