# Mathematical Literacy Grade 12 P2 2026 Memo (Eng)

> Grade 12 Mathematical Literacy Paper 2 memorandum from the NSC November Prediction Exam 2026 (English), 10 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/grade-12-mathematical-literacy-2026-nsc-november-prediction-exam-memorandum-paper-2/78b8ea00-3906-4414-a74b-2e64005d989d
- Updated: 2026-10-29
- Subject: Mathematical Literacy
- Grade: Grade 12
- Language: English
- Document type: Memorandum
- Year: 2026
- Exam period: NSC November Prediction Exam
- Paper: 2
- Publisher: Hlayiso
- Curriculum: CAPS
- Pages: 10

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## About this document

Mathematical Literacy · Grade 12 · NSC November Prediction Exam · 2026 · English. Memorandum, 10 pages. Read online or download the PDF.

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## Document text

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### Page 1

hlayiso mock exams
                           Practice Series:
                           Grade 12 NSC Preparation
                           WWW.HLAYISO.COM

                                NATIONAL
                           SENIOR CERTIFICATE

                                    GRADE 12

                        MATHEMATICAL LITERACY P2
                      PREDICTION EXAMINATION 2026
                            MARKING GUIDELINES

MARKS: 150

                     These marking guidelines consist of 10 pages.

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### Page 2

Mathematical Literacy/P2                        2                             Hlayiso/Prediction 2026
                                      NSC – Marking Guidelines

SYMBOL AND EXPLANATION
 Symbol   Explanation                               Symbol    Explanation
 M        Method                                    A         Accuracy
 MA       Method with accuracy                      CA        Consistent accuracy
 MCA      Method with consistent accuracy           C         Conversion
 D        Definition                                SF        Substitution in a formula
 J        Justification                             O         Opinion/Reason/Conclusion
 P        Penalty (units, rounding)                 R         Rounding
 RT/RG/RM Reading from a table/graph/map            S         Simplification
 M/MP/P   Topic (Measurement/Maps/Prob.)            L1–L4     Taxonomy level
NOTE:

    • If a candidate answers a question TWICE, only mark the FIRST attempt.
    • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines. Stop marking at the
      second calculation error.
    • Answers only, without working, are awarded full marks unless the question requires calculations
      to be shown (e.g. “Verify, showing ALL calculations”).
    • For verification questions, the final conclusion (J/O) is only awarded if it is supported by
      calculations.
    • Measurements from the map and plan: accept a tolerance of ±2 mm (answer book printed at
      100% on A4). If the candidate’s measurements differ because of printing, mark CA from the
      candidate’s measured values.
    • The topic and taxonomy level of each item is shown at the bottom of the explanation column.

QUESTION 1 [28 MARKS]

 1.1.1       B                                                        ✓✓A correct letter
                                                                      M/L1                       (2)

 1.1.2       J                                                        ✓✓A correct letter
                                                                      MP/L1                      (2)

 1.1.3       H                                                        ✓✓A correct letter
                                                                      M/L1                       (2)

 1.1.4       D                                                        ✓✓A correct letter
                                                                      P/L1                       (2)

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### Page 3

Mathematical Literacy/P2                        3                             Hlayiso/Prediction 2026
                                      NSC – Marking Guidelines

 1.1.5       F                                                        ✓✓A correct letter
                                                                      M/L1                      (2)

 1.2.1       100 mℓ ÷ 1 000                                           ✓C dividing by 1 000
             = 0,1 ℓ                                                  ✓A answer in litres
                                                                      M/L1                      (2)

 1.2.2       4 years old: dose = 7,5 mℓ                               ✓RT correct dose
             Maximum = 4 × 7,5 mℓ                                     ✓A maximum volume
             = 30 mℓ                                                  M/L1                      (2)

 1.2.3       06:45 + 4 hours = 10:45                                  ✓M adding 4 hours
             = 10:45 a.m.                                             ✓A 12-hour format with a.m.
             (Accept 10:45 in the morning; 1 mark if not in 12-hour   M/L1                    (2)
             format)

 1.2.4       March 2027                                               ✓RT month
                                                                      ✓RT year
                                                                      M/L1                      (2)

 1.2.5       ◦ F = (1,8 × 25) + 32                                    ✓SF substitution of 25
             = 77 ◦ F                                                 ✓A answer
                                                                      M/L1                      (2)

 1.3.1       3 + 1 + 1 + 1 + 6 + 12 + 6                               ✓MA adding ALL quantities
             = 30 pieces                                              ✓A answer
                                                                      MP/L1                 (2)

 1.3.2       2 washers                                                ✓✓A answer
             (one on each side of the leg)                            MP/L1                     (2)

 1.3.3       D                                                        ✓RD letter
             Ash tray                                                 ✓RD name
                                                                      MP/L1                     (2)

 1.3.4       A                                                        ✓✓A correct letter
                                                                      M/L1                      (2)

                                                                                               [28]

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### Page 4

Mathematical Literacy/P2                          4                            Hlayiso/Prediction 2026
                                        NSC – Marking Guidelines

QUESTION 2 [32 MARKS]

 2.1.1       R528                                                      ✓✓RM correct road
                                                                       MP/L1                      (2)

 2.1.2       East                                                      ✓✓A direction
             (Accept east-north-east)                                  MP/L1                      (2)

 2.1.3       Ebenezer Dam                                              ✓✓RM correct dam
                                                                       MP/L1                      (2)

 2.1.4       Towns on the map: Polokwane, Mankweng,                    ✓RM 4 towns
             Haenertsburg, Tzaneen, Modjadjiskloof = 5                 ✓RM 5 towns
             Towns on the R71: Polokwane, Mankweng,                    ✓A percentage
             Haenertsburg, Tzaneen = 4                                 P/L2                       (3)
                               4
             P(town on R71) = × 100%
                               5
             = 80%
             (If Polokwane and Tzaneen are excluded as end points:
             2
             5 = 40%, max. 1 mark for the 5-town denominator)

 2.1.5       From the airport, travel south on the N1 to Polokwane.    ✓RM N1 south
             Turn left onto the R71 and travel east through            ✓RM R71 east
             Mankweng and Haenertsburg.                                ✓RM through the pass/past
             Continue on the R71 (north-east) through the              Haenertsburg
             Magoebaskloof Pass.                                       ✓RM left onto the gravel
             Turn left (north) onto the gravel road to the Debengeni   road
             Falls.                                                    MP/L2                    (4)

 2.1.6       Measured distance on map ≈ 12,8 cm                        ✓A measuring map distance
             (Accept 12,6 cm – 13,0 cm)                                ✓A measuring bar scale
             Bar scale: 1,8 cm represents 10 km                        ✓M dividing
             Distance =
                          12,8
                               × 10 km                                 ✓M multiplying by 10
                           1,8                                         ✓CA answer in km
             = 71,11 km                                                MP/L3                  (5)
             (Accept 70 km – 72,2 km)

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### Page 5

Mathematical Literacy/P2                         5                               Hlayiso/Prediction 2026
                                       NSC – Marking Guidelines

 2.1.7       Difference = 98 − 71,11 = 26,89 km                          ✓M difference
             % longer =
                         26,89
                               × 100%                                    ✓M percentage concept
                         71,11                                           ✓CA percentage
             = 37,8%                                                     ✓O conclusion
             37,8% > 30%, so his statement is VALID.                     MP/L4                      (4)
             OR
             130% × 71,11 km = 92,44 km; 98 km > 92,44 km ∴
             VALID
             (CA from 2.1.6)

 2.2.1       1 450 m                                                     ✓✓RG reading
             (Accept 1 440 m – 1 460 m)                                  MP/L1                      (2)

 2.2.2       1 380 − 700                                                 ✓RG both values
             = 680 m                                                     ✓A difference
             (Accept start 1 370 m – 1 390 m; answer 670 m – 690         MP/L2                      (2)
             m; CA from readings)

 2.2.3       Time = 09:10 − 07:40 = 1 h 30 min = 1,5 h                   ✓A 1 h 30 min
             Speed =
                      distance 34 km
                              =                                          ✓C 1,5 h
                        time    1,5 h                                    ✓M dividing distance by
             = 22,67 km/h                                                time
                                                                         ✓CA speed
                                                                         MP/L3                      (4)

 2.2.4       Any ONE, e.g.                                               ✓✓O valid reason
             • The cyclists have just finished the long uphill climb     MP/L4                      (2)
             and will be tired and thirsty.
             • It is before the long, fast descent where cyclists
             cannot easily stop to drink.
             • It is the highest and most strenuous point of the race.

                                                                                                   [32]

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### Page 6

Mathematical Literacy/P2                        6                              Hlayiso/Prediction 2026
                                      NSC – Marking Guidelines

QUESTION 3 [32 MARKS]

 3.1.1       2 (the front door and the back door)                      ✓✓A answer
                                                                       MP/L1                      (2)

 3.1.2       North                                                     ✓✓A direction
             (the front door opens onto the stoep)                     MP/L1                      (2)

 3.1.3       Measured length = 14 cm (Accept 13,8 cm – 14,2 cm)        ✓A measurement
             10,5 m = 1 050 cm                                         ✓C converting to cm
             Scale = 14 : 1 050                                        ✓M ratio in the same units
             = 1 : 75                                                  ✓CA scale in the form 1 : …
             (Accept 1 : 74 – 1 : 76; CA from measurement)             MP/L3                     (4)

 3.1.4       In South Africa (southern hemisphere) the sun is in the   ✓✓O valid reason
             northern sky, so the north-facing living room receives    MP/L4                      (2)
             the most sunlight: it is warmer in winter and has more
             natural light during the day.
             (Accept: saves electricity for heating/lighting)

 3.2.1       Living room = 6 × 4,8 = 28,8 m2                           ✓SF living room dimensions
             Kitchen = 3,6 × 2,4 = 8,64 m2                             ✓A 28,8 m2
             Total = 28,8 + 8,64                                       ✓A 8,64 m2
             = 37,44 m2                                                ✓M adding
                                                                       (Answer given: no mark for
                                                                       37,44 only)
                                                                       MP/L2                    (4)

 3.2.2       Area of one tile = 0,6 × 0,6 = 0,36 m2                    ✓C 0,6 m
             Tiles = 37,44 ÷ 0,36 = 104                                ✓A 104 tiles
             With 10% extra: 104 × 1,1 = 114,4 ≈ 115 tiles             ✓M 10% extra
             Boxes = 115 ÷ 4 = 28,75                                   ✓M dividing by 4
             ≈ 29 boxes                                                ✓R rounding up to 29
             OR                                                        M/L3                       (5)
             Living room: 10 × 8 = 80 tiles; kitchen: 6 × 4 = 24
             tiles; total 104 tiles …

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### Page 7

Mathematical Literacy/P2                        7                              Hlayiso/Prediction 2026
                                      NSC – Marking Guidelines

 3.2.3       Tiles = 29× R289,90 = R8 407,10                           ✓CA cost of tiles
             Adhesive: 37,44 ÷ 5 = 7,488 ≈ 8 bags                      ✓R 8 bags
             8× R139,95 = R1 119,60                                    ✓A cost of adhesive
             Grout = 2× R89,99 = R179,98                               ✓A grout
             Labour = 37,44× R110 = R4 118,40                          ✓A labour
             Total = R8 407,10 + R1 119,60 + R179,98 +                 ✓CA total
             R4 118,40                                                 ✓O conclusion
             = R13 825,08                                              M/L4                       (7)
             R13 825,08 < R14 000, so the budget IS enough.
             (CA from 3.2.2)
             If adhesive is calculated on 41,18 m2 : 9 bags =
             R1 259,55, total R13 965,03 < R14 000; award R for 9
             bags but max. 6/7 (wrong area). If labour is calculated
             on 41,184 m2 : R4 530,24, total R14 236,92 > R14 000,
             NOT enough; penalise once (labour A mark), CA for
             total and conclusion.

 3.3.1       Radius = 4,2 ÷ 2 = 2,1 m                                  ✓A radius
             Area = 21 × 3,142 × (2,1)2                                ✓SF substitution
             = 6,93 m2                                                 ✓CA area
                                                                       M/L2                       (3)

 3.3.2       Diameter on drawing = 420 cm ÷50 = 8,4 cm (radius         ✓C 8,4 cm diameter (4,2 cm
             4,2 cm)                                                   radius)
                                                                       ✓A semicircle shape (curved
                                                                       arc and straight diameter)
                                                                       ✓A accurate size (±2 mm)
                                                                       MP/L2                      (3)

                       8,4 cm
             (diagram not to scale in this memo)

                                                                                                 [32]

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### Page 8

Mathematical Literacy/P2                        8                         Hlayiso/Prediction 2026
                                      NSC – Marking Guidelines

QUESTION 4 [32 MARKS]

 4.1.1       7,5 ÷ 2                                             ✓M dividing by 2
             = 3,75 cm                                           ✓A radius
                                                                 M/L1                       (2)

 4.1.2       Volume = 3,142 × (3,75)2 × 10                       ✓SF radius
             = 441,84 cm3                                        ✓SF height
                                                                 ✓CA volume
                                                                 M/L2                       (3)

 4.1.3       Mass of one candle = 0,9 × 441,84 = 397,66 g        ✓M density concept (mass =
             Mass for 60 candles = 60 × 397,66 = 23 859,6 g      density × volume)
             = 23,86 kg                                          ✓A 397,66 g
             Slabs = 23,86 ÷ 5 = 4,77                            ✓M ×60
             ≈ 5 slabs                                           ✓C g to kg (or 5 kg = 5 000
                            12
             OR (wax only, 13  of the mass): 22,02 kg            g)
             ÷5 = 4,40 ≈ 5 slabs                                 ✓M dividing by 5
             (CA from 4.1.2)                                     ✓R rounding up to 5
                                                                 M/L3                      (6)

 4.1.4       Fragrance oil = 23 859,6 ÷ 12 = 1 988,3 g           ✓M using the ratio
             Bottles = 1 988,3 ÷ 250 = 7,95                      ✓M dividing by 250
             ≈ 8 bottles                                         ✓R 8 bottles
                      1
             (Accept 13  of the total mass: 1 835,4 g            M/L2                       (3)
             ÷250 = 7,34 ≈ 8)

 4.1.5       Circumference = 3,142 × 7,5 = 23,565 cm             ✓SF circumference
             Length of label = 23,565 + 1 = 24,565 cm            ✓M adding the overlap
             Area = 24,565 × 6                                   ✓M multiplying by 6
             = 147,39 cm2                                        ✓CA area
             (Without the overlap: 141,39 cm2 , max. 3 marks)    M/L2                       (4)

 4.1.6       185 = (1,8 × ◦ C) + 32                              ✓SF substitution of 185
             ◦ C = 185 − 32                                      ✓M changing the subject
                      1,8                                        ✓A answer
             = 85 ◦ C                                            M/L2                       (3)

 4.2.1       (a) L                                               ✓A (a)
             (b) R                                               ✓A (b)
             (c) LLa                                             ✓A (c)
                                                                 P/L2                       (3)

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### Page 9

Mathematical Literacy/P2                         9                              Hlayiso/Prediction 2026
                                       NSC – Marking Guidelines

                           1
 4.2.2       P(L and R) =                                               ✓A numerator
                           6
             (Accept 0,17 or 16,67%)                                    ✓A denominator
                                                                        P/L2                      (2)

 4.3         Box: 12 × 2,54 = 30,48 cm; 9 × 2,54 = 22,86 cm;            ✓C converting the
             4 × 2,54 = 10,16 cm                                        dimensions
             Height: 10,16 cm > 10 cm, so the candles fit upright.      ✓A height check
             Along the length: 30,48 ÷ 7,5 = 4,06 → 4 candles           ✓M dividing by 7,5
             Along the width: 22,86 ÷ 7,5 = 3,05 → 3 candles            ✓R 4 and 3 (rounding down)
             Number of candles = 4 × 3 = 12                             ✓CA 12 candles
             Her claim is VALID.                                        ✓O conclusion
             (If a candidate argues, with calculations, that the wick   M/L4                    (6)
             makes the candle taller than 10,16 cm and concludes
             NOT VALID: award the O mark.)

                                                                                                 [32]

QUESTION 5 [26 MARKS]

 5.1.1       37 × 30,48 = 1 127,76 cm                                   ✓C feet to cm
             11 × 2,54 = 27,94 cm                                       ✓C inches to cm
             Total = 1 127,76 + 27,94 = 1 155,70 cm                     ✓M adding
             = 11,56 m                                                  ✓C cm to m
                                                                        M/L2                      (4)

 5.1.2       Width = 7 × 30,48 + 6 × 2,54 = 228,6 cm = 2,286 m          ✓C width in metres
             Across the width: 2,286 ÷ 1,0 = 2,29 → 2 pallets           ✓M dividing
             Along the length: 11,56 ÷ 1,2 = 9,63 → 9 pallets           ✓R 2 and 9 (rounding down)
             Maximum = 2 × 9 = 18 pallets                               ✓CA 18 pallets
             (CA from 5.1.1)                                            M/L3                    (4)

 5.1.3       Mass of one loaded pallet = 80 × 15 + 25 = 1 225 kg        ✓M cartons × 15 kg
             18 pallets = 18 × 1 225 = 22 050 kg                        ✓M adding the pallet
             In pounds: 22 050 × 2,2046 = 48 611,43 lb                  ✓A 22 050 kg
             48 611,43 lb < 64 500 lb                                   ✓C conversion
             The payload will NOT be exceeded, so his statement is      ✓A comparing
             NOT VALID.                                                 ✓O conclusion
             OR                                                         M/L4                      (6)
             64 500 ÷ 2,2046 = 29 257,01 kg; 22 050 kg
             < 29 257,01 kg ∴ NOT VALID

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### Page 10

Mathematical Literacy/P2                         10                               Hlayiso/Prediction 2026
                                       NSC – Marking Guidelines

 5.2.1       6 900 × 1,852                                               ✓C multiplying
             = 12 778,8 km                                               ✓A answer
                                                                         M/L1                        (2)

                     6 900
 5.2.2       Time =        = 405,88 hours                                ✓M dividing distance by
                       17
             = 16 days 21,88 hours                                       speed
             0,88 × 60 ≈ 53 min → 16 days 21 h 53 min                    ✓A 405,88 h
             Mon 2 Nov 16:00 + 16 days = Wed 18 Nov 16:00                ✓M converting to days and
             + 21 h 53 min → Thursday 19 November 2026 at                hours
             13:53                                                       ✓CA day and date
             (Accept 13:52 – 13:54)                                      ✓CA time
                                                                         M/L3                    (5)

                        3
 5.3         Valencia = × 1 440                                          ✓M total parts (8)
                        8
             = 540 cartons                                               ✓M 83 of 1 440
                                                                         ✓A answer
                                                                         M/L2                        (3)

 5.4         Any ONE, e.g.                                               ✓✓O valid reason
             • The voyage takes more than two weeks; cooling             M/L4                        (2)
             keeps the oranges fresh and stops them from ripening
             too fast or rotting.
             • Export/quality regulations require the fruit to be kept
             cold (cold sterilisation against pests).

                                                                                                    [26]

                                                                                        TOTAL:        150
Topic and level summary: Measurement 86 marks; Maps, plans and other representations 54 marks; Probability
10 marks. L1 44 (29%), L2 44 (29%), L3 33 (22%), L4 29 (19%).

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