# Physical Sciences Grade 11 P1 2020 Memo (Eng) > Grade 11 Physical Sciences Paper 1 memorandum from the National Exemplar November Exam 2020 (English), 32 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/grade-11-physical-sciences-2020-national-exemplar-november-exam-memorandum-paper-1-english/306eb51f-162e-40b7-bce9-063679b31fa7 - Updated: 2026-09-28 - Subject: Physical Sciences - Grade: Grade 11 - Language: English - Document type: Memorandum - Year: 2020 - Exam period: National Exemplar November Exam - Paper: 1 - Curriculum: CAPS - Pages: 32 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 11](https://www.hlayiso.com/library/grade-11) › [Physical Sciences](https://www.hlayiso.com/library/grade-11/physical-sciences) › [Physical Sciences Grade 11 P1 2020 Memo (Eng)](https://www.hlayiso.com/library/grade-11-physical-sciences-2020-national-exemplar-november-exam-memorandum-paper-1-english/306eb51f-162e-40b7-bce9-063679b31fa7) ## About this document Physical Sciences · Grade 11 · National Exemplar November Exam · 2020 · English. Memorandum, 32 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Matching paper and memo - [PHYS P1 GR11 QP NOV2020 English](https://www.hlayiso.com/library/grade-11-physical-sciences-2020-national-exemplar-november-exam-question-paper-paper-1-english/1a172f0c-e8d7-45e3-aa21-8c3dea0460fe) — QP · 2020 · Eng ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 NATIONAL SENIOR CERTIFICATE GRADE 11 NOVEMBER 2020 PHYSICAL SCIENCES P1 (EXEMPLAR) MARKS: 150 TIME: 3 hours *IPHSCE1* This question paper consists of 19 pages including 2 datasheets. ### Page 2 2 PHYSICAL SCIENCES P1 (EC/NOVEMBER 2020) INSTRUCTIONS AND INFORMATION 1. Write your full NAME and SURNAME in the appropriate space on the ANSWER BOOK. 2. This question paper consists of TEN questions. Answer ALL the questions in the ANSWER BOOK. 3. Start EACH question on a NEW page. 4. Number the answers correctly according to the numbering system used in this question paper. 5. Leave ONE line between two sub questions, for example between QUESTION 2.1 and QUESTION 2.2. 6. You may use a non-programmable calculator. 7. You may use appropriate mathematical instruments. 8. Show ALL formulae and substitutions in ALL calculations. 9. Round off your FINAL numerical answers to a minimum of TWO decimal places. 10. Give brief motivations, discussions, et cetera where required. 11. You are advised to use the attached DATA SHEETS. 12. Write neatly and legibly. Copyright reserved Please turn over ### Page 3 (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1 3 QUESTION 1: MULTIPLE-CHOICE QUESTIONS Four possible options are provided as answers to the following questions. Each question has only ONE correct answer. Choose the best answer and only write down (A–D) next to the question numbers (1.1–1.10) in the ANSWER BOOK, for example 1.11 D. 1.1 Which ONE of the following forces CANNOT be equal to zero? A Normal force B Frictional force C Gravitational force D Applied force (2) 1.2 The diagram below represents four vectors Q, R, S and T. Q R T S Which ONE of the vectors is the resultant of the other three vectors? A Q B R C S D T (2) 1.3 A girl of weight 600 N is standing on a bathroom scale in a lift that is moving and she noticed that the scale reads 560 N. Which ONE of the following is the CORRECT conclusion about the motion of the lift? The lift is … A accelerating upwards. B accelerating downwards. C moving upwards at constant velocity. D moving downwards at constant velocity. (2) 1.4 Passengers in a moving car are advised to wear safety belts. This will reduce their chances of getting injured in the event of an accident. This precaution is an application of which ONE of the following Physics laws? A Newton’s first law B Newton’s second law C Newton’s third law D Newton’s law of universal gravitation (2) Copyright reserved Please turn over ### Page 4 4 PHYSICAL SCIENCES P1 (EC/NOVEMBER 2020) 1.5 Which ONE of the graphs below represents the relationship between the gravitational force F between two objects and the distance r between the objects? A B F (N) F (N) 1 ‫ݎ‬ଶ 1 ‫ݎ‬ଶ C D F (N) F 1 1 ‫ݎ‬ଶ ‫ݎ‬ଶ (2) Copyright reserved Please turn over ### Page 5 (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1 5 1.6 A light ray passes from air into a glass prism. The ray is refracted through the prism and emerges out of the prism as shown in the diagram below. ߠଵ ߠଶ ߠଷ ߠସ Which ONE of the following statements is TRUE regarding the diagram above? A ߠସ = ߠଷ B ߠସ = ߠଵ C ߠସ = ߠଶ D ߠଵ = ߠଶ 1.7 Every point of a wave front serves as a point source of spherical, secondary waves that move forward with the same speed as the wave. This definition represents … A refraction. B diffraction. C wave front. D Huygens’ principle. (2) Copyright reserved Please turn over ### Page 6 6 PHYSICAL SCIENCES P1 (EC/NOVEMBER 2020) 1.8 Two identical neutral spheres P and Q are placed on insulating stands. They are brought into contact with each other and a charged rod is brought near sphere P as shown on the diagram below. P Q Charged rod After the spheres made contact, they were separated and it was found that electrons were transferred from sphere P to sphere Q. Which ONE of the following concerning the charges on the two spheres is TRUE? SPHERE P SPHERE Q A Positive Positive B Positive Negative C Negative Negative D Negative Positive (2) 1.9 The magnitude of the induced emf across the ends of a loop is equal to the … A radius of the loop. B thickness of the wire. C temperature of the wire. D rate of change the magnetic flux linkage with the wire. (2) Copyright reserved Please turn over ### Page 7 (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1 7 1.10 In the circuit diagrams below the SAME battery and SAME IDENTICAL resistors are used. The internal resistance of the battery is ignored. In which ONE of the following circuits will the resistors have the highest potential difference? A B A A R1 R1 R2 R3 R2 R3 C D A R1 A R2 R1 R2 R3 R3 (2) [20] Copyright reserved Please turn over ### Page 8 8 PHYSICAL SCIENCES P1 (EC/NOVEMBER 2020) QUESTION 2 A pulley system is used to keep a crate of mass M kg stationary as shown on the diagram below. T2 S 30o 245 N M kg T1 2.1 Define the term resultant vector. (2) 2.2 Calculate the: 2.2.1 Vertical and horizontal components of T 2 (4) 2.2.2 Magnitude of T1 (2) 2.2.3 Mass M of the crate (3) [11] Copyright reserved Please turn over ### Page 9 (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1 9 QUESTION 3 A 250 N force is applied on a block of mass 25 kg. The 25 kg block is connected to a 10 kg block by a light inextensible string through a frictionless pulley as shown on the diagram below. The 250 N force acts at an angle of 25o to the horizontal so that the system of blocks accelerates to the left. The coefficient of kinetic frictional force between the 25 kg block and the surface is 0,15. 250 N 25 kg 25o 10 kg 3.1 Define the term kinetic frictional force. (2) 3.2 Draw a labelled free-body diagram of all forces acting on the 25 kg block. (5) 3.3 Calculate the: 3.3.1 Normal force exerted by the surface on the 25 kg block (3) 3.3.2 Acceleration of the system of blocks (7) [17] Copyright reserved Please turn over ### Page 10 10 PHYSICAL SCIENCES P1 (EC/NOVEMBER 2020) QUESTION 4 Two blocks of masses 1,5 kg and 3,2 kg are connected by a light inextensible string. A 24 N force is applied on a system of blocks to move them up an inclined surface which is 25o to the horizontal at a CONSTANT VELOCITY as shown on the diagram below. The 1,5 kg box experiences a constant frictional force of 2 N as it moves up the incline. 24 N 20o 4.1 State Newton’s Second Law of Motion in words. (2) 4.2 Draw a labelled free-body diagram of all forces acting on the 1,5 kg block. (4) 4.3 Calculate the: 4.3.1 Tension in the string connecting the blocks (5) 4.3.2 Coefficient of kinetic frictional force between the 3,2 kg block and the surface (6) [17] Copyright reserved Please turn over ### Page 11 (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1 11 QUESTION 5 A satellite of mass 1 000 kg is orbiting the earth at a distance of 200 km from the surface of the earth as shown on the diagram below. Earth Satellite 200 km 5.1 State Newton’s Law of Universal Gravitation in words. (2) 5.2 Calculate the magnitude of the force that the earth exerts on the satellite to keep it in orbit. (5) 5.3 Calculate the weight of the satellite on the earth surface. (3) 5.4 The same satellite is now orbiting the earth at a distance twice the radius of the earth from the centre of the earth. Without any further calculations, determine the force that the earth exerts on the satellite at the new distance. Explain how you arrived at your answer. (3) [13] Copyright reserved Please turn over ### Page 12 12 PHYSICAL SCIENCES P1 (EC/NOVEMBER 2020) QUESTION 6 A light ray from a ray box is incident on a rectangular glass prism and the path of the incident ray and emergent ray was traced to obtain the diagram below. The refractive index of air and the refractive index of a glass are 1,00 and 1,52 respectively. 50o ߠ 6.1 State Snell’s law in words. (2) 6.2 Calculate the: 6.2.1 Angle ߠ, on the diagram (4) 6.2.2 Speed of light in glass (3) 6.2.3 Critical angle for glass (4) 6.3 Define total internal reflection. (2) 6.4 State TWO conditions necessary for total internal reflection to occur. (2) [17] Copyright reserved Please turn over ### Page 13 (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1 13 QUESTION 7 A learner is investigating a certain phenomenon of light. He viewed red light through a single slit and observed the pattern that was formed on a screen. He repeated the experiment using blue light and observed the pattern on a screen again. 7.1 Name the phenomenon that the leaner is investigating. (1) 7.2 Draw separate diagrams for the patterns for red light and blue light that the learner observed on the screen. Label clearly red and blue bands. (4) 7.3 Explain the differences observed in the patterns for red and blue light. (2) 7.4 Which nature of light does the phenomenon investigated demonstrate? (1) 7.5 What are the changes, if any, that the learner will observe if the slit width is made smaller? Explain your answer. (3) [11] Copyright reserved Please turn over ### Page 14 14 PHYSICAL SCIENCES P1 (EC/NOVEMBER 2020) QUESTION 8 Two identical point charges are placed 100 mm apart in a vacuum as shown below. The electrostatic force that Q1 exerts on Q2 is 5,09 N. Q1 Q2 + + 100 mm 8.1 Draw the electric field pattern between the two charges. (3) 8.2 Calculate the magnitude of each charge. (4) 8.3 Calculate the net electric field at point P, as shown on the diagram below. Q1 Q2 + + P 100 mm 50mm (5) 8.4 A third charge Q3 of magnitude 5 —C is now placed at point P as shown in the diagram below. Q1 Q2 Q3 + + + 100 mm 50 mm Calculate the net electrostatic force experienced by point charge Q2 due to point charge Q1 and Q3. (5) [17] Copyright reserved Please turn over ### Page 15 (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1 15 QUESTION 9 9.1 The diagram below represents a current-carrying conductor. Draw the magnetic field pattern around this conductor. (2) 9.2 A solenoid with a radius of 5 cm and 350 turns is pulled out of a magnetic field of strength 5,20 T in 0,1 second. The solenoid is placed perpendicular to the magnetic field. 9.2.1 State Faraday’s law in words. (2) 9.2.2 Calculate the magnetic flux linkage (Ȱ) with the solenoid. (3) 9.2.3 Calculate the induced emf in the solenoid. (3) [10] Copyright reserved Please turn over ### Page 16 16 PHYSICAL SCIENCES P1 (EC/NOVEMBER 2020) QUESTION 10 10.1 A learner sets up the circuit below to investigate the relationship between current and potential difference across the ends of a conductor. She closes the switch and records the ammeter and voltmeter readings. She repeats the experiment three times; each time she increases the number of cells in the circuit. Then she reads and records the ammeter and voltmeter readings. A R V A graph of her results is shown below. I (A) 1,0 0,8 0,4 0,2 0,6 1,2 2,4 3,0 V (V) 10.1.1 Which physical quantity does the gradient of the graph represent? (1) 10.1.2 Use the information from the graph to calculate the resistance of the resistor that the learner used in the investigation. (3) Copyright reserved Please turn over ### Page 17 (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1 17 10.2 The battery in the circuit diagram below has negligible internal resistance. The resistance of resistor R is unknown. When the switch is closed, the voltmeter reads 15 V and the ammeter A1 reads 1 A. 15V V A R 1A A1 12 Ÿ 6Ÿ 6Ÿ Calculate the: 10.2.1 Current in ammeter A (3) 10.2.2 Resistance of resistor R (5) 10.3 The resistor R of unknown resistance is now removed from the circuit. How will this change in the circuit affect the reading of the ammeter A? Answer INCREASE, DECREASE or REMAIN THE SAME. Explain your answer. (2) 10.4 The power rating on an electric stove is 1 500 W. If the stove is used for 3 hours and 30 minutes, calculate how much it will cost to use the stove. 1 unit of electricity (1 kWh of electricity) costs R1,15. (3) [17] TOTAL: 150 Copyright reserved Please turn over ### Page 18 18 PHYSICAL SCIENCES P1 (EC/NOVEMBER 2020) DATA FOR PHYSICAL SCIENCES GRADE 11 PAPER 1 (PHYSICS) GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 11 VRAESTEL 1 (FISIKA) TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES SYMBOL/ NAME/NAAM VALUE/WAARDE SIMBOOL Acceleration due to gravity / g 9,8 m•s-2 Swaartekragversnelling Universal gravitational constant / G 6,67 × 10-11 N•m2.kg-2 Universelegravitasiekonstant Speed of light in a vacuum / Spoed van lig in ƌ c 3,0 × 108 m•s-1 vakuum Planck's constant / Planck se konstante h 6,63 × 10-34 J•s Coulomb's constant / Coulomb se konstante k 9,0 × 109 N•m2•C-2 Charge on electron / Lading op elektron e -1,6 × 10-19 C Electron mass / Elektronmassa me 9,11 × 10-31 kg Mass of earth / Massa op aarde M 5,98 × 1024 kg Radius of earth / Radius van aarde RE 6,38 × 103 km TABLE 2: FORMULAE/TABEL 2: FORMULES MOTION/BEWEGING vf vi  a 't ǻx v i ǻt  21 a't 2 or/of ǻy v i ǻt  21 a't 2 2 2 2 2 § vi  v f · § vi  v f · vf v i  2a'x or/of v f v i  2a'y ǻx ¨ ¸ ǻt or/of ǻy ¨ ¸ ǻt © 2 ¹ © 2 ¹ FORCE/KRAG Fnet ma w mg Gm 1 m2 ௙ ೘ೌೣ F 2 ߤ௦ = ೞ ே d ௙ ߤ௞ = ேೖ Copyright reserved Please turn over ### Page 19 (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1 19 WAVES, SOUND AND LIGHT/GOLWE, KLANK EN LIG kQ 1Q 2 F F (k = 9,0 x 109 N.m2.C-1) E r2 q kQ Q E (k = 9,0 x 109 N.m2.C-1) n= r2 qe ELECTROMAGNETISM/ ELEKTROMAGNETISME ȟȰ Ȱ = BA cos ߠ ɂ = െܰ ȟ‫ݐ‬ ELECTRIC CIRCUITS/ELEKTRIESE STROOMBANE ொ V I= R ୼௧ I 1 1 1   ... Rs R1  R 2  ... Rp R1 R 2 W = Vq W P ǻt W = VI ' t P = VI W= I2R ' t P = I2R 2 V2 W= V ǻt P R R Copyright reserved Please turn over ### Page 21 NATIONAL/NASIONALE SENIOR CERTIFICATE/SERTIFIKAAT GRADE/GRAAD 11 NOVEMBER 2020 PHYSICAL SCIENCES P1/ FISIESE WETENSKAPPE V1 MARKING GUIDELINE/NASIENRIGLYN (EXEMPLAR/EKSEMPLAAR) MARKS/PUNTE: 150 This marking guideline consists of 10 pages. Hierdie nasienriglyn bestaan uit 10 bladsye. ### Page 22 2 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2020) QUESTION 1/VRAAG 1 1.1 C ‫ضض‬ (2) 1.2 B ‫ضض‬ (2) 1.3 A ‫ضض‬ (2) 1.4 A ‫ضض‬ (2) 1.5 D ‫ضض‬ (2) 1.6 C ‫ضض‬ (2) 1.7 D ‫ضض‬ (2) 1.8 B ‫ضض‬ (2) 1.9 D ‫ضض‬ (2) 1.10 B ‫ضض‬ (2) [20] QUESTION 2/VRAAG 2 2.1 The vector sum of two or more vectors. ‫ضض‬ Die som van twee of meer vektore. OR/OF A single vector having the same effect as two or more vectors acting together. ‫ضض‬ ƌ Enkele vektor wat dieselfde effek het as twee of meer vektore wat saam inwerk. (2) 2.2 2.2.1 OPTION 1/ OPSIE 1 OPTION 2/ OPSIE 2 T2X = Tcosߠ T2X = Tsinߠ T2X = 245 cos 30o ‫ض‬ T2X = 245 sin 60o ‫ض‬ T2X = 212,18 N ‫ض‬ T2X = 212,18 N ‫ض‬ T2Y = Tsinߠ T2Y = Tcosߠ T2Y = 245 sin 30o ‫ض‬ T2Y = 245 cos 60o ‫ض‬ T2Y = 122,5 N ‫ض‬ T2Y = 122,5 N ‫ض‬ (4) 2.2.2 T1 = T2X ‫ض‬ T1 = 212,18 N ‫ض‬ (2) 2.2.3 W = T2Y W = 122,5 N W = mg Any one/Enige een ‫ض‬ 122,5 = m x 9,8 ‫ض‬ m = 12,5 kg ‫ض‬ (3) [11] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 23 (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 3 QUESTION 3/VRAAG 3 3.1 The force that opposes the motion of a moving object relative to the surface. ‫ضض‬ Die krag wat die beweging van ƌ bewegende voorwerp relatief tot die oppervlak teenwerk. (2) 3.2 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 FN ‫ض‬ FY FN ‫ض‬ ‫ض‬ F‫ض‬ T‫ض‬ T‫ض‬ Ff ‫ض‬ FX Ff ‫ض‬ Fg‫ض‬ Fg‫ض‬ Mark awarded for arrow and label./ Punt toegeken vir byskrif en pyltjie. Do not penalise for length of arrows since drawing is not drawn to scale./ Moenie vir die lengte van die pyltjie penaliseer nie aangesien diagram nie volgens skaal geteken is nie. Any other additional force(s)./ Enige ander addisionele krag(te). 4ൗ5 If force(s) do not make contact with body. / As krag(te) nie kontak met die voorwerp maak nie. Max./ Maks. 4ൗ5 (5) 3.3 3.3.1 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 N = Fg – F sin ș ‫ض‬ FY = F sin ș N = 25x 9,8 – 250 sin 25o ‫ض‬ = 250 sin 25° N = 139,35 N ‫ض‬ = 105,66 N N = Fg – FY ‫ض‬ N = 25x 9,8 – 105,66 ‫ض‬ N = 139,34 N ‫ض‬ (3) 3.3.2 POSITIVE MARKING FROM 3.1.1/POSITIEWE NASIEN VANAF 3.1.1 Fnet = ma Any one/Enige een ‫ض‬ Fnet = Fcos ș – T – f [250 cos 25° ‫ – ض‬T – (0,15 x 139,35) ‫ = ض ] ض‬25a 25a = 205,6744468 – T ...(1) Any one of 25a or 10a/ Fnet = T – Fg Enige een van 25a of T – 98 ‫ =ض‬10a . . . (2) 10a ‫ض‬ Adding the two equations/Tel die twee vergelykings bymekaar: 35a = 107,6744468 a = 3,08 m.s-2 ‫ض‬ (7) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 24 4 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2020) QUESTION 4/VRAAG 4 4.1 When a resultant force acts on an object, the object will accelerate in the direction of the force. The acceleration is directly proportional to the resultant force ‫ ض‬and inversely proportional to the mass ‫ض‬of the object. Wanneer ‘n resulterende krag op ‘n voorwerp inwerk, sal die voorwerp in die rigting van die krag versnel. Die versnelling is direk eweredig aan die resulterende krag en omgekeerd eweredig aan die massa van die voorwerp. (2) 4.2 FN ‫ض‬ T‫ض‬ FN ‫ض‬ T‫ض‬ Ff ‫ض‬ Fg‫ضצ‬ Ff Fg‫ض‬ Fg٣‫ض‬ (4) Mark awarded for arrow and label. / Punt toegeken vir pyltjie en byskrif. Do not penalise for length of arrows since drawing is not drawn to scale./ Moenie vir die lengte van die pyltjie penaliseer nie aangesien diagram nie volgens skaal geteken is nie. Any other additional force(s)./ Enige ander addisionele krag(te). 3ൗ4 If force(s) do not make contact with body. / As krag(te) nie kontak maak met die voorwerp nie. Max/ Maks 3ൗ4 4.3 4.3.1 Fnet = ma Fnet = T – Fg// - f T – Fg// - f = ma Any one/Enige een ‫ض‬ T – Fg// - f = 0 [T – (1,5 x 9,8 sin20o) ‫ض‬- 2] ‫ = ض‬0 ‫ض‬ T = 7,03 N ‫ض‬ (5) 4.3.2 Fnet = ma Fnet = F – T – Fg// - f Any one/ Enige een ‫ض‬ F – T – Fg// - f = ma F – T – Fg// - f = 0 [24 – 7,03 – (3,2 x 9,8 sin20o) – fk] = 0 ‫ض‬ fk = 6,22425 N fk = — k N ‫ض‬ [6,22425 = —k x 3,2 x9,8 cos 20o‫ض ]ض‬ —k = 0,21 ‫ض‬ (6) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 25 (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 5 QUESTION 5/VRAAG 5 5.1 Every particle attracts every other particle in the universe with a gravitational force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres. ‫ضض‬ Elke deeltjie lok enige ander deeltjie in die heelal met ‘n gravitasiekrag wat direk eweredig is aan die produk van hul massas en omgekeerd eweredig is aan die kwadraat van die afstand tussen hul middelpunte. (2) 5.2 GM1M2 F= ‫ض‬ r2 6,67 x10 -11 x 5,98 x10 24 x1000 ‫ض‬ F= (6,38 x10 6 +2 x10 5 )2 ‫ضض‬ F = 9 212,45 N ‫ض‬ (5) 5.3 OPTION 1 / OPSIE 1 OPTION 2 / OPSIE 2 W = mg ‫ض‬ GM1M2 W= ‫ض‬ W = 1 000 x 9,8 ‫ض‬ r2 W = 9 800 N ‫ض‬ 6,67 x10 -11 x1000 x 5,98 x10 24 W= ‫ض‬ (6,38 x10 6 )2 W = 9 799,09 N ‫ض‬ (3) 5.4 900 W= ‫ = ض‬2 450 N ‫ض‬ 4 When the distance doubles the force will decrease by a factor of 4 ‫ض‬. Wanneer die afstand verdubbel, sal die krag vier (4) keer verminder. (3) [13] QUESTION 6/VRAAG 6 6.1 The ratio of the sine of the angle of incidence in one medium to the sine of the angle of refraction in the other medium is constant. ‫ضض‬ Die verhouding tussen die sinus van die invalshoek in die een medium en die sinus van die brekingshoek in die ander medium is konstant. (2) 6.2 6.2.1 n2 sinș1 = ‫ض‬ n1 sinș 2 1,52‫ ض‬sin40° = ‫ض‬ 1 sinș 2 ߠଶ = 25,02o ‫ض‬ (4) 6.2.2 c n= ‫ض‬ v 3 x10 8 1,52 = ‫ض‬ v v = 1,97 x 108 m.s-1 ‫ض‬ (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 26 6 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2020) 6.2.3 n2 sinș1 = ‫ض‬ n1 sinș 2 1,52 ‫ ض‬sin90° = ‫ض‬ 1 sinș 2 ߠଶ = 41,14o ‫ض‬ (4) 6.3 A phenomenon that occurs when light travels from a denser medium to a less dense medium and the refracted ray does not emerge from the medium, but is reflected back into the medium. ‫ضض‬ ƌ Verskynsel wat voorkom wanneer lig van ƌ digter medium na ƌ minder digte medium beweeg en die gebreekte straal nie uit die medium kom nie, maar weer terug in die medium weerkaats. (2) 6.4 The light must travel from a denser medium to a less dense medium. ‫ض‬ The angle of incidence must be greater than the critical angle of the denser medium. ‫ض‬ Die lig moet van ƌ digter medium na ƌ minder digte medium beweeg. Die invalshoek moet groter wees as die grenshoek van die digter medium. (2) [17] QUESTION 7/VRAAG 7 7.1 Diffraction/ Diffraksie ‫ض‬ (1) 7.2 ‫ضض‬ ‫ضض‬ (4) 7.3 The coloured bands for red light are broader than those of blue light. ‫ض‬ The wavelength for red light is longer than that of a blue light. ‫ض‬ Die gekleurde bande vir rooi lig is breër as dié van blou lig. Die golflengte vir rooi lig is langer as dié van blou lig. (2) 7.4 Light has a wave nature / Lig het golf-aard ‫ض‬ (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 27 (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 7 7.5 The coloured bands will become broader./ Die gekleurde bande sal breër word. ‫ض‬ The slit width is inversely proportional to the degree of diffraction. ‫ضض‬ Die spleetwydte is omgekeerd eweredig aan die mate van diffraksie. OR/OF Smaller width gives broader diffraction./ Kleiner breedte gee breër diffraksie. ‫( ضض‬3) [11] QUESTION 8/VRAAG 8 8.1 CRITERIA FOR MARKING/ KRITERIA VIR NASIEN Correct shape/ Korrekte vorm. ‫ض‬ Direction of field lines./ Rigting van veldlyne ‫ض‬ Field lines not crossing each other./ Veldlyne kruis nie ‫ض‬ mekaar nie. (3) 8.2 kQ1Q 2 F= ‫ض‬ r2 9 x109 x Q 2 5,09 ‫=ض‬ ‫ض‬ 0,12 Q = 2,38 x 10-6 C ‫ض‬ (4) 8.3 kQ E= ‫ض‬ r2 9 x109 x 2,38 x10 -6 E1 = ‫ض‬ 0,15 2 E1 = 952 000 NC-1 right / regs 9 x109 x 2,38 x10 -6 E2 = ‫ض‬ 0,05 2 E2 = 8 568 000 NC-1 right / regs Enet = E1 + E2 Enet = 952 000 + 8 568 000 ‫ض‬ Enet = 9 520 000 NC-1 right / regs ‫ض‬ (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 28 8 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2020) 8.4 kQ1Q 2 F= ‫ض‬ r2 9 x109 x 2,38 x10 -6 x 2,38 x10 -6 F1 = ‫ض‬ 0,12 F1 = 5,10 N right 9 x109 x 2,38 x10 -6 x 2,38 x10 -6 F2 = ‫ض‬ 0,05 2 F2 = 42,84 N left / links Fnet = F1 + F2 Fnet = 42,84 – 5,10 ‫ض‬ Fnet = 37,74 N left / links ‫ض‬ (5) [17] QUESTION 9/VRAAG 9 9.1 X CRITERIA FOR MARKING/ KRITERIA VIR NASIEN Circular shape/ Korrekte vorm ‫ض‬ Field direction/ Veldrigting ‫ض‬ (2) 9.2 9.2.1 The magnitude of the induced emf across a conductor is directly proportional to the rate of change in the magnetic flux linkage with the conductor. ‫ضض‬ Die grootte van die geïnduseerde emk oor die geleier is direk eweredig aan die tempo van verandering in die magnetiese vloed met die geleier. (2) 9.2.2 Ȱ = B A cosߠ Any one/Enige een ‫ض‬ Ȱ = B (ߨr2 ) cos ߠ Ȱ = 3,5 (ߨ x 0,052 ) cos0o ‫ض‬ Ȱ = 0,03 Wb ‫( ض‬0,027 Wb) (3) 9.2.3 -Nǻĭ İ= ‫ض‬ ǻt -350(0 - 0,03) İ= ‫ض‬ 0,1 ߝ= 105 V ‫ض‬ (3) [10] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 29 (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 9 QUESTION 10/VRAAG 10 10.1 10.1.1 The inverse of the resistance / Die omgekeerde van die weerstand 1 OR/ OF ‫ض‬ R (1) 10.1.2 OPTION 1/ OPSIE 1 OPTION 2/ OPSIE 2 ǻI V Gradient/ Gradiënt = R= ‫ض‬ ǻv I 1,0 - 0,2 3.0 Gradient/ Gradiënt = ‫ض‬ R= ‫ض‬ 3,0 - 0,6 1,0 Gradient/ Gradiënt = 1 R=3Ÿ‫ض‬ 3 1 1 Gradient/ Gradiënt = = ‫ض‬ R 3 R=3Ÿ‫ض‬ (3) 10.2 10.2.1 OPTION 1/ OPSIE 1 OPTION 2/ OPSIE 2 R1 = R2 V R= I1 = I 2 = 1 A ‫ض‬ I I = I 1 + I2 ‫ض‬ R = 6 + 6 = 12 Ƕ I=1+1=2A‫ض‬ Vp 12 = 1 Vp = 12 V 12 12 = I I=1A‫ض‬ I = I1 + I2 ‫ض‬ I=1+1=2A‫ض‬ (3) 10.2.2 V R= ‫ض‬ I Vp 12 = ‫ض‬ 1 Vp = 12 V V = V s + Vp 15 = Vs + 12 ‫ض‬ Vs = 3 V ௏ R= ூ ଷ R= ଶ‫ض‬ R = 1,5 Ÿ ‫ض‬ (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 30 10 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2020) 10.3 Increase, ‫ ض‬the total resistance decreases and the current increases. ‫ض‬ Verhoog, die totale weerstand verlaag en die stroom verhoog. 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