# Mathematical Literacy Grade 12 P1 NSC November 2025 Memo > Grade 12 Mathematical Literacy Paper 1 memorandum from the NSC November Exam 2025 (Afrikaans), 23 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/grade-12-mathematical-literacy-2025-nsc-november-exam-memorandum-paper-1-afrikaans/50f6c58e-9617-47b9-85d2-1f697b021b7f - Updated: 2026-09-28 - Subject: Mathematical Literacy - Grade: Grade 12 - Language: Afrikaans - Document type: Memorandum - Year: 2025 - Exam period: NSC November Exam - Paper: 1 - Curriculum: CAPS - Pages: 23 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Mathematical Literacy](https://www.hlayiso.com/library/grade-12/mathematical-literacy) › [Mathematical Literacy Grade 12 P1 NSC November 2025 Memo](https://www.hlayiso.com/library/grade-12-mathematical-literacy-2025-nsc-november-exam-memorandum-paper-1-afrikaans/50f6c58e-9617-47b9-85d2-1f697b021b7f) ## About this document Mathematical Literacy · Grade 12 · NSC November Exam · 2025 · Afrikaans. Memorandum, 23 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12 MATHEMATICAL LITERACY P1 / WISKUNDIGE GELETTERDHEID V1 NOVEMBER 2025 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 Symbol/Kode Explanation/Verduideliking MA Method with accuracy/Metode met akkuraatheid CA Consistent accuracy/Volgehoue akkuraatheid A Accuracy/Akkuraatheid C Conversion/Herleiding S Simplification/Vereenvoudiging RT Reading from a table/graph/document/diagram/Lees vanaf tabel/grafiek/dokument/diagram SF Correct substitution in a formula/Korrekte vervanging in 'n formule O Opinion/Explanation/Opinie/Verduideliking P Penalty, e.g. for no units, incorrect rounding off, etc./Penalisasie, bv. vir geen eenhede, verkeerde afronding, ens. R Rounding off/Afronding NPR No penalty for rounding/Geen penalisasie vir afronding nie NPU No penalty for omitting correct unit/Geen penalisasie vir die uitlos van die korrekte eenheid nie. AO Answer only/Slegs antwoord MCA Method with consistent accuracy/Metode met volgehoue akkuraatheid RCA Rounding consistent with accuracy/Afronding met volgehoue akkuraatheid These marking guidelines consist of 23 pages. Hierdie nasienriglyne bestaan uit 23 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 2 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 2 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however it stops at the second calculation error or break-down. • If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra item presented. • Rounding is an independent mark. • General principle of marking, if the candidate makes one mistake one mark is deducted. • A conclusion mark can only be given if relevant calculations precedes it (at least a 1 of the mark 3 before conclusion). • No penalty for rounding (NPR) if the first decimal is correct, except questions involving money. LET WEL: • As 'n kandidaat 'n vraag TWEE KEER beantwoord, sien slegs die EERSTE poging na. • As 'n kandidaat 'n antwoord van 'n vraag doodtrek (kanselleer) en nie oordoen nie, sien die doodgetrekte (gekanselleerde) poging na. • Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas; dit hou egter op by die tweede berekeningsfout of 'break-down'. • Wanneer 'n kandidaat aflesings vanaf 'n grafiek, tabel, uitlegplan en kaart neem en ekstra antwoorde gee, penaliseer vir elke ekstra item. • Afronding tel as 'n afsonderlike punt. • Die algemene beginsel van merk as 'n leerder een fout maak, word een punt afgetrek. • 'n Gevolgtrekkingspunt kan slegs gegee word indien relevante berekeninge dit voorgaan (ten minste 'n 1 van die punt voor die gevolgtrekking). 3 • Geen penalisering vir ronding (NPR) as die eerste desimaal korrek is nie, behalwe as vrae geld insluit. QUESTION/VRAAG 1 [30 MARKS/PUNTE] ANSWER ONLY FULL MARKS Q/V Solution/Oplossing Explanation/Verduideliking T&L F 1.1.1 Cape Town / Kaapstad ✓✓RT 2RT correct city L1 (2) E F 1.1.2 Cost per kilogram / Koste per kilogram L1 ✓RT 1RT R41,41 E = R41,41 ÷ 5 1A simplification = R8,282 OR R8,28 ✓A OR / OF OR / OF 5kg : R41,41 1kg : ? 1 = × R41,41 ✓RT 1RT R41,41 5 = R8,282 OR R8,28 ✓A 1A simplification (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 3 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 3 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 1.1.3 Ratio / Verhouding L1 ✓RT ✓RT 1RT 165,52 E 165,52 : 169,62 1RT 169,92 1 : 1,025 ✓A 1A simplification (3) * F 1.1.4 Total price / Totale prys L1 E = R18,07 + R111,59 + R41,41 + R105,24 + R41,91 + R223,23 + R52,38 + R104,96 + R163,31 + R101,94 ✓MA 1MA adding all values = R964,04 ✓A 1A simplification (2) F 1.2.1 D ✓✓A 2A correct option L1 (2) E F 1.2.2 C ✓✓A 2A correct option L1 (2) E F 1.2.3 F ✓✓A 2A correct option L1 (2) E D 1.2.4 G ✓✓A 2A correct option L1 (2) E * D 1.3.1 Indian / Asian OR / OF L1 ✓✓RT Indiër / Asiaties 2RT correct population M (2) D 1.3.2 Discrete / Diskrete ✓✓A 2A correct classification L1 (2) E * D 1.3.3 Questionnaire / Survey / Census / Interview L1 ✓✓A 2A correct instrument E Vraelys / Opname / Sensus / Onderhoud (2) * D 1.3.4 60 604 992 ✓✓RT 2RT correct population total L1 (2) E D 1.3.5 49 070 809 ✓✓A 2A correct number L1 (2) E Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 4 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 4 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L D 1.3.6 Percentage / Persentasie L1 RT E 2 242 589 1RT both correct values =  100% MA 29 624 882 1MA percentage calculation = 7,569950827% A 1A simplification (3) [30] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 5 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 5 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 2 [32 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.1.1 Unemployment Insurance Fund / Werkloosheids- L1 versekeringsfonds ✓✓A 2A correct acronym E (2) F 2.1.2 SARS / SAID ✓✓A L1 E OR / OF 2A correct government institution South African Revenue Services / Suid-Afrikaanse Inkomstediens ✓✓A (2) F 2.1.3 Employer Medical Aid contribution / Werkgewer Mediese L2 fonds bydrae M = R2 531,54 ÷ 2 ✓MA 1MA divide by 2 = R1 265,77 ✓A 1A simplification OR / OF OR / OF Total Medical Aid contribution / Totale Mediese fonds bydrae 3 =  R2 531,54 2 = R3 797,31 Employer Medical Aid contribution / Werkgewer Mediese fonds bydrae = R3 797,31 ÷ 3 MA OR R3 797,31– R2 531,54 1MA divide by 3 = R1 265,77 A 1A simplification AO (2) F 2.1.4(a) A = R6 298 ✓✓RT 2RT correct value L2 (2) M Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 6 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 6 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L CA from Question 2.1.4 (a) F 2.1.4(b) B = Gross salary – UIF – PAYE Tax – medical aid L2 = Bruto salaris – WVF – LBS Belasting – mediese fonds M = R35 000 – R177,12 – R6 298 – R2 531,54 ✓MCA 1MCA subtracting values = R25 993,34 ✓CA 1CA simplification OR / OF OR / OF B = R35 000 – (R177,12 + R6 298 + R2 531,54) = R35 000 – R9 006,66 ✓MCA 1MCA subtracting total value = R25 993,34 ✓CA 1CA simplification AO (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 7 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 7 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.1.4(c) Annual taxable income / Jaarlikse belasbare inkomste L4 D = R35 000 × 12 = R420 000 A 1A annual taxable income Annual tax payable before rebates / Jaarlikse belasting betaalbaar voor kortings MCA 1MCA correct tax bracket = R77 362 + 31% of the taxable income above R370 500 = R77 362 + 31% (R420 000 – R370 500) = R77 362 + (31% × R49 500) = R77 362 + R15 345 = R92 707,00 CA 1CA simplification Annual tax payable after rebates/Jaarlikse belasting betaalbaar na kortings RT 1RT correct tax rebate = R92 707,00 – R17 235 – (R364 × 12) = R92 707,00 – R17 235 – R4 368 MA 1MA subtracting MTC = R71 104,00 CA 1CA simplification Monthly tax payable / Annual tax payable / Maandelikse belasting Jaarlikse belasting betaalbaar OR / OF betaalbaar = R71 104,00 ÷ 12 = R6 298 × 12 = R5 925,33 = R75 576 CA 1CA tax amount CA from Question 2.1.4 (a) Her statement is VALID / Haar bewering is GELDIG. O 1O conclusion (8) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 8 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 8 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.2.1 % paid / % betaal L2 M R4,20 = × 100% ✓MA 1MA dividing correct values R14,20 = 29,58% ✓A 1A simplification % savings / % besparing = 100% – 29,58% = 70,42% ✓CA 1CA simplification OR / OF OR / OF % savings / % besparing ✓MA 1MA subtracting correct R14, 20 − R4, 20 values =  100% R14, 20 ✓A 1A correct denominator = 70,42% ✓CA 1CA simplification (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 9 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 9 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.2.2 Cost per trip / Koste per rit L2 ✓RT 1RT R465,60 D R465, 60 = 1MA dividing by 44 44 ✓MA = R10,58 ✓CA 1CA simplification Saving per trip / Besparing per rit = R14,20 – R10,58 ✓MCA 1MCA subtracting values = R3,62 ✓CA 1CA simplification OR/OF OR/OF Total cost / Totale koste ✓RT 1RT R14,20 = R14,20 × 44 = R624,80 Difference / Verskil = R624,80 – R465,60 ✓MCA 1MCA subtracting values = R159,20 ✓CA 1CA simplification Saving per trip / Besparing per rit R159, 20 = 44 ✓MA 1MA dividing by 44 = R3,62 ✓CA 1CA simplification (5) P 2.2.3 Probability / Waarskynlikheid L2 E 0 2A correct probability = 0 / 0% / impossible / onmoontlik / ✓✓A 4 0 Accept: = 3 (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 10 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 10 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L * F 2.2.4 Package amount left / Pakketbedrag oor L3 M = R416,30 – R35,00 ✓RT 1RT R35 = R381,30 ✓A 1A simplification Number of weekly trips / Aantal weeklikse ritte ✓MCA 1MCA dividing values = R381,30 ÷ R127,10 OR R127,10 × 3 = 3 CA = R381,30 1CA simplification = R381,10 OR / OF OR / OF Package amount left / Pakketbedrag oor ✓RT 1RT R127,10 = R416,30 – R127,10 – R127,10 – R127,10 ✓MA 1MA subtracting values = R35 ✓A 1A simplification Number of weekly trips / Aantal weeklikse ritte = 3 CA 1CA simplification (4) [32] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 11 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 11 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 3 [30 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L * D 3.1.1 Median / Mediaan L2 M = 43% 46% 51% 54% 56% 57% ✓MA 1MA arranging values ✓RT 51% + 54% 1RT 51% and 54% = 2 ✓MA 1MA concept of median = 52,5% ✓CA 1CA simplification AO (4) P 3.1.2 Probability / Waarskynlikheid L2 ✓A M 4 1A numerator = 1A denominator 6 ✓A = 0,67 ✓CA 1CA simplification (3) D 3.1.3(a) Total number of users / Totale aantal gebruikers L2 M 100 ✓MA ÷ 54% OR ÷0,54 = 405 000 000  1MA percentage calculation 54 = 750 000 000 / 750 million / 750 miljoen ✓CA 1CA simplification OR / OF OR / OF Number of male users / Aantal manlike gebruikers 46 = × 405 000 000 54 = 345 000 000 ✓A 1A 345 000 000 Total number of users / Totale aantal gebruikers = 405 000 000 + 345 000 000 = 750 000 000 / 750 million / 750 miljoen ✓CA 1CA simplification AO (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 12 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 12 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L CA from Question 3.1.3 (a) D 3.1.3(b) Male users / Manlike gebruikers L4 M 46 ✓MCA = 750 000 000  1MCA calculating 46% 100 = 345 000 000 ✓CA 1CA simplification Difference / Verskil = 405 000 000 – 345 000 000 = 60 000 000 ✓CA 1CA difference Her statement is NOT VALID / Haar bewering is NIE GELDIG NIE. ✓O 1O conclusion OR / OF OR / OF Based on the answer of Question 3.1.3 (a) / Gebaseer op die antwoord in 3.1.3 (a) = 405 000 000 – 345 000 000 ✓✓MCA 2MCA difference = 60 000 000 ✓CA 1CA simplification Her statement is NOT VALID / Haar bewering is NIE GELDIG NIE. ✓O 1O conclusion OR / OF OR / OF Percentage difference / Presentasie verskil = 54% – 46% = 8% ✓CA 1CA percentage difference = 8% × 750 million / miljoen ✓MCA 1MCA calculating 8% = 60 000 000 ✓CA 1CA simplification Her statement is NOT VALID / Haar bewering is NIE GELDIG NIE. ✓O 1O conclusion (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 13 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 13 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L * D 3.2.1 Stacked bar graph / Stapelstaafgrafiek ✓✓A L1 E OR / OF 2A correct graph Compound bar graph / Saamgestelde staafgrafiek ✓✓A (2) D 3.2.2(a) Limpopo (LP) and North West (NW) / Limpopo (LP) en L2 Noordwes (NW) ✓✓A 2A correct pair of provinces M OR/OF OR/OF Mpumalanga (MP) and Eastern Cape (EC) / Mpumalanga (MP) en Oos-Kaap (OK) ✓✓A 2A correct pair of provinces (2) D 3.2.2(b) Number of devices in Limpopo 2022 / Aantal toestelle in L2 Limpopo 2022 M ✓RT 1RT both correct values = 11 000 000 – 4 000 000 ✓MA 1MA subtracting values = 7 000 000 OR 7 million / miljoen ✓CA 1CA simplification OR / OF OR / OF Number of devices in Limpopo 2022 / Aantal toestelle in Limpopo 2022 1RT both correct values ✓RT 1MA subtracting values = 18 500 000 – 4 000 000 – 7 500 000 ✓MA = 7 000 000 OR 7 million / miljoen ✓CA 1CA simplification AO (3) D 3.2.2(c) Provincial range 2021 / Provinsiale omvang 2021 L3 M Range = Highest Value – Lowest Value 1RT highest value ✓RT ✓RT 1RT lowest value Range = 16 000 000 – 1 000 000 ✓MA 1MA concept of range = 15 000 000 OR 15 million / miljoen ✓CA 1CA simplification AO (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 14 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 14 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L D 3.2.3 60 000 000 L3 D 50 000 000 40 000 000 31 500 000 ✓A 30 000 000 ✓A 20 000 000 14 000 000 ✓A 10 000 000 ✓A 0 2021 2022 2023 1A KwaZulu-Natal End point / Eindpunt: 31 500 000 1A KwaZulu-Natal complete stacked bar graph / Voltooi stapel-staafgrafiek 1A Mpumalanga End Point / Eindpunt: 14 000 000 1A Mpumalanga complete stacked bar graph / Voltooi stapel-staafgrafiek (4) P 3.2.4 Probability/Waarskynlikheid L2 E 2 ✓A 1A numerator = 1A denominator 9 ✓A (2) [30] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 15 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 15 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 4 [28 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L * ✓A ✓A 1A deposit F 4.1.1 Cost = R1 000 + (R500 × n) 1A variable cost L2 Koste = R1 000 + (R500 × n) M OR / OF OR / OF ✓A ✓A Cost = R1 000 + (R500 × number of days) 1A deposit Koste = R1 000 + (R500 × aantal dae) 1A variable cost (2) ✓A F 4.1.2 B = R1 000 + (R350 × 5) ✓MA 1MA multiplying values L2 1A adding R1 000 M = R2 750 ✓CA 1CA simplification OR / OF OR / OF ✓A B = R2 050 + R350 + R350 ✓MA 1A R2 050 1MA adding values = R2 050 + R700 = R2 750 ✓CA 1CA simplification AO (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 16 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 16 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 4.1.3 (a) Income for both trailers / Inkomste vir beide waentjies L4 ✓MA M = (R1 350 × 2) + (R1 500 × 6) 1MA multiplying values = R2 700 + R9 000 ✓A 1A simplification = R11 700 ✓CA 1CA simplification Total income after refund / Totale inkomste na terugbetaling = R11 700 – R7 000 ✓MCA 1MCA subtracting R7 000 = R4 700 ✓CA 1CA simplification Statement NOT VALID / Bewering is NIE GELDIG NIE.✓O 1O conclusion OF/OR OF/OR Income for small trailer / Inkomste vir klein waentjie = R350 × 2 ✓MA 1MA multiplying values = R700 ✓CA 1CA simplification Income for large trailer / Inkomste vir groot waentjie = R500 × 6 = R3 000 ✓A 1A simplification Total income after refund / Totale inkomste na terugbetaling = R700 + R3 000 + R1 000 ✓MCA 1MCA adding R1 000 = R4 700 ✓CA 1CA simplification Statement NOT VALID / Bewering is NIE GELDIG NIE.✓O 1O conclusion OF / OR OF / OR Total cost for all trailers / Totale koste vir alle waentjies ✓MA 1MA multiplying values = (R1 000 × 8) + R700 + R3 000 ✓MA 1MA adding values = R11 700 ✓CA 1CA simplification Total income after refund / Totale inkomste na terugbetaling = R11 700 – R7 000 ✓MCA 1MCA subtracting R7 000 = R4 700 ✓CA 1CA simplification Statement NOT VALID / Bewering is NIE GELDIG NIE.✓O 1O conclusion (6) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 17 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 17 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L * F 4.1.3(b) Labour cost / Arbeidskoste L4 M = R480 × 2 ✓MA 1MA multiplying by 2 = R960 ✓CA 1CA simplification Total cost / Totale koste = R960 + R242 = R1 202 ✓CA 1CA simplification The deposit of R1 000 will not be sufficient /Die deposito van R1 000 sal nie voldoende wees nie. ✓O 1O conclusion OR / OF OR / OF Remaining amount / Oorblywende bedrag ✓A 1A R480 = R1 000 – R480 – R480 – R242 ✓MCA 1MCA subtracting values = – R202 ✓CA 1CA simplification The deposit of R1 000 will not be sufficient /Die deposito van R1 000 sal nie voldoende wees nie. ✓O 1O conclusion (4) F 4.2.1 Value of V / Waarde van V L2 M = 25 593 ÷ 39 279 ✓MA 1MA dividing values = 0,651569541 ✓CA 1CA simplification = 0,652 ✓R 1R correct rounding OR / OF OR / OF 39 279 Vendors : R25 593 million 1 Vendor : ? 1 = × 25 593 ✓MA 1MA dividing values 39 279 = 0,651569541 ✓CA 1CA simplification = 0,652 ✓R 1R correct rounding AO (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 18 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 18 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L * D 4.2.2 Manufacturing / Vervaardiging ✓✓A 2A correct sector L1 (2) E * D 4.2.3 Mean in R million / Gemiddeld in R miljoen: L2 ✓MA 1MA adding values M (221322 + 73893 + 76826 + 25593 + 29418 + 32458 + 22141) = 7 481 651 = ✓MA 1MA concept of mean 7 = 68 807,29 ✓CA 1CA simplify NPU (3) ✓RT 1RT all correct values D 4.2.4(a) 2 658 15 258 33 825 39 279 46 901 86 610 197 178 1A ascending order L1 ✓A (2) E CA from Question 4.2.4a D 4.2.4(b) Inter–quartile range (IQR) = Q3 – Q1 L3 E 2 658 15 258 33 825 39 279 46 901 86 610 197 178 Q1 = 15 258 ✓A 1A 15 258 IQR = 86 610 – 15 258 ✓MCA 1MCA subtracting values IQR = 71 352 ✓CA 1CA simplification (3) [28] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 19 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 19 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 5 [30 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L F 5.1.1 Total maintenance cover for option B / Totale onderhouds- L1 dekking vir opsie B E ✓RT = £24 × 48 1RT £24 = £1 152 ✓CA 1CA simplification AO (2) ✓✓O F 5.1.2(a) The deposit and first-month instalment is much lower / L4 Die deposito en paaiement vir die eerste maand is heelwat E laer. OR / OF 2O reason Option A has a smaller deposit / Opsie A het ‘n kleiner deposito. ✓✓O (2) F 5.1.2(b) Total price excluding VAT / Totale prys BTW uitgesluit L3 ✓RT ✓A ✓A 1RT correct values D £1 173,66 + (£195,61 × 47) + (£25,36 × 48) 1A 47 instalments 1A 48 insurance payments = £1 173,66 + £ 9 193,67 + £ 1 217,28 ✓MCA 1MCA adding all values = £ 11 584,61 excl VAT ✓CA 1CA total excl VAT Total price including VAT / Totale prys BTW ingesluit ✓MCA 120 1MCA calculating VAT = £11 584, 61  £11 584,61 × 1,2 100 = £13 901,53 ✓CA 1CA total including VAT OR / OF OR / OF Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 20 Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 20 DBE/November 2025 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 5.1.2(b) Total price excluding VAT / Totale prys BTW uitgesluit L3 ✓RT ✓MA ✓MA 1RT £1 173,66 D £1 173,66 + (£195,61 × 47) + (£25,36 × 48) 1MA 47 instalments 1MA 48 insurance payments = £1 173,66 + £ 9 193,67 + £ 1 217,28 ✓MCA 1MCA adding all values = £ 11 584,61 excl VAT ✓CA 1CA total excl VAT VAT amount / BTW bedrag 20 = £11 584,61  ✓MCA 100 1MCA calculating VAT = £2 316,92 Total price including VAT / Totale prys BTW ingesluit = £11 584,61 + £2 316,92 = £13 901,53 ✓CA 1CA total including VAT OR / OF OR / OF Deposit and first instalment incl VAT / Deposito en eerste paaiement BTW ingsl ✓RT = £1 173,66 × 1,2 ✓MA 1RT £1 173,66 = £1 408,39 ✓CA 1MA calculating VAT 1CA total incl VAT Balance of instalments incl VAT / Balans van paaiemente BTW ingsl = £195,61 × 1,2 × 47 ✓A 1A 47 instalments = £11 032,40 Maintenance amount incl VAT / Instandhoudingskoste BTW ingesl = £25,36 × 1,2 × 48 ✓A 1A 48 insurance payments = £1 460,74 Total / Totaal = £1 408,39 + £11 032,40 + £1 460,74 ✓MCA 1MCA adding all values = £13 901,53 ✓CA 1CA total including VAT (7) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Text truncated here. 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