# Mathematical Literacy Grade 12 P2 NW June 2025 Memo (Eng)

> Grade 12 Mathematical Literacy Paper 2 memorandum from the NW June Exam 2025 (English), 9 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-12-mathematical-literacy-2025-nw-june-exam-question-paper-paper-2-english/d0aa859a-f0ef-4c4f-bfc2-9bd9f197c677
- Updated: 2026-10-29
- Subject: Mathematical Literacy
- Grade: Grade 12
- Language: English
- Document type: Memorandum
- Year: 2025
- Exam period: NW June Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 9

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Mathematical Literacy · Grade 12 · NW June Exam · 2025 · English. Memorandum. Read online or download the PDF.

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### Page 1

PROVINCIAL ASSESSMENT

                                           GRADE 12

                           MATHEMATICAL LITERACY P2
                                  JUNE 2025
                             MARKING GUIDELINES

MARKS: 100

         Symbol      Explanation
          MA         Method with accuracy
          MCA        Method with consistent accuracy
           CA        Consistent accuracy
            A        Accuracy
            C        Conversion
            S        Simplification
           RT        Reading from a table/a graph/document/diagram
           SF        Correct substitution in a formula
           O         Opinion/Explanation/Reasoning
            P        Penalty, e.g. for no units, incorrect rounding off, etc.
            R        Rounding off
          NPR        No penalty for correct rounding
           AO        Answer only

                            These marking guidelines consist of 9 pages.

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### Page 2

Mathematical Literacy/P2                       2                                     NW/June 2025
                                   Grade 12 – Marking Guidelines

NOTE:
  If a candidate answers a question TWICE, only mark the FIRST attempt.
  If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the
   solution, mark the crossed out (cancelled) version.
  Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it
   stops at the second calculation error.
  NOTE: consistent accuracy (CA) does not apply in cases of a breakdown.
  If the candidate presents any extra solution when reading from a graph, table, layout plan and
   map, then penalize for every extra item presented.
  General principle of marking, if the candidate makes one mistake one mark is deducted.
  Rounding is an independent mark.
  In opinion type questions marks will only be awarded if relevant calculations are shown.

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### Page 3

Mathematical Literacy/P2                       3                                     NW/June 2025
                                   Grade 12 – Marking Guidelines

 QUESTION 1 [20 MARKS] ANSWER ONLY FULL MARKS
 QUE Solution                                                              Explanation                 T/L
 1.1.1 Radius is the line drawn from the centre of a circle to a point on 2A explanation               M
       the circle.A                                                                                  L1
       OR
       Radius is the line joining the centre of a circle to a point on the
       circle.A
       OR Radius is half of a diameter.A                                                       (2)
 1.1.2 Scale is the factor that relates the measurement on paper with 2A explanation                   MP
       the real measurement.A                                                                        L1
       OR
       Scale is a ratio that gives the relationship between the
       measurement on paper and the real measurement.A
                                                                                                 (2)

 1.1.3    Probability is a chance/likelihood of an event to occur / 2A explanation                    P
          happen.A                                                                              (2) L1
 1.2.1    B A                                                     2A answer                         M
                                                                                                 (2) L1
 1.2.2    D A                                                          2A answer                    M
                                                                                                 (2) L1
 1.2.3    F A                                                          2A answer                    M
                                                                                                 (2) L1
 1.2.4    G A                                                          2A answer                    M
                                                                                                 (2) L1
 1.3.1    Bar scale OR Linear scale OR Graphic scale.A                 2A answer                    MP
                                                                                                  (2) L1
 1.3.2    5                                                            2A answer                    MP
                                                                                                  (2) L1
 1.3.3    PretoriaA                                                                                  MP
          JohannesburgA                                                                              L1
          OR                                                             1A answer
          MusinaA                                                       1A answer
          Accept WeipeA                                                  (2)
                                                                                             [20]

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### Page 4

Mathematical Literacy/P2                        4                                       NW/June 2025
                                    Grade 12 – Marking Guidelines

 QUESTION 2 [28 MARKS]
 Ques Solution                                                      Explanation                         T/L
 2.1  Limpopo riverA                                              2A answer                           MP
                                                                                                    (2) L1
 2.2      Probability = 0% A                                      2A answer                           MP
                                                                                                   (2) L2
 2.3      NWA                                                     2A answer                           MP
          OR                                                                                        (2) L2
          NorthwestA
 2.4      Measured length = 1,8 cm A                               1A measured distance                 MP
          1,8 cm: 125 kmMA                                         1MA correct ratio                    L4
          1,8 cm: 125 × 100 000 cm                                  1C conversion
          1,8 cm: 12 500 000 cmC                                   1S simplification
          1 : 6 944 444 S                                          1O opinion
          ∴The claim is not valid.O
          OR
          Measured length = 18 mm A
          18 mm: 125 kmMA
          18 mm: 125 × 1 000 000 mm
          18 mm: 125 000 000 mmC                                   [Accept 1,7 cm to 1,9 cm
          1 : 6 944 444 S                                          OR 17 mm to 19 mm]
          ∴The claim is not valid. O                                                              (5)
 2.5.1               1 852 𝑘𝑚                                       1SF substitution                     MP
          Time = 80 𝑘𝑚/ℎ SF
                                                                                                         L2
                 = 23,15 hoursS                                    1S simplification
                   A         A                                    1A hours
               = 23 hours and 9 minutes                             1A minutes
                                                                                                   (4)
 2.5.2    Total time for the trip                                   CA from Q2.5.1                       MP
          = 23 hours 9 min + 48 min + 1 hour 30 minMCA             1MCA adding correct values           L3
          = 25 hours 27 minutesCA                                  1CA total
                                                                    1CA day
          Day of arrival is Saturday CA= 24 hours
                                                                    1MCA addition
          Arrival time = 13:15 + 1:27MCA
                       = 14: 42CA                                  1CA arrival time
          OR                                                        OR
          Total time for the trip                                   1MA adding time spent at
          13:15 + 48 = 14:03MA                                     border
          14:03 + 1:30 = 15:33MCA                                  1MCA adding time spent at
                                                                    Bulawayo
                                                                    1MCA adding travelling time
          15:33 + 23:09 = 38:42MCA                                 1CA day
          Day of arrival = SaturdayCA at 14:42CA                  1CA arrival time
                                                                                              (5)
 2.5.3    Stretch legs OR Bathroom break OR Refreshments            2R reason                     MP
          OR Petrol OR Sight-seeingR                                                       (2) L4
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### Page 5

Mathematical Literacy/P2                        5                                      NW/June 2025
                                    Grade 12 – Marking Guidelines

 2.6.1    Livingstone islandA                                     2A answer                          MP
                                                                                                   (2) L1
 2.6.2    Turn right at the entrance then turn left A              1A turn right and left             MP
          At the crossroad turn rightA                             1A turn right                      L2
          Walk along the footpath, pass the right junctionA        1A pass right junction
          Turn left A                                              1A turn left
          Then you will be facing point ⑨                           OR
          OR                                                        1A turn right a
          Turn right at the entrance A                             1A turn left
          Pass toilets then turn left. A                           1A pass right
          Walk along the footpath then turn right at the            1A turn left
          T-JunctionA                                                                             (4)
          Turn left A
          Then you will be facing point ⑨
                                                                                               [28]

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### Page 6

Mathematical Literacy/P2                         6                                       NW/June 2025
                                     Grade 12 – Marking Guidelines

 QUESTION 3 [28 MARKS]
 Ques Solution                                                       Explanation                         T/L
 3.1.1 Perimeter is the total length around the borders of the       2A answer                           M
       silo.R                                                                                      (2) L1
 3.1.2 3 000 mm = 3 mC                                              1C conversion                       M
                       2
          Volume = s × h                                                                                 L2
                = (2,3 m)2 × 3 mSF                                  1SF substitution
                = 15,87 m3 S                                        1S simplification
                = 16 m3 R                                           1R rounding
                                                                                                     (4)
 3.1.3    Area = 4s × height + s
                               2
                                                                                                           M
              = 4 × 2,3 m × 3 m + (2,3 m)2 SF                       1SF substitution                      L3
                           2
               = 27,6 m + 5,29S                                     1S simplification
               = 32,89 m2S                                          1S simplification
           Total area for 3 silo covers = 3 × 32,89 m2 MCA          1MCA multiplying by 3
                                        = 98,67 m2 CA               1CA answer
                                                                                                 (5)
 3.1.4    To avoid damageR OR to protect them from                 2R reason                             M
          getting moistR OR to protect from rustingR                                             (2)   L4
          Accept any relevant reason
 3.2.1    3 962,5808 gallons = 3 962,5808 × 3,7854 litresC          1C conversion to litres               M
                              = 14 999,95336 litresS                1S simplification                     L2
                              = 15 000 litresR                      1R rounding
                              = 15 m3 C                             1C conversion to m3
          OR                                                         OR
          962,5808 gallons = 3 962,5808 × 3,7854 litresC            1C conversion to litres
                           = 14 999,95336 litresS                   1S simplification
                           = 14,99995336 m3 C                       1C conversion to m3
                           = 15 m3 R                                1R rounding
                                                                                                     (4)
 3.2.2                                                               CA from Q3.2.1                        M
          Radius = 2,3 m ÷ 2 = 1,15 mA                              1A radius                             L3
          15 m3 = 3,142 × (1,15 m)2 × hSF                           1SF substitution
                     15 𝑚3
          h = 3,142 × (1,15 𝑚)2MA
                                                                     1MA changing subject
          h = 3,609852008 mS
                                                                     1S simplification
                                                                     NPR
                                                                                                     (4)

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### Page 7

Mathematical Literacy/P2                             7                                       NW/June 2025
                                         Grade 12 – Marking Guidelines

 3.2.3    Total area to be painted = 3 × 34,33 m2 MA                    1MA multiplying by 3               M
                                   = 102,99 m2 A                        1A total area                      L4
                             102,99 𝑚2
          First coat paint = 9 𝑚2 /𝑙𝑖𝑡𝑟𝑒MCA
                                                                         1MCA dividing
                           = 11,443333333 litresCA                      1CA simplification

                                    102,99 𝑚2
          Subsequent coat paint = 12𝑚2 /𝑙𝑖𝑡𝑟𝑒
                          = 8,5825 litresS
          Total paint = 11,4433333333 litres + 8,5825 litres             1S simplification
                   = 20,026 litresCA OR 21 litresCA
          ∴ The claim is valid.O                                        1CA total paint
          OR                                                             1O opinion
                             34,33 𝑚2                                    OR
          First coat paint = 9𝑚2 /𝑙𝑖𝑡𝑟𝑒MA                               1MA dividing
                           = 3,814444444 litresS                        1S simplification
                                        34,33 𝑚2
          Subsequent coat paint = 12𝑚2 /𝑙𝑖𝑡𝑟𝑒
                           = 2,860833333 litresS
                                                                         1S simplification
          1 silo paint = 3,814444444 litres + 2,860833333 litres
                       = 6,675277777 litresCA
                                                                         1CA paint for 1 silo
          Total paint = 3 × 6,675277777 litres MCA                      1MCA multiplying by 3
                      = 20,02583333 litres CA                           1CA total paint
          ∴ The claim is valid.O                                        1O opinion
          OR                                                             OR
                             34,33 𝑚2
          First coat paint = 9𝑚2 /𝑙𝑖𝑡𝑟𝑒MA                               1MA dividing
                           = 3,814444444 litresS                        1S simplification
                                        34,33 𝑚2
          Subsequent coat paint = 12𝑚2 /𝑙𝑖𝑡𝑟𝑒
                           = 2,860833333 litresS                        1S simplification
          1 silo paint = 3,814444444 litres + 2,860833333 litres
                       = 7 litresCA                                     1CA paint for 1 silo
          Total paint = 3 × 7 litres MCA                                1MCA multiplying by 3
                      = 21 litres CA                                    1CA total paint
          ∴ The claim is valid.O                                        1O opinion

                                                                                                     (7)
                                                                                                    [28]

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### Page 8

Mathematical Literacy/P2                                 8                                        NW/June 2025
                                             Grade 12 – Marking Guidelines

 QUESTION 4 [24 MARKS]
 Ques Solution                                                               Explanation                          T/L
 4.1  Body Mass IndexA                                                     2A answer                            M
                                                                                                              (2) L1
 4.2      4 + 3 + 2 = 9A                                                    1A adding values                     M
                                  2                                                                2              L3
          Supper calories =           × 2 500MCA                            1MCA multiplying
                                  9                                                                9
                              = 555,55S                                     1S simplification
                              = 560R                                        1R rounding
          OR                                                                 OR
          4 + 3 + 2 = 9A                                                    1A adding values
                            2 500
          Unit calory =               CA
                              9                                              1CA unit calory
                     = 277,78
          Supper calories = 277,78 × 2MCA                                   1MCA multiplying by 2
                              = 555,555
                              = 560R                                        1R rounding
                                                                                                      (4)
 4.3                                      RT                                1RT correct male calories      M
          Maximum daily calory intake = 2 500 – 500MA                       1MA subtracting 500            L2
                                      = 2 000 caloriesCA                    1CA answer
                                                                                                        (3)
 4.4      170 cm = 1,7 mC                                                   1C conversion                  M
                      mass in kg                                                                            L3
          BMI =
                     (height in m)2                                          1SF substitution
                              𝑚𝑎𝑠𝑠
          23,1 kg/m =   2
                                       SF                                   1MA changing subject
                           (1,7 𝑚)2
                                                                             1A answer
          Mass = 23,1 kg/m2 × (1,7 m)2 MA
                                                                             NPR
               = 66,759 kgA
                                                                                                        (4)
 4.5      450° = (1,8 × ℃) + 32°SF                                          1SF substitution               M
          ℃ = (450° - 32°) ÷ 1,8MA                                          1MA changing subject           L4
          ℃ = 232,222°
          ℃ = 230°AR                                                        1AR rounded answer
          ∴ Mac converted correctly.O                                       1O opinion
                                                                                                              (4)
 4.6.1    Street mapA                                                      2A answer                              MP
                                                                                                              (2)   L1
 4.6.2    Francis Baard StreetA                                            2A answer                              MP
                                                                                                              (2)   L2

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### Page 9

Mathematical Literacy/P2                       9                                     NW/June 2025
                                   Grade 12 – Marking Guidelines

 4.6.3    Farenden Street; Arcadia StreetA                        1A first two correct streets     MP
          Beckett Street, Park StreetA                            1A second two correct streets L2
          Farenden Street A                                       1A last correct street
                                                                                                (3)
                                                                                              [24]

                                                                                       TOTAL: 100

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