# Mathematical Literacy Grade 12 P1 North West June 2024 Memo > Grade 12 Mathematical Literacy Paper 1 memorandum from the North West June Exam 2024 (English), 9 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/grade-12-mathematical-literacy-2024-north-west-june-exam-question-paper-paper-1-english/b8c7ce8a-9ac8-4960-9ab3-3d5def4d6653 - Updated: 2026-10-29 - Subject: Mathematical Literacy - Grade: Grade 12 - Language: English - Document type: Memorandum - Year: 2024 - Exam period: North West June Exam - Paper: 1 - Curriculum: CAPS - Pages: 9 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Mathematical Literacy](https://www.hlayiso.com/library/grade-12/mathematical-literacy) › [Mathematical Literacy Grade 12 P1 North West June 2024 Memo](https://www.hlayiso.com/library/grade-12-mathematical-literacy-2024-north-west-june-exam-question-paper-paper-1-english/b8c7ce8a-9ac8-4960-9ab3-3d5def4d6653) ## About this document Mathematical Literacy · Grade 12 · North West June Exam · 2024 · English. Memorandum. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 PROVINCIAL ASSESSMENT GRADE 12 MATHEMATICAL LITERACY P1 JUNE 2024 MARKING GUIDELINES MARKS: 100 Symbol Explanation M Method MA Method with accuracy MCA Method with consistent accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT Reading from a table/a graph/document/diagram SF Correct substitution in a formula O Opinion/Explanation/Reasoning P Penalty, e.g. for no units, incorrect rounding off, etc. R Rounding off NPR No penalty for correct rounding AO Answer only These marking guidelines consist of 9 pages. Copyright reserved Please turn over ### Page 2 Mathematical Literacy/P1 2 NW/June 2024 Grade 12 – Marking guidelines NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at the second calculation error. • NOTE: consistent accuracy (CA) does not apply in cases of a breakdown. • If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalize for every extra item presented. • As a general marking principle, if a candidate has incurred one mistake and there is evidence of sound mathematics thereafter, then that candidate should lose one mark only. • Rounding is an independent mark. • In opinion type questions marks will only be awarded if relevant calculations are shown. QUESTION [19 MARKS] Answer only AO – full marks Q Solution Explanation T/L 1.1.1 Numerical data✓✓A 2A correct classification D (2) L1 1.1.2 ✓RT 1RT all correct values D R10; R15; R18; R20; R30; R35; R79 ✓ A 1A ascending order L1 (2) 1.1.3 Store B ✓✓RT 2RT correct store D (2) L1 1.1.4 ✓RT 1RT correct values D 20 : 18 ✓A 1A values in correct order L1 = 1 : 0,9 ✓A 1A simplification (3) Price per one 410 g baked beans 1MA dividing by 5 F 1.1.5 R64,00 L1 = ✓MA 5 1A price per tin/baked beans = R12,80 ✓ A (2) 1.2.1 GEPF✓✓A 2A correct acronym F (2) L1 1.2.2 Stop Order: An arrangement between the client and a 2O explanation F bank to pay a fixed amount of money from the client L1 account into another account on a specific date every month.✓✓O OR Stop Order: An instruction that an employer or bank to pay/divert monthly or regularly transfer a certain amount to a person or an account. ✓✓O Copyright reserved Please turn over ### Page 3 Mathematical Literacy/P1 3 NW/June 2024 Grade 12 – Marking guidelines OR Stop Order: An instruction that an employee (individual) issue to the employer (bank) to make a series of future dated regular deductions.✓✓O OR Stop Order: Future dated regular monthly deductions. ✓✓O (2) 1.2.3 R2 660 582 2A correct wording F Two million six hundred and sixty thousand five L1 hundred and eight two rand. ✓✓A (2) 1.2.4 Current annual salary F R490 312✓ RT 1RT correct value L1 = R490 000✓R 1R rounding (2) [19] QUESTION 2 [36 MARKS] 2.1.1 The value of A F L1 ✓RT = 9273 – 24 kl ✓M 1RT identifying values = 9 249 kl ✓ 1M subtracting 1A answer (3) 2.1.2 Total water charge F ✓MA ✓RT ✓M 1MA identifying 6, 9, 9 B = (6 × R18,12) + (9 × R29,86) + (9 × R36,58) 1RT identifying R18,12; = R108,72 + R268,74 + R329,22 R29,86; R36,58 L4 1M multiplying = R706, 68✓A 1A simplification Adding fixed cost to water charge = R706, 68 + R727,85✓RT 1RT fixed cost = R1 434,53 The statement is VALID ✓O 1O opinion (6) 2.2.1 25/02/2016 ✓✓A 2A correct date F (2) L1 2.2.2 R 69 1MA dividing by 1,15 F Amount without VAT = ✓MA 1,15 L2 = R60,00  VAT amount = R69,00 – R60,00✓M 1M subtracting = R 9,00✓A 1A VAT amount Copyright reserved Please turn over ### Page 4 Mathematical Literacy/P1 4 NW/June 2024 Grade 12 – Marking guidelines OR OR 100% 100% Amount without VAT = R69 × ✓MA 1MA multiplied by 115% 115% = R60,00  VAT amount = R69,00 – R60,00✓M 1M subtracting = R 9,00✓A 1A VAT amount OR OR ✓MA 15% 1MA multiplying by 15% VAT amount = R69 ,00 × 115% ✓M 1M dividing by 115% = R9,00✓A 1A VAT amount (3) 2.2.3 Total amount of administration fee F ✓RT L1 = R69,00 × 240 ✓MA 1RT 240 months = R16 560,00✓A 1MA multiplying 1A answer (3) 2.2.4 Total amount CA from 2.2.3 F ✓RT L2 = R1 862,06 × 240 ✓ SF 1RT monthly instalment = R446 894,40 ✓A 1SF correct substitution 1A answer (3) 2.2.5 CA from 2.2.4 F Extra amount paid L3 ✓RT 1RT R2 300,00 = R2 300,00 – R1 862,06 ✓MA 1MA subtracting = R437,94 ✓CA Extra amount paid for 3 months 1CA simplification = R437,94 × 3 months✓MCA 1MCA multiplying by 3 = R1 313,82 ✓CA 1CA answer OR Amount paid for 3 months OR ✓RT 1RT R2 300,00 = R2 300 ,00 × 3 ✓MA 1MA multiplying by 3 = R6 900,00✓ CA 1CA simplification Amount to be paid for 3 months = R1 862,06 × 3 1CA simplification = R5 586,18 ✓CA Extra amount paid = R6 900,00 – R5 586,18 1CA answer = 1 313,82 ✓CA (5) Copyright reserved Please turn over ### Page 5 Mathematical Literacy/P1 5 NW/June 2024 Grade 12 – Marking guidelines 2.2.6 To prevent money laundering ✓✓O 2O reason F OR L4 To prevent fraud✓✓O OR To view privately / Confidential✓✓O (2) 2.3.1 Total cost = R750 + 15p, where p = number of plates F ✓SF L2 R1 950 = R750 + 15p 1SF correct substitution R1 950 –R 750 = 15p ✓MA 1MA subtracting R750 R1 200 = 15p ✓S 1S simplification p = 80 ✓CA 1CA answer (4) 2.3.2 F INCOME AND COST OF SELLING CHOW MEIN PLATES 3500 L2 3000 2500 Amount in rand 2000 1500 1000 500 0 0 10 20 30 40 50 60 70 80 90 100 Number of plates of Chow Mein 1A Start point (0, 750)✓ 1A End point (100, R2 250)✓ 1A correct straight line✓ (3) 2.3.3 F 50 plates ✓✓RT 2RT number of plates L2 OR OR 30p = R750 + 15p ✓MA 1MA breakeven concept R750 = 15p 1A answer p = 50 ✓A (2) [36] Copyright reserved Please turn over ### Page 6 Mathematical Literacy/P1 6 NW/June 2024 Grade 12 – Marking guidelines QUESTION 3 [ 22 MARKS] 3.1 The value that appear the most in a data set.✓✓O 2O explanation D (2) L1 3.2 Arranging D L2 294 204; 298 607; 313 030; 341 363; 361 948; 1A arranging values 421 835; 441 067; 450 005 ✓A ✓RT 1RT two middle values 341 363 + 361 948 1MA concept of median Median = ✓MA 2 1CA simplification = 351 655,5 ✓CA (4) 3.3 Range D = Maximum value – Minimum value L2 ✓RT 1RT correct values = 85,7% – 71,3% ✓MA 1MA concept of range = 14,4% ✓A 1A simplification (3) 3.4 Percentage decrease D ✓RT 1RT correct values L2 421 835 − 450 005 1A correct denominator = × 100% 450 005 ✓A = – 6,3 % ✓ A 1A simplification NPR OR ✓RT OR 421 835 =  100% ✓MA 1RT correct values 450 005 1MA calculating % = 93, 7400695548% = 93,7400695548% – 100% 1A simplification = – 6,3% ✓A NPR (3) 3.5 Value A ✓MA D 46,4 + 45,0 + 45,4 + A + 57,7 + 49,1 + 60,4 + 56,7 1MA concept of mean L3 51,9 = 8 ✓MA 360,7 + A 1MA adding values 51,9 = 8 1M changing the subject of A = 51,9 × 8 – 360,7 ✓M the formula A = 415,2 – 360,7 1CA simplification A = 54,5% ✓CA (4) Copyright reserved Please turn over ### Page 7 Mathematical Literacy/P1 7 NW/June 2024 Grade 12 – Marking guidelines 3.6 ✓O 1O decrease 2020 to 2021 D The performance decreased from 2020 to 2021, L4 ✓O 1O increase in 2022 increased in 2022 and decreased again in 2023✓O. 1O decrease in 2023 (3) 3.7 Probability P L3 ✓A 62 979 1A numerator = 294 204 ✓A 1A denominator = 0,2✓CA 1CA simplification NPR (3) [22] Copyright reserved Please turn over ### Page 8 Mathematical Literacy/P1 8 NW/June 2024 Grade 12 – Marking guidelines QUESTION 4 [23 MARKS] Q Solution Explanation T/L 4.1.1 Tax bracket 1✓✓RT 2RT tax bracket F (2) L1 CA from Q 4.1.1 4.1.2 Income tax F 18 1MCA calculating 18% L4 = 120 278 × ✓MCA 100 = R 21 650,04 ✓ CA 1CA simplification ✓MA = R21 650,04 – (R9 444 + R17 235)✓MA 1MA subtracting R9 444 = R21 650,04 – R26 679 1MA subtracting R17 235 = – R5 028,96 ✓CA 1CA simplification His statement is VALID ✓O 1O conclusion OR OR Annual Taxable Income = R120 278 Rebates 1MA adding rebates = R9 444 + R17 235 ✓MA 1CA simplification = R26 679✓ CA Tax Threshold = R26 679 ÷18% ✓ MCA 1MCA dividing by 18% = R148 216,67✓CA 1CA simplification R148 216,67 is greater than R120 278 ✓O 1O reason His statement is VALID ✓O 1O conclusion (6) 4.2.1 Amount in Chinese Yuan F 1MA multiplying by 0,39 L2 R2 600 CN¥ = × 0,39 CN¥ ✓MA R1 1A simplification = 1 014 CN¥ ✓A OR OR R2 600 1MA dividing = ×1 CN¥ ✓MA R2,5641025 64 1A simplification = 1 014 CN¥ ✓A (2) Copyright reserved Please turn over ### Page 9 Mathematical Literacy/P1 9 NW/June 2024 Grade 12 – Marking guidelines 4.2.2 Interest after 1 year = R550,00 × 9,5%✓MA 1MA multiplying by 9,5% F = R52,25 ✓A 1A interest 1st year L3 Amount after 1 year = R550,00 + R52,25 = R602,25✓CA 1CA 1st year amount Interest after 2 years = R602,25 × 9,5% = R57, 21 ✓CA 1CA interest 2nd year Amount after 2 years = R602,25 + R57,21 = R659,46✓CA 1CA answer OR OR 100% + 9,5% = 109,5% ✓A 1A 109,5% Amount after 1 year = R 550,00 × 109,5%✓MA 1MA multiplying 109,5% = R602, 25 ✓A 1A 1st year amount Amount after 2 years = R602,25 × 109,5%✓M 1M multiplying by 109,5% = R659,46✓ CA 1CA answer (5) 4.3.1 75% ✓✓ A 2A correct percentage D (2) L2 4.3.2 IQR = Q3 – Q1 ✓MA 1MA concept of IQR D ✓RT ✓RT L3 = 56,7 – 34 1RT correct value (Q3) = 22,7 ✓CA 1RT correct value (Q1) 1CA simplification (4) 4.3.3 The median of the data is the highest in 2023.✓✓O 2O explanation D OR L4 Q3 is higher in 2023 than in 2022.✓✓ O OR Extra classes.✓✓ O Improved learner and teacher attendance.✓✓ O Self-disciplined learners.✓✓ O Parental involvement.✓✓ O Curriculum coverage.✓✓ O Effective school management .✓✓ O (2) [23] TOTAL: 100 Copyright reserved ## Related documents - [MATHS LIT P1 GR12 QP JUNE 2024 English](https://www.hlayiso.com/library/maths-lit-p1-gr12-qp-june-2024-english/f81e30c2-023e-4bb1-86a4-beb109ba7b94) — Mathematical Literacy · QP · 2024 · Eng - [MATH LITERACY P1 GR12 QP SEPT2024 English](https://www.hlayiso.com/library/math-literacy-p1-gr12-qp-sept2024-english/ba8b43d2-ba89-4f66-af6c-f594cd738b05) — Mathematical Literacy · QP · 2024 · Eng - [Gr 12 Mathematic Literacy P1 (English) 2024 Question Paper X05](https://www.hlayiso.com/library/gr-12-mathematic-literacy-p1-english-2024-question-paper-x05/a372ac22-cc57-41ff-9d4c-816d7cefcbda) — Mathematical Literacy · QP · 2024 · Eng - [MATHS LIT P1 GR12 MEMO SEPT2022 English (Approved)](https://www.hlayiso.com/library/maths-lit-p1-gr12-memo-sept2022-english-approved/5a64a94d-eb36-49e3-baaa-d90dae2dbde8) — Mathematical Literacy · Memo · 2022 · Eng - [MATHS LIT P1 GR12 MEMO SEPT 2021 English](https://www.hlayiso.com/library/maths-lit-p1-gr12-memo-sept-2021-english/9e0090b1-9cc7-4ae4-abe6-f4cf6ea5bce3) — Mathematical Literacy · Memo · 2021 · Eng - [Grade 12 NSC Mathematical Literacy P1 (English) 2020 Preparatory Possible Answers](https://www.hlayiso.com/library/grade-12-nsc-mathematical-literacy-p1-english-2020-preparatory-possible-answers/d1485a44-4dbf-41f8-bef0-0376485fcde9) — Mathematical Literacy · Memo · 2020 · Eng ## More from Grade 12 Mathematical Literacy - [MATHS LIT P2 GR 12 SEPT 2025 ADDENDUM AFR watermark](https://www.hlayiso.com/library/maths-lit-p2-gr-12-sept-2025-addendum-afr-watermark/813c6e54-f134-474a-b01a-1260e38b4c8f) — Addendum · 2025 · Afr - [Maths LIT Grade 12 NSC P1 QP September 2025 Free State](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-qp-september-2025-free-state/45f0ab2a-afdd-46df-bf98-5505c4021e64) — QP · 2025 - [Maths LIT Grade 12 NSC P1 ANSWER BOOK September 2025 KZN](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-answer-book-september-2025-kzn/b0b358eb-c897-437a-8694-910fe61dfcbc) — Addendum · 2025 - [Maths LIT Grade 12 NSC P1 QP September 2025 Limpopo](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-qp-september-2025-limpopo/c5d7a167-2d27-4e33-80ef-fad9cde4ebd2) — QP · 2025 - [Maths LIT Grade 12 NSC P2 QP September 2025 Limpopo](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p2-qp-september-2025-limpopo/f22349c1-8dbf-420e-ae8d-13d53bcb300b) — QP · 2025 - [Maths LIT Grade 12 NSC P2 QP September 2025 North West](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p2-qp-september-2025-north-west/7ce5b7fe-941b-4148-80dc-d9cde7bdbfd7) — QP · 2025 ## Collection - [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.