# Technical Sciences Grade 11 P1 November Mock 2026 Memo (Eng)

> Grade 11 Technical Sciences Paper 1 memorandum from the November Mock Exam 2026 (English), 10 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-11-technical-sciences-2026-november-mock-exam-memorandum-paper-1/65b0c7a2-444e-4c34-be24-f5a66dbd3379
- Updated: 2026-10-29
- Subject: Technical Sciences
- Grade: Grade 11
- Language: English
- Document type: Memorandum
- Year: 2026
- Exam period: November Mock Exam
- Paper: 1
- Publisher: Hlayiso
- Curriculum: CAPS
- Pages: 10

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## About this document

Technical Sciences · Grade 11 · November Mock Exam · 2026 · English. Memorandum, 10 pages. Read online or download the PDF.

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## Matching paper and memo

- [Grade 11 Technical Sciences P1 November 2026 Mock](https://www.hlayiso.com/library/grade-11-technical-sciences-2026-november-mock-exam-question-paper-paper-1/341b03d8-bb2f-4ff7-87c9-293ec0ba0013) — QP · 2026 · Eng

## Document text

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### Page 1

hlayiso mock exams
                             Practice Series:
                             Grade 11 Exam Preparation
                             WWW.HLAYISO.COM

                                  NATIONAL
                             SENIOR CERTIFICATE

                                     GRADE 11

                             TECHNICAL SCIENCES P1
                      NOVEMBER EXAMINATION 2026 (MOCK)
                               MARKING GUIDELINES

  MARKS: 150

                     These marking guidelines consist of 10 pages.

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### Page 2

Technical Sciences/P1                       2                              Hlayiso/Mock 2026
                                 NSC – Marking Guidelines

GENERAL MARKING GUIDELINES

  1. Calculations: Marks are awarded for the correct formula, correct substitution and the
     correct final answer WITH the correct unit, as indicated by the ticks (✓). No mark is
     awarded for a formula that is not followed by a substitution. If an incorrect formula is
     used, no further marks are awarded for that calculation.
  2. Units: The final-answer mark is only awarded if the correct unit is given. Penalise an
     omitted or incorrect unit only ONCE per question.
  3. Rounding: Accept final answers rounded to a minimum of TWO decimal places. Small
     differences caused by rounding of intermediate values are accepted.
  4. Positive marking: Where an incorrect answer from a previous question is used correctly
     in a later calculation, full marks are awarded for the later calculation.
  5. Negative marking: If a candidate must explain or motivate a choice (e.g. INCREASES
     or DECREASES) and the choice is incorrect, no marks are awarded for the explanation.
  6. Definitions/laws: Where key words are underlined, deduct 1 mark for EACH key word
     or phrase that is omitted. Accept equivalent wording that conveys the same meaning.
  7. Free-body diagrams: ONE mark for each force represented by an arrow with a correct
     label. Penalise ONCE for: no arrows, gaps between the arrows and the dot, dotted lines,
     or additional (non-applicable) forces.
  8. Sign convention: Candidates may choose either direction as positive, provided it is
     applied consistently.

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### Page 3

Technical Sciences/P1                          3                            Hlayiso/Mock 2026
                                    NSC – Marking Guidelines

QUESTION 1
1.1     C ✓✓                                                                               (2)
1.2     B ✓✓                                                                               (2)
1.3     D ✓✓                                                                               (2)
1.4     A ✓✓                                                                               (2)
1.5     C ✓✓                                                                               (2)
1.6     B ✓✓                                                                               (2)
1.7     D ✓✓                                                                               (2)
1.8     A ✓✓                                                                               (2)
1.9     B ✓✓                                                                               (2)
1.10    D ✓✓                                                                               (2)
                                                                                          [20]

QUESTION 2
2.1     A single vector that has the same effect as two or more vectors acting together
        (at a point). ✓✓                                                                   (2)
2.2     VECTOR ✓                                                                           (1)
2.3.1   F3x = F3 cos 30◦ = 50 cos 30◦ ✓
        F3x = 43,30 N ✓                                                                    (2)
2.3.2   F3y = F3 sin 30◦ = 50 sin 30◦ ✓
        F3y = 25,00 N ✓                                                                    (2)
2.4     POSITIVE MARKING FROM QUESTION 2.3
        Right (east) and up (north) positive:
        Rx = 60 + (–43,30) ✓ = 16,70 N (to the right)
        Ry = 35 + (–25) ✓ = 10,00 N (upwards)
        R2 = R2x + R2y ✓
        R2 = (16,70)2 + (10,00)2 ✓
        R = 19,46 N ✓                                                                      (5)
2.5     POSITIVE MARKING FROM QUESTION 2.4
                Ry 10,00
        tan θ =    =       ✓
                Rx 16,70
        θ = 30,92◦ (above the horizontal, to the right / east) ✓
                        10 or cos θ = 16,70 . Range: 30,90◦ – 30,95◦ .
        Accept sin θ = 19,46          19,46                                                (2)
                                                                                          [14]

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### Page 4

Technical Sciences/P1                          4                         Hlayiso/Mock 2026
                                    NSC – Marking Guidelines

QUESTION 3
3.1     The gravitational force that the Earth exerts on an object. ✓✓                  (2)
3.2     Fg = mg ✓
        Fg = (1 500)(9,8) ✓
        Fg = 14 700 N ✓                                                                 (3)
3.3     NON-CONTACT force ✓                                                             (1)
3.4     Any ONE: Magnetic force / electrostatic (electric) force ✓                      (1)
3.5.1   8 + 6 = 14 km ✓                                                                 (1)
3.5.2   ∆x2 = 82 + 62 ✓
        ∆x = 10 km ✓
        Accept 10 000 m. Direction not required.                                       (2)
                                                                                      [10]

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### Page 5

Technical Sciences/P1                            5                                   Hlayiso/Mock 2026
                                      NSC – Marking Guidelines

QUESTION 4
4.1     The force that opposes the (tendency of) motion of an object and acts parallel
        to the surface in contact. ✓✓                                                                 (2)
4.2.1   Normal force / total mass of the block ✓                                                      (1)
4.2.2   Frictional force (maximum static / kinetic) ✓                                                 (1)
4.2.3   Any ONE: Type (nature) of surfaces in contact / same block / same table /
        horizontal surface ✓                                                                          (1)
4.3
                           N / FN / normal force ✓

         fk / friction ✓                             F / FA / applied force ✓

                              Fg / w / weight ✓
        Accept FT / tension for the applied force. Do not penalise for relative lengths of arrows.    (4)
4.4     N = Fg = mg ✓
        N = (2,0)(9,8) = 19,6 N ✓                                                                     (2)
4.5     fmax
         s   = µs N ✓
        6,86 = µs (19,6) ✓
        µs = 0,35 ✓      (no unit)                                                                    (3)
4.6     fk = µk N ✓
        4,90 = µk (19,6) ✓
        µk = 0,25 ✓      (no unit)                                                                    (3)
4.7     For each mass, the kinetic frictional force is SMALLER than the maximum static
        frictional force ✓ / µk < µs .
        A smaller applied force is therefore needed to keep the block moving than to
        start it moving. ✓                                                                            (2)
4.8     REMAINS THE SAME ✓                                                                            (1)
4.9     Any TWO: Walking without slipping / grip of car tyres on the road / car brakes
        or brake pads / belt drives and pulleys / striking a match / nails and screws
        holding in wood / holding objects ✓✓                                                          (2)
                                                                                                     [22]

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### Page 6

Technical Sciences/P1                           6                        Hlayiso/Mock 2026
                                     NSC – Marking Guidelines

QUESTION 5
5.1     A wave in which the particles of the medium vibrate perpendicular (at right
        angles) to the direction of propagation of the wave. ✓✓                          (2)
5.2     The maximum displacement of a particle from its rest (equilibrium) position.
        ✓✓                                                                               (2)
5.3.1   12 cm / 0,12 m ✓                                                                 (1)
5.3.2   0,8 m ✓                                                                          (1)
5.4.1   Any ONE pair: A and C / A and F / C and F / B and E ✓                            (1)
5.4.2   Any ONE pair: A and B / A and E / C and B / C and E / F and B / F and E ✓
        Also accept any pair that includes D with a crest or trough.                     (1)
5.5     2 (two) ✓                                                                        (1)
             2
5.6     T=     = 0,4 s ✓
             5
            1    1
        f= =         ✓
            T 0,4
        f = 2,5 Hz ✓
        OR: f = numbertime
                        of waves = 5 ✓✓ = 2,5 Hz ✓
                                   2                                                     (3)
5.7     POSITIVE MARKING FROM QUESTIONS 5.3.2 AND 5.6
        v = fλ ✓
        v = (2,5)(0,8) ✓
        v = 2 m·s–1 ✓                                                                    (3)
5.8     DECREASES ✓                                                                      (1)
5.9     The speed of the wave remains constant (same medium / same rope). ✓
        Since v = fλ , the wavelength is inversely proportional to the frequency
        (wavelength is halved). ✓                                                       (2)
                                                                                       [18]

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### Page 7

Technical Sciences/P1                        7                               Hlayiso/Mock 2026
                                  NSC – Marking Guidelines

QUESTION 6
6.1     A wave in which the particles of the medium vibrate parallel to the direction of
        propagation of the wave. ✓✓                                                         (2)
6.2.1   Compression ✓                                                                       (1)
6.2.2   Rarefaction ✓                                                                       (1)
            1
6.3.1   T=     ✓
            f
              1
        T=       ✓
            235
        T = 4,26 × 10–3 s ✓                                                                 (3)
6.3.2   v = fλ ✓
        340 = (235)λ ✓
        λ = 1,45 m ✓                                                                        (3)
6.4     Sound waves with frequencies higher than 20 kHz / above the upper limit of
        the human hearing range. ✓✓                                                         (2)
                                                       0,12
6.5     Time for the pulse to reach the seabed: ∆t =        = 0,06 s ✓
                                                         2
            ∆x
        v=     ✓
            ∆t
                 ∆x
        1 500 =      ✓
                0,06
        ∆x = 90 m ✓
        OR: 2∆x = v∆t = (1 500)(0,12) = 180 m ✓✓✓; depth = 90 m ✓. If 180 m is given as
        the depth: max 2/4.                                                                 (4)
6.6     Amplitude ✓                                                                         (1)
                                                                                           [17]

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### Page 8

Technical Sciences/P1                            8                              Hlayiso/Mock 2026
                                      NSC – Marking Guidelines

QUESTION 7
7.1     The region (in space) around a magnet in which another magnet or a
        ferromagnetic material will experience a (magnetic) force. ✓✓                           (2)
7.2.1

               N                  N

        Criteria: Correct shape – lines bend away from each other (no lines joining the two
        north poles) ✓; Direction of arrows away from both north poles ✓; Field lines do not
        cross / touch ✓. (Null point not required.)                                             (3)
7.2.2   REPEL ✓                                                                                 (1)
7.3     Any TWO ✓✓:
        Field lines never cross (intersect) each other.
        Field lines are closest together where the field is strongest (at the poles).
        Outside a magnet, field lines point from the north pole to the south pole.
        Field lines form closed loops (inside the magnet from S to N).                          (2)
7.4.1   SOUTH (magnetic pole) ✓                                                                 (1)
7.4.2   It deflects charged particles from the Sun (solar wind) / cosmic rays away from
        the Earth’s surface. ✓
        Accept: protects the atmosphere (ozone layer) from being stripped away by the solar
        wind.                                                                                   (1)
7.5     Any TWO: Iron / nickel / cobalt / steel / alloys of these metals ✓✓                     (2)
                                                                                               [12]

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### Page 9

Technical Sciences/P1                           9                      Hlayiso/Mock 2026
                                     NSC – Marking Guidelines

QUESTION 8
8.1     The net (total) charge in an isolated (closed) system remains constant (is
        conserved). ✓✓                                                                 (2)
            Q1 + Q2 (+6 × 10–9 ) + (–2 × 10–9 )
8.2     Q=          =                           ✓
               2                 2
        Q = +2 × 10–9 C (on each sphere) ✓                                             (2)
8.3     POSITIVE MARKING FROM QUESTION 8.2
            ∆Q
        n=      ✓
             e
            (+2 × 10–9 ) – (–2 × 10–9 )       6×10–9 –2×10–9 for P)
        n=                              ✓ (or
                   1,6 × 10–19                  1,6×10–19
        n = 2,5 × 1010 electrons ✓                                                     (3)
8.4     FROM Q TO P ✓                                                                  (1)
8.5     POSITIVE MARKING FROM QUESTION 8.2
            kQ1 Q2
        F=          ✓
               r2
            (9 × 109 )(2 × 10–9 )(2 × 10–9 )
        F=                                   ✓✓
                         (0,3)2
        F = 4 × 10–7 N ✓
        1 mark for substitution of both charges, 1 mark for (0,3)2 .                   (4)
8.6     POSITIVE MARKING FROM QUESTION 8.5
            F
        E= ✓
            q
            4 × 10–7
        E=           ✓
            2 × 10–9
        E = 200 N·C–1 ✓                                                               (3)
                                                                                     [15]

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### Page 10

Technical Sciences/P1                         10                        Hlayiso/Mock 2026
                                    NSC – Marking Guidelines

QUESTION 9
9.1     The potential difference across a conductor is directly proportional to the
        current in the conductor at constant temperature. ✓✓                           (2)
9.2.1   Rs = R1 + R2 = 5 + 12 ✓
        Rs = 17 Ω ✓
             V             12
        R= ✓         17 =
              I             I
        I = 0,71 A ✓                                                                   (4)
9.2.2   POSITIVE MARKING FROM QUESTION 9.2.1
            V
        R= ✓
            I
            V
        5= 1 ✓
           0,71
        V1 = 3,53 V ✓ (Accept 3,55 V when 0,71 A is used.)                             (3)
              R 2 R3   (12)(6)              1   1 1
9.3.1   Rp =         =         ✓     OR       =  + ✓
             R2 + R3    12 + 6              Rp 12 6
        Rp = 4 Ω ✓
        RT = R1 + Rp = 5 + 4 ✓
        RT = 9 Ω ✓                                                                     (4)
9.3.2   POSITIVE MARKING FROM QUESTION 9.3.1
             V
        R= ✓
              I
             12
        9=      ✓
              I
        I = 1,33 A ✓                                                                   (3)
9.3.3   POSITIVE MARKING FROM QUESTIONS 9.3.1 AND 9.3.2
        Vp = IRp ✓
        Vp = (1,33)(4) ✓
        V2 = 5,33 V ✓    (Accept 5,32 V)
        OR: V1 = (1,33)(5) = 6,67 V ✓; V2 = 12 – 6,67 ✓ = 5,33 V ✓                     (3)
9.3.4   POSITIVE MARKING FROM QUESTION 9.3.3
             V
        R= ✓
             I
            5,33
        6=        ✓
              I3
        I3 = 0,89 A ✓                                                                  (3)
                                                                                      [22]
                                                                           TOTAL:     150

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