# Mathematical Literacy Grade 12 P2 2024 Memo (Eng)

> Grade 12 Mathematical Literacy Paper 2 memorandum from the Eastern Cape Prelim Exam 2024 (English), 12 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-12-mathematical-literacy-2024-eastern-cape-prelim-exam-memorandum-paper-2-english/4cc228d4-c593-4bf4-b06a-ea956fc56b64
- Updated: 2026-10-30
- Subject: Mathematical Literacy
- Grade: Grade 12
- Language: English
- Document type: Memorandum
- Year: 2024
- Exam period: Eastern Cape Prelim Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 12

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## About this document

Mathematical Literacy · Grade 12 · Eastern Cape Prelim Exam · 2024 · English. Memorandum, 12 pages. Read online or download the PDF.

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### Page 1

NATIONAL
                      SENIOR CERTIFICATE

                            GRADE 12

                        SEPTEMBER 2024

             MATHEMATICAL LITERACY P2
               MARKING GUIDELINES
MARKS: 150

        Symbol                             Explanation
          M      Method
         MA      Method with accuracy
          CA     Consistent accuracy
           A     Accuracy
           C     Conversion
           S     Simplification
          RT     Reading from a table/graph/diagram
          SF     Correct substitution in a formula
           O     Opinion/Explanation/Reasoning
           P     Penalty, e.g. for no units, incorrect rounding off etc.
           R     Rounding Off/Reason
         NPR     No penalty for correct rounding minimum two decimal places
          AO     Answer only
         MCA     Method with consistent accuracy
         RCA     Rounding with consistent accuracy

                 This marking guidelines consist of 12 pages.

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### Page 2

2                                     MATHEMATICAL LITERACY P2                      (EC/SEPTEMBER 2024)

MARKING GUIDELINES

NOTE:

•   If a candidate answers a question TWICE, only mark the FIRST attempt.

•   If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution,
    mark the crossed out (cancelled) version.

•   Consistent Accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops
    at the second calculation error.

•   If the candidate presents any extra solution when reading from a graph, table, layout plan and
    map, then penalise for every extra incorrect item presented.

LET WEL:

•   As ŉ kandidaat ŉ vraag TWEE keer beantwoord, merk slegs die EERSTE poging.

•   As ŉ kandidaat ŉ antwoord van ŉ vraag doodtrek (kanseleer) en nie oordoen nie, merk die
    doodgetrekte (gekanseleerde) poging.

•   Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas, maar dit
    hou by die tweede berekeningsfout op.

•   Wanneer ŉ kandidaat aflees van ŉ grafiek, tabel, uitlegplan, en kaart en ekstra antwoorde gee,
    penaliseer vir elke ekstra verkeerde item.

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### Page 3

(EC/SEPTEMBER 2024)                MATHEMATICAL LITERACY P2                                        3

 KEY TO TOPIC SYMBOL:
 F = Finance; M = Measurement; MP = Maps, Plans and Other representations; P = Probability

 QUESTION 1 [28 MARKS]                                         ANSWER ONLY FULL MARKS

 Ques.                             Solution                            Explanation          Level
 1.1.1                                       125                    1M divide by 1000        M
           Volume of heavy whipping cream = 1 000 M
                                                                    1A answer                L1
                                           = 0,125 litres A
                                                                                   (2)

 1.1.2                                                  50
           Grams of cocoa powder needed for 12 people = 4 × 12 ✓MA 1MA divide by 4            M
                                                                   and multiply by 12         L1
                                                      = 150 g A
                                                                   1A answer
                                     OR
                                                        12                OR
           Grams of cocoa powder needed for 12 people = 4 ×50 ✓MA 1MA divide by 4
                                                      = 150 g A   and multiply by 50
                                                                   1A answer
                                                                                   (2)

 1.1.3     Total time = (15 min + 6 min)                            1MA adding time           M
                     = 21 min × 2 MA                               and multiply by 2         L1
                     = 42 minutes A                                1A answer
                                                                                    (2)

 1.1.4     Time = 12:05                                             1M subtracting            M
                  = 0:21 (prep. and cooking)                        both times                L1
                  = 1:00 (chilling)         M                      1A correct time
                = 10:44 A                                                            (2)

 1.2.1     A OR Word Scale A AND                                   1A first scale           MP
           C OR Ratio ScaleA                                       1A second scale          L1
                                                                                      (2)

 1.2.2     Winburg ✓A                                              2A correct town          MP
                                                                                      (2)    L1

 1.2.3     4 national roads ✓RT                                    2RT number of            MP
                                                                    national roads           L1
                                                                                      (2)

 1.2.4     Edenburg ✓RT                                            2RT correct town         MP
                                                                                   (2)       L1

 1.3.1     Radius = 132 ÷ 2 M                                      1M divide by 2            M
                  = 66 cm A                                        1A correct radius         L1
                                                                                     (2)

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### Page 4

4                                      MATHEMATICAL LITERACY P2                     (EC/SEPTEMBER 2024)

    1.3.2 Total number of tanks = 920 × 2 MA                            1MA multiply correct            M
                                = 1 840 A                               values                          L1
                                                                         1A number of tanks
                                                                                            (2)

    1.3.3 B ✓A OR cubic metres ✓A                                      2A correct unit                 M
                                                                                                         L1
                                                                                                 (2)

    1.3.4 The diameter is the distance from one side of the circle to the 2A definition                  M
          other side of the circle, through the centre of the circle. ✓A                        (2)     L1

    1.4.1 Number of days = 5 ✓A                                         2A correct number of            M
          (Accept 4 days = 1 Mark)                                       days                            L1
                                                                                             (2)

    1.4.2 Year born = 2024 – 57 M                                       1M subtracting 57 from          M
                    = 1967 ✓A                                            2024                            L1
                                                                         1A correct year
                                                                                              (2)
                                                                                            [28]

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### Page 5

(EC/SEPTEMBER 2024)                         MATHEMATICAL LITERACY P2                                     5

 QUESTION 2 [34 MARKS]

 Ques.                                   Solution                           Explanation             Level
 2.1.1     National Roads ✓A                                          2A correct road               MP
                                                                                              (2)    L1

 2.1.2     Northeast OR NE ✓A                                         2A correct direction         MP
                                                                                              (2)   L1

 2.1.3     Eastern Cape                                                2A correct province          MP
                                                                                              (2)   L2
                            ✓A
 2.1.4     Speed      =
                          Distance                                                                  MP
                           Time
                                                                                                    L3
                          614,6 km    SF                              1SF substitution
           120 km/h =
                            Time

                  614,6 km                                          1MA change subject
           Time =           MA
                  120 km/h                                          and answer
                = 5,121666667 hours
           0,12166… × 60 = 7,3 minutes C                           1C hours to minutes
           Time taken to reach Vryheid = 5 hours and 7,3 minutesCA 1CA total time
           (Accept 5 hours and 7 minutes)                                               (4)

 2.2.1      • From the Free State, drive on the N3 till she reaches    1O N3                        MP
               Pietermaritzburg. O                                    1O left on N2 and            L4
            • Pass Pietermaritzburg and turn left onto the N2.         passing Richard’s Bay
               Continue driving on the N2 till she passes Richard’s    and Empangeni
               Bay, turn left and pass Empangeni. O                   1O continue to Eshowe
            • Continue on the road from Empangeni until she reaches    from Empangeni
               Eshowe. O
           (Accept any other relevant explanation.)                                           (3)

 2.2.2                                       5,9                       1MA dividing correct
           Number of litres of petrol =     × 614,9 l MA
                                        100                            values and multiply by
                                      = 36,2614 × 2 M                 614,9
                                      = 72,5228                        1M multiply by 2
                                                       CA
                                      ≈ 72,523 litres                  1CA number of litres
           (Accept 72,5 OR 72,52)                                      NPR
                                                                                            (3)

 2.2.3     Petrol cost = 72,523 litres × R24,45 MCA                   CA from 2.2.2                    F
                       = R1 773,18735                                  1MCA multiply by                 L1
                       ≈ R1 773,19 CA                                 R24,45
                                                                       1CA answer
                                                                                              (2)

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### Page 6

6                                      MATHEMATICAL LITERACY P2                    (EC/SEPTEMBER 2024)

    2.3.1   One unit on the map represents 350 units in reality. ✓A 2A explanation                   MP
                                                                                                      L1
                                       OR
                                                                 ✓A
            One unit on the map equals 350 units on the floor.                                  (2)

    2.3.2   Elevator ✓A OR Stairs ✓A                                 2A one correct feature         MP
                                                                                                (2)   L1
    2.3.3   Hata Street entrance ✓A                                   2A correct entrance            MP
                                                                                                (2)   L1

    2.3.4   Number of restrooms = 4 ✓A                                2A correct number of           MP
                                                                       restrooms                      L2
                                                                                                (2)

    2.3.5   Impossible OR None OR 0 OR 0% ✓A                          2A answer                      P
                                                                                                (2)   L2

    2.3.6   34 mm ✓A                                                  2A correct length in mm        MP
            (Accept 33 – 35 mm)                                                              (2)      L1

    2.3.7   Actual length = 34 × 350                                   CA from 2.3.6                  MP
                          = 11 900 mm MCA                             1MCA multiply with             L2
                            11 900                                     correct scale and answer
                       ⸫ = 1 000 C
                                                                       1C divide by 1000
                          = 11,9 m ✓MCA
                                                                       1MCA answer
                          = 12 m R
                                                                       1R rounding
            (Accept 11,55 m – 12,25 m) and (12 m)
                                                                                              (4)
                                                                                             [34]

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### Page 7

(EC/SEPTEMBER 2024)                    MATHEMATICAL LITERACY P2                                       7

 QUESTION 3 [30 MARKS]

 Ques.                            Solution                            Explanation              Level
 3.1.1     Area of rectangular school hall = length × width                                     M
                                           = 18 m × 12 m SF    1SF substitution                L3
                                           = 216 m2 A          1A area

           Area of stage                     = length × width
                                             = 10 m × 5,5 m
                                             = 55 m2 A         1A area

           Area of floor to be tiled = 216 m2 – 55 m2 MCA      1MCA subtracting areas
                                     = 161 m2CA                1CA answer
                                                                                    (5)

 3.1.2     Area of tile = 60 cm × 60 cm         M              1M calculating area              M
 (a)                    = 3 600 cm2                             1C conversion                    L2
                            3 600
                        = 100 × 100 C                          1CA area in m2
                        = 0,36 m2 CA
                                                                          OR
                                                                1C conversion
                                      OR
                             C                                 1M calculating area
           Area of tile = 0,6 m × 0,6 m M
                                                                1CA area in m2
                        = 0,36 m2 CA
                                                                                        (3)

 3.1.2                                161                       CA from 3.1.1 and                M
           Number of tiles needed =          MCA
 (b)                                  0,36                      3.1.2(a)                         L2
                                 = 447,22… × 1,1 M             1MCA dividing correct
                                 = 491,94 …                     values
                                 ≈ 492 tiles CA                1M multiply by 10%
                                                                1CA number of tiles
                                                                                    (3)

 3.1.2     Cutting OR breakages OR wastage ✓O                  2O reason                        M
 (c)                                                                                    (2)      L4

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### Page 8

8                                      MATHEMATICAL LITERACY P2                      (EC/SEPTEMBER 2024)

    3.1.3   Scale = 60 mm : 18 m M                                    1M correct ratio                   M
                  = 60 : 18 000 C                                     1C converting 18m to mm            L3
                           S C                                       1S unit ratio
                  = 1: 300
                                   OR                                             OR
                                M
            Scale = 60 mm: 18 m                                        1M correct ratio
                  = 0,06: 18 C                                        1C converting 6 mm to m
                  = 1 : 300 S                                         1S unit ratio
                                                                                             (3)
    3.2.1   Diameter = 8 cm × 2 M                                     1M multiplying by 2                M
                     = 16 cm × 10                                      1C diameter in mm                  L2
                     = 160 mm C

                                      OR                                          OR
                                            C
            Diameter: 8 cm × 10 = 80 mm                                1C diameter in mm
                           M                                          1M multiplying by 2
                   ⸫ 80 mm × 2 = 160 mm                                                          (2)

    3.2.2   Dimensions of unshaded part:                                                                  M
            Length = 28,5 cm – 2,5 cm – 2,5 cm M                      1M subtracting 2,5 twice           L3
                   = 23,5 cm CA                                       from length
                                                                       1CA length
            Width = 22 cm – 2,5 cm – 2,5 cm                            1CA width
                  = 17 cm CA                                                                 (3)

    3.2.3   Perimeter = 2 (length + width)                             CA from 3.2.2                      M
                      = 2 (23,5 cm + 17 cm) SF                        1SF correct length and             L1
                      = 81 cm CA                                      width
                                                                       1CA perimeter
                                                                                                 (2)

    3.2.4   Area of certificate without border and (circle included)   CA from 3.2.2                      M
            = length × width                                                                              L4
            = 23,5 cm × 17 cm SF                                      1SF correct dimensions
            = 399,5 cm2 MCA                                           1MCA area

            Area of circle = 3,142 × radius2
                           = 3,142 × 82 SF                            1SF substitution
                           = 201,088 cm2 CA                           1CA area of circle

            ⸫ Area of unshaded part (excluding border and circle):
            = 399,5 cm2 – 201,088 cm2 MCA                             1MCA subtracting areas
            = 198,412 cm2                                              1CA unshaded area
            ≈ 198 cm2 CA                                              1O opinion
            ⸫ Her statement is valid O                                                      (7)
                                                                                            [30]

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### Page 9

(EC/SEPTEMBER 2024)                    MATHEMATICAL LITERACY P2                                        9

QUESTION 4 [35 MARKS]

Ques.                          Solution                                    Explanation            Level
4.1.1 Dimensions in mm = 17 inch × 25,4                                 1C converting              M
                       = 431,8 mm C                                    dimension                  L2
      ⸫ Volume         = length × width × height                        1SF substitution
                       = 431,8 mm × 431,8 mm × 431,8 mm SF             1CA volume
                       = 80 509 645,43 mm3 CA
                                                                                            (3)

4.1.2    Total surface area:                                                                          M
         = 2 (l × w) + 2 (l × h) + 2 (w × h)                                                          L4
         = 2 (431,8 × 431,8) + 2 (431,8 × 431,8) + 2 (431,8 × 431,8) SF 1SF substitution
         = 372 902,48 + 372 902,48 + 372 902,48 M                       1M multiply by 2
                                2
         = 1 118 707,44 mm
                   1 118 707,44                                          1C conversion
         ⸫ TSA =                  C
                    1 000 000                                            1CA surface area
                 = 1,12 m2CA (Accept 1,119 m2)                          1O opinion
                 ⸫ His statement is invalid O
                                                                                 OR
                                         OR
         Total surface area:
         = 2 (l × w) + 2 (l × h) + 2 (w × h)                             1C conversion
         = 2 (0,4318 × 0,4318 ) + 2 (0,4318 × 0,4318 ) + 2 (0,4318 ×     1SF substitution
           0,4318) C SF                                                1M multiply by 2
         = 0,37290248 + 0,37290248 + 0,37290248 M                       1CA surface area
         = 1,12 m2CA (Accept 1,119 m2)                                  1O opinion
         ⸫ His statement is invalid O                                   NPR
                                                                                            (5)

4.1.3                                    2,2                            1M dividing correct       MP
         Number of boxes in length =            M
                                       0,4318                           values                    L3
                                  = 5,094…                              1A number of boxes
                                  = 5 boxes A

                                        1,5
         Number of boxes in width =
                                       0,4318                           1A correct number
                                  = 3,473…                              of boxes
                                  = 3 boxes A

                                        1,6
         Number of boxes in height =
                                       0,4318                           1A correct number
                                  = 3,705…                              of boxes
                                  = 3 boxes A
                                                                        1MCA
         Total number of boxes    =5×3×3                                multiplication and
                                  = 45 boxes MCA                       total number of
                                                                        boxes
                                                                                          (5)

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### Page 10

10                                    MATHEMATICAL LITERACY P2                (EC/SEPTEMBER 2024)

 4.2.1 Distance = Speed × Time      18h48min = 18,8 hrs C       1C converting time           MP
         1 268 = Speed × 18,8 h SF                              1SF substitution             L3
                      1 268                                      1M changing subject
         ⸫ Speed =            M
                       18,8                                      1CA speed
                 = 67,45 miles/h CA                             NPR
         (Accept 67 OR 67,447 OR 67,5 miles/h)                                          (4)

 4.2.2 1 157 miles = 1 862 km                                                                 MP
                         1 862                                   1M dividing by 1 157         L2
          1 mile       =        M
                          1 157                                  1CA answer
                     = 1,609334… CA                             1R rounding
                     ≈ 1,609 km R                                                   (3)

 4.3.1 Number of arches needed = 11 × 5 MA                      1MA multiply correct         M
                               = 55 arches A                    values                       L2
                                                                 1A number of arches
                                                                                     (2)

 4.3.2 Number of poles needed = 20 M                            1M dividing by 5             M
                                5                                1CA number of poles          L2
                              = 4 poles CA                                         (2)

 4.3.3 Number of steel rods needed = 11 arches × 5 pegs M       1M multiply correct          M
                                  = 55 steel rods CA            values                       L4
       The statement is valid O                                 1CA simplification
                                                                 1O opinion
                                                                                        (3)

 4.3.4 Volume of a rectangular prism = length × width × height                                M
                                                       C        1C conversion                L3
                                          = 1,2 × 1 × 1,4 SF    1SF substitution
                                          = 1,68 m3CA           1CA simplification
                                          = 1,68 kl C           1C total kilolitres
                                                                                        (4)

 4.3.5 Mask is for protection when spraying fertilisers. ✓O     2O opinion                   M
                                                                                        (2)   L4

 4.3.6 Rainwater ✓A                                             2A answer                    M
                                     OR                                                       L4
         Underground water ✓A
                                     OR
         Borehole ✓A
         (Accept any relevant answer.)                                                  (2)
                                                                                       [35]

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### Page 11

(EC/SEPTEMBER 2024)                           MATHEMATICAL LITERACY P2                                     11

QUESTION 5 [23 MARKS]

Ques.                     Solution                                     Explanation                 Level
5.1.1 Probability = 2 A                                       1A numerator                         P
                         × 100%
                    6 A                                       1A denominator                       L2
                  = 33,33% CA                                 1CA %
                                                               (NPR)
                          (Accept 33,3% OR 33,333%)                                          (3)

5.1.2    Actual distance = 815,6 km – 144,9 km M              1M subtract correct values           MP
                         = 670,7 km                            1C conversion                        L2
                         ⸫ 670,7 × 1 000 C                    1CA answer
                         = 670 700 m CA                                                     (3)

5.1.3                         81 560 000                       1MA dividing correct values          MP
         Map distance =                      MA
                                 9 600 000                     1CA answer                           L2
                            = 8,4958… CA                      1R one decimal place
                            ≈ 8,5 cm R                                                      (3)

5.1.4                    Distance                                                                   MP
         Speed       =
                          Time                SF              1SF substitution                     L3
         80 km/h = 815,6 km ÷ Time
                   815,6 km M
         Time    =                                             1M changing subject
                         80 km/h
                     = 10,195h
                                                               1CA time in hours and minutes
                     = 10 hours 11 minutes 42 seconds CA
                                                               1A Total time for stopovers (1h
         ⸫ Time bus travelled = 10:11:42
                                                               45 min)
                                    A                         1M subtract time
                        M = 01:45:00                          1CA time bus travelled
                              = 08:26:42
                                                               NPR
                              = 8 hours 26 minutes 42
                               seconds CA
         (Accept 8h 26 min OR 8h 27 min)                                                     (6)

5.2.1    The space left allow for movement of the fluid 2O opinion                                  M
         during temperature change or transportation of the                                         L4
         bottles. ✓O
         (Accept any other relevant response.)                                               (2)

5.2.2                                           3
         Number of rectangular bottles in box = × 75 MA 1MA multiply correct fraction              P
                                                5        with 75                                    L2
                                              = 45 A    1A number of rectangular bottles
                        45
         ⸫ Probability = CA                             1CA correct probability
                        75                                                             (3)

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### Page 12

12                                  MATHEMATICAL LITERACY P2              (EC/SEPTEMBER 2024)

 5.2.3     Volume = 3,142 × radius2 × height         1SF substitution                     M
                   = 3,142 × 42 × 5 SF                                                   L4
                   = 251,36 m3
                   ≈ 251 m3 CA                      1CA volume
           ⸫ Pam’s statement is invalid O           1O opinion
                                                                                  (3)
                                                                                 [23]

                                                                        TOTAL: 150

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- [Maths LIT Grade 12 NSC P1 ANSWER BOOK September 2025 KZN](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-answer-book-september-2025-kzn/b0b358eb-c897-437a-8694-910fe61dfcbc) — Addendum · 2025
- [Maths LIT Grade 12 NSC P1 QP September 2025 Limpopo](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-qp-september-2025-limpopo/c5d7a167-2d27-4e33-80ef-fad9cde4ebd2) — QP · 2025
- [Maths LIT Grade 12 NSC P2 QP September 2025 Limpopo](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p2-qp-september-2025-limpopo/f22349c1-8dbf-420e-ae8d-13d53bcb300b) — QP · 2025
- [Maths LIT Grade 12 NSC P2 QP September 2025 North West](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p2-qp-september-2025-north-west/7ce5b7fe-941b-4148-80dc-d9cde7bdbfd7) — QP · 2025

## Collection

- [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers)

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Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.
