# Technical Sciences Grade 10 P1 November Mock 2026 Memo (Eng)

> Grade 10 Technical Sciences Paper 1 memorandum from the November Mock Exam 2026 (English), 9 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-10-technical-sciences-2026-november-mock-exam-memorandum-paper-1/ece6d5ad-d988-4a6c-94e5-dd0e0df35cb5
- Updated: 2026-10-29
- Subject: Technical Sciences
- Grade: Grade 10
- Language: English
- Document type: Memorandum
- Year: 2026
- Exam period: November Mock Exam
- Paper: 1
- Publisher: Hlayiso
- Curriculum: CAPS
- Pages: 9

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## About this document

Technical Sciences · Grade 10 · November Mock Exam · 2026 · English. Memorandum, 9 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Matching paper and memo

- [Grade 10 Technical Sciences P1 November 2026 Mock](https://www.hlayiso.com/library/grade-10-technical-sciences-2026-november-mock-exam-question-paper-paper-1/6bee5edc-3ef4-4857-98cd-70ec77d56ff1) — QP · 2026 · Eng

## Document text

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### Page 1

hlayiso mock exams
                             Practice Series:
                             Grade 10 Exam Preparation
                             WWW.HLAYISO.COM

                                  NATIONAL
                             SENIOR CERTIFICATE

                                    GRADE 10

                            TECHNICAL SCIENCES P1
                     NOVEMBER EXAMINATION 2026 (MOCK)
                              MARKING GUIDELINES

  MARKS: 150

                     These marking guidelines consist of 9 pages.

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### Page 2

Technical Sciences/P1                       2                              Hlayiso/Mock 2026
                                 NSC – Marking Guidelines

GENERAL MARKING GUIDELINES

  1. Calculations: Marks are awarded for the correct formula, correct substitution and the
     correct final answer WITH the correct unit, as indicated by the ticks (✓). No mark is
     awarded for a formula that is not followed by a substitution. If an incorrect formula is
     used, no further marks are awarded for that calculation.
  2. Units: The final-answer mark is only awarded if the correct unit is given. Penalise an
     omitted or incorrect unit only ONCE per question.
  3. Rounding: Accept final answers rounded to a minimum of TWO decimal places. Small
     differences caused by rounding of intermediate values are accepted.
  4. Positive marking: Where an incorrect answer from a previous question is used correctly
     in a later calculation, full marks are awarded for the later calculation.
  5. Negative marking: If a candidate must explain or motivate a choice and the choice is
     incorrect, no marks are awarded for the explanation.
  6. Definitions: Where key words are underlined, deduct 1 mark for EACH key word or
     phrase that is omitted. Accept equivalent wording that conveys the same meaning.
  7. Free-body diagrams: ONE mark for each force represented by an arrow with a correct
     label. Penalise ONCE for: no arrows, gaps between the arrows and the dot, dotted lines,
     or additional (non-applicable) forces.
  8. Vectors: Where a direction is asked for (displacement, velocity, acceleration, resultant
     force), the final mark is only awarded if the direction is given.

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### Page 3

Technical Sciences/P1              3               Hlayiso/Mock 2026
                        NSC – Marking Guidelines

QUESTION 1
1.1     C ✓✓                                                      (2)
1.2     A ✓✓                                                      (2)
1.3     B ✓✓                                                      (2)
1.4     C ✓✓                                                      (2)
1.5     D ✓✓                                                      (2)
1.6     B ✓✓                                                      (2)
1.7     A ✓✓                                                      (2)
1.8     C ✓✓                                                      (2)
1.9     B ✓✓                                                      (2)
1.10    D ✓✓                                                     (2)
                                                                [20]

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### Page 4

Technical Sciences/P1                            4                                    Hlayiso/Mock 2026
                                      NSC – Marking Guidelines

QUESTION 2
         450
2.1.1         ✓ = 0,45 kg ✓
        1 000                                                                                        (2)
2.1.2   15 × 60 ✓ = 900 s ✓                                                                          (2)
2.1.3   5,6 × 10–3 ✓ A ✓      (1 mark for 5,6; 1 mark for the correct power of ten)                  (2)
2.2     A physical quantity that has both magnitude and direction. ✓✓                                (2)
2.3.1   600 + 250 ✓ = 850 m ✓                                                                        (2)
2.3.2   East positive: ∆x = 600 + (–250) ✓
        ∆x = 350 m ✓ east ✓                                                                          (3)
2.3.3
                            600 m east

                                           250 m west
           resultant: 350 m east
        Criteria: 600 m vector to the east with label ✓; 250 m vector to the west, drawn
        head-to-tail ✓; resultant drawn from tail of first to head of last vector ✓; resultant
        labelled 350 m east ✓.                                                                       (4)
                distance
2.3.4   speed =          ✓
                    ∆t
                850
        speed =      ✓
                170
        speed = 5 m·s–1 ✓                                                                            (3)
2.3.5   POSITIVE MARKING FROM QUESTION 2.3.2
            ∆x 350
        v=     =     ✓
            ∆t 170
        v = 2,06 m·s–1 ✓ east ✓                                                                      (3)
            1
2.4.1   ∆t =  ✓ = 0,02 s ✓
           50                                                                                        (2)
2.4.2   CONSTANT (velocity) ✓                                                                        (1)
2.4.3   POSITIVE MARKING FROM QUESTION 2.4.1
        ∆t = 10 × 0,02 = 0,2 s ✓ (10 spaces between 11 dots)
            ∆x
        v=      ✓
            ∆t
            0,20
        v=        ✓
             0,2
        v = 1 m·s–1 ✓
        If 11 intervals are used (∆t = 0,22 s, v = 0,91 m·s–1 ): max 3/4.                            (4)

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### Page 5

Technical Sciences/P1                            5                                Hlayiso/Mock 2026
                                      NSC – Marking Guidelines

            ∆v
2.5     a=      ✓
            ∆t
            15 – 0
        a=         ✓
              6
        a = 2,5 m·s–2 east ✓                                                                     (3)
                                                                                                [33]

QUESTION 3
3.1     A push or a pull that one object exerts on another object. ✓✓                             (2)
3.2     Fg = mg ✓
        Fg = (40)(9,8) ✓
        Fg = 392 N (downwards) ✓                                                                  (3)
3.3     Tension / applied force ✓                                                                 (1)
3.4
                     N / FN / normal force ✓

         f / friction ✓                        T / FA / applied force ✓

                          Fg / w / weight ✓
        Do not penalise for relative lengths of arrows. Accept a box drawn instead of a dot.      (4)
3.5     East positive: Fres = 180 + (–120) ✓
        Fres = 60 N ✓ east ✓                                                                      (3)
3.6     NO ✓
        The resultant (net) force on the crate is NOT zero (60 N east). ✓                        (2)
                                                                                                [15]

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### Page 6

Technical Sciences/P1                         6                                Hlayiso/Mock 2026
                                   NSC – Marking Guidelines

QUESTION 4
4.1     The turning effect of a force; it is the product of the force and the perpendicular
        distance from the pivot (fulcrum) to the line of action of the force. ✓✓               (2)
4.2     τ = F × r⊥ ✓
        τ = (80)(0,3) ✓
        τ = 24 N·m ✓                                                                           (3)
4.3     The perpendicular distance from the nut (pivot) is greater. ✓
        The same force produces a larger moment (torque) / a smaller force is needed
        for the same moment. ✓                                                                 (2)
4.4.1   For a body in equilibrium, the sum of the clockwise moments about any point
        is equal to the sum of the anticlockwise moments about the same point. ✓✓              (2)
4.4.2   Take moments about L:
        Σ clockwise moments = Σ anticlockwise moments ✓
        (400)(2) + (600)(5) + (200)(7) ✓ = R(8) ✓
        5 200 = 8R
        R = 650 N ✓
        Take moments about R:
        L(8) ✓ = (400)(6) + (600)(3) + (200)(1) ✓
        L = 550 N ✓
        OR, after R has been calculated: L = 1 200 – 650 ✓✓ = 550 N ✓                          (7)
4.4.3   POSITIVE MARKING FROM QUESTION 4.4.2
        Upward forces: 550 + 650 = 1 200 N ✓
        Downward forces: 400 + 600 + 200 = 1 200 N ✓
        ∴ upward forces = downward forces                                                      (2)
4.5.1   The ratio of the load to the effort (load divided by effort). ✓✓                       (2)
              load
4.5.2   MA =        ✓
             effort
             900
        MA =      ✓
             150
        MA = 6 ✓      (no unit)                                                                (3)
4.5.3   First-class lever (class 1) ✓                                                          (1)
4.5.4   Any ONE: Scissors / pliers / see-saw / claw hammer pulling a nail / tin-lid lever
        / balance ✓                                                                            (1)
                                                                                              [25]

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### Page 7

Technical Sciences/P1                         7                               Hlayiso/Mock 2026
                                   NSC – Marking Guidelines

QUESTION 5
5.1     The energy that an object possesses because of its position (height) relative
        to a reference point (the ground). ✓✓                                                (2)
5.2     Ep = mgh ✓
        Ep = (250)(9,8)(18) ✓
        Ep = 44 100 J ✓    (accept 4,41 × 104 J / 44,1 kJ)                                   (3)
5.3     The energy that an object possesses because of its motion. ✓✓                        (2)
5.4     Ek = 12 mv2 ✓
        Ek = 12 (0,16)(30)2 ✓
        Ek = 72 J ✓                                                                          (3)
5.5.1   The sum of the gravitational potential energy and the kinetic energy of an
        object. ✓✓                                                                           (2)
5.5.2   EM = Ep + Ek ✓
        EM = (2)(9,8)(4) ✓ + 21 (2)(6)2 ✓
        EM = 78,4 + 36 = 114,4 J ✓                                                          (4)
                                                                                           [16]

QUESTION 6
6.1     MORE THAN ✓                                                                          (1)
6.2     Sphere B is negatively charged / has an excess of electrons. ✓                       (1)
6.3     The net (total) charge in an isolated (closed) system remains constant (is
        conserved). ✓✓                                                                       (2)
            Q1 + Q2
6.4     Q=          ✓
               2
            (+7 × 10–9 ) + (–3 × 10–9 )
        Q=                              ✓
                         2
        Q = +2 × 10–9 C (on each sphere) ✓                                                   (3)
6.5     POSITIVE MARKING FROM QUESTION 6.4
            ∆Q
        n=      ✓
             e
            (+2 × 10–9 ) – (–3 × 10–9 )            –9      –9
        n=                              ✓ (or 7×10 –2×10
                                                       –19    for sphere A)
                   1,6 × 10  –19                1,6×10
        n = 3,13 × 1010 electrons ✓ (accept 3,125 × 1010 )                                   (3)
6.6     FROM B TO A ✓                                                                        (1)
6.7     REPEL ✓
        Both spheres are positively charged; like charges repel. ✓                          (2)
                                                                                           [13]

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### Page 8

Technical Sciences/P1                            8                                 Hlayiso/Mock 2026
                                      NSC – Marking Guidelines

QUESTION 7
7.1     The rate of flow of charge. ✓✓
        Accept: the amount of charge that passes a point in a conductor per second.                (2)
            Q
7.2     I=     ✓
            ∆t
            18
        I=      ✓
            60
        I = 0,3 A ✓
        If 1 is used for ∆t (18 A): max 1/3.                                                       (3)
7.3     The opposition that a material (conductor) offers to the flow of electric current.
        ✓✓                                                                                         (2)
7.4     Any THREE ✓✓✓:
        Length of the conductor
        Cross-sectional area (thickness) of the conductor
        Type of material (resistivity)
        Temperature of the conductor                                                               (3)
7.5
                          S
                                        A
        3 cells
                                       bulb              V

                                 R
        Criteria: Battery of three cells, switch, bulb and resistor ALL in series ✓; ammeter in
        series ✓; voltmeter in parallel across the bulb ONLY ✓. Correct symbols must be used.      (3)
                                                                                                  [13]

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### Page 9

Technical Sciences/P1                         9                               Hlayiso/Mock 2026
                                   NSC – Marking Guidelines

QUESTION 8
8.1     The maximum energy provided (work done) by a battery per coulomb (unit) of
        charge passing through it. ✓✓
        Accept: the potential difference across the terminals of a battery when NO current
        flows.                                                                                (2)
         1     1   1
8.2        =     +   ✓
        Rp R2 R3
         1    1 1
           = + ✓
        Rp 6 3
        Rp = 2 Ω ✓                                                                            (3)
8.3     POSITIVE MARKING FROM QUESTION 8.2
        RT = R1 + Rp = 4 + 2 ✓
        RT = 6 Ω ✓                                                                            (2)
8.4     POSITIVE MARKING FROM QUESTION 8.3
           V
        R= ✓
            I
           12
        6=    ✓
            I
        I=2A✓                                                                                 (3)
8.5     POSITIVE MARKING FROM QUESTION 8.4
        V = IR ✓
        V1 = (2)(4) ✓
        V1 = 8 V ✓                                                                            (3)
8.6     POSITIVE MARKING FROM QUESTION 8.5
        VT = V1 + V2 12 = 8 + V2 ✓
        V2 = 4 V ✓
        OR: V2 = IRp = (2)(2) ✓ = 4 V ✓                                                       (2)
                                                                                             [15]
                                                                                 TOTAL:      150

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