# Mathematics Grade 11 Paper 1 North West June 2017 Memo

> Grade 11 Mathematics Paper 1 memorandum from the North West June 2017, 9 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/grade-11-mathematics-2017-north-west-june-memorandum-paper-1/6fa7396a-5760-4bd7-a7c4-0ec8f7fac2f2
- Updated: 2026-10-29
- Subject: Mathematics
- Grade: Grade 11
- Document type: Memorandum
- Year: 2017
- Exam period: North West June
- Paper: 1
- Curriculum: CAPS
- Pages: 9

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## About this document

Mathematics · Grade 11 · North West June · 2017. Memorandum, 9 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

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### Page 1

GRADE 11

                       MATHEMATICS P1 MEMORANDUM

                                     JUNE 2017

MARKS: 100

                     This memorandum consists of 9 pages..

Copyright reserved                                           Please turn over

### Page 2

Mathetics/P1                                     2                  June/2017
                                                NSC

QUESTION 1

 1.1.1
                2x2 – 7x = 0                          factors
                x(2x – 7) = 0                         x = 0

               x = 0 or x =
                                                      x =                      (3)

 1.1.2.            2x (x – 3) = 1
                   2x2 – 6x – 1 = 0                   2x2 – 6x – 1 = 0

                                                       formula

                                                      sub. into correct formula

                                                      answer                     (4)
                       x = 3,16 or x = – 0,16

 1.1.3
                                                      

                                                       squaring
          Square both sides, 1+ x = x2 – 10x + 25     standard form
                      x2 – 11 x + 24 = 0
                                                      factors
                     (x – 8 )( x – 3 ) = 0
                                                      answer
                           x = 8 or x = 3 N/A
                                                                                 (5)

 1.1.4

                                                       
                                                           x2 + 3x = k
                   Let        x2 + 3x = k

                                                      std form in k

                                                      factors
                   k2 – 26k – 56      = 0
                                                      vales of k

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### Page 3

Mathetics/P1                                        3                                  June/2017
                                                   NSC

                 ( k – 28 )(k + 2 ) = 0

                                                                           2 eqs. in x
                     k = 28 or k = – 2
                                                                           4 values of x          (7)
                 x2 + 3x = 28       or          x2 + 3x = – 2

                 x2 + 3x– 28 = 0         or      x2 + 3x + 2 = 0

                 (x +7) (x – 3) = 0       or (x + 2)(x + 1) = 0

                 x = –7 or       x =3         or x = – 2 or x = – 1

                                                                          ( x – 3)( 2 – x) > 0

 1.1.5               ( x + 3)( 2 – x) > 0                                 end values
                 ( x + 3)( x – 2) < 0                           -         notation                 (3)
                                                         -3           2
                 –     3 < x < 2

 1.1.6

                                                                           factors

                                                                          

                                                                           x = 16                  (4)
                      N/A
                              x = 16

 1.2       x2 – 2xy – 3y2 and 3x + y – 2 = 0
                                                                           y = 2 – 3x
                                                y = 2 – 3x

               x2 – 2x(2 – 3x) – 3(2 – 3x )2 = 0                          sub. of y

           x2 – 4x + 6x2 – 3(4 – 12x + 9x2 ) = 0

           x2 – 4x + 6x2 – 12+ 36x – 27x2 ) = 0

                              –20 x2 + 32x –12 = 0                        std form

                                  5 x2 – 8x + 3 = 0
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### Page 4

Mathetics/P1                                   4                  June/2017
                                              NSC

                               (5x – 3) (x – 1) = 0   factors

                                  or x = 1            
                                                       x = 1
                                   or y = 2 – 3 (1)

                                                      y values                 (7)
               y =                       y = –1
 1.3.1

                                                       sub of k in
         When k = 5,
                            = 0
          Roots are real and equal
                                                      equal and real           (2)
 1.3.2   For non-real roots,                          
                               25 – 5k < 0
                                   k>5                k>5                       (2)

QUESTION 2

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### Page 5

Mathetics/P1                            5                June/2017
                                       NSC

2.1.1

                     =                        taking common factor
                                             outside
                     =
                                             ans                          (2)
                     = 3

2.1.2
                           =                 

                           = 6x – 2x

                           = 4x              ans                      (2)

2.1.3

                                             Convert base into prime
         =                                   numbers

                                             removing the bracket

        =
                                             apply the law

        =

        =
                                             answer                 (4)

        =
Copyright reserved                                  Please turn over

### Page 6

Mathetics/P1                                            6                           June/2017
                                                       NSC

 2.2.1

                                                                        
                                                                        taking common factor
                                                                        outside
                                                                        answer                         (3)
 2.2.2

                                                                        

                                                                        

                               x = –1                                   answer                         (3)

QUESTION 3
 3.1
                   2            6       12        20

                       4            6         8

                                2       2

         T5 = 30                                                         T5 = 30
         T6 = 42                                                        T6 = 42                  (2)

 3.2     2a = 2 ;               3a + b = 4;             a+b+c = 2       3a + b = 4;
           a= 1                3(1) + b = 4              1 +1 + c = 2   a+b+c = 2
                                     b =1                     c =0      value of a
                                                                        Value of b
         Tn = n2 + n                                                    value of c               (5)

QUESTION 4

 4.1.1                 i m
               (
         i eff = 1 +
                       m   )
                           -1                                            formula

                                                                        correct sub. into formula

               =

               = 0.087747961...
                                                                        answer                   (3)

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### Page 7

Mathetics/P1                                   7                  June/2017
                                              NSC

         Rate = 8,77%

 4.1.2
                                                      formula

                                                      sub. into the formula
            = R 18273,54                              answer              (3)
 4.2
                                                      formula

               = 150000(1- 0,124)5
                                                      sub. into the formula
            = R77376,98
                                                      answer              (3)
 4.3
                                                      i
                                                       equation
                                                       x(3,52612449) = 20000
                          x(3,52612449) = 20000
                                                      answer                  (4)
                                       x = R5671,95

QUESTION 5
 5.1

          x = -2 or x = 6
                                                       OA = 2
          OA = 2 and OB = 6                            OB = 6             (2)
 5.2

                  = -24                                x =0
                                                      y = -24                 (2)
            C(0; -24)
 5.3
         Axis of symmetry is x = 1
                                                      x=1

                                     = -30
                                                       TP(1 ; -30)
                                TP(1 ; -30)
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### Page 8

Mathetics/P1                           8                June/2017
                                      NSC

                         Range is y         ans                (3)

 5.4                                        Notation
                                            end values         (2)
 5.5     c = - 24
                                            c = -24

         Passing through (6 ;0)             sub. of (6;0)

         m= 4
                                             m= 4                (3)
 5.6      T.P of h(x) is ( 1 ; 30)           x value
                                            y value              (2)

QUESTION 6

6.1.1   Asymptotes are x = 3 and y = - 2           x = 3
                                                   y = -2
6.1.2

                                                   making y = 0

        x –intercepts:

          2(x -3) = 2                               x =4

               2x = 8

               x = 4                                making x = 0

        y-intercepts                               y =
                                                                      (4)
                         =

6.1.3                                              x-int
                                                   y-int
                                                    shape

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### Page 9

Mathetics/P1                       9         June/2017
                                  NSC

6.1.4
        Domain is                       answer            (1)

6.1.5    y = (x – 3) – 2
                                         m= 1
           = x – 5                      c = -5            (2)

6.2

        q = –1                          value of q

        Passing through (0; -2)

                                        Sub. of (0;-2)
         a = -1
                                         value of a

                                        sub. of

         -3 = b-1

          b =                           value of b
                                                           (5)

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