# Mathematical Literacy Grade 12 P2 2018 Memo (Eng)

> Grade 12 Mathematical Literacy Paper 2 memorandum from the Eastern Cape Mock Exam 2018 (English), 11 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-12-mathematical-literacy-2018-eastern-cape-mock-exam-memorandum-paper-2-english/e2a6c446-ca3b-4344-b5d0-740a823e7e3e
- Updated: 2026-09-28
- Subject: Mathematical Literacy
- Grade: Grade 12
- Language: English
- Document type: Memorandum
- Year: 2018
- Exam period: Eastern Cape Mock Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 11

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## About this document

Mathematical Literacy · Grade 12 · Eastern Cape Mock Exam · 2018 · English. Memorandum, 11 pages. Read online or download the PDF.

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## Document text

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### Page 1

NATIONAL
                           SENIOR CERTIFICATE

                                   GRADE 12

                             SEPTEMBER 2018

                 MATHEMATICAL LITERACY P2
                    MARKING GUIDELINE

MARKS:     150

Symbol           Explanation
M                Method
M/A              Method with Accuracy
MCA              Method with Consistent Accuracy
CA               Consistent Accuracy
A                Accuracy
C                Conversion
S                Simplification
RT/RG/RM         Reading from a table OR Reading from a graph OR Read from map
F                Choosing the correct formula
SF               Substitution in a formula
J                Justification
P                Penalty, e.g. for no units, incorrect rounding off etc.
R                Rounding Off OR Reason
AO               Answer only
NPR              No penalty for rounding

                      This marking guideline consists of 11 pages.

### Page 2

2                           MATHEMATICAL LITERACY P2                (EC/NOVEMBER 2018)

QUESTION 1 [39]
 Ques.                            Solution                             Explanation         Level
 1.1.1  Municipality = 87 × 5 × 30                               1MA Multiply 5            L3
                     = 13 050 litres                             and 30
                                                                  1A Number of
                                                                  litres
              Tank water = 250 – 87
                         = 163 litres                            1CA Litres for
                                                                  tank water
              Tanks = 163 × 5 × 30                                1CA Total litres
                    = 24 450 litres                              for the month

              Total for municipality and tanks
              = 13 050 litres + 24 450 litres
              = 37 500 litres                                    1MCA Total litres
                                                                                  (5)
    1.1.2     Litres used from tank = 24 450                      CA from 1.1.1       L3
              No. of kilolitres = 24 450 ÷ 1 000                  1C Converting to    and
                                = 24,45 kℓ                       kilolitres          L4

              First 6 = 6 × 0
              7 to 10 kℓ next 4 = 4 × 7,14
                                = R28,56                         1MA 2nd Tariff
              11 to 15 kℓ = 5 × 12,07
                           = R60,35                              1MA 3rd Tariff
              16 to 20 kℓ = 5 × 17,65
                           = R88,25                              1MA 4th Tariff
              21 to 30 kℓ = 4,45 × 24,23
                           = R106,93                             1MA 5th Tariff
              Total amount = R28,56 + R60,35 + R88,25 + R106,93
                             = R284,09                           1CA Total amount
              Amount with VAT = R284,09 x 1,14                   1M Calculating
                                 = R323,86                       VAT
                                                                  1CA VAT incl
              Statement is valid                                 1O Valid       (9)

Copyright reserved                                                      Please turn over

### Page 3

(EC/NOVEMBER 2018)                   MATHEMATICAL LITERACY P2                                3

  1.1.3     Tank 1:
            Volume = πr2h                                              1C mm to cm             L3
                                  105 2                                  1SF Substitution
                     = 3.142 × (     ) × 142                            1MA Finding the
                                   2
                     = 1 229 739,525 ÷ 1 000                            radius
                     = 1 229,7                                          1S Simplification
                     = 1 000 litres                                     1C Convert to
                                                                         litres
                                                                         1R Nearest
                                                                         thousand
            Tank 2:
            Volume = πr2h
                    = 3,142 × (90)2 × 210
                    = 5 344 542 ÷ 1 000
                    = 5 344, 542
                    = 5 000 litres                                      1CA Rounded to
                                                                         nearest thousand
            Total = 1 000 + 5 000
                  = 6 000 litres                                        1CA Total volume
                                                                         for two tanks
            Water needed from tanks = 24 450 litres

            Statement invalid. Cannot have enough water if it does not
            rain. 
                                                                         1O Not valid     (9)

Copyright reserved                                                            Please turn over

### Page 4

4                              MATHEMATICAL LITERACY P2           (EC/NOVEMBER 2018)

    1.2.1   Grade 10 : Grade 11 : Grade 12                                               L3
            Ratio 5 : 3 : 2
            Grade 10 = 250 book packs
            Total = 5 + 3 + 2                                   1M Adding ratio
                   = 10                                        1M Concept of
             5                                                  ratio
                × total no. of book packs = 250                1M Changing
            10
            0,5 × total number of book packs = 250             subject of formula
                                             250                1M Dividing
            Total number of book packs =                       1CA Number of
                                              0,5
                                           = 500 book packs    book packs
                                         OR
            5 = 250
            1 = 250 ÷ 5                                         1MA Unit ratio
               = 50 
                                                                1MA Finding
            3 = 50 × 3                                          value of 3
              = 150 
                                                                1MA Finding
            2 = 50 × 2                                          value of 5
              = 100 
                                                                1M Addition
            Total = 250 + 150 + 100                            1CA Total book
                  = 500                                        packs         (5)
    1.2.2   Amount for books packs = R320 × 500                 CA from 1.2.1             L4
                            = R160 000                         1MCA Cost for
                                                                book packs
                                       R160 000                 1M Dividing by
            Amount without VAT =                               1,15
                                          1,15
                                      = R139 130,43            1CA Amount
                                                                before VAT
            VAT = R160 000 – R139 130,43                       1M Subtraction
                = R20 869,57                                   1CA VAT amount

            Amount for 50 = R3 20 × 50
                          = R16 000                            1MCA Amount of
                                                                50 book packs
            Statement is valid                                 1O Valid        (7)
    1.2.3                 150   100                             CA from 1.2.1             L2
            Probability =     +                                 1MCA Adding
                          500    500
                                                                correct fractions
                             250                               1CA Numerator
                         =           × 100                     1CA Denominator
                             500 
                                                                1CA Percentage
                         = 50%                                                  (4)

Copyright reserved                                                    Please turn over

### Page 5

(EC/NOVEMBER 2018)                 MATHEMATICAL LITERACY P2                                  5

Question 2 [43]
 Ques.    Solution                                                        Explanation             Level
2.1.1 (a) Mean 2015                                                                                L2
          = 59,6 + 76,9 + 75,7 + 68,2 + 97,1 + 77 + 84 + 70,4 +71,4 +
          49,1 + 58,6                                                    1M Adding
            788                                                           1M Dividing by 11
          =      
             11                                                           1CA Mean
          = 71,64                                                                       (3)
2.1.1 (b) Mean 2016                                                                                L4
          = 69,5 + 75,4 + 73,7 + 65,3 + 97,4 +76,5 + 84 + 70,5 + 71,3 +
              57,1 + 52
              = 786,7                                                     1MA Adding and
                786,7                                                     dividing
              =       
                  11
              = 71,52                                                    1CA Mean
              Statement invalid                                          1O Invalid       (3)
2.1.2         2015                                                                                 L4
              49,1; 58,6; 59,6; 68,2; 70,4; 71,4; 75,7; 76,9; 77; 84;     1M Ascending
              97,1                                                       order
              Q3 (A) = 77%                                               1CA Q3 (A)

              IQR = 77 – 59,6                                             1CA IQR
                  = 17,4% 

              2016
              51,5; 52,0; 65,3; 69,5; 70,5; 71,3; 73,7; 75,4; 76,5;
              84,0,97,4

              Q1 (B) = 65,3%                                             1A Q1 (B)

              IQR = 76,5 – 65,3
                  = 11,2%                                                1CA IQR

              Statement valid                                            1O Valid         (6)

Copyright reserved                                                             Please turn over

### Page 6

6                           MATHEMATICAL LITERACY P2                   (EC/NOVEMBER 2018)

2.2.1         Annual income = R31 625 × 12                           1MA Annual                L3
                            = R379 500                              income                   and
                                                                                               L4
              Tax = 61 910 + 31% of taxable income above 296 540    1RT Correct tax
                  = 61 910 + 0,31 × (379 500 – 296 540)             bracket
                  = 61 910 + 0,31 × 82 960                          1SF Substitution
                  = 61 910 + 25 717,6                                1S Simplification
                  = 87 627,6 – R13 635                              1M Subtract
                  = 73 992 ÷ 12                                      rebate
                  = 6 166,05                                        1CA Monthly tax

              Grants for 10 children = 380 × 10                      1MA Child grant
                                     = 3 800                        for 10
              2 old age people = 1 600 × 2
                                = 3 200                             1MA Old age
              Total = 3 200 + 3 800                                  grant for 2
                    = R7 000                                        1CA Total grants
              Statement invalid                                     1O Invalid
                                                                                  (10)
2.2.2         Amount after first year                                1M Multiplying by        L2
              = R31 625 × 1,058                                     5,8%
              = R33 459, 25                                         1CA Value for 1st
              Amount after second year                               year
              = R33 459, 25 × 1,068
              = R35 734,48                                          1CA Value for 2nd
                                                                     year
              Annual salary                                          1M Multiplying by
              = R35 734,48 × 12                                     12
              = R428 813,75                                         1CA Annual
                                                                     salary
                                      OR
              Total annual income
              = 31 625 × 12                                         1M Multiplying by
              = 379 500  × 1,058 × 1,068                          12
              = R428 813,75                                         1CA Salary
                                                                     1CA Value for 1st
                                                                     year

                                                                     1CA Value for 2nd
                                                                     year
                                                                     1CA Annual
                                                                     salary        (5)

Copyright reserved                                                         Please turn over

### Page 7

(EC/NOVEMBER 2018)                                 MATHEMATICAL LITERACY P2                            7

2.3.1         KZN = OAG + CSG                                                       1RT Correct             L2
                  = 669 634 + 2 776 098                                            values for KZN
                  = 3 445 732                                                      1CA Total

              WC = OAG + CSG
                 = 330 039 + 993 038                                                1CA Total
                 = 1 323 077 

              Difference = 3 445 732 – 1 323 077
                         = 2 122 655                                               1CA Difference(4)
2.3.2         Northern Cape                                                       2RT Province (2)        L2
2.3.3         Gauteng has a greater population                                    2A Reason     (2)       L4
2.3.4         FS and NW  remains the same  in 2017 and 2018                       1A Both FS & NW         L4
                                                                                    1A Remains the
              The number of the rest of the provinces  decreases                  same
                                                                                    1A Rest of
                                                                                    provinces
                                                                                    1A Decrease (4)

2.3.5                                                                                                       L2
                                     War Veteran grant for the EC, KZN, NC and LP
                                                   for 2017 and 2018

                                25

                                                                                    Both bars plotted
                                20                                                  correctly for

                Number of WVG
                                15                                                  1MA EC
                                                                                    1MA KZN
                                10                                                  1MA NC
                                                                                    1MA LP
                                5

                                0
                                       OK   KZN   NK   LP
                                                            Provinces

                                                                                                     (4)

Copyright reserved                                                                       Please turn over

### Page 8

8                            MATHEMATICAL LITERACY P2                    (EC/NOVEMBER 2018)

Question 3 [31]
Ques.    Solution                                                      Explanation              Level
3.1.1    Measured distance from Cape Town to Durban                                              L4
         = 8,1 cm  Accept 7,9 cm to 8,3 cm                           2A Measure
         Bar Scale                                                     distance
         3 cm = 500 km Accept 2,9 cm to 3,1 cm                        1A Measure bar
         Actual Distance                                               scale
           500 𝑥 8,1                                                   1C Convert
         =           
              3
                                                                       distance using
         = 1 350 km 
                                                                       bar scale
                                                                       1CA Distance
              Time taken by first family
              = 21:00 – 8:00 – 1,5
                                                                       1CA Time
              = 11,5 hrs 
                                1 350 𝑘𝑚
              Speed of family = 11,5ℎ𝑟𝑠
                               = 117,39 km/h                          1CA Speed

              Time taken by second family
              = 21:00 – 8,50 – 1,5
              = 11 hrs                                                1CA Time
                                1 350 𝑘𝑚
              Speed of family = 11ℎ𝑟𝑠                                  1CA Speed
                               = 122,72 km/h                          1O Valid
              Statement is valid                                      NPR          (10)
3.1.2         Zambia                                                 2A Country (2)            L2
3.2.1         Unknown length (1) = 12 cm – 6 cm                        1M Finding 6 cm           L2
                                  = 6 cm

              Unknown length (2) = 10 cm – 2 cm – 4 cm                 1M Finding 4 cm
                                 = 4 cm
                                                                       1M Adding all
              Perimeter = 10 + 4 + 4 + 2 + 12 + 6+ 6 + 2 + 6 + 4    values
                         = 56cm                                       1CA Perimeter(4)
3.2.2         Area = ℓ × b                                             CA from 3.2.1             L3
              Figure 1 = 10 cm × 4 cm
                        = 40 cm2                                      1MA Calculating
              Figure 2 = 4 cm × 6 cm                                   area
                        = 24 cm2                                      1MCA Area
              Figure 3 = 6 cm × 6 cm
                        = 36 cm2                                      1MCA Area
              Total area = 40 cm + 24 cm +36 cm
                          = 100 cm2                                   1CA Total area
              Area of page = 28 cm × 20 cm
                            = 560 cm2                                 1CA Area of page
              Area of unshaded part = 560 – 100                       1M Subtraction
                                     = 460 cm2                        1CA Unshaded
                                                                       area          (7)

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### Page 9

(EC/NOVEMBER 2018)                  MATHEMATICAL LITERACY P2                                   9

3.3.1         Satara to Olifants = 54km                                    1RT Correct             L2 &
              N’wanetsi to Lower Sabi = 108km                              distance                 L4
                                                                            1RT Correct
              Distance is half; therefore, it can take them half the time   distance
              to travel.                                                  2 Explanation (4)
3.3.2         Punda to Mopani = 130 km                                      1RT Correct             L2 &
              Mopani to Paul Kruger = 220 km                               values                   L4
              Total = 130 km + 220 km                                       1MA Adding
                    = 350 km                                               distances

              Skukuza to Pafuri = 380 km

              Difference = 380 km – 350 km
                         = 30 km                                           1CA Difference
              Statement valid                                              1O Valid      (4)

Copyright reserved                                                               Please turn over

### Page 10

10                         MATHEMATICAL LITERACY P2                (EC/NOVEMBER 2018)

QUESTION 4 [37]
 Ques.  Solution                                                 Explanation              Level
 4.1.1  Not offered at certain universities                    2A Reason                 L4
                                    OR
        No students registered for the course                                (2)
 4.1.2  Fees for Business at Bond = $33 640                      1RT Both values           L3
        Fees for Engineering at Edith Cowan = $ 25 760          correct
        Total = 33 640 + 25 760
              = 59 400                                          1CA Total
        $1 = R9,68
        $59 400 = 9,68 × 59 400                                 1C Convert to
                 = R 574 992                                    Rand
                                                                 1CA Amount in
                                                                 Rand           (4)
     4.1.3    Fees greater than $15 000, but less than $ 30000   1A Numerator              L2
                 7                                               1A Denominator
              =    
                10                                               1CA Decimal
              = 0,7                                                            (3)
     4.2.1                 38 249−29 678                       1RT Using                 L2
              % increase =                    × 100             correct values
                                 29 678
                         = 28,88%                               1SF Substitution
                                                                 1M Multiply by
                                                                 100
                                                                 1CA Percentage
                                                                 NPR            (4)
     4.2.2    December                                          1A Month                 L2 &
              People get bonuses in December                   2R Reason                 L4
                                        OR
              People budget to spend in December                            (3)
     4.2.3    August 2015 – 30 633                               1RT Both values           L3
              August 2016 – 31 556                              correct
              Difference = 31 556 – 30 633                       1MCA Difference
                         = 923 
              Amount = 923 × 550 000                             1MCA Amount
                       = R507 650 000 

              14, 81 = 1 Euro
                                  507 650 000                    1C Convert to €
              507 650 000 = 1 ×                                  1CA Amount in €
                                  14,81 
                          = 34 277 515,19 Euro                                (5)

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### Page 11

(EC/NOVEMBER 2018)                  MATHEMATICAL LITERACY P2                       11

   4.3.1      Hours worked:                                                              L4
              Level 3: Day 1 = 5 hours                         1A Hrs for Day 1
                       Day 2 to 13 = 10 hrs × 12                1MA Hrs for Day
                                   = 120                       2 to 13
                       Day 14 = 8 hrs
              Total number of hours = 5 + 120 + 8 hours         1CA Total
                                    = 133 hours                number of hours

              Level 2 = 133 hours
                                                                1M Subtracting
              Level 1 = 133 – 4                                1CA Calculating
                      = 129 hours                              hours for Level 1

              Amount for Level 3 = 248 × 133 × 2                1MCA Amount
                                = R65 968                      Level 3

              Amount for Level 2 = 133 × 218,24 × 6             1MCA Amount
                     = R174 155,52                             Level 2

              Amount for Level 1 = 129 × 163,68 × 32            1MCA Amount
                     = R675 671,04                             Level 1

              Total Amount = 65 968 + 174 155,52 + 675 671,04   1CA Total
                            = R915 794,56                      amount
              Statement invalid                                1O Invalid     (10)
   4.3.2      Distance for 14 days = 14 km × 2 × 14 days       CA from 4.3.1            L4
                                   = 392 km                    1MA Return
                                                                multiply by 14
                                                                1CA Total
              Transport Cost for all employees                  distance
              = 392 km × 3,18 × 40
              = R49 862,40 
                                                                1MCA Transport
                                       49 862,40                cost
              Amount as a fraction =                           1M Dividing
                                      915 794,56
                                  = 0,05                       values
              Statement is valid                               1CA Decimal
                                                                1O Valid    (6)
                                                                         TOTAL:          150

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