# Mathematical Literacy Grade 11 P2 North West June 2017 Memo

> Grade 11 Mathematical Literacy Paper 2 memorandum from the North West June 2017, 6 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-11-mathematical-literacy-2017-north-west-june-memorandum-paper-2/8fbc9c77-92a8-48a1-a772-36439d2bafd2
- Updated: 2026-10-29
- Subject: Mathematical Literacy
- Grade: Grade 11
- Document type: Memorandum
- Year: 2017
- Exam period: North West June
- Paper: 2
- Curriculum: CAPS
- Pages: 6

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Mathematical Literacy · Grade 11 · North West June · 2017. Memorandum, 6 pages. Read online or download the PDF.

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### Page 1

NATIONAL
                          SENIOR CERTIFICATE

                                   GRADE 11

                       MATHEMATICAL LITERACY P2

                                      JUNE 2017

                           MARKING GUIDELINES

MARKS: 75

            SYMBOL       EXPLANATION
            M            Method
            M/A          Method with accuracy
            CA           Consistent accuracy
            A            Accuracy
            C            Conversion
            D            Definition
            S            Simplification
            RT/RG/RD     Reading from a table/Reading from a graph
            F            Choosing the correct formula
            SF           Correct substitution in a formula
            O            Opinion/Example
            P            Penalty, e.g. for no units, incorrect rounding off etc.
            R            Rounding off
            J            Justification/Reason
            NP           No penalty for rounding OR omitting units

                       This marking guideline consists of 6 pages

### Page 2

Mathematical Literacy/P2                       2           NW/June 2017
                                          NSC – Grade 11

MARKING GUIDELINES

QUE.    SOLUTIONS                                          EXPLANATIONS        TL
        QUESTION 1 [32 MARKS]
1.1.1   150 g × 50                                        1M Multiplying by   2
         = 7 500 g                                        50
        = 7,5 kg                                          1S simplification
                                                           1C answer in kg
                                                           (3)
1.1.2   0,25 kg = 250g                                    1C conversion       4

                                                           1M method
        number of loaves to be baked =       
                                     = 33,333              1No.of loaves
                                     = 33
        Yes, comment is valid                             1O opinion

        OR                                                 OR
                                                           1M method
        7,5g × 50 = 375 g                                1S simplification
                 = 0,375 kg                               1C conversion
        Yes, comment is valid                             1O opinion
                                                           (4)
1.2.1   A = R400 + R3,50 × 120                            1M method           2
          = R400 + R420                                    1A answer for A
          = R820                                          1M method
                                                           1A answer for B
        OR                                                 (4)

        A = R680 + R140
          = R820

        B=        = 160 loaves
1.2.2   Cost = R400 + R3,50 × number of loaves           1A R400 +           2
                                                           1A product
                                                           (2)
1.2.3   Cost = R400 + R3,50 × 50                          1SF substitution    2
             = R575                                       1A answer
                                                           (2)

### Page 3

Mathematical Literacy/P2                                        3                             NW/June 2017
                                                           NSC – Grade 11

1.2.4

                         Cost and Income of Loaves of bread
                       2000

                       1800

                       1600
                                                                       Income
                       1400                                                                   1A (0,400)

      Amount in rand
                                                                                              1A (280,1 380)
                       1200                                                 Cost
                                                                                              1A joining the
                       1000                                                                   points
                       800                                                                    1A labelling the
                                                                                              graph
                       600                                                                    1A any other
                       400                                                                    correct point
                       200                                                                    (5)
                                                                                                                  3
                         0
                              0    40       80       120    160     200      240        280

                                                 Loaves of bread

1.2.5                  (160, R960)                                                          1A number of        2
                                                                                              loaves
                                                                                              1A amount
                                                                                              (2)
1.2.6                  Cost of 200 loaves = R1 100                                           1RT cost            3
                       Income from 200 loaves = R1 200                                       1RT income
                       Profit = R1 200 – R1 100 = R100                                       1A profit
                                                                                              (3)
1.2.7                                                                                         1M percentage       4
                                                                                              1A answer
                       Percentage =        × 100%
                                                                                              1Conclusion
                                  = 9,09%                                                    (3)
                       Thus, claim is not valid
                       OR

                                     
                       = R110
                       Thus, claim is not valid
1.3                    Total time = 30 hours                                                 1A total time       4
                              15                                                              1M method
                       Then       × 30 hours = 4,5 hours                                    1CA expected time
                             100
                       Time given to languages = 4 hours which is less than expected          for languages
                       Thus, the time allocated is not according the staff agreement         1O opinion
                       OR
                       Total time = 30 hours                                                 (4)

### Page 4

Mathematical Literacy/P2                         4                       NW/June 2017
                                            NSC – Grade 11

         Then       100%
         = 13,3%
         Thus, claim is not valid
         QUESTION 2[21 MARKS]
2.1.1    Total monthly cost of electricity                               1M method           3
         = 324kWh × 117,86cents                                         1A in cents
         =38 186,64 cents                                               1A in rand
         = R381,87                                                      (3)
2.1.2    Total monthly cost of electricity                               1M block 1          3
         = 350kWh × 117,86 cents+ 244,8× 163,19 cents                  1M block 2
         =41 251 cents + 39 948,912 cents                               1S simplification
         = 81 199,912 cents                                             1A in cents
         =R812,00                                                       1A in rand
                                                                         (5)
2.1.3    Too many appliances used that consumes a lot of electricity   2A answer           4

         OR                                                              (2)

         Heaters used for warming up the house

         OR

         High consumption of water from the geyser

         Accept any relevant reason
2.2.1                                                                    1SF substitution    2
                                                                         1A answer
         BMI =                                                           1R rounding

                                                                         (3)
         BMI =          
             = 28,25096981 kg/m2
             = 28,3 kg/m2 

2.2.2    Overweight                                                    2CA answer          2
                                                                         (2)
2.2.3    Diet                                                          2A reason           4

         OR                                                              (2)

         Ill-health

         OR

         Use of weight-loss products

         Accept any other relevant reason
2.2..4   ˚C= (˚F – 32˚)÷1,8                                              1SF temp. in ˚C     3
         43˚=(˚F – 32˚) ÷1,8                                            1S simplification

### Page 5

Mathematical Literacy/P2                           5                  NW/June 2017
                                              NSC – Grade 11

        ˚F = 43˚×1,8 +32˚                                            1A answer
        ˚F = 109,4˚                                                  1R rounding
        ˚F = 110˚                                                    (4)
                                                                      Penalise for
                                                                      rounding

        QUESTION 3[22 MARKS]
3.1.1                                                                 1RT using correct       4
                                                                      values
        Percentage =           × 100
                                                                      1M method
                    = 69,48051948
                                                                      1A answer
        No, the claim is not valid                                   1O opinion
        OR                                                            (4)

             × 443 520
        = R310 464
        No, the claim is not valid
3.1.2                    R 10 047                                     1M method               4
        Average cost =             
                            27                                        1A answer
                      = R372,1111                                     (2)
                      = R370
3.1.3                          57 120                                 1M method               4
        Overseas donations =          
                                 0,08                                 1A answer
                             = ¥ 714 000                             1O opinion
        Thus, the claim is correct                                   (3)
3.1.4   Deliver food parcels                                        2O opinion              4
        OR Fuel
        OR Maintenance                                              (2)
        OR Going to buy garden material
        OR Asking for donations
        OR Attending board meetings
        Accept any relevant reason
3.2.1   Volume = 100×60×30                                           1SF substitution        3
                 = 180 000 cm3                                       1S simplification
                = 180 litres                                         1C conversion
                                                                       (3)
3.2.2                   180 litres                                    1M method               4
        Number of fish=              
                         7 litres                                     1A no. of fish
                      = 25,7142857                                    1O opinion
                      = 25                                           OR
        No, 26 fish cannot fit in the tank                           1M method
                                                                      1A volume needed
        OR                                                            1O opinion
                                                                      (3)
        Volume for 26 fish= 26 × 7 litres                            [2 out of 3 if no. of
                                                                      fish is 26]
                           = 182 litres
        No, the volume needed is less than the volume of the tank.
3.3     180 litres = 180 × 1,7598 pint                               1M method               3
                   = 316,764 pint                                    1A in pint

### Page 6

Mathematical Literacy/P2                         6                 NW/June 2017
                                            NSC – Grade 11

        316,764 pints = 316,764 ×0,125 gallons                    1M method
                      = 39,5955 gallons                           1A in gallons
                      = 40 gallons                                1CA answer
                                                                   (5)

QUESTION PAPER ANALYSIS

QUESTION              TL2               TL3                  TL3
QUESTION 1
1.1.1                 3
1.1.2                                                        4
1.2.1                 4
1.2.2                 2
1.2.3                 2
1.2.4                                   5
1.2.5                                   2
1.2.6                                   3
1.2.7                                                        3
1.3                                                          4
QUESTION 2
2.1.1                                   3
2.1.2                                                        5
2.1.3                                                        2
2.2.1                 3
2.2.2                 2
2.2.3                                                        2
2.2.4                                   4
QUESTION 3
3.1.1                                                        4
3.1.2                 2
3.1.3                                                        3
3.1.4                                                        2
3.2.1                                   3
3.2.2                                                        3
3.3                                     5

TOTAL MARKS           18                25                   32
PERCENTAGES           24                33                   43

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