# Mathematical Literacy Grade 12 P1 NSC June 2024 Memo (Afr) > Grade 12 Mathematical Literacy Paper 1 memorandum from the NSC June Exam 2024 (Afrikaans), 19 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/grade-12-mathematical-literacy-2024-nsc-june-exam-memorandum-paper-1-afrikaans/81e7ae91-bdaf-4338-9e6a-d677332e641e - Updated: 2026-09-28 - Subject: Mathematical Literacy - Grade: Grade 12 - Language: Afrikaans - Document type: Memorandum - Year: 2024 - Exam period: NSC June Exam - Paper: 1 - Curriculum: CAPS - Pages: 19 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Mathematical Literacy](https://www.hlayiso.com/library/grade-12/mathematical-literacy) › [Mathematical Literacy Grade 12 P1 NSC June 2024 Memo (Afr)](https://www.hlayiso.com/library/grade-12-mathematical-literacy-2024-nsc-june-exam-memorandum-paper-1-afrikaans/81e7ae91-bdaf-4338-9e6a-d677332e641e) ## About this document Mathematical Literacy · Grade 12 · NSC June Exam · 2024 · Afrikaans. Memorandum, 19 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 SENIOR CERTIFICATE EXAMINATIONS/ NATIONAL SENIOR CERTIFICATE EXAMINATIONS SENIORSERTIFIKAAT-EKSAMEN/ NASIONALE SENIORSERTIFIKAAT-EKSAMEN MATHEMATICAL LITERACY P1/ WISKUNDIGE GELETTERDHEID V1 MAY/JUNE/MEI/JUNIE 2024 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 Symbol/Kode Explanation/Verduideliking MA Method with accuracy/Metode met akkuraatheid CA Consistent accuracy/Volgehoue akkuraatheid A Accuracy/Akkuraatheid C Conversion/Herleiding S Simplification/Vereenvoudiging RT Reading from a table/graph/document/diagram/Lees vanaf tabel/grafiek/dokument/diagram SF Correct substitution in a formula/Korrekte vervanging in 'n formule O Opinion/Explanation/Opinie/Verduideliking P Penalty, e.g. for no units, incorrect rounding off, etc./Penalisasie, bv. vir geen eenhede, verkeerde afronding, ens. R Rounding off/Afronding NPR No penalty for rounding/Geen penalisasie vir afronding nie NPU No penalty for omitting correct unit/Geen penalisasie vir die uitlos van die korrekte eenheid nie. AO Answer only/Slegs antwoord MCA Method with consistent accuracy/Metode met volgehoue akkuraatheid RCA Rounding consistent with accuracy/ Afronding met volgehoue akkuraatheid These marking guidelines consist of 19 pages. Hierdie nasienriglyne bestaan uit 19 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 2 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 2 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however it stops at the second calculation error or break-down. • If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra item presented. • Rounding is an independent mark. • General principle of marking, if the candidate makes one mistake one mark is deducted. • A conclusion mark can only be given if relevant calculations precedes it (at least 1 mark before conclusion). • No penalty for rounding (NPR) if the first decimal is correct, except questions involving money. LET WEL: • As 'n kandidaat 'n vraag TWEE KEER beantwoord, sien slegs die EERSTE poging na. • As 'n kandidaat 'n antwoord van 'n vraag doodtrek (kanselleer) en nie oordoen nie, sien die doodgetrekte (gekanselleerde) poging na. • Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas; dit hou egter op by die tweede berekeningsfout of ‘break-down’. • Wanneer 'n kandidaat aflesings vanaf 'n grafiek, tabel, uitlegplan en kaart geneem en ekstra antwoorde gee, penaliseer vir elke ekstra item. • Afronding tel as 'n afsonderlike punt. • Die algemene beginsel van merk as 'n leerder een fout maak, word een punt afgetrek. • 'n Gevolgtrekkingspunt kan slegs gegee word indien relevante berekeninge dit voorgaan (ten minste een punt voor die gevolgtrekking). • Geen penalisering vir ronding (NPR) as die eerste desimaal korrek is nie, behalwe as vrae geld insluit. QUESTION/VRAAG 1 [32 MARKS/PUNTE] ANSWER ONLY FULL MARKS Q/V Solution/Oplossing Explanation/Verduideliking T&L D 1.1.1 Kenya / Kenia ✓✓A 2A correct country L1 (2) E D 1.1.2 Zambia / Zambië ✓✓A 2A first correct country L1 Malawi / Malawi ✓A 1A second correct country E (3) D 1.1.3 Malawi / Malawi ✓✓A 2A correct country L1 (2) M * D 1.1.4 People for Studying Purposes / Mense vir Studiedoeleindes 1RT correct values L1 ✓RT 1MA adding four correct M = 83 + 98 + 475 + 83 ✓MA values = 739 tourists ✓A 1A simplification (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 3 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 3 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 1.2.1 Price of 1 teabag / Prys van 1 teesakkie L1 E = R50,00 ÷ 40 ✓MA 1MA R50 divided by 40 = R1,25 ✓A 1A simplification OR / OF OR / OF ✓A = R1,25 × 40 ✓MA 1A R1,25 = R50 1MA R1,25 multiplied by 40 (2) * ✓RT F 1.2.2 185 : 100 ✓MA 1RT correct values L1 1MA values in correct order M 37 : 20 OR / OF 1 : 0,54 OR / OF 1,85 : 1 ✓A 1A simplification (3) F 1.2.3 Total of purchase / Totaal van aankope L1 ✓RT 1RT correct values E = R185,00 + R100,00 + R16,00 ✓MA 1MA adding 3 correct values = R301,00 ✓A 1A simplification (3) * F 1.3.1 Namibia / Namibië ✓✓A 2A correct country L1 (2) E * F 1.3.2 Zambian Kwacha ✓✓A L1 E OR / OF 2A correct currency Zambia / ZMW ✓✓A (2) F 1.3.3 1 ✓MA 1MA dividing correct values L1 Malawian Kwacha = 1RT reading correct value E 56, 211355 ✓RT = 0,017790 OR / OF OR / OF 1MA dividing correct values 1 ✓MA Malawian Kwacha = 0, 017790 1RT calculating correct = 56,211355 ✓RT value NPR (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 4 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 4 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L D 1.4.1 One million one hundred and five thousand six hundred and L1 eighty five / Een miljoen een honderd en vyf duisend ses E honderd vyf en tagtig. ✓✓A 2A answer in words (2) D 1.4.2 P = 131 693 + 254 139 ✓MA L1 E = 385 832 ✓A OR / OF 1MA adding correct values P = 64 943 + 66 694 + 56 +136 510 + 114 436 + 3 193 ✓MA 1A simplification = 385 832 ✓A (2) * D 1.4.3 Increase / Verhoging L1 E = 359 686 – 131 693 ✓MA 1MA subtracting correct values = 227 993 ✓A 1A simplification (2) ✓A ✓A 1A correct month D 1.4.4 February / Februarie 2022 OR / OF Feb '22 OR / OF 1A correct year L1 02/2022 (2) E [32] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 5 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 5 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 2 [31 MARKS/PUNTE] NPU FOR QUESTION 2.2 Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.1.1 R2 000,00 ✓✓A 2A correct amount L1 Accept (– R2 000,00) E NPU (2) * F 2.1.2 For security reasons / Vir veiligheidsredes ✓✓A 2A reason L4 (2) E 1RT 2 correct values F 2.1.3 Available money / Geld beskikbaar 1MA adding correct values L2 ✓MA ✓RT 1MA subtracting from M =R20 000 – (R5 656,22 + R6 020,00) ✓MA R20 000 = R20 000 – R11 676,22 = R8 323,78 OR / OF OR / OF 1RT 2 correct values ✓MA ✓RT 1MA subtracting correct = R20 000 – R5 656,22 – R6 020,00 ✓MA values = R8 323,78 1MA subtracting from R20 000 OR / OF OR / OF ✓MA ✓RT 1RT 2 correct values = R5 656,22 + R6 020,00 + R8 323,78 1MA adding correct values = R20 000 ✓MA 1MA getting to R20 000 (3) * F 2.1.4 Price per litre / Prys per liter L2 ✓RT 1RT correct rand value M R1 376,15 = ✓MA 1MA dividing by litres 54,1365 litres = R25,42 ✓CA 1CA simplification OR / OF OR / OF ✓MA = R25,42/ℓ × 54,1365 ℓ ✓RT 1RT correct rand value 1MA multiplying = R1 376,15 ✓CA 1CA simplification AO (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 6 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 6 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.1.5 100% – 17,5% = 82,5% ✓MA 1MA calculate discounted L2 percentage D Original price / Oorspronklike prys 1RT correct value 100 ✓RT 1MA percentage calculation =  R3 299,99 ✓MA 82,5 = R3 999,99 ✓CA 1CA simplification OR / OF OR / OF ✓MA 1MA calculate discounted 100% – 17,5% = 82,5% = 0,825 percentage ✓RT 1RT correct value R3 299,99 1MA divide by 0,825 = ✓MA 0,825 = R3 999,99 ✓CA 1CA simplification NPR (4) F 2.2.1 Bar sales and Functions / Kroegverkope en Funksies ✓✓RT 2RT correct item L1 Accept: Bar sales E (2) F 2.2.2 Projected amount / Geprojekteerde bedrag L2 D 47 49 1MA concept of ratio = ✓MA 23 500 B 1RT 23 500 ✓RT 1MA divide by 47 B = 1 151 500  47 ✓MA = 24 500 ✓CA 1CA simplification OR / OF OR / OF 47 49 : ✓MA 1MA concept of ratio 23 500 B ✓RT 1RT 23 500 23 500 B= × 49 47 ✓MA 1MA divide by 47 = 500 × 49 = R24 500 ✓CA 1CA simplification OR / OF OR / OF Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 7 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 7 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L 2.2.2 Total ratio / Totale verhouding = 47 + 49 = 96 ✓RT 96 1RT 23 500 Total Income / Totale Inkomste = 23500 × 47 ✓MA 1MA concept of ratio = 48 000 1MA subtracting values B = 48 000 – 23 500 ✓MA 1CA simplification = 24 500 ✓CA (4) F 2.2.3 Difference in income / Verskil in inkomste L3 ✓RT 1RT correct values M = £(455 869 – 396 453) 1CA difference = £59 416 ✓CA 1MA % calculation 59 416 1MA correct denominator % change / verandering = 100%✓MA 396 453 ✓MA ✓CA = 14,9868… % = 14,99 OR 15% 1CA simplification OR / OF OR / OF % change / verandering new price/new prys - old price/ou prys = × 100% 1RT correct values old price/ ou prys 1MA % calculation ✓RT 1MA correct denominator 455 869 - 396 453 = 100% ✓MA 396 453 ✓MA 1CA correct difference ✓CA 59 416 1CA simplification = 100 396 453 = 14,9868 ... %= 14,99% OR/OF 15% ✓CA OR / OF OR / OF Current percentage / Huidige persentasie 1RT correct values ✓RT 1MA % calculation 455 869 =  100% ✓MA 396 453 1A correct percentage = 114,9937067% ✓A Difference in % income / Verskil in % inkomste 1MCA correct difference = 114,9937067% – 100% ✓MCA 1CA simplification = 14,99% OR/OF 15% ✓CA (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 8 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 8 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.2.4 Year 1's inflation / Jaar 1 se inflasie: L4 1RT correct value D ✓RT 1,82 = × £257 460 100 = £4 685,772 After year 1's inflation / Na jaar 1 se inflasie: = £257 460 + £4 685,772 ✓MCA 1MCA adding correct values = £262 145,77 ✓CA 1CA simplification Year 2's inflation / Jaar 2 se inflasie: 2 = × £262 145,77 100 = £5 242£,9154 After year 2's inflation / Na jaar 2 se inflasie: = £262 145,77 + £5 242£,9154 = £267 388,69 ✓CA 1CA amount year 2 Difference / Verskil = £284 000 – £267 388,69 ✓MCA 1MCA subtracting values = £16 611,31 His statement is VALID / Sy bewering is GELDIG. ✓O 1O conclusion OR / OF OR / OF Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 9 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 9 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L 2.2.4 After year 1's inflation / Na jaar 1 se inflasie: ✓MA ✓RT = × 1,0182 101,82 1RT correct value  £257 460 1MA percentage increase 100 = £262 145,77 ✓CA 1CA simplification After year 2's inflation / Na jaar 2 se inflasie: 102  £262 145,77 100 = £267 388,69 ✓CA 1CA amount year 2 Difference / Verskil = £284 000 – £267 388,69 ✓MCA 1MCA subtracting values = £16 611,31 His statement is VALID / Sy bewering is GELDIG. ✓O 1O conclusion (6) [31] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 10 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 10 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 3 [30 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L D 3.1.1 29 ✓✓A 2A correct number L1 (2) E D 3.1.2 30 ✓✓A 2A mode L2 (2) E ✓RT D 3.1.3 3 1RT correct fraction L2 D = × 40 ✓MA 1MA multiplying with 40 M 5 = 24 periods ✓CA 1CA simplification OR / OF OR / OF 3 + D + 26 + 30 + 32 ... 33 = 29 933 + D 33 = ✓RT 1RT correct fraction 29 33 × 29 = 933 + D ✓MA 1MA changing the subject of the formula D = 957 – 933 D = 24 ✓CA 1CA simplification OR / OF OR / OF ✓RT D = 0,6 × 40 ✓MA 1RT correct fraction 1MA multiplying with 40 D = 24 periods ✓CA 1CA simplification AO (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 11 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 11 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L D 3.1.4 Median / Mediaan = 35 ✓✓A 2A median L4 E The median has half the staff above and half the staff below. ✓O Die mediaan toon die helfte van die personeel bo en helfte van die personeel onder. OR / OF The outliers affect the calculation of the mean, hence it is not a reliable average. Die uitskieters affekteer die berekenining van die gemiddels, daarom is dit nie 'n betroubare punt nie. ✓O 1O reason OR / OF More than 58,62% of staff has 35 periods or more. ✓O Meer as 58,62% van die personeel het 35 periodes of meer. (3) P 3.1.5 Probability / Waarskynlikheid L2 E 16 ✓A 1A numerator = 21 ✓A 1A denominator (2) * D 3.2.1 Scatter plot / Spreidingsdiagram ✓✓A 2A correct graph L1 (a) (2) E D 3.2.1 Range / Omvang L2 (b) ✓RT ✓RT 1RT highest E = 81 − 15 1RT lowest = 66 ✓CA 1CA simplification AO (3) * D 3.2.1 Learner / Leerder H ✓✓A 2A correct learner L4 (c) D The marks for both Task 1 and Task 2 are much lower compared to the other learners / Beide Taak 1 en Taak 2 se punte is heelwat laer in vergelyking met die ander leerders. ✓✓O 2O correct reason The learner failed while all the other learners passed / Die leerder het gedruip terwyl al die ander leerders geslaag het. (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 12 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 12 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L D 3.2.2 53 + 69 + 53 + 49 + 50 + 47 + 61 + 15 + 47 + 81 ✓MA 1MA correct concept of mean L4 Mean = M 10 525 ✓CA 1CA correct adding of values = 10 = 52,5 ✓CA 1CA mean Difference / Verskil = 66,7 – 52,5 = 14,2 ✓CA 1CA simplification 1O conclusion VALID / GELDIG ✓O (5) * D 3.2.3 90 L2 M 80 70 ✓A A 60 L 50 Task 2 40 ✓A A K 30 20 10 0 0 20 40 60 80 100 Task 1 2A first point plotted (68;40) 2A second point plotted (88;64) (4) [30] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 13 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 13 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 4 [26 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L * F 4.1.1 Total cost before discount /Totale koste voor afslag L3 ✓MA ✓MA 1MA multiply correct values M = (R149,95  16,7) + (R99,99  13) 1MA multiply correct values = R2 504,165 + R1 299,87 ✓MCA 1MCA adding cost = R3 804,04 ✓CA 1CA simplification Discount amount / Afslag bedrag 15 =  R3 804,04 ✓MCA 1MCA calculating 15% 100 = R570,61 ✓CA 1CA simplification Total amount /Totale koste 85 = R3 804,04 – R570,61 =  R3 804,04 = R3 233,43 ✓CA 100 1CA simplification OR / OF OR / OF Discounted chops / Afslag tjops ✓MA ✓MCA 85 1MA multiply correct values = R149,95  16,7  = R2 128,54 ✓CA 1MCA calculating 85% 100 1CA simplification Discounted boerewors / Afslag boerewors ✓MA ✓MCA 85 1MA multiply correct values = R 99,99  13  = R1 104,89 ✓CA 1MCA calculating 85% 100 1CA simplification Total amount / Totale bedrag = R2 128,54 + R1 104,89 = R3 233,43 ✓CA 1CA simplification OR / OF OR / OF Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 14 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 14 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L * 4.1.1 Total cost before discount /Totale koste voor afslag ✓MA ✓MA 1MA multiply correct values = (R149,95  16,7) + (R99,99  13) 1MA multiply correct values = R2 504,165 + R1 299,87 ✓MCA 1MCA adding cost = R3 804,04 ✓CA 1CA simplification Total amount /Totale koste ✓MCA 1MCA calculating 15% = R3 804 ,04 – (15% × R3 804,04) = R3 804,04 – R570,606 ✓MCA 1MCA subtracting correct values = R3 233, 43 ✓CA 1CA simplification (7) CA from Question 4.1.1 F 4.1.2 Total cost / Totale koste 1MCA adding value from L2 ✓MCA Q 4.1.1 M = R3 233,43 + R850 ✓A 1A adding R850 = R4 083,43 Cost of 1 plate / Koste vir 1 bord = R4 083,43  200 ✓MCA 1MCA correct value  200 = R20,42 ✓CA 1CA simplification Accept: R20,40 OR / OF OR / OF Cost of meat for 1 plate / Koste van vleis vir 1 bord ✓MCA 1MCA dividing value from R3 233,43 Q 4.1.1 = 200 ✓MCA 1MCA correct value  200 = R16,16715 Cost of salad, relish etc for 1 plate / Koste van slaai, sous ens vir een bord R850 = 200 = R4,25 ✓A 1A R4,25 Total cost / Totale koste = R16,16715 + R4,25 = R20,42 ✓CA 1CA simplification Accept: R20,40 (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 15 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 15 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L CA from Question 4.1.2 F 4.1.3 Profit per plate / Wins per bord L3 D = R35,00 – R20,42 ✓MA 1MA subtracting values = R14,58 ✓CA 1CA simplification Number of plates / Getal borde = R2 850,00 ÷ R14,58 ✓MCA 1MCA dividing by profit = 195,47 ✓CA 1CA simplification Total number of plates / Totale getal borde = 200 + 195,47 = 395,47 ✓CA 1CA total number of plates = 400 ✓R 1R correct rounding OR / OF OR / OF Profit per plate / Wins per bord ✓MA (200  R35) − R4 083, 43 1MA subtracting values = 200 R2916,57 = 200 = R14,58 ✓CA 1CA simplification Number of plates / Aantal borde R2 850 = ✓MCA R14,58 1MCA dividing by profit =195,47 ✓CA 1CA simplification Total number of plates / Totale aantal borde = 200 + 195,47 = 395,47 ✓CA 1CA total number of plates = 400 ✓R 1R correct rounding (6) P 4.2.1 15% ✓✓RT 2RT correct value L1 Accept: 14,5 – 15,2 E (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 16 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 16 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L * P 4.2.2 Probability / Waarskynlikheid L2 M 4 052 572 ✓A 1A numerator = 43 378 959 ✓A 1A denominator = 0,0934… ✓CA 1CA simplification = 0,093 OR 9,342% ✓R 1R rounding (4) D 4.2.3 25 – 34 age group / ouderdomsgroep ✓✓A 2A correct group L4 M The largest population is in this group / Die grootste bevolking is in die groep. ✓O 1O reason (3) [26] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 17 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 17 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 5 [31 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L * F 5.1.1 2 / TWO / TWEE ✓✓A 2A number of rebates L1 (2) E CA from Question 5.1.1 F 5.1.2 Tax before rebates / Belasting voor kortings L3 ✓RT 1RT correct bracket M 251 258 + 41% of taxable income above 857 900 ✓SF = R251 258 + 41% (R981 500 − R857 900) 1SF substitute R981 500 = R251 258 + 41% (R123 600) = R251 258 + R50 676 = R301 934 ✓CA 1CA amount before rebates Tax after rebates / Belasting na kortings = R301 934 − R17 235 − R9 444 ✓MCA 1MCA subtracting rebates = R275 255 ✓CA 1CA simplification Monthly Tax / Maandelikse belasting R275 255 = 12 ✓MCA 1MCA dividing by 12 = R22 937,92 ✓CA 1CA simplification (7) F 5.2.1 Interest rate is the percentage of the total value you have to L1 pay extra for taking the loan. E Rentekoers is die persentasie van die totale waarde wat jy ekstra moet betaal vir die uitneem van die lening. OR / OF ✓✓A 2A correct definition Interest rate is a percentage charged on the loan taken to buy a motor vehicle / Rentekoers is 'n persentasie gehef op die lening uitgeneem om die voertuig te koop. (2) F 5.2.2 Difference / Verskil L1 E = R6 115,47 – R5 498,19 ✓MA 1MA subtracting correct values = R617,28 ✓CA 1CA simplification AO (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 18 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 18 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L ✓SF 1SF substitution in bracket F 5.2.3 X = (R6 115,47 × 6 × 12) – R300 000 ✓A 1A subtracting R300 000 L2 E = R440 313,84 – R300 000 = R140 313,84 ✓CA 1CA simplification AO (3) * CA from Question 5.2.3 – F 5.2.4 Balloon payment / Ballonpaaiement R334 000 only L3 ✓RT 1RT correct values M = 20% × R300 000 1A simplification = R60 000 ✓A ✓MA 1MA correct value × 72 Y = (R5 498,19 × 72) + R60 000 ✓MCA 1MCA adding balloon payment = R455 869,68 ✓CA 1CA simplification (5) * F 5.2.5 The vehicle serves as security for the loan / L4 ✓✓O 2O reason Die voertuig dien as sekuriteit vir die lening. E (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 19 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 19 DBE/May/June/Mei/Junie 2024 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L D 5.3.1 24 ✓✓RT 2RT correct answer L2 NPU E (2) CA from Question 5.3.1 D 5.3.2 Interquartile Range / Interkwartielomvang L4 D Electrical / Elektries 1RT using correct values ✓RT (28,8 – 29,2) = 29% − 24% ✓MA 1MA concept of IQR = 5% ✓CA 1CA simplification(4,8 – 5,2) Plug-in hybrid / Inprophibried = 24% − 6% = 18% ✓CA 1CA simplification Quarter of Plug-in / Kwart van 'n inprop 1 ✓CA 1CA simplification =  18% = 4,5% ≠ 5% OR 4 Electric × 4 = 5% × 4 = 20% ≠ 18% OR / OF 5 1 1 = = ≠ ✓CA 18 3,6 4 OR / OF 5 =  100 = 27,8% ✓CA 18 INVALID / NIE GELDIG NIE ✓O 1O conclusion (6) [31] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou ## Related documents - [MATH LITERACY P1 GR12 QP SEPT2024 Afrikaans](https://www.hlayiso.com/library/math-literacy-p1-gr12-qp-sept2024-afrikaans/8324352d-0dfe-4f56-a690-09b4668305c9) — Mathematical Literacy · QP · 2024 · Afr - [Gr 12 Mathematical Literacy P1 (Afrikaans) June 2024 Question Paper](https://www.hlayiso.com/library/gr-12-mathematical-literacy-p1-afrikaans-june-2024-question-paper/862f41ea-86b5-468a-bac9-0f1c76be2e36) — Mathematical Literacy · QP · 2024 · Afr - [MATHS LIT P1 GR12 MEMO SEPT 2019 Afrikaans](https://www.hlayiso.com/library/maths-lit-p1-gr12-memo-sept-2019-afrikaans/425d97d9-9130-46cd-b01a-5c5a5983d22d) — Mathematical Literacy · Memo · 2019 · Afr - [Mathematical Literacy P1 June July 2015 Memo Eng](https://www.hlayiso.com/library/mathematical-literacy-p1-june-july-2015-memo-eng/8011ca4f-6eaa-424d-b4c0-3031bced554a) — Mathematical Literacy · Memo · 2015 · Eng - [MATHS LIT P1 GR12 QP JUNE 2023 Afrikaans](https://www.hlayiso.com/library/maths-lit-p1-gr12-qp-june-2023-afrikaans/2d599711-ccd3-42d3-862f-4c1b72b92e44) — Mathematical Literacy · QP · 2023 · Afr - [MATHS LIT P1 GR12 ADDENDUM SEPT 2021 Afrikaans](https://www.hlayiso.com/library/maths-lit-p1-gr12-addendum-sept-2021-afrikaans/bb93ab59-ebbf-4bfc-94fd-43fb313fe26a) — Mathematical Literacy · Addendum · 2021 · Afr ## More from Grade 12 Mathematical Literacy - [MATHS LIT P2 GR 12 SEPT 2025 ADDENDUM AFR watermark](https://www.hlayiso.com/library/maths-lit-p2-gr-12-sept-2025-addendum-afr-watermark/813c6e54-f134-474a-b01a-1260e38b4c8f) — Addendum · 2025 · Afr - [Maths LIT Grade 12 NSC P1 QP September 2025 Free State](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-qp-september-2025-free-state/45f0ab2a-afdd-46df-bf98-5505c4021e64) — QP · 2025 - [Maths LIT Grade 12 NSC P1 ANSWER BOOK September 2025 KZN](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-answer-book-september-2025-kzn/b0b358eb-c897-437a-8694-910fe61dfcbc) — Addendum · 2025 - [Maths LIT Grade 12 NSC P1 QP September 2025 Limpopo](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p1-qp-september-2025-limpopo/c5d7a167-2d27-4e33-80ef-fad9cde4ebd2) — QP · 2025 - [Maths LIT Grade 12 NSC P2 QP September 2025 Limpopo](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p2-qp-september-2025-limpopo/f22349c1-8dbf-420e-ae8d-13d53bcb300b) — QP · 2025 - [Maths LIT Grade 12 NSC P2 QP September 2025 North West](https://www.hlayiso.com/library/maths-lit-grade-12-nsc-p2-qp-september-2025-north-west/7ce5b7fe-941b-4148-80dc-d9cde7bdbfd7) — QP · 2025 ## Collection - [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. 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