# Mathematical Literacy Grade 12 P2 North West June 2024 Memo

> Grade 12 Mathematical Literacy Paper 2 memorandum from the North West June Exam 2024 (English), 9 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-12-mathematical-literacy-2024-north-west-june-exam-question-paper-paper-2-english/12f37481-5144-4f52-8e3b-c4d297608118
- Updated: 2026-10-29
- Subject: Mathematical Literacy
- Grade: Grade 12
- Language: English
- Document type: Memorandum
- Year: 2024
- Exam period: North West June Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 9

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Mathematical Literacy · Grade 12 · North West June Exam · 2024 · English. Memorandum. Read online or download the PDF.

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### Page 1

PROVINCIAL ASSESSMENT

                                        GRADE 12

                            MATHEMATICAL LITERACY P2
                                   JUNE 2024
                              MARKING GUIDELINES

MARKS: 100

         Symbol      Explanation
           M         Method
          MA         Method with accuracy
          MCA        Method with consistent accuracy
           CA        Consistent accuracy
            A        Accuracy
            C        Conversion
            S        Simplification
           RT        Reading from a table/a graph/document/diagram
           SF        Correct substitution in a formula
           O         Opinion/Explanation/Reasoning
            P        Penalty, e.g. for no units, incorrect rounding off, etc.
            R        Rounding off
          NPR        No penalty for correct rounding
           AO        Answer only

                            These marking guidelines consist of 9 pages.
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### Page 2

Mathematical Literacy/P2                        2                               NW/June 2024
                                   Grade 12 – Marking Guideline

NOTE:
•  If a candidate answers a question TWICE, only mark the FIRST attempt.
•  If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the
   solution, mark the crossed out (cancelled) version.
•  Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it
   stops at the second calculation error.
•  NOTE: consistent accuracy (CA) does not apply in cases of a breakdown.
•  If the candidate presents any extra solution when reading from a graph, table, layout plan and
   map, then penalize for every extra item presented.
•  As a general marking principle, if a candidate has incurred one mistake and there is evidence
   of sound mathematics thereafter, then that candidate should lose one mark only.
•  Rounding is an independent mark.
•  In opinion type questions marks will only be awarded if relevant calculations are shown.
  QUESTION 1 [20 MARKS] Answer only AO – full marks
  Ques Solution                                                     Explanation            T/L
  1.1.1 C✓✓A                                                        2A answer              P
                                                                                       (2) L1
  1.1.2     A✓✓ A                                                   2A answer              M
                                                                                       (2) L1
  1.1.3     E✓✓ A                                                   2A answer              MP
                                                                                       (2) L1
  1.2.1                               90𝑚𝑙                          1MA division           M
            Number of tablespoons =          ✓ MA
                                      15𝑚𝑙                          1A answer              L1
                                   =6✓A                                                (2)
  1.2.2         ✓RT                                                 1RT correct values     M
            75 g : 375 g✓ MA                                        1MA correct order      L1
            1 : 5✓ A                                                1A unit ratio
                                                                                       (3)
  1.2.3                                 1                                                  M
            Amount of brown sugar = 12 cup
                                        1                                                  L1
                                   = 1 × 250 g ✓MA                  1MA multiplication
                                      2
                                   = 375 g✓S                        1S simplification
                                   = 0,375 kg✓C                     1C conversion
                                     OR
                    1
            1 cup + 2 cup = 250 g + 125 g✓MA                                 OR
             1                                                      1MA addition
            12 cup of sugar = 375 g ✓S                              1S simplification
                            = 0,375 kg✓C                            1C conversion
                                                                                         (3)
  1.3.1     National Road map✓✓A                                    2A answer                MP
                                                                                         (2) L1
  1.3.2     1 unit on the map represents 50 000 units on the        2A explanation           MP
            ground.✓✓A                                                                   (2) L1
  1.3.3     Netcare Mulbarton Hospital✓A                                                     MP
            Netcare Sunward Park Hospital✓A                         1A answer                L1
            Netcare Alberton ✓A                                     1A answer
            Any 2 correct answers                                                        (2)
                                                                                        [20]

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### Page 3

Mathematical Literacy/P2                            3                              NW/June 2024
                                       Grade 12 – Marking Guideline

QUESTION 2 [28 MARKS]
Ques Solution                                                         Explanation                T/L
2.1.1 Strip chart✓✓A                                                  2A answer                  MP
                                                                                             (2) L1
2.1.2     964 km✓✓A                                                   2A answer                  MP
                                                                                             (2) L1
2.1.3                distance                                         CA from Q2.1.1             MP
          Speed =
                      time                                            1SF substitution           L3
                        964 km
          120 km/h =             ✓SF
                         time                                         1M changing the
                     964 km
           Time =               ✓M                                    subject
                     120 km/h
                 = 8,033333h✓CA
                                                                      1CA answer
                                                                      NPR                  (3)
2.1.4                  ✓A                 RT✓                         1A 60 km                 MP
          Distance = 60 km + 74 km + 24 km + 158 km✓M                 1RT 3 correct distances L2
                   = 316 km✓CA                                        1M addition
                                                                      1CA answer
                                                                                           (4)
2.1.5     To rest from driving.✓✓O                                    2O reason                MP
                                     OR                                                        L4
          To do site viewing.✓✓O
                                     OR
          To catch up with his friend.✓✓O
          Accept any relevant reason.                                                        (2)
2.2.1     N3✓A                                                        1A answer                      MP
          N2✓A                                                        1A answer                      L1
                                                                                             (2)
2.2.2     Bar scale✓✓A                                                2A answer              MP
                                                                                         (2) L1
2.2.3     North-West✓✓A                                               2A answer              MP
                                  OR                                                         L2
          NW✓✓A                                                                          (2)
2.2.4     Scale                                                                              MP
              ✓A                                                      1A measured distance   L3
          22 mm : 10 km
          22 mm : 10 000 000 mm✓C                                     1C conversion
          1 : 5454 545✓S                                              1S simplification
                                  OR                                  OR
          Scale
          ✓A                                                          1A measured distance
          2,2 cm : 10 km
          2,2 cm : 1 000 000 cm✓C                                     1C conversion
          1: 454 545✓S                                                1S simplification
          [Accept 21 mm – 23 mm or 2,1 cm – 2,3 cm]                                          (3)
2.3.1     810 m ✓✓A                                                   2A answer                  MP
                                                                                             (2) L2
2.3.2     Distance = 45 km ✓✓A                                        2A answer                  MP
          Accept [44 – 46 km]                                                                (2) L2

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### Page 4

Mathematical Literacy/P2                       4                                 NW/June 2024
                                  Grade 12 – Marking Guideline

2.3.3     Insufficient training.✓✓O                                 2O reason                      MP
                                      OR                                                           L4
          Injuries ✓✓O
                                     OR
          Poor nutrition and hydration (cramping, fatigue, energy
          depletion)✓✓O
                                     OR
          Mental challenges (anxiety)✓✓O
                                     OR
          Medical issues (fainting)✓✓O
                                     OR
          Environmental issues (weather conditions, excessive
          heat or cold)✓✓O
                                     OR
          Equipment issues (inappropriate footwear or gear)✓✓O

                                                                                          (2)
                                                                                         [28]

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### Page 5

Mathematical Literacy/P2                        5                                NW/June 2024
                                   Grade 12 – Marking Guideline

QUESTION 3 [32 MARKS]
Ques Solution                                                         Explanation              T/L
3.1.1 Perimeter is the total length around a shape or object.✓✓A      2A answer                M
                                    OR                                                     (2) L1
      Perimeter is the total length of the boundary of a shape or
      object.✓✓A
3.1.2 Area = 2(l × b) + 2(b × h) + (l × h)                                                         M
               ✓SF                    ✓SF                             1SF substitution             L2
      = 2(0,4 m × 0,29 m) + 2(0,29 m × 0,54 m) +                      1SF substitution
      (0,4 m × 0,54 m)✓SF                                             1SF substitution
      = 0,232 m2 + 0,3132 m2 + 0,216 m2 ✓S                            1S simplification
      = 0,7612 m2 ✓CA                                                 1CA answer
                                                                                           (5)
3.1.3                                                                 CA from Q3.1.2          M
         Double coats = 0,7612 m2 × 2✓MCA                             1MCA multiplication L4
                      = 1,5224 m2 ✓CA                                 1CA answer
                                                                      1MCA multiplication
         Amount of paint = 1,5224 × 0,8 litres✓MCA                    by rate
                          = 1,21792 litres ✓CA                        1CA answer
         ⸫ Correct ✓O                                                 1O opinion
                                    OR                                         OR
         Amount of paint = 0,7612 m2 × 0,8 litres/m2✓MCA              1MCA multiplication
                          = 0,60896 ✓CA                               by rate
         Double coats = 0,60896 × 2✓MCA                               1CA answer
                      = 1,21792 litres ✓CA                            1MCA multiplication
                                                                      1CA answer
         ⸫ Correct ✓O                                                 1O opinion
                                                                                          (5)
3.1.4    Total length                                                                         M
         = perimeter of front edges + the inner length of one shelf   1SF substitution of     L4
                 ✓SF                      ✓M                          front edges
         = 2(0,4 m + 0,54 m) + 0,4 m – 2 × 0,02 m                     1M subtracting 2 ×
         = 1,88 m + 0,4 – 0,04 m                                      0,02 m
         = 1,88 m + 0,36 m✓S                                          1S simplification
         = 2,24 m✓CA                                                  1CA answer
         ⸫ Not valid✓O                                                1O opinion
                                                                                          (5)
3.2.1    Mass = 149 × 0,454 kg✓C                                      1C conversion           M
              = 67, 646 kg✓A                                          1A answer               L2
             ≈ 68 kg✓R                                                1R rounding
                                                                                          (3)

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### Page 6

Mathematical Literacy/P2                            6                           NW/June 2024
                                       Grade 12 – Marking Guideline

3.2.2                  mass in kg                                     CA from Q3.2.1               M
          BMI =
                     (height in m)2                                   1SF substitution             L2
                      68 kg
               =                 ✓SF
                     (1,52 m)2                                        1CA answer
               = 29,4 kg/m2 ✓CA                                                              (2)
3.2.3                                                                 CA from Q3.2.2               M
          Overweight ✓✓O                                              2O opinion                   L4
                                                                                             (2)
3.3.1                   ✓RT                                           1RT correct values           M
          Dose = 40 mg × 60✓MA                                        1MA multiplication           L2
               = 2 400 mg                                                                    (2)
3.3.2                                                                 CA from Q3.3.1               M
                         2 400×5                                      1MCA multiplication          L2
          Volume =                 ml✓MCA
                           400                                        and division
                      = 30 ml✓CA                                      1CA answer
                                                                                             (2)
3.3.3     ℉ = (℃ × 1,8) + 32°                                                                      M
          70° = (°C × 1,8) + 32°✓SF                                   1SF substitution             L3
          ℃ = (70°- 32°) ÷ 1,8✓M                                      1M changing subject
          °C = 21, 111°✓A                                             1A answer
          °C = 20°✓R                                                  1R rounding
                                                                                             (4)
                                                                                            [32]

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### Page 7

Mathematical Literacy/P2                       7                                  NW/June 2024
                                  Grade 12 – Marking Guideline

QUESTION 4 [20 MARKS]
Ques Solution                                                       Explanation                    T/L
4.1  The theatre has seats allocated for people using               2O explanation                 MP
     wheelchairs.✓✓O                                                                               L4
                                  OR
     Disabled people are also welcome in the theatre.✓✓O

         Accept any relevant explanation.                                                  (2)
4.2      To be entertained.✓✓O                                      2O reason                      MP
                                     OR                                                            L4
         For education/religion /social purposes. ✓✓ O
                                     OR
         To relax.✓✓O
                                     OR
         To while away time.✓✓O
                                     OR
         To take away their minds from worries.✓✓O
                                     OR
         To watch a play.✓✓O
                                     OR
         To distress.✓✓O

         Accept any relevant reason.                                                       (2)
4.3                        5✓A                                      1A numerator                   P
         Probability =
                           26✓A                                     1A denominator                 L3
                     = 0,1923…
                       = 0,2✓R                                      1R rounding

                                                                                           (3)
4.4                                   ✓A                            1A easterly                    MP
         Move to the aisle and walk Easterly along the aisle        1A north                       L2
                ✓A ✓A                         ✓A                    1A G7
         Turn North at G7. Walk in the North direction until you    1A North
         reach G17.
                                    OR                              OR
                                      ✓A                            1A east
         Move to the aisle and walk East passing rows K, J and H.   1A north
                ✓A ✓A                 ✓A                            1A G7
         Turn North at G7 then walk straight until you reach G17.   1A straight

                                    OR                              OR
                         ✓A                ✓A ✓A
         Move in the north direction, turn east at L18 then move    1A north
         ✓A                                                         1A east
         easterly until you reach G17.                              1A L18
                                                                    1A easterly
         Accept left, right and down.                                                      (4)

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### Page 8

Mathematical Literacy/P2                        8                                      NW/June 2024
                                         Grade 12 – Marking Guideline

4.5     85 minutes = 1 hour 25 minutes✓A                                1A time in hours and              M
        End time = 15:15 + 1:25✓M                                       minutes                           L2
                = 16:40✓A                                               1M addition
                                  OR                                    1A exact time
        End time = 15:15 + 85 minutes✓M                                            OR
                    ✓A                                                  1M addition
                 = 16:40✓A                                              1A hours
                                                                        1A minutes
                                 OR                                                OR
        End time = 15:15 + 45 minutes + 40 minutes✓M                    1M addition
                    ✓A                                                  1A hours
                 = 16:40✓A                                              1A minutes
                                                                                                   (3)
4.6                                          ✓MA                        1MA 12 × 21ˊˊ                     M
        Total length = 2 × 20ˊˊ + 1× 22ˊˊ + 12 × 21ˊˊ✓M                 1M addition                       L3
                     = 40ˊˊ + 22ˊˊ + 252ˊˊ
                     = 314ˊˊ✓S                                          1S simplification
                           314
                       =           cm
                           0,394
                       = 796,9543147 cm✓C                               1C conversion to cm
                           796,9543147
                       =
                                 100                                    1C conversion to m
                    = 7,96… m✓C
                                                                        1R rounding
                    = 8 m✓R
                                                                                   OR
                                OR
                                                                        1C conversion to cm
                             ✓C
        20ˊˊ = 50,7614 … cm:
                                                                        1M addition
        22ˊˊ = 55,837… cm:
                                                                        1MA 12 × 53,2999…. cm
        21ˊˊ = 53,2999…. cm
                                                                        1S simplification
        Total length
                            ✓M                  ✓MA
                                                                        1C conversion to m
        = 2 × 50,76 … cm + 1× 55,83… cm + 12 × 53,29…cm
                                                                        1R rounding
        = 101,52222…cm + 55,837….cm + 639,59…cm
        = 796,9543858 cm✓S
            796,9543858
        =
                100
        = 7,96… m✓C
        = 8 m✓R

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### Page 9

Mathematical Literacy/P2                     9                                       NW/June 2024
                                      Grade 12 – Marking Guideline

4.6     OR                                                            OR                             M
                                 ✓C                                                                  L3
        20ˊˊ = 50,7614 … cm:                                         1C conversion to cm
        22ˊˊ = 55,837… cm:
        21ˊˊ = 53,2999…. cm:                                         1C conversion to m
                           ✓C
        50,7614 … cm = 0,507614 … m
        55,837… cm = 0,55837… m
        53,2999…. cm = 0,532999…. m

        Total length                                                 1MA 12 × 0,532999…. M
                                         ✓MA                         1M addition
        = 2 × 0,50 … m + 1× 0,55… m + 12 × 0,53…. m ✓M
        = 1,0152222…m + 0,55837….m + 6,3959…m                        1S simplification
        = 7,969543858 cm✓S                                           1R rounding
        = 8 m✓R                                                                              (6)
                                                                                           [20]
                                                                                     TOTAL: 100

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