# Physical Sciences Grade 11 KZN September Test 2024 QP & Memo

> Grade 11 Physical Sciences question paper and memo from the KZN September Test 2024, 16 pages. Read online or get the free PDF download.

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- Updated: 2026-09-28
- Subject: Physical Sciences
- Grade: Grade 11
- Document type: Question paper and memo
- Year: 2024
- Exam period: KZN September Test
- Curriculum: CAPS
- Pages: 16

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### Page 1

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                                   NATIONAL
                              SENIOR CERTIFICATE

                                       GRADE 11

                               PHYSICAL SCIENCES

                                   COMMON TEST

                                  SEPTEMBER 2024

TIME:     2 hours

MARKS: 100

                 This question paper consists of 8 pages and two data sheets.

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Physical Sciences               2       com                        September Common Test 2024
                               NSC

INSTRUCTIONS AND INFORMATION TO CANDIDATES

1.     Write your name on the ANSWER BOOK.

2.     This question paper consists of SEVEN questions. Answer ALL the questions in the
       ANSWER BOOK.

3.     Start EACH question on a NEW page in the ANSWER BOOK.

4.     Number the answers correctly according to the numbering system used in this question
       paper.

5.     Leave ONE line between two subsections, for example between
       QUESTION 2.1 and QUESTION 2.2.

6.     You may use a non-programmable calculator.

7.     You may use appropriate mathematical instruments.

8.     You are advised to use the attached DATA SHEET.

9.     Show ALL formulae and substitutions in ALL calculations.

10.    Round off your final numerical answers to a minimum of TWO decimal places.

11.    Give brief motivations, discussions, et cetera where required.

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Physical Sciences               3       com                         September Common Test 2024
                               NSC
QUESTION 1

Four options are provided as possible answers to the following questions. Each question
 has only ONE correct answer. Write only the letter (A - D) next to the question number
(1.1 — 1.5) in the ANSWER BOOK, for example 1.6 D.

 1.1 The number of hydrogen atoms in one mole of ammonia (NH3) is…

      A     3
      B     1,204 x 1024
      C     1,806 x 1024
      D     6,02 x 1023                                                                     (2)

 1.2 Which ONE of the following gases occupies the largest volume at STP?

      A     32 g of O2(g)
      B     34 g of NH3(g)
      C     7 g of N2(g)
      D     4 g of He(g)                                                                    (2)

 1.3 Real gas behaviour deviates from ideal gas behaviour at…

      A     Low temperatures and low pressures
      B     Moderate temperatures and high pressures
      C     Moderate temperatures and low pressures
      D     Low temperatures and high pressures                                             (2)

 1.4 In a chemical reaction, the difference between the potential energy of the
     products and the potential energy of reactants is equal to:

      A     Enthalpy of the reaction
      B     Rate of the reaction
      C     Enthalpy change of the reaction
      D     Total potential energy of the particles                                         (2)

 1.5 Which ONE of the following is the correct description of a solution of hydrochloric
     acid of concentration 0,1 mol∙dm-3 ?

      A     Dilute strong acid
      B     Dilute weak acid
      C     Concentrated strong acid
      D     Concentrated weak acid                                                           (2)
                                                                                            [10]

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Physical Sciences               4       com                          September Common Test 2024
                               NSC

 QUESTION 2

 2.1    Define the term molar mass.                                                        (2)

 2.2    Calculate the percentage of carbon in cane sugar C12H22O11.                        (2)

 2.3    CxHy is a compound made up of carbon (C) and hydrogen (H) only.
        1,97g of this compound reacts with excess O2 (g) to produce 6,2g of CO2 (g).
        Determine the empirical formula of this compound.                                  (6)

 2.4    A metal M forms two chlorides, MCℓ2 and MCℓx, that contain 55,9% and 65,5%
        chlorine by mass respectively. Determine the:

        2.4.1 Relative atomic mass of M                                                   (4)

        2.4.2 Value of x. Show all working.                                               (4)
                                                                                          [18]

 QUESTION 3

 In an experiment, a 300 cm3 solution of hydrochloric acid (HCℓ) of concentration 0,5 mol.dm-3
 reacts with calcium carbonate powder. The HCℓ is in excess.

 The following balanced reaction takes place at 250C.

                  CaCO3(s) + 2HCℓ(aq) → CaCℓ2(aq) + H2O(ℓ) + CO2(g)
 The volume of carbon dioxide gas produced is measured at regular time intervals and the
 following graph is drawn:

                                         2    4      6                  12

                                                  Time (minutes)

 3.1    Define the term concentration.                                                           (2)

 3.2    Give a reason why the graph is horizontal after 6 minutes.                               (1)

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Physical Sciences               5       com                               September Common Test 2024
                               NSC

 3.3    Determine the maximum number of moles of carbon dioxide gas (CO2) produced.
        Take the molar gas volume at 25°C to be 24000cm3.                                          (3)

 3.4    Calculate the concentration of the HCℓ solution after 6 minutes. Assume that the
        volume of the solution remains at 300 cm3.                                                 (7)

                                                                                                   [13]

 QUESTION 4

 4.1    A laboratory assistant prepares a solution of calcium nitrate of volume 250cm 3 using
        Ca(NO3)2∙4H2O (s) as the solute:

                     Ca(NO3)2   → Ca2+(aq) + 2NO3- (aq)

        If the concentration of the nitrate ions in the solution is 0,15 mol∙dm-3, calculate the
        mass of solute that the laboratory assistant used.                                           (5)

 4.2    The chemical reaction for the production of aspirin(C9H8O4), from salicylic acid
        (C7H6O3) and acetoacetic acid(C4H6O3), is represented by the balanced equation
        below.

                           2C7H6O3 +      C4H6O3 →       2C9H8O4      +    H 2O
                                                          aspirin

        A chemist reacts 14 g salicylic acid with 10 g of acetoacetic acid.

        4.2.1 Define limiting reagent.                                                               (2)

        4.2.2 By means of a suitable calculation, determine which of the reactants is the
              limiting reagent.                                                                      (4)

        4.2.3 The actual mass of aspirin obtained at the end of the reaction is 11,5 g.
              Calculate the percentage yield of this reaction.                                       (5)

                                                                                                    [16]

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Physical Sciences               6       com                            September Common Test 2024
                               NSC

 QUESTION 5

 A group of learners perform an experiment to verify a gas law. The results of the experiment
 are shown in the graph of pressure vs the inverse of volume drawn below.

                                                 1   x 10-2     cm-3
                                              volume

 5.1    NAME the law being verified.                                                             (1)

 5.2    Write down an investigative question for this experiment.                                (2)

 5.3    Name TWO variables that must be kept constant during the experiment.                     (2)

 5.4    Calculate the volume occupied by the gas when the pressure exerted by the gas is
        200kPa.                                                                                  (3)

 5.5    Determine the pressure exerted by the gas when its volume is 11,11cm3                    (3)

 5.6    State 2 properties of an Ideal Gas                                                       (2)

                                                                                                [13]

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Physical Sciences               7       com                               September Common Test 2024
                               NSC

 QUESTION 6

 The graph below shows the energy changes for a certain reaction. Study the graph, and answer
 the questions that follow.

 6.1    Is the reaction EXOTHERMIC or ENDOTHERMIC?
        Give a reason for the answer.                                                               (2)

 6.2    Define the term activation energy.                                                          (2)

 6.3    Write down the values for the:

        6.3.1 Energy of the reactants                                                               (1)
        6.3.2 Energy of the products                                                                (1)
        6.3.3 Activation energy for the reverse reaction                                            (1)
        6.3.4 Activation energy for the catalysed forward reaction                                  (1)
        6.3.5 Energy of the activated complex in the absence of a catalyst                          (1)

 6.4    Calculate the heat of reaction, (∆H), for the reverse reaction.                             (2)

 6.5    What effect will the addition of the catalyst have on:
        (Choose from INCREASES, DECREASES or REMAINS THE SAME)
        6.5.1 The energy of the products?                                                           (1)
        6.5.2 The heat of reaction?                                                                 (1)
        6.5.3 The activation energy for the reverse reaction?                                       (1)
                                                                                                   [14]

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Physical Sciences               8       com                           September Common Test 2024
                               NSC

 QUESTION 7

 7.1 Given the following acid-base reaction:
                               NH3 + H3PO4 ⇌ NH4+ + H2PO4 -
      7.1.1 Define a base according to the Lowry-Bronsted theory.                          (1)

      7.1.2 Identify the TWO bases in the above reaction.                                  (2)

      7.1.3 Define the term ampholyte.                                                     (2)

      7.1.4 Write down the FORMULA of an ampholyte in the above reaction.                  (1)

 7.2 A learner reacts 20 cm3 of a 0,2 mol∙dm-3 solution of sodium carbonate,
     completely with 12 cm3 of hydrochloric acid solution. The balanced equation for
     this reaction is:
                       Na2CO3 + 2HCℓ → 2NaCℓ + CO2 + H2O
      Calculate the:

      7.2.1 Number of moles of Na2CO3 that reacted.                                         (3)

      7.2.2 Concentration of the hydrochloric acid solution.                                (4)

      7.2.3 pH of the hydrochloric acid solution before it reacted.                          (3)
                                                                                            [16]

                                                                            TOTAL : 100

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Physical Sciences               9       com                 September Common Test 2024
                               NSC

                       DATA FOR PHYSICAL SCIENCES GRADE 11
                                   PAPER 2 (CHEMISTRY)

           TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES

              NAAM/NAME                 SIMBOOL/SYMBOL     WAARDE/VALUE
       Standard pressure
                                                p           1,013 × 105 Pa
       Standaarddruk
       Molar gas volume at STP
                                                Vm           22,4 dm3∙mol-1
       Molêre gasvolume teen STD
       Standard temperature
                                                Tθ                273 K
       Standaardtemperatuur
       Charge on electron
                                                e             1,6 × 10-19 C
       Lading op elektron
       Avogadro’s constant
                                                NA           6,02 × 1023 mol-1
       Avogadro se konstante

                      TABLE 2: FORMULAE/TABEL 2: FORMULES

           m                        n           m
      n= M                      c= V        c = MV       p1V1 = p2V2

            N                  cA VA   nA
      n= N                           =
               A               cB VB   nB

            V
      n=
           Vm

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Physical Sciences               10       com   September Common Test 2024
                                NSC

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                              Education
                              KwaZulu-Natal Department of Education
                              REPUBLIC OF SOUTH AFRICA

                             PHYSICAL SCIENCES
                            MARKING GUIDELINES
                                 COMMON TEST
                               SEPTEMBER 2024

                                     NATIONAL
                              SENIOR CERTIFICATE

                                      GRADE 11

                     NB: This marking guideline consists of 6 pages.

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Physical Sciences f rom St anmorephysics.
                                      2 com                        September 2024 Common Test
                                     NSC

QUESTION ONE

 1.1     C 
 1.2     B 
 1.3     D 
 1.4     C 
 1.5     A                                                                                [10]

QUESTION TWO

 2.1     The mass of one mole of a substance.                                              (2)

 2.2     M (C12H22O11) = 12(12) + 22(1) + 11(16)
                      = 144 + 22      + 176
                      = 342 g.mol-1 

         % C = 144 x 100 = 42,11% 
                342
                                                                                             (2)

 2.3     Mass of C in 6,2g of CO2:
         12
         44
            ×6,2 = 1,69g                                              C           H
         ∴ mass of C in CxHy is 1,69 g
                                                       Mass         1,69 g      0,28 g
         Mass of H in CxHy            = 1,97 – 1,69
                                      = 0,28g          n = m/M       1,69        0,28
                                                                      12         1
                                                                     = 0,14     = 0,28

                                                       Divide by      0,14       0,28
                                                       smallest       0,14       0,14
                                                       Ratio            1         2
                                                       Empirical formula is CH2
                                                                                             (6)
 2.4.1    M                               71
              ×100 = 44,1 OR                 ×100 = 55,9
         M+71                            M+71
                                             
         M = 56 g·mol-1
                                                                                             (4)
 2.4.2    x(35,5)         65,5
         56+x(35,5)
                       =          
                           100

         x = 3                                                                               (4)
                                                                                             [18]

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Physical Sciences f rom St anmorephysics.
                                      3 com                     September 2024 Common Test
                                     NSC

 QUESTION 3

 3.1    The amount of solute per dm3 of solution. / The number of moles of a
        substance per unit volume.                                                  (2)

 3.2    No more carbon dioxide is produced. / The reaction has ended / All the       (1)
        CaCO3 has reacted.

 3.3                  V
                  n=     
                      Vm
                   = 500 
                     24000
                   = 0,0208 mol 
                                                                                      (3)

 3.4    POSITIVE MARKING FROM 3.3

        MARKING CRITERIA:
          • Substitution / answer: calculation of initial moles of HCl. 
          • Apply ratio of moles of HCl to CO2.(2:1). 
          • Subtracting moles that reacted from initial moles of HCl. 
          • Formula to calculate concentration. 
          • Substitution into concentration formula. 
          • Final answer. 

        OPTION 1
                                                                                      (7)
        ni = cV = 0,5 x 0,3                                n
                = 0,15 mol                             c=       
                                                            V

                                                       = 0,1084
        nreacted = 2 x 0,0208
                 = 0,0416 mol                             0,3
                                                       = 0,361 mol.dm-3
        nexcess    = ni - nreacted
                   = 0,15 – 0,0416
                   = 0,1084 mol

        OPTION 2

                          CaCO3      2HCI      CaCI2        H2O           CO2
         Ratio              1          2         1           1              1
         Initial                      0,15                                 0
         Change                     -0,0416                             0,0208
         End                        0,1084    
                                                                                      [13]

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Physical Sciences f rom St anmorephysics.
                                      4 com                           September 2024 Common Test
                                     NSC

 QUESTION 4

 4.1.    n (NO3-) =CxV
                  = 0,15 x 0,25 
                  = 0,0375 mol
         n (Ca(NO3-)) = ½(0,0375) 

                       = 0,01875 mol

          ∴ mass of Ca(NO3)2·4H2O used
                     m = nM 
                       = 0,01875(164 +4(18)) 
                       = 4,425 g                                                            (5)

 4.2.1 The reactant that is used up first/completely in a chemical reaction.               (2)
       OR the reactant that determines the amount of product that is formed
                           m                                                   m
 4.2.2 n (C7H6O3) =                                             n (C4H6O3) =
                           M                                                   M

                        = 14                                              = 10 
                         138                                                 102
                        = 0,10 mol                                         = 0,10 mol

         From balanced equation:
         n(C7H6O3) : n(C4H6O3)
               2 :       1

         ∴ 0,1 mol of C7H6O3 needs 0,05 mol of C4H6O3 

         ∴ The limiting reactant is C7H6O3                                                  (4)
                            m
 4.2.3 n (C9H8O4) =
                            M                % yield =     actual yield x 100
                                                         theoretical yield
                            m
                0,1 =
                           180                          11,5
                                                    =           × 100 
                                                         18
                     ∴m = 18 g (18,26 g) 
                                                    = 63,90% (62,98%)
                                                                                             (5)
                                                                                            [16]

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Physical Sciences f rom St anmorephysics.
                                      5 com                       September 2024 Common Test
                                     NSC

 QUESTION 5
 5.1 Boyle’s Law                                                                          (1)

 5.2     What is the relationship between the pressure exerted and the volume
         occupied by a fixed mass of (dry) gas at constant temperature?                  (2)

 5.3     Mass (of gas)  or
         Temperature (of gas)                                                             (2)

 5.4          At 200kPa 1/v = 6,7 x 10-2 
                           ∴v=      1       
                                 6,7 x 10-2
                              v = 14,93 cm-3 
                                                                                           (3)
 5.5        p1v1 = p2v2
         120(25) = p2 (11,11)  (or any other correct combinations for p1 and
                                             v1 from the graph)
                p2 = 270,03 kPa                                                           (3)
 5.6     The particles of the ideal gas: (any 2)
            • Occupy no volume.
            • Are identical in all ways.
            • Exert no forces on each other except during a collision.
            • All collisions between gas molecules are completely elastic.                  (2)
                                                                                           [13]

 QUESTION 6

 6.1     Exothermic.
         ΔH < 0  / Eproducts < Ereactants                                                 (2)

 6.2     The minimum energy needed for a reaction to take place                          (2)

 6.3.1 208,2 kJ                                                                           (1)

 6.3.2 86,5 kJ                                                                            (1)

 6.3.3 154,3 kJ OR 130,8 kJ                                                               (1)

 6.3.4 9,1 kJ                                                                             (1)

 6.3.5 240,8 kJ                                                                           (1)

 6.4     ΔH = Eproducts - Ereactants
             = 208,2      –   86,5  = 121,7 kJ
                                                                                           (2)
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Physical Sciences f rom St anmorephysics.
                                      6 com             September 2024 Common Test
                                     NSC

 6.5.1 Remains the same .                                                       (1)
 6.5.2 Remains the same.                                                        (1)
 6.5.3 Decreases.                                                               (1)
                                                                                [14]

 QUESTION 7

 7.1.1 A base is a proton acceptor.                                             (1)

 7.1.2 NH3  and H2PO4 -                                                        (2)

 7.1.3 A substance that acts as an acid and base.                              (2)

 7.1.4 H2PO4 -                                                                  (1)

 7.2.1 n (Na2CO3) = c x V 
                  = 0,2 x 0,02 
                  = 0,004 mol                                                   (3)

 7.2.2 POSITIVE MARKING FROM QUESTION 7.2.1
       OPTION 1:                         OPTION 2:
       n (Na2CO3) : n (HCI)
               1   : 2
                                         cA VA   nA
       ∴ n (HCI) = 2 x 0,04 = 0,008 mol       =
                                         cB VB nB
              n                                      
         c=                                   cA ×12     2
              v                                        = 
           = 0,008                          0,2 ×20    1
             0,012 
                                             cA = 0,67 mol·dm-3
           = 0,67 mol.dm-3 
                                                                                 (4)
        LEAVE OUT (FORMULA NOT GIVEN IN DATA SHEET)
       Refer to conversion sheet for question 7
 7.2.3 pH = -log[H30+] 

            = - log (0,67) 

            = 0,17                                                              (3)
                                                                                [16]

                                    TOTAL: 100

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